Answer:
encourage all attempts at reading, writing, and speaking
Explanation:
Topic : Collisions and Conservation of Momentum
1. Two children are standing still on ice and push off each other. Each has a momentum after the push. Do they violate the conservation of law? Initial momentum is zero.
2. Describe how the conservation law works with elastic and inelastic collisions.
3. In general, for elastic collisions with stationary objects, when will the first object bounce back? When will it follows the stationary object after the collision?
4. What is the use of airbags in vehicles?
5. Why are seatbelt designed to be stretchable?
It is amount of force or motion that cause the movement or moving of body.
Thus it is well explained.
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1.No they do not violate the conservation of law. Because the initial momentum can be zero.
2. The momentum is conserved in both elastic and inelastic collision.
What is the law of conservation of momentum?The momentum of the body before the contact is always equal to the momentum of the body after the impact, according to the rule of conservation of momentum.
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
[tex]\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)[/tex]
1.No they do not violate the conservation of law. Because the initial momentum can be zero.
2. The momentum is conserved in both elastic and inelastic collision. Hence the conservation law works with elastic and inelastic collisions.
3. An elastic collision is one in which kinetic energy is conserved, meaning that the total kinetic energy before and after the impact is the same.
The object bounces once after the body gets struck. When the body's final velocity is zero it follows the stationary object after the collision.
4.. Airbags are meant to inflate automatically in the case of an abrupt deceleration or impact force indicative of a collision.
When the bag is fully inflated, it protects the driver and/or passenger by Increasing cushioning around the driver's neck, head, and spine.
5. Stretchable seatbelts are meant to allow a passenger's considerable velocity to be slowly reduced, preventing the passenger from being flung forward abruptly.
As a result, if the automobile collides, serious casualties can be avoided.
Hence no they do not violate the conservation of law. Because the initial momentum can be zero.
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The resistance of a 60.-watt lightbulb operated at
120 volts is approximately
Answer:
The resistance of a 60 watt light bulb designed to operate at 120 volts is 240 Ω.
Explanation:
Please help solve. Image down below
Answer:
thats is so hard
Explanation:
i cant answer that
A pendulum bob has it maximum speed at 3ms at the lowest position 0. Calculate the height of the bob above 0,where it velocity is 0
Hello!
We know that at the BOTTOM of the pendulum's trajectory, the bob has a maximum speed. This means that its KINETIC ENERGY is at a maximum, while its Gravitational POTENTIAL ENERGY is at a minimum.
On the other hand, when the bob is at its highest points, the bob has a velocity of 0 m/s, so its KE is at a minimum and its PE is at a maximum.
We can use the work-energy theorem to solve. Let the Initial Energy equal the bob's energy at one of the sides, while the final Energy equals the bob's energy at the bottom.
[tex]E_i = E_f\\\\PE = KE[/tex]
Recall that:
PE = mgh
m = mass (kg)
g = acceleration due to gravity (m/s²)
h = height (m)
KE = 1/2mv²
m = mass (kg)
v = velocity (m/s)
Set the two equal and solve for 'h'.
[tex]mgh = \frac{1}{2}mv^2[/tex]
Cancel mass.
[tex]gh = \frac{1}{2}v^2[/tex]
Solve for 'h'.
[tex]h = \frac{v^2}{2g}\\\\h = \frac{3^2}{2(9.8)} = \boxed{0.459 m}[/tex]
A basketball player must jump 1.2m in the air in order to dunk. What is the total time he is in the air?
Answer:
0.98 [sec].
Explanation:
1) the time when the player is moving up equals the time the player falls, it can be 't'. Then
2) the equation of moving down can be written as
[tex]\frac{g*t^2}{2} =h, \ where[/tex]
g=10 [m/s²], t - time, h - the given height.
3) according to the formula above the time spent to moving down is:
[tex]t=\sqrt{\frac{2h}{g}};[/tex]
[tex]t=\sqrt{\frac{2.4}{10}}=\sqrt{0.24} =0.49[s].[/tex]
4) finally, the total time is t*2=0.98[sec].
As a block falls through the air by 40 meter it does work equal to -1800 joule. Determine the mass of a block.
Answer:
m = 4.5 kg
Explanation:
w = - 1800 j
Fd = - 1800 j
mgd = - 1800 j
m = - 1800 ÷(gd)
m = - 1800 ÷( 10×-40)
m = 4.5 kg
The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. The lift of a wing with an area
of 280 square feet is 27,800 pounds when the plane is going 220 miles per hour. Find the lifting force on the wing if the plane slows down to 130 miles per hour.
(Leave the variation constant in fraction form or round to at least 5 decimal places. Round off your final answer to the nearest pound.)
Answer:
If the lifting force varies jointly with wing surface area and the square of the plane's velocity, then:
F = kAv²
If the lift is 27,800 pounds when the area is 190 sq. ft and the velocity is 230 mph, then the constant of proportionality is:
27,800 = k(190)(230)²
k = (27,800) / (190)(230)² = 139/50255
The lifting force the plane slows down to 200 mph is:
F = (139/50255)(190)(200)²
F = 21,020.79
Rounded to the nearest pound, the lifting force is 21,021 pounds.
You are riding a bicycle up a gentle hill. It is fairly easy to increase your potential
energy, but to increase your kinetic energy would be harder.
True or false
Need help with the following - question 2
Answer:
Find the change in momentum of the upper stage, that is:
∆p = m(vf - vi)
m being the mass of the upper stage
vf being the final velocity which was given
vi being the initial which was also given
find ∆p
then use ∆p in the same equation
∆p being the answer you got above
m being the mass of the lower stage (given)
vi being the initial velocity (given)
vf being the final velocity of the lower stage which you were asked to find
Explanation:
During a collision the change in momentum (∆p) for both objects is equal regardless of their speeds or masses before or after the equation
Find out the three methods of energy transfer (conduction, convection and radiation). think about
2 situations of daily life where you know or think you know that each one applies
Explanation:
conduction- putting a metal spoon in fire
convection- boiling water. In ventilation
Radiation- suns heat reaches us by radiation. heat from fire place reaches us by radiation.
help me get a answer
Answer:
I think D sorry if I'm wrong
Which statement correctly describes the relationship between frequency and wavelength?
A :As the frequency of a wave increases, the longer its wavelength is
B: As the frequency of a wave increases, the shorter its wavelength is.
C: As the frequency of a wave increases, its wavelength remains the same.
Answer:
It is B
Explanation:
Option B talks about how the frequency of the wave increases the shorter it's wavelengths
Answer:
It's b
Explanation:
A horizontal push of 197 N is applied to a 49.1 kg crate to slide it along a level floor. The crate is accelerating at 3.337 m/s2 (speeding up). What is the magnitude of the kinetic friction force between the crate and the floor
The magnitude of the kinetic friction force between the crate and the floor is 33.15 N.
Kinetic frictional force
The magnitude of kinetic frictional force is determined by applying Newton's second law of motion as shown below;
F - Ff = ma
where;
Ff is kinetic frictional forcea is acceleration of the crateF is the applied forceSubsitute the given parameters and solve for kinectic frictional force
197 - Ff = 49.1(3.337)
197 - Ff = 163.85
Ff = 33.15 N
Thus, the magnitude of the kinetic friction force between the crate and the floor is 33.15 N.
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. A rope is being used to pull a mass of 10 kg vertically upward. Determine the tension on the rope, if starting from rest, the mass acquires a velocity of 4 ms-1 in 8s [g= 10ms-2]
[tex]\text{Given that,}\\\\\text{Mass, m =10 kg}\\\\\text{Time, t = 8 sec}\\\\\text{Velocity, v = 4~m/s}\\\\\text{When a body is moving upwards,}\\\\\text{Tension,}~ T=mg +ma\\\\~~~~~~~~~~~~~~~=mg+m\left(\dfrac{v-u}t \right)\\\\~~~~~~~~~~~~~~~=10(10)+10\left(\dfrac{4-0}8\right)\\\\~~~~~~~~~~~~~~~=100+10\left(\dfrac 12\right)\\\\~~~~~~~~~~~~~~~=100+5\\\\~~~~~~~~~~~~~~~=105~N[/tex]
Which of the following is NOT an example of force?
A. gravity
B. mass
C. a push
D. remain at rest
Answer:
D. remain at rest
Explanation:
ions, giving canoe 1 a speed of 0.58 m>s and canoe 2 a speed of 0.42 m>s. If the
Answer:
Draw a table showing the different forms of the first law for the four processes described.
Select the correct answer. Based on the law of conservation of energy, which statement is correct? O A. Energy is always being added to all parts of the Universe. O B. Energy is often destroyed in some parts of the Universe. O C. Energy in a closed system cannot change forms. O D. Energy in an isolated system remains constant.
Answer:
d. energy in an isolated system remains constant.
Explanation:
energy can neither be replaced or destroyed
A curve is banked at an angle of 29.1 degrees above the horizontal and the road surface has a coefficient of static friction of 0.4. What must the radius of curvature be for the safe minimum speed of 27.1 m/s?
Hi there!
We can begin by summing the forces acting on the car.
Along the axis of the incline, the forces of friction and gravity are working. The force of friction points towards the top of the ramp, while the force of gravity works towards the bottom.
We can use trigonometry to determine the force due to gravity along the ramp.
[tex]F_g = Mg sin\theta[/tex]
The force due to friction is equal to:
[tex]F_f = \mu N[/tex]
The normal force is the vertical component of the force due to gravity, so:
[tex]F_f = \mu Mgcos\theta[/tex]
Now, the combination of these two forces produces a component of the centripetal force. Drawing a diagram, we see that the true centripetal force is the HYPOTENUSE, while these forces sum up to its horizontal component along the ramp.
Therefore:
[tex]F_c sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]
The centripetal force is equivalent to:
[tex]F_c = \frac{Mv^2}{r}[/tex]
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Rewrite:
[tex]\frac{Mv^2}{r}sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]
Cancel out 'M'.
[tex]\frac{v^2}{r}sin\theta = gsin\theta - \mu gcos\theta[/tex]
Rearrange to solve for 'r'.
[tex]r = \frac{v^2sin\theta}{gsin\theta - \mu gcos\theta}[/tex]
Plug in values and solve.
[tex]r = \frac{(27.1^2)sin(29.1)}{(9.8)sin(29.1) - 0.4(9.8)cos(29.1)} = \boxed{266.365 m}[/tex]
match each term to its definition.
the vocabulary
Volt
electric potential energy
electric potential difference
electric potential
the definitions
the SI unit of electric potential difference
difference in electric potential between two positions
potential energy an electric charge has due
to its location in a field
electric potential energy of a charged particle divided by its charge
here are the answers
Electric potential difference is the difference in electric potential between two positions and it is measured in volts.
What is electric potential energy?This is the potential energy of an electric charge has due to its location in a field.
What is electric potential?The electric potential of a charged particle is the electric potential energy of the charged particle divided by its charge magnitude.
What is electric potential difference?Electric potential difference is the difference in electric potential between two positions.
What is volt?Volt is the SI unit of electric potential difference.
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I NEED HELP FAST
Match the term with the appropriate image
A) Focal length
B) Object position
C) Image position
1st image - B) Object position
2nd image - A) Focal length
3rd image - C) Image position
object position is from the lens to the object.image position is from the lens to where both rays meet together.Focal length is where the ray meets the principal axis.The gauge pressure in a balloon in measured by means of an open-tube manometer that uses water (density=1.00×103 kg/m3) . What gauge pressure is indicated by a difference of 0.0171 m in the heights of the water columns?
The gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is 167.58 Pa.
Gauge pressure of the balloon
The gauge pressure in the balloon is the pressure inside the balloon due to the water columns relative to the atmospheric pressure.
The gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is calculated as follows;
P = ρgΔh
P = (1,000)(9.8)(0.0171)
P = 167.58 Pa
Thus, the gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is 167.58 Pa.
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static frictional Force
Answer:
The static frictional force is the force between the magnetic forces statically and contains only two objects during this physical reaction. It results in electricity and a slight shock.
A women runs a kilometer using a of 210N and a pwower output of 500W how long does it take this woman to complete 1 kilometer
Answer:
7 minutes
Explanation:
Explanation:
Power = work / time
Power = force × distance / time
500 W = 210 N × 1000 m / t
t = 420 s
t = 7 min
A man of mass 70 kg climbs stairs of vertical height 2.5m. Calculate the work done against the force of gravity. (Take g = 9.81 ms?)
Answer:
1716.75 J
Explanation:
Step 1: First check what we are provided with. As per given question we have:
mass (m) = 70 kg, height (h) = 2.5 m and acceleration due to gravity (g) = 9.81 m/s².
Step 2: Check what we are asked to find out.
Work done = Change in Potential energy
The stuff required to solve this question is potential energy. Using the formula: P = mgh. Where P is Potential energy, m is mass, g is acceleration due to gravity and h is height.
Step 3: Substitute the known values in the above formula.
→ P = 70 × 2.5 × 9.81
→ P = 1716.75 J
Hence, the work done against the force of gravity is 1716.75 J.
Examine the image below:
Which term describes the wave phenomenon in the image?
Answer:
C
Explanation:
Reflection.
Read the materials on Biomolecules. Summarize and creatively translate them into a poem describing
what you have learned about biomolecules write your answer
Biomolecules are fundamental for life. They required both energy supply and building structures.
What are biomolecules?Biomolecules are organic molecules that fundamental for life and must be ingested from the regular diet.
Biomolecules include proteins (e.g., meal proteins), lipids (fats) and also carbohydrates (e.g., glucose).
Biomolecules required both energy supply (e.g., glucose) and building structures (e.g., amino acids in proteins).
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the taipei 101 in taiwan is a 1667-foot tall, 101-story skyscraper. the skyscraper is the home of the world's fastest elevator. the elevators transport visitors from the ground floor to the observation deck on the 89th floor at speeds up to 16.8 m/s. determine the power delivered by the motor lift the 10 passengers at this speed. the combined mass of the passengers and cabin is 1250 kg
The power delivered by the motor lift in elevating the 10 passengers at the speed of 16.8 m/s is 205800 Watts
What is power?Power is simply defined as the rate at which energy is consumed. It can be expressed mathematically as
Power (P) = Force (F) × velocity (v)
P = Fv
How to determine the force Mass (m) = 1250 KgAcceleration due to gravity (g) = 9.8 m/s²Force (F) =?F = ma
F = 1250 × 9.8
F = 12250 N
How to determine the power Velocity (v) = 16.8 m/sForce (F) = 12250 NPower (P) =?P = Fv
P = 12250 × 16.8
P = 205800 Watts
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Explain why is dressing table mirror may become dirsty if wiped with a cloth on a warm day.
When you rub a dry cloth across glass, it creates charged static electricity, which attracts little non-charged dust particles.
How fast must a proton move so that its kinetic energy is 70% of its total
energy?
I thought it would be 0.7c but that is wrong. I really don't know how to do this type of problem and my text book isn't any help.
Try this solution, all the details are in the attachment. note, the answer is marked with orange colour. If it is possible, check the provided solution in other sources.
Answer: ≈0.81c.
An experiment is set up as follows:
A mass m = 9.4kg is sent down a frictionless ramp with an initial velocity of 2.5m/s. The ramp is 87cm
long and has an angle of 36°above the horizontal. At the bottom of the ramp is a horizontal surface with a
kinetic friction coefficient of μk = 0.27. At the far side of the horizontal surface, 48cm away, is a spring with
k-constant ks = 3,413.7N
m that will be compressed as the mass collides with the spring. The experiment
ends as the spring is fully compressed and the mass is at rest.
Note: The distance that the spring is compressed is in addition to the 48cm.
7) Find the initial energy of the mass. (10pts)
8) How far will the spring compress if there is no surface friction under the spring? (10pts)
9) How far will the spring compress if the surface friction continues under the spring? (20pts)
(a) The initial energy of the mass is 76.485 J.
(b) The compression of the spring in the absence of friction is 21.2 cm.
(c) The compression of the spring in the presence of friction is 19.4 cm.
Initial energy of the massThe initial energy of the mass is determined as follows;
E = K.E + P.E
E = ¹/₂mv² + mgh
where;
h is the height of the rampE = ¹/₂mv² + mg x Lsinθ
P.E = ¹/₂(9.4)(2.5)² + (9.4)(9.8)(0.87)(sin36)
P.E = 76.485 J
Compression of the spring when there is no surface tensionThe compression of the spring in the absence of friction is calculated as follows;
Ux = E
¹/₂kx² = 76.485
kx² = 2(76.485)
x² = (2 x 76.485)/k
x = √(2 x 76.485)/k
x = √(2 x 76.485 / 3413.7)
x = 0.212 m
x = 21.2 cm
Compression of the spring in presence of frictionThe compression of the spring in the presence of friction is determined by applying the principle of conservation of energy.
E - Fd = Ux
E - μmgd = ¹/₂kx²
76.11 - (0.27 x 9.4 x 9.8 x 0.48) = ¹/₂(3413)x²
64.17 = 1706.5x²
x² = 0.0376
x = √0.0376
x = 0.194
x = 19.4 cm
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