Dylan owns a bag that contains 7 blue marbles, 5 purple marbles, 12 red marbles, and 6 orange marbles. If he randomly pulls a marble from the bag, What is the probability of him pulling a red marble? What is the probability of him pulling a blue or purple marble?

Answer: 26 degrees

Step-by-step explanation:

An interior angle and its exterior angle are supplementary.

Answer:

you cant see the picture

Step-by-step explanation:

Answer:

14/23

Step-by-step explanation:

There are 253 tokens in all. Since 77 are blue and 77 are green, the probability of selecting either a blue token or a green token is 154/253, which reduces to 14/23.

[tex]a = 6(4) - 3 = 24 - 3 = 21[/tex]

Let's see

[tex]\\ \rm\rightarrowtail (fog)(x)=f(g(x))[/tex]

[tex]\\ \rm\rightarrowtail f(5x-4)=20x+p[/tex]

[tex]\\ \rm\rightarrowtail 4(5x-4)+3=20x+p[/tex]

[tex]\\ \rm\rightarrowtail 20x-16+3=20x+p[/tex]

[tex]\\ \rm\rightarrowtail -13=p[/tex]

Answer:

[tex]\sf p = -13[/tex]

Step-by-step explanation:

Given functions:

[tex]\sf f(x)=4x+3[/tex]

[tex]\sf g(x)=5x-4[/tex]

[tex]\sf fg(x)=20x+p[/tex]

[tex]\sf fg(x)=f[g(x)][/tex]

This means g(x) is substituted for x in f(x).

[tex]\sf \implies f[g(x)]=4[g(x)]+3[/tex]

                 [tex]\sf =4(5x-4)+3[/tex]

                  [tex]\sf= 20x-16+3[/tex]

                  [tex]\sf =20x-13[/tex]

[tex]\sf f[g(x)]=f[g(x)][/tex]

[tex]\sf \implies 20x+p=20x-13[/tex]

[tex]\sf \implies p=-13[/tex]

Step-by-step explanation:

a scale factor normally applies to lengths (one-dimensional sizes).

the perimeter of a triangle is calculated only by using lengths, so we can apply the scaling factor directly to the perimeter.

perimeter of the new triangle = 2 × perimeter of the old triangle = 2×8 = 16

Answer:  "How do u calculate the diameter of a circle"?

Step-by-step explanation:  Calculating diameter is easy you just need the radius, the circumference, or the area. Even if you don't have any of those dimensions, you can still find the diameter if you have a drawing of the circle.

Answer:

The student spent 48 minutes and 45 seconds playing basketball.

Answer:

Step-by-step explanation:

10% = 15.30

40%=61.20

1% = 1.53

2%=3.06

61.20+3.06=64.26

153+ 64.26=217.26

Answer:

The circumference (C) of a circle is found by the equation C = 2*[tex]\pi[/tex]*radius

There is a second relationship between [tex]\pi[/tex] and circles.  That of the area (A) of the circle which is found by the formula A = [tex]\pi*radius^{2}[/tex]

Step-by-step explanation:

Answer: 6 units squared.

Step-by-step explanation: The equation for area of a triangle is 1/2 * length of base * the length of the height.

The length of the base is D to E, which is 3 units.

The length of the height is from F to the base of the triangle, which is 4 units.

Therefore, the area of the triangle would be 1/2 * 3 * 4 = 6 units squared.

The explicit rule formula an = -2n + 8 is an arithmetic progression

The value of a11 is -14

The explicit rule formula is given as:

an = -2n + 8

Substitute 11 for n to calculate a11

a11 = -2 * 11 + 8

Evaluate the product

a11 = -22 + 8

Evaluate the sum

a11 = -14

Hence, the value of a11 is -14

Read more about explicit rules at:

https://brainly.com/question/12119793

The length of the side AB and side CD of kite abcd which is shown in the figure is 15 units and 20 units respectively.

Pythagoras theorem says that in a right angle triangle the square of hypotenuse side is equal to the sum of square of other two legs of right angle triangle.

Let the intersection point of dignoals is O. The figure of the kite ABCD, is attached below. The sides of the kite ABCD, are,

[tex]AO=12\\OB=9\\CO=12\\OD=16[/tex]

In the triangle AOB using the pythagours theorem,

[tex]AB=\sqrt{(AO)^2+(OB)^2}\\AB=\sqrt{(12)^2+(9)^2}\\AB=\sqrt{225}\\AB=15[/tex]

Similarly, in the triangle DOC using the pythagours theorem,

[tex]CD=\sqrt{(CO)^2+(OD)^2}\\CD=\sqrt{(12)^2+(16)^2}\\CD=\sqrt{400}\\CD=20[/tex]

Thus, the length of the side AB and side CD of kite abcd which is shown in the figure is 15 units and 20 units respectively.

Learn more about the Pythagoras theorem here;

https://brainly.com/question/343682

Answer:

its B

Step-by-step explanation:

Answer:

127

Step-by-step explanation:

Given :

On differentiating,

At x = 2

First differentiate

So

[tex]\\ \rm\Rrightarrow \dfrac{d}{dx}(30x^2+7x)[/tex]

[tex]\\ \rm\Rrightarrow 60x+7[/tex]

Put x=2

Answer:

8:20 or if you want it simplified 2:5

Step-by-step explanation:

Step-by-step explanation:

the original side length is x.

the volume of a block is length × width × height.

so, for a cube with all sides being equal, the volume in our case is x³ (x × x × x).

now, with the same formula but with every side shortened by 1 cm we get

(x-1)(x-1)(x-1) = x³ - 91 (the original volume minus 91)

now, we have to do the multiplications.

(x-1)(x-1) = x² - 2x + 1

(x²-2x+1)(x-1) = x³ - x² - 2x² + 2x + x - 1 = x³ -3x² + 3x -1

x³ - 3x² + 3x - 1 = x³ - 91

-3x² + 3x = -90

-x² + x = -30

x² - x = 30

x² - x - 30 = 0

the general solution to such a squared equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -1

c = -30

x = (1 ± sqrt((-1)² - 4×1×-30))/(2×1) =

= (1 ± sqrt(1 + 120))/2 = (1 ± sqrt(121))/2 =

= (1 ± 11)/2

x1 = (1 + 11)/2 = 12/2 = 6

x2 = (1 - 11)/2 = -10/2 = -5

a negative number does not make any sense for a side length, so our solution is x = 6 cm.

the original side length of the cube is 6 cm.

to check :

6³ = 216

(6-1)³ = 5³ = 125

216 - 125 = 91

perfect.

[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: log_{4}(39.2) [/tex]

[tex]\qquad \sf  \dashrightarrow \: log_{4}( {2}^{3} \times {7}^{2} \times 10 {}^{ - 1} ) [/tex]

[tex]\qquad \sf  \dashrightarrow \: log_{4}( {2}^{3} ) + log_{4}( {7}^{2} ) + log_{4}(10 {}^{ - 1} ) [/tex]

[tex]\qquad \sf  \dashrightarrow \: log_{ {2}^{2} }( {2}^{3} ) + log_{ {2}^{2} }( {7}^{2} ) + log_{ {2}^{2} }(10 {}^{ - 1} ) [/tex]

[tex]\qquad \sf  \dashrightarrow \: \frac{3}{2} log_{2}(2) + \frac{2}{2} log_{2}(7) - \frac{1}{2} log_{2}(10) [/tex]

[tex]\qquad \sf  \dashrightarrow \: \frac{3}{2} + a - \frac{b}{2} [/tex]

That's the required result ~

also you can take it's LCM and write it as :

[tex]\qquad \sf  \dashrightarrow \: \dfrac{2a - b + 3}{2} [/tex]

Answer:

20320 minutes

Step-by-step explanation:

divided the minutes by 24 then get your answer

[tex]\displaystyle \int csc^2(9x) dx \\\\=\dfrac 19\displaystyle \int \csc^2 u ~du~~~~~~~;\left[\text{Let}~u= 9x \implies dx = \dfrac{du}9\right]\\\\=-\dfrac 19 \cot u + C\\\\=-\dfrac 19 \cot(9x)+C[/tex]

Answer:

[tex]\frac{5}{36}[/tex]

Step-by-step explanation:

the total number of possible combinations of rolling two dice is 36 because a side has 6 sides and [tex]6^{2}=36[/tex]

and possible combinations that sum to 8 are

which are 5 possible combinations which gives [tex]\frac{5}{36}[/tex]

Answer:

1 and 7

Step-by-step explanation:

let me know if this is helpful!

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

[tex]d=\sqrt{\frac{3h}{2} }[/tex]

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

[tex]d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)[/tex]

For Addison h=85(1/3)

[tex]d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)[/tex]

Subtracting both distances we get

[tex]8\sqrt{2}-6\sqrt{2} =2\sqrt{2}[/tex]

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

https://brainly.com/question/1392973

Answer:

2 root 2mi.

Step-by-step explanation:

Edge2020

Answer:

44.5 percent is shaded.

from whole model, 44.5% is shaded of 100%

Answer:

10.38 = 0.60b + 1.74p

Step-by-step explanation:

Answer:

The answer to your question would be -0.383

Step-by-step explanation:

I have no idea why it's deleting my answers, but that's the best choice.

=========================================================

Explanation:

The LCM of 3 and 5 is 3*5 = 15.

Every 15 days, the two people will swim together on the same day.

And so on.

Keep this process going of adding on 15 to find this sequence

1, 16, 31, 46, 61, 76, ...

We stop the sequence once we either reach 70 or go over it because there are 7*10 = 70 days in ten weeks. This assumes we use a 7 day week rather than a 5 day week.

As shown in bold, there are 5 items smaller than 70. So the two people swam together a total of 5 times

-----------------

Alternatively, you can solve 15n+1 = 70 for n to get n = 4.6 which rounds down to n = 4 to represent the set {0,1,2,3,4} which has 5 items in it to represent the five times total they swim together.

and so on until reaching n = 4 corresponding to day 15(4)+1 = 61.

Answer:

b) -b/a

Step-by-step explanation:

Slopes of perpendicular lines are negative reciprocals. That means to flip the fraction and change the sign. :-)

Answer:

a)0.012 kg

b)0.007kg

c)35.015kg

d)0.675kg

Step-by-step explanation:

please mark me as brainlest