the zeros of f(x)=20x^2 - 19x + 3

The value of k is 1/2π, and X and Y are independent because their joint density function factors into a product of their Probability density functions.

To find the value of k, we use the fact that the total area under the joint probability density function equals 1. That is:

integral from 0 to infinity of integral from 0 to infinity of kxye^(-x^2-y^2) dx dy = 1

Using polar coordinates (x = r cos(theta), y = r sin(theta)), the double integral can be written as:

integral from 0 to 2pi of integral from 0 to infinity of k r^3 e^(-r^2) dr d(theta) = 1

The integral over theta is just 2pi, so we can simplify to:

2pi k integral from 0 to infinity of r^3 e^(-r^2) dr = 1

Solving this integral, we get:

2pi k (-1/2) e^(-r^2)| from 0 to infinity = 1

Since e^(-r^2) goes to 0 as r goes to infinity, we have:

pi k = 1/2

Therefore, k = 1/(2pi).

To prove that X and Y are independent, we need to show that the joint probability density function can be factored into the product of the marginal probability density functions:

f(x,y) = f_X(x) * f_Y(y)

The marginal probability density function of X is given by:

f_X(x) = integral from 0 to infinity of kxye^(-x^2-y^2) dy

= kxe^(-x^2) * integral from 0 to infinity of ye^(-y^2) dy

The integral from 0 to infinity of ye^(-y^2) dy is a known integral equal to 1/2, so we have:

f_X(x) = kxe^(-x^2) / 2

Similarly, the marginal probability density function of Y is given by:

f_Y(y) = kye^(-y^2) / 2

Therefore, we have:

f_X(x) * f_Y(y) = k^2 xy e^(-(x^2+y^2))

Comparing this to the joint probability density function given in the problem, we can see that:

f(x,y) = f_X(x) * f_Y(y)

Thus, X and Y are independent.

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____The given question is incomplete, the complete question is given below:

The joint probability density function of two-dimensional continuous random variable (X,Y) is given by > 0, y >0; f(x,y) = 0, otherwise, kxye-(x2+y2). Find the value of k and prove also that X and Y are independent.

The regression coefficient associated with X1 and X2 interpret it increased by 33 and 22.

Test statistic represents that X2 makes a significant contribution to the model.

The regression coefficient associated with variable X1 is 33.

This means,

Holding all other variables constant, for every one unit increase in X1, Y is expected to increase by 33 units.

The regression coefficient associated with variable X2 is 22.

This means ,

Compared to the reference category  ,

Average value of Y for the category represented by X2 is expected to be 22 units higher.

Holding all other variables constant.

Null hypothesis for testing the contribution of variable X2 is that the coefficient of X2 is equal to zero,

X2 does not make a significant contribution to the model.

Alternative hypothesis is that the coefficient of X2 is not equal to zero,

X2 does make a significant contribution to the model.

The t-statistic for X2 is 3.21, and the p-value associated with this statistic is less than 0.10.

Reject the null hypothesis at the 0.10 level of significance.

p-value is less than 0.10,

Conclude evidence that variable X2 makes a significant contribution to the model.

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The above question is incomplete, the complete question is:

Suppose X1 is a numerical variable and X2 is a dummy variable with two categories and the regression equation for a sample of n =1919

is Modifying  Y with Y = 77 + 33X1 +22X2

a. Interpret the regression coefficient associated with variable

X1.

b. Interpret the regression coefficient associated with variable

X2.

c. Suppose that the test statistic for testing the contribution of variable

X2 is 3.213.21.

At the 0.100.10 level of​ significance, is there evidence that variable

X2 makes a significant contribution to the​ model?

Interpret the regression coefficient associated with variable X1?

The magnitude and direction of the resultant vector are 50.479 and 73 degrees, respectively.

What is vector addition?

Vector addition is the operation of adding two or more vectors together into a vector sum. The so-called parallelogram law gives the rule for the vector addition of two or more vectors. For two vectors, the vector sum is obtained by placing them head to tail and drawing the vector from the free tail to the free head.

To find the magnitude and direction of the resultant vector, we need to add the two given vectors. We can do this using vector addition, where we add the corresponding components of each vector.

First, let's convert the given magnitudes and directions into component form. We can use the following equations to find the x and y components of each vector:

Magnitude = √(x² + y²)

Direction = tan⁻¹(y/x)

For the first vector with magnitude 28 and direction 500, we have:

Magnitude = 28

Direction = 500 degrees

x = Magnitude * cos(Direction) = 28 * cos(500) = -14

y = Magnitude * sin(Direction) = 28 * sin(500) = -24.202

Therefore, the first vector can be written as v1 = <-14, -24.202>

Similarly, for the second vector with magnitude 75 and direction 1250, we have:

Magnitude = 75

Direction = 1250 degrees

x = Magnitude * cos(Direction) = 75 * cos(1250) = 28.481

y = Magnitude * sin(Direction) = 75 * sin(1250) = 72.929

Therefore, the second vector can be written as v2 = <28.481, 72.929>

To find the resultant vector, we can add the components of the two vectors:

v = v1 + v2 = <-14, -24.202> + <28.481, 72.929> = <14.481, 48.727>

The magnitude of the resultant vector is:

Magnitude = √(x² + y²) = √(14.481² + 48.727²) = 50.479

Rounding to the thousandth place, the magnitude of the resultant vector is 50.479.

The direction of the resultant vector can be found using the following equation:

Direction = tan⁻¹(y/x) = tan⁻¹(48.727/14.481) = 72.636 degrees

Rounding to the nearest degree, the direction of the resultant vector is 73 degrees.

Therefore, the magnitude and direction of the resultant vector are 50.479 and 73 degrees, respectively.

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The expression 1/30(ln(15/22))t = x when solved for t has a solution of t = -78.95x

Given the following expression

1/30(ln(15/22))t =

The above expression cannot be solved for t

This is so because the expression is not an equation or inequality

To do this, we must equate the expression to a value (say x)

So, we have

1/30(ln(15/22))t = x

Multiply through by 30

This gives

ln(15/22)t = 30x

Evaluate the natural logarithm expression

This gives

-0.38t = 30x

Divide both sides by -0.38

So, we have

t = -78.95x

Hence, the solution for t is t = -78.95x

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The converted linear programming problem in standard form is given by

maximize 2^i - f x₂ + 0x₁ + 0s₁ + 0s₂ + 0s₃ + 0s₄ where s₁, s₂, s₃, and s₄ are the slack variables.

convert the linear programming problem to standard form,

Introduce slack variables to represent the inequalities,

And rewrite the objective function as a linear expression.

First, let us introduce the slack variables,

x₁ + s₁= 2

x₂ + s₂ = 3 + 2t

2x₂ + s₃ = 5

s₄ = -x₂

where s₁, s₂, s₃, and s₄ are the slack variables.

Rewrite the objective function as a linear expression,

Maximize 2^i - f x2

= maximize 2^i - f x₂ + 0x₁ + 0s₁ + 0s₂ + 0s₃ + 0s₄

Now we have the linear programming problem in standard form,

maximize 2^i - f x₂ + 0x₁ + 0s₁ + 0s₂ + 0s₃ + 0s₄

subject to,

x₁ + s₁ = 2

x₂ + s₂ = 3 + 2t

2x₂ + s₃ = 5

s₄ = -x₂

x₁ >= 0, s₁ >= 0

x₂ >= 0, s₂ >= 0, t >= 0

s₃ >= 0, s₄ >= 0

Added a new variable t to represent the inequality

x₂ % 2 < 3,

which can be rewritten as x₂ = 2t + r,

where r is the remainder of x₂ divided by 2.

Require t to be non-negative, and r to be less than 2.

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The cοst οf painting the triangle bοrder at the given rate is Rs. [tex]108\sqrt{(2)[/tex].

A triangle is a geοmetric shape that cοnsists οf three line segments, οr sides, that are cοnnected tο fοrm three angles.

Tο find the cοst οf painting the triangle bοrder, we first need tο find its area. Let's call the third side οf the triangle "x".

We knοw that the perimeter οf the triangle is 24cm, sο we can write an equatiοn:

6cm + 8cm + x = 24cm

Simplifying this, we get:

x = 10cm

Nοw we can use Herοn's fοrmula tο find the area οf the triangle:

s = (6cm + 8cm + 10cm)/2 = 12cm

Area [tex]= \sqrt{(s(s-6cm)(s-8cm)(s-10cm))[/tex]

[tex]= \sqrt{(12cm6cm4cm*2cm)[/tex]

[tex]= 2\sqrt{(72cm^2)[/tex]

[tex]= 12\sqrt{(2) cm^2[/tex]

Finally, we can calculate the cοst οf painting the bοrder at a rate οf Rs. 9 per square cm:

Cοst = (Area) x (Rate)

[tex]= (12\sqrt{(2)} cm^2) x (Rs. 9/cm^2)[/tex]

[tex]= Rs. 108\sqrt{(2)[/tex]

Therefοre, the cοst οf painting the triangle bοrder at the given rate is= [tex]Rs. 108\sqrt{(2)[/tex]

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From the table, the calculated equation of h(x) in vertex form is h(x) = (x + 1)² + 2

To find the equation of the quadratic function h(x) in vertex form, we need to first determine the coordinates of the vertex.

The vertex form of a quadratic function is given by

y = a(x - h)² + k, where (h, k) is the vertex of the parabola.

From the table, we have

(h, k) = (-1, 2)

So, we have

y = a(x + 1)² + 2

To determine the value of 'a', we can substitute any other point from the table into the vertex form equation and solve for 'a'.

For example, using the point (0, 3), we have:

a(0 + 1)² + 2 = 3

a = 1

So, we have

y = (x + 1)² + 2 as the equation

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the maximum potential loss for this strategy is limited to the net cost of $3 if the stock price stays below the breakeven point of $63, but can be unlimited if the stock price rises significantly above the breakeven point

The maximum potential loss for this strategy can be calculated as the difference between the premiums received and paid. In this case, the customer pays a premium of $6 to buy the ABC May 60 call and receives a premium of $3 for selling the ABC May 17th call. Hence, the total cost for this strategy is $6 - $3 = $3.

The breakeven point for this strategy can be calculated as the strike price of the long call plus the net cost of the strategy, which is $60 + $3 = $63.

If the ABC stock price stays below the breakeven point of $63, both options will expire worthless, and the maximum loss for this strategy will be the net cost of $3.

However, if the ABC stock price rises above the breakeven point of $63, the short call option that was sold will be in the money, and the buyer of the option can exercise it, forcing the seller to sell the shares at the strike price of $17. This means that the maximum loss for this strategy will be unlimited if the stock price rises significantly above the breakeven point.

In summary, the maximum potential loss for this strategy is limited to the net cost of $3 if the stock price stays below the breakeven point of $63, but can be unlimited if the stock price rises significantly above the breakeven point. Therefore, it's important to have a risk management plan in place to mitigate potential losses in case the stock price moves against the expected direction.

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a customer buys one abc may 60 call at 6 and sells one abc may 17th call at 3 when abc stock is selling at 63% the maximum potential loss is?

In this data set, the only value that is an outlier is 100, since it is above the upper bound of 98.25.

To identify the outliers in the data set, we can use the concept of the interquartile range (IQR) and the 1.5×IQR criterion.

First, we need to find the first and third quartiles (Q1 and Q3) of the data set. To do this, we can order the data set from smallest to largest:

54, 72, 75, 81, 81, 82, 83, 83, 83, 85, 100

The median of the data set is the middle value, which is 82.

The lower half of the data set will consists of:

54, 72, 75, 81, 81

The median of the lower half is (72 + 75)/2 = 73.5, which is the value halfway between the two middle values.

The upper half of the data set will consists of:

83, 83, 83, 85, 100

The median of the upper half is (83 + 85)/2 = 84, which is the value halfway between the two middle values.

Therefore, the first quartile (Q1) is 73.5 and the third quartile (Q3) is 84.

The interquartile range (IQR) is the difference between Q3 and Q1:

IQR = Q3 - Q1 = 84 - 73.5 = 10.5

To identify the outliers in the data set using the 1.5×IQR criterion, we need to calculate the lower and upper bounds:

Lower bound = Q1 - 1.5×IQR = 73.5 - 1.5×10.5 = 57.75

Upper bound = Q3 + 1.5×IQR = 84 + 1.5×10.5 = 98.25

Any data point that is below the lower bound or above the upper bound is considered an outlier.

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Answer:

B. $6 per part

Step-by-step explanation:

The average cost per part can be computed as follows

Average Cost = (324-300)/(104-100)

= 24/4

=$6

Answer: B. $6 per part

Answer:

$129

Step-by-step explanation:

26 students x 3 markers each= 78 markers

Markers are being sold in sets of 5, so she needs at least 16 packs of markers. that will cost her $116

the logarithmic regression of aids cases over time is 4.6

A type of regression called logarithmic regression is used to simulate situations where growth or decay initially increases quickly and then gradually slows down.

A better prediction model is produced by applying the logarithm to your variables, which results in a much more distinct and/or adjusted linear regression line through the base of the data points.

y ≈ 33.7·ln(x) -45.9

4.6

Detailed explanation:

Logarithmic regression can be carried out using a spreadsheet or a graphing calculator. The log curve with the best least-squares fit is about...

y ≈ 33.7·ln(x) -45.9

Around 4.6 is the anticipated value of x needed to get y = 5.2.

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[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{q}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{q}-\stackrel{y1}{3}}}{\underset{\textit{\large run}} {\underset{x_2}{7}-\underset{x_1}{(-3)}}} ~~ = ~~\stackrel{\stackrel{\textit{\small slope}}{\downarrow }}{ \cfrac{ -7 }{ 10 }}\implies \cfrac{q-3}{7+3}=\cfrac{ -7 }{ 10 }\implies \cfrac{q-3}{10}=\cfrac{ -7 }{ 10 } \\\\\\ q-3=-7\implies q=-4[/tex]

The positive difference between the greatest sum and the least sum in the sample space of the output of the two cubes is 10.

A sample space is a mathematical collection or set of possible outcomes of a random experiment. A sample space is represented by the symbol "S". The possible outcome of an experiment is called the events.

The greatest sum is obtained by adding the largest number on the first cube with the largest number on the second cube. The least number can be obtained by adding the smallest number on the first cube with the smallest number on the second cube.

The possible numbers displayed by the first cube are; 1, 2, 3, 4, 5, 6

The possible numbers displayed by the second cube are also; 1, 2, 3, 4, 5, 6

The positive difference between the greatest sum and the least sum in the sample space is therefore;

12 - 2 = 10

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The graph's function limit at x=4 is 6.

In mathematics, the limit of a function is the value that the function approaches as the input approaches a certain value or as the input approaches infinity or negative infinity. A function may or may not have a limit at a given point or as the input goes to infinity or negative infinity.

The formal definition of the limit of a function f(x) as x approaches a value a is as follows:

For every positive number ε (epsilon), there exists a corresponding positive number δ (delta) such that if 0 < |x-a| < δ, then |f(x)-L| < ε.

Limit f(x) at x tend to 4⁺ =6.

Limit f(x) at x tend to 4⁻ =6

Hence, the graph's function limit at x=4 is 6.

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The population of interest is the group of students who submitted an application to the college in 2017.

A sample is a subset of a population that is selected and studied in order to make inferences or conclusions about the population. The sample is usually selected to be representative of the population in some way, so that the conclusions drawn from the sample can be generalized to the population as a whole.

The correct answer is C.

The purpose of the study is to determine why students who are interested in the college decide to enroll or not. Therefore, the population of interest is the group of students who submitted an application to the college in 2017.

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Answer:

x = 2

y = -3/4

Step-by-step explanation:

1. Substitute y=1/8x -1 in −5x+4y=−13

-5x+4(1/8x -1) = -13

2. Solve for x

-5x + 4/8x - 4 = -13

-9/2x - 4 = -13

-9/2x = -9

x = 2

3. Now that you know x = 2, plug it into y=1/8x - 1 to find what y is.

y= 1/8(2) - 1

y= 2/8 - 1

y= -3/4

The statements that are true would be :

f(x) = 2√x has the same domain and range as f(x) = √x:

Both functions have a square root, so the domain must be x ≥ 0 in both cases. Since f(x) = 2√x is a vertical stretch of f(x) = √x by a factor of 2, the range of both functions starts at 0 and goes to positive infinity.

f(x) = -√x has the same domain as f(x) = √x but a different range:

In this relation, both functions have a square root, so the domain must be x ≥ 0 in both cases as it was in the first option. f(x) = -√x is a reflection of f(x) = √x over the x-axis, so the range is y ≤ 0, which is different from the range of f(x) = √x (y ≥ 0).

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As per the axial force, the support reaction at A is equal in magnitude to the axial force that is applied at the other end of the bar.

To determine the support reaction at A, we will draw a free-body diagram of the bar.

Since the bar is fixed at A, the support reaction at that end will be a vertical force, and we will label it as RA.

Using Newton's second law of motion, we can write the equation of equilibrium for the bar in the vertical direction:

ΣFy = 0

where ΣFy is the sum of all the forces in the vertical direction. Since there are only two forces acting on the bar, the axial force and the support reaction, we can write:

-FA + RA = 0

where FA is the axial force that is applied at one end, and RA is the support reaction at the other end.

From this equation, we can solve for RA:

RA = FA

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Complete Question:

Determine the support reaction at A

The axially loaded bar is fixed at A and loaded as shown. Draw a free-body diagram and determine the support reaction at A.

The rate of change (or slope) of this linear function is -1/2.

A linear function is a mathematical function that has a constant rate of change, meaning that the output (y-value) changes at a constant rate for every unit increase in the input (x-value). In other words, the graph of a linear function is a straight line.

The general form of a linear function is y = mx + b, where m is the slope of the line (the rate of change) and b is the y-intercept (the point where the line crosses the y-axis). The slope represents how much the y-value changes for every one-unit increase in the x-value.

Linear functions can be used to model many real-world situations, such as distance vs. time or cost vs. quantity. They are also commonly used in economics, physics, and engineering.

The rate of change of a linear function represents the slope of the line. We can calculate the slope using the formula:

slope = (change in y) / (change in x)

Let's use the points (0, -3) and (2, -4) to calculate the slope:

slope = (-4 - (-3)) / (2 - 0)

slope = -1 / 2

Therefore, the rate of change (or slope) of this linear function is -1/2.

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Between 3.26 on the low end and 3.30 on the high end is where UGPAS's middle 50% lies.

Provided that the parabola's vertex is at the origin and that it is symmetric about the y-axis. So, depending on whether the parabola expands upward or downward, the equation can take the form x2 = 4ay or x2 = -4ay.

Because we are interested in the top 5%, the region to the right of the z-score is 0.05. n,... As a result, we can apply the following z-score formula:

z = (x - μ) / σ

x = z * σ + μ

Substituting the values we have, we get:

x = 1.645 * 0.15 + 3.25 = 3.66

Therefore, the z-scores corresponding to the 25th and 75th percentiles are:

z1 = -0.675

z2 = 0.675

Using the same formula as before, we can find the UGPAs corresponding to these z-scares:

x1 = -0.675 * 0.15 + 3.25 = 3.26

x2 = 0.675 * 0.15 + 3.25 = 3.30

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Therefore, if the recipe requires 4 cups of stock for one batch of soup, he will need 8 cups of stock to double the recipe.

Ratio is a mathematical term used to compare two or more quantities of the same kind. It is a way of expressing the relationship between two numbers or values. Ratios are usually expressed in the form of a:b, where a and b are the two quantities being compared.

by the question.

Let's assume that the recipe for one batch of soup requires 4 cups of stock. If Mr. West wants to make:

1 batch of soup: he would need 4 cups of stock.

2 batches of soup: he would need 8 cups of stock (4 cups x 2 batches).

3 batches of soup: he would need 12 cups of stock (4 cups x 3 batches).

Therefore, the ratio of cups of stock to batches of soup would be:

1 batch of soup requires 4 cups of stock.

2 batches of soup require 8 cups of stock, so the ratio would be 8 cups of stock per 2 batches of soup, or 4 cups of stock per batch of soup.

3 batches of soup require 12 cups of stock, so the ratio would be 12 cups of stock per 3 batches of soup, or 4 cups of stock per batch of soup.

To double the recipe, Mr. West would need to use twice the amount of each ingredient, including the stock.

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None of these courses were being taken by seniors is 9.

A Venn diagram is a type of graphic representation that uses circles to emphasise the relationships between certain items or constrained groups of things. Circles with overlaps exhibit certain traits, but circles without overlaps do not.

Total number of students=150

Number of students Math =80

Number of students Spanish =41

Number of students Physics=54

Number of students Math and Spanish=10

Number of students Math and Physics=19

Number of students Physics and Spanish=12

Number of students Physics and Spanish and math=7

seniors were taking none of these courses =150-(80+41+54)+10+19+12-7

=9

Diagram is attached below:

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Answer:

A) the sides all have the same slopes.

Step-by-step explanation:

Every time a square in a graph is a square, their slopes MUST be the same, either that or nothing, it can't be a square.

Answer:

Natural

Step-by-step explanation:

Ln in mathematics mean natural log. Natural log is the log of a number with base e where e=2.71828. For understanding if the number is 2.71828^10 then the ln of 2.71828^10 is 10.

Answer: Factors of 24 include: 1 and 24, 2 and 12, 3 and 8, 4 and 6

Step-by-step explanation:

The given matrices are in the following form,

Reduced echelon form is Matrix A .

Only echelon form is Matrix B.

Neither echelon form nor reduced echelon form is Matrix C.

Matrix A is in reduced echelon form.

In matrix A,

Each row has a leading entry of 1

That is farther to the right than the leading entry of the row above it.

Additionally, all entries below a leading 1 are 0.

This meets the requirements for a matrix to be in reduced echelon form.

Matrix B is in echelon form only.

In matrix B,

Each row has a leading entry

That is farther to the right than the leading entry of the row above it.

However, not all entries below a leading entry are 0.

In the third row, there is a leading 1.

But the entries below it are not all 0.

Matrix is in echelon form only, but not in reduced echelon form.

Matrix C is in neither echelon form nor reduced echelon form.

In matrix C,

The first and third rows have leading entries.

But the second row does not.

In the first row, the leading 1 is not farther to the right than the leading entry of the row below it.

This matrix does not meet the requirements for echelon form or reduced echelon form.

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The total amount of money Carol originally invested is £22,000 in the bank account.

Compound interest is interest that is calculated not only on the initial amount of money invested or borrowed, but also on any accumulated interest from previous periods.

This results in exponential growth or accumulation of interest over time.

Let X be the amount that Carol originally invested in the account.

After 1 year, the amount of money in the account will be X(1+0.025) = X(1.025).

After Carol withdrew £1000, the amount of money in the account will be X(1.025) - £1000.

After 2 years (i.e. on 1st January 2016), the amount of money in the account will be (X(1.025) - £1000)(1+0.025) = (X(1.025) - £1000)(1.025).

We know that the amount of money in the account on 1st January 2016 was £23,517.60, so we can write the equation:

(X(1.025) - £1000)(1.025) = £23,517.60

Expanding the left-hand side and simplifying, we get:

X(1.025)² - £1000(1.025) = £23,517.60

X(1.025)² = £24,567.63

Dividing both sides by (1.025)², we get:

X = £22,000 (rounded to the nearest pound)

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The complete question is -

On the 1st of January 2014, Carol invested some money in a bank account. The account pays 2.5% compound interest per year. On the 1st of January 2015, Carol withdrew £1000 from the account. On the 1st of January 2016, she had £23 517.60 in the account. Work out how much Carol originally invested in the account?

The closed formula for this particular sequence is an = n² + 2.

Take note that the odd numbers 3, 5, 7, 9, and 11 are separate consecutive terms. This shows that the first n odd numbers can be added to the initial term, az, to get the nth term. Hence, the following is how we may represent the nth term a = az + 1 + 3 + 5 + ... + (2n-3) (2n-3). We may utilize the formula for the sum of an arithmetic series to make the sum of odd integers simpler that is 1 + 3 + 5 + ... + (2n-3) = n².

As a result, we get a = az + n^2 - 1. In conclusion, the equation for the series (an)n21, where a1 = az and an is the result of adding the first n odd numbers to az, is as a = az + n^2 - 1. We have the following for the given series where a1 = az = 3.

So, the closed formula for this particular sequence is an = n² + 2.

To learn more about arithmetic sequences, refer to:

Your question is incomplete. The complete question is:

Find the closed formula for the sequence (an)n21. Assume the first term given is az. an = 3, 6, 11, 18, 27... Hint: Think about the perfect squares.

Answer:

B: 9

Step-by-step explanation:

We know

Caleb took 24 photos at the zoo. 3/8 of his photos are of giraffes.

How many of Caleb’s photos are of giraffes?

We Take

24 x 3/8 = 9 photos

So, 9 of Caleb's photos are of giraffes.