Mr. Takaya can eat three slices of pizza in five minutes. If he continues to eat at the same rate, how many slices
could he eat in half of an hour?

Answers

Answer 1

Answer:

18.

Step-by-step explanation:

3 x 6 = 18. He eats 3 slices every 5 minutes so 5 minutes x 6 is half an hour. so 18 is your answer.

Answer 2

If Takaya continues to eat three slices of pizza in five minutes, he could eat 18 slices in half of an hour.

What is the Linear equation in one variable?

The Linear equation in one variable is an algebraic equation of degree one.

it can be expressed in the form of Ax +B = 0 where x is a variable, and A and B are two integers.

Takaya can eat three slices of pizza in five minutes.

for half an hour it would be 6 times five minutes.

So, in half an hour Takaya can eat 3 × 6 = 18

Therefore, If Takaya continues to eat three slices of pizza in five minutes, he could eat 18 slices in half of an hour.

Learn more about Linear equations in one variable here:

https://brainly.com/question/2501033


Related Questions

Of 77 third graders, on Monday 3 were absent from Room 101, 4 were absent from Room 102, and 2 were absent from Room 103. How many third graders attended school that day? ​

Answers

Answer:

68

Step-by-step explanation:

Their are 77 total, 77-3= 74-4= 70-2= 68

there are 68 3rd graders left

Do 9-77

Which of the following shows the least expensive unit price?

Answers

it would be the first one because each orange costs $0.34

Answer:

A (3 Oranges For $1.02)

Step-by-step explanation:

3 Oranges for $1.02 is $0.34 for each Orange

4 Oranges For $1.52 is $0.38 for each Orange

6 Oranges for $2.46 is $0.41 for each Orange

5 Oranges for $1.75 is $0.35 for each Orange

Which Makes The First One The Cheapest Out Of All

please please i need this

Answers

Answer:

for 3. the answer is 9

for 4. the answer is 12

Step-by-step explanation:

hope this helped!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Solve for C.
5x – 4> 12
OR 12.c +5<-4

Answers

Answer:

x>16/5 or c<-1/12

Answer: x≥  

x≥16/5 or x≤-3/4

Step-by-step explanation: I think this is the answer but i´m not completely sure of it.



Can someone please help me with this problem. Thank you

Answers

Answer:

B

Step-by-step explanation:

Point B has coordinates ​(4,1​). The​ x-coordinate of point A is -8. The distance between point A and point B is 13 units. What are the possible coordinates of point​ A?

Answers

Answer:

The possible coordinates of point A are (-8,-4) or (-8,6)

Step-by-step explanation:

The distance between two points is given by the formula

[tex]d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }[/tex]

For point A [tex](x_{1} , y_{1})[/tex]; [tex]x_{1}= -8[/tex] and [tex]y_{1}[/tex] is unknown

For point B [tex](x_{2} , y_{2})[/tex]; (4,1) i.e [tex]x_{2}=4[/tex] and [tex]y_{2}=1[/tex]

and d = 13

Putting the values into the equation,

[tex]13= \sqrt{[(4-(-8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{[(4+8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{12^{2} + (1-y_{1})^{2} }\\13^{2} = 12^{2} + (1-y_{1})^{2} \\169 = 144 +(1-y_{1})^{2}\\169-144 = (1-y_{1})^{2}\\25 = 1 -2y_{1} +y_{1}^{2} \\y_{1}^{2} -2y_{1}+1-25 =0\\y_{1}^{2} -2y_{1}-24 =0\\y_{1}^{2} -6y_{1} + 4y_{1} -24 =0 \\y_{1}(y_{1}-6) +4(y_{1} -6) = 0\\(y_{1}+4)(y_{1}-6) =0\\(y_{1}+4)=0 or (y_{1}-6) =0[/tex]

[tex]y_{1}+4= 0[/tex] or [tex]y_{1}-6 =0[/tex]

[tex]y_{1} =-4[/tex] or [tex]y_{1} = 6[/tex]

Hence, the possible coordinates of point A are (-8,-4) or (-8,6)

On a middle school basketball court, there is a large circle painted on the
floor. The diameter of the circle is 12 feet. What is the area of the circle?
Jse 3.14 for a

Answers

Answer:

113.04 feet²

Step-by-step explanation:

Use the circle area formula, A = [tex]\pi[/tex]

Sine the diameter is 12 feet, the radius is 6 feet

Plug in 6 as r into the formula, and 3.14 as pi, then solve:

A = [tex]\pi[/tex]r²

A = (3.14)(6²)

A = (3.14)(36)

A = 113.04

So, the area of the circle is approximately 113.04 feet²

Answer:

113.04 feet²

Step-by-step explanation:

Hope this helps

meena has 2 boxes the first box weighs 3 and one half pounds the secound box is three fourths the weight of the first box what is the weight of the secound box

Answers

Answer:

The second box is 1.125 pounds

Step-by-step explanation:

This is found by multiplying 1.5 by .75

heelllpppppp plzzzzzzz

Answers

Answer:

-2x-6

Step-by-step explanation:

Distribute -2x -2(3) = -2x-6

whats .82 in simplest form'

Answers

Answer:

0.82 = 82/100

simplified= 41/50

Step-by-step explanation:

Answer:

.8

Step-by-step explanation:

you can round, and since two is a number lower than five, the number stays the same so...

.8

what does s equal?pls help me plsss.

Answers

Answer:

s< -7/11

Step-by-step explanation:

1. y-23=55 2. x-14= -8




3. -15 = n + 18 4. 18.3 + a = 2.7
what are the answers for all of these i need help FAST!!!

Answers

Answer:

1. y = 32

2. x = 6

3. -33 = n

4. a = -15.6

Step-by-step explanation:

1.

y-23=55

 +23  +23          (23 cancels)

y = 32

2.

x - 14 = -8

 +14      +14           (-14 cancels)

   x = 6

3.

-15 = n + 18

    -18       -18          (18 cancels)

    -33 = n

4.

18.3 + a = 2.7

-18.3        -18.3        (18.3 cancels)

         a = -15.6

Ali and Jake went on a cross-country
trip. They took a train part of the way,
and took a bus the rest of the way. They
traveled a total of 1100 kilometers,
riding on the train 350 more kilometers
than on the bus.
Let x = kilometers traveled by bus. Let
y = kilometers traveled by train.

Answers

Answer:

Let x = Kilometers  by bus  

then x + (x + 350) = 1100

2x = 750

x = 375 by bus

x - 350 + x = 1100

2x = 1450

x = 725 by train

i hope this helps a little bit

answer to 8–5+5r+9r+8

Answers

Answer:

14r+11

Step-by-step explanation:

3+5r+9r+8

=11+14r

A rocket travels in a trajectory given by the equation s = -4.9t 2 + v0t, where s is meters above ground, t is time in seconds and v0 is the initial velocity.

If the intial velocity is 49 m/sec, after how many seconds will the rocket reach its maximum height?

a. 5
b. 15
c. 10

Answers

C. Is your answer
Have any more questions? Please add in the comments
-Josh-

A linguist at a large university was studying the word length of papers submitted by students en
humanities programs. From a random sample of 25 papers, the linguist counted the number of words
used in each paper. The 95 percent confidence interval was calculated to be (20,995, 22,905).
Assuming all conditions for inference are met, which of the following is a correct interpretation of the
interval?

Answers

Answer:

We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words

Step-by-step explanation:

The confidence interval is used to predict the mean for the entire humanities program, not just the sample.

4.6 isosceles and Equilateral Triangles

Answers

Step-by-step explanation:

3).20⁰

4).60⁰

180-70+70_180-140__20

Which equation has a solution of k = 6.5? F -3k = 19.5 G-1 + k = 7.5 H -7k = -45.5 J -2 + k = -8.5​

Answers

Answer:

i don't know

Step-by-step explanation:

4ax + 2bx =??
Es urgente

Answers

Answer:

2x(2a + b)

Step-by-step explanation:

4ax+ 2bx

= 2x (2a + b)

please help first image pleaseeeeee............................................

Answers

I think the answer is 2 for the math , not sure mark brainliest pls

Answer:

1:2

Step-by-step explanation:

What is decimal of 78

Answers

0.78 would be decimal form for 78%

Which equation below would be perpendicular to the line y = 2?

Answers

I believe that the answer is Y=1/5x

can someone help it’s due in 40mins!!

Answers

Answer:

Step-by-step explanation:

[tex] \frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4} [/tex]

[tex] \frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2} [/tex]

[tex] \frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2} [/tex]

[tex] \frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2} [/tex]

Michael's class held a food drive for the holidays. There are a total of 29 students in his class. On average, each boy and girl bought 3 cans of food apiece. If the class brought in a total of 87 cans of food, how many boys and how many girls are in the class ?

Answers

Answer:

19 girls snd 10 boys

Two data sets contain an equal number of values. The double box and whisker plot represents the values in the data set. Compare the data sets using measures of center and variation.

Answers

Answer with explanation:

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. = 14

Median or second quartile i.e. = 18

Third quartile or upper quartile i.e. =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. = 26

Median or second quartile i.e. = 30

Third quartile or upper quartile i.e. = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

   The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.

   And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e.

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

Hence, the number is : 1.5

Answer:

ive seen this before

Step-by-step explanation:

The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in grams, M.
after n half-lives have elapsed if there was an initial mass of 590 grams before decay. Then, use the equation to determine the mass remaining
after 36 hours have passed
Mn = 590. ()": M3 – 148
D
M, = 590 C4)*-* : My ~ 148
Mn = 590 - ()": Mz - 74
Mi = 590 - (1) * + : Mz - 74

Answers

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

what is the sum of (5m+9)+(9b-3)+(8c+6) simplified

Answers

5m+9b+8c+12.....i think ? lolz

Plz help will mark you brainliest if correct

Answers

Answer:

B

Step-by-step explanation:

5/1 is not equal to 6/2 or 7/3 or 8/4

Answer:

The answer would be B instead of D


for what value of x is JKLM a parallelogram?

help i’ll give brainliest

Answers

Answer:

Step-by-step explanation:

21

Can someone please help? I will mark brainliest random answers will be reported

Answers

Answer:

5.1

Step-by-step explanation:

hope it helps thank you

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