Which of the following products is defined?

GH
FE
EH
FG
All of the above are undefined

The value of the expression 2.1 × 1.6 = 3.36.

Decimals are a collection of numbers falling between integers on a number line. They are only an additional mathematical representation of fractions. Decimals allow us to express quantifiable quantities like length, weight, distance, money, etc. with more accuracy. Integers, also known as whole numbers, are represented to the left of the decimal point, while decimal fractions are shown to the right of the decimal point.

Given that the expression is: 2.1 × 1.6.

2.1 × 1.6 can be written as:

2.1 × 1.6 = 21/10 × 16/10

Multiply the numerator and denominator:

21/10 × 16/10 = 336/100

Covert the fraction into decimal:

336/100 = 3.36

Hence, the value of the expression 2.1 × 1.6 = 3.36.

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Answer: D

Step-by-step explanation:

i think so

Therefore, if the recipe requires 4 cups of stock for one batch of soup, he will need 8 cups of stock to double the recipe.

Ratio is a mathematical term used to compare two or more quantities of the same kind. It is a way of expressing the relationship between two numbers or values. Ratios are usually expressed in the form of a:b, where a and b are the two quantities being compared.

by the question.

Let's assume that the recipe for one batch of soup requires 4 cups of stock. If Mr. West wants to make:

1 batch of soup: he would need 4 cups of stock.

2 batches of soup: he would need 8 cups of stock (4 cups x 2 batches).

3 batches of soup: he would need 12 cups of stock (4 cups x 3 batches).

Therefore, the ratio of cups of stock to batches of soup would be:

1 batch of soup requires 4 cups of stock.

2 batches of soup require 8 cups of stock, so the ratio would be 8 cups of stock per 2 batches of soup, or 4 cups of stock per batch of soup.

3 batches of soup require 12 cups of stock, so the ratio would be 12 cups of stock per 3 batches of soup, or 4 cups of stock per batch of soup.

To double the recipe, Mr. West would need to use twice the amount of each ingredient, including the stock.

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The probability that a randomly selected bottle is correctly placed AND is a Plastic #4 bottle is 0.25 or 25%

What is Conditional probability?

Conditional probability is the probability of an event occurring given that another event has occurred or is known to have occurred. It is denoted by P(A|B), which reads as "the probability of A given B."

The formula for conditional probability is:

P(A|B) = P(A and B) / P(B)

where P(A and B) is the probability of both events A and B occurring, and P(B) is the probability of event B occurring.

The total number of Plastic #2 bottles is 8 (correctly placed) + 5 (incorrectly placed) = 13.

The total number of Plastic #4 bottles is 5 (correctly placed) + 2 (incorrectly placed) = 7.

The probability that a randomly selected bottle is correctly placed AND is a Plastic #4 bottle is given by:

(number of Plastic #4 bottles correctly placed) / (total number of bottles)

So the probability is:

5/20 = 1/4 = 0.25

Therefore, the probability that a randomly selected bottle is correctly placed AND is a Plastic #4 bottle is 0.25 or 25%.

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The composition f(g(x)) will not be a function of real values if g(x) is not a real number or f(g(x)) is not defined. Thus, the answer is f(x) = sqrt(2,9)(x) = -22. The correct option is A).

The composition f(g(x)) will not be a function of real values if there exists a value of x such that g(x) is not a real number or f(g(x)) is not defined for the output of g(x).

f(x) = sqrt(2,9)(x) = -22

This function is not well-defined because the square root of a negative number is not a real number. Therefore, the composition f(g(x)) is not a function of real values.

f(x) = -22, g(x) = sqrt(π)

g(x) is not a real number because the square root of pi is not a rational number. Therefore, the composition f(g(x)) is not a function of real values.

f(x) = x², g(x) = -22

The composition f(g(x)) = (-22)² = 484 is a real number. Therefore, the composition is a function of real values.

f(x) = ln(x), g(x) = -22

The input of f(x) must be positive because the natural logarithm of a non-positive number is not a real number. Since g(x) is a constant value of -22, the composition f(g(x)) = ln(-22) is not a real number. Therefore, the composition is not a function of real values.

f(x) = -22, g(x) = x²

The composition f(g(x)) = -22 is a real number. Therefore, the composition is a function of real values.

f(x) = -22, g(x) = ln(2)

The composition f(g(x)) = -22 is a real number. Therefore, the composition is a function of real values.

Therefore, the answer option is (A) f(x) = sqrt(2,9)(x) = -22.

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_____The given question is incomplete, the complete question is given below:

Which of the following functions will result in the composition f(g(x)) not being a function of real values? A. f(x) = V2,9(x) = -22 B. f(x) = -22, g(x) = VƏ c. f(x) = x², 9(x) = -22 D. f(x) = ln(x), g(x) = -22 E. f(x) = -22, g(x) = x2 F. f(x) = -22, g(x) = ln(2) G. None of the above.

Y1,Y2,Y3 denote a random sample from an exponential distribution with density funtion where θ(hat)1, θ(hat)2, θ(hat)3  and θ(hat)5 are unbiased. θ(hat)2 has the smallest variance among the unbiased estimators

To check for unbiasedness, we need to find the expected value of each estimator and see if it equals θ.

θ(hat)1 = Y1

E(θ(hat)1) = E(Y1) = θ

Thus, θ(hat)1 is an unbiased estimator.

θ(hat)2 = (Y1+Y2)/2

E(θ(hat)2) = E[(Y1+Y2)/2] = (1/2)[E(Y1) + E(Y2)] = θ

Thus, θ(hat)2 is an unbiased estimator.

θ(hat)3 = (Y1+2Y2)/3

E(θ(hat)3) = E[(Y1+2Y2)/3] = (1/3)[E(Y1) + 2E(Y2)] = θ

Thus, θ(hat)3 is an unbiased estimator.

θ(hat)4 = min(Y1,Y2,Y3)

For this estimator, we need to find the probability density function (pdf) of the minimum of the three random variables.

Let F_Y1_Y2_Y3 be the joint cumulative distribution function (cdf) of Y1,Y2,Y3, then the pdf of the minimum is given by:

f(θ(hat)4) = d/dy [F_Y1_Y2_Y3(y,y,y)] = 3(1/θ)e^-y/θf, y>0

E(θ(hat)4) = ∫0^∞ y(3/θ)e^-y/θ dy

= (3/θ) ∫0^∞ ye^-y/θ dy

Using integration by parts, we get:

= (3/θ) [θ + θ^2]

= 3θ + 3θ^2

Thus, θ(hat)4 is biased.

θ(hat)5 = Y (bar)

E(θ(hat)5) = E(Y (bar)) = E[(Y1+Y2+Y3)/3] = (1/3)[E(Y1) + E(Y2) + E(Y3)] = θ

Thus, θ(hat)5 is an unbiased estimator.

To compare the variances of the unbiased estimators, we need to compute their variances.

Var(θ(hat)1) = Var(Y1) = θ^2

Var(θ(hat)2) = Var[(Y1+Y2)/2] = (1/4)Var(Y1) + (1/4)Var(Y2) + (1/2)Cov(Y1,Y2)

Since Y1,Y2 are independent and identically distributed, Cov(Y1,Y2) = 0.

Thus, Var(θ(hat)2) = (1/4)θ^2 + (1/4)θ^2 = (1/2)θ^2

Var(θ(hat)3) = Var[(Y1+2Y2)/3] = (1/9)Var(Y1) + (4/9)Var(Y2) + (4/9)Cov(Y1,Y2)

Again, Cov(Y1,Y2) = 0, so Var(θ(hat)3) = (1/9)θ^2 + (4/9)θ^2 = (5/9)θ^2

Var(θ(hat)4) = Var(min(Y1,Y2,Y3))

Let X = min(Y1,Y2,Y3). Then,

F_X(x) = P(X ≤ x) = P(min(Y1,Y2,Y3) ≤ x)

= 1 - P(Y1 > x and Y2 > x and Y3 > x)

Since Y1,Y2,Y3 are independent,

= 1 - P(Y1 > x)P(Y2 > x)P(Y3 > x)

= 1 - (e^-x/θ)^3

Thus, the pdf of X is given by:

f_X(x) = d/dx[F_X(x)] = 3(e^-x/θ)^2 (1/θ)e^-x/θf, x>0

Using the formula for the variance of a continuous random variable, we get:

Var(θ(hat)4) = ∫0^∞ [x - E(θ(hat)4)]^2 f_X(x) dx

= ∫0^∞ [x - (3θ + 3θ^2)]^2 3(e^-x/θ)^2 (1/θ)e^-x/θf dx

= 6θ^2

Thus, Var(θ(hat)4) = 6θ^2.

Var(θ(hat)5) = Var(Y (bar)) = Var[(Y1+Y2+Y3)/3]

= (1/9)Var(Y1) + (1/9)Var(Y2) + (1/9)Var(Y3) + (2/9)Cov(Y1,Y2) + (2/9)Cov(Y1,Y3) + (2/9)Cov(Y2,Y3)

Since Y1,Y2,Y3 are independent, Cov(Yi,Yj) = 0 for i ≠ j.

Thus, Var(θ(hat)5) = (1/9)θ^2 + (1/9)θ^2 + (1/9)θ^2 = (1/3)θ^2.

Therefore, among the unbiased estimators, θ(hat)1, θ(hat)2, θ(hat)3, and θ(hat)5, the one with the smallest variance is θ(hat)2.

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After 30 seconds the bugs will be apart by (x -y) = 30 units

The speed of an object, aIso known as "v" in everyday speech and kinematics, is a scaIar quantity that measures how much its position changes over time or how much it changes per unit of time.

The distance traveIIed by an object during a time intervaI is equaI to the duration of the intervaI divided by the object's speed, with the instantaneous speed being the upper Iimit of the average speed as the intervaI's duration gets cIoser to zero. VeIocity differs from speed. Distance divided by time is the formuIa for measuring speed. A metre per second (m/s) is the metric unit of speed.

a) The speed of F is 12 units in 4 seconds, or 3 units per second.

x = 3t

The speed of S is 8 units in 4 seconds, or 2 units per second.

y = 2t

b) x-y = 3t -2t = t

After 30 seconds the bugs will be apart by (x -y) = 30 units

c) x - y = 100 = t

The bugs will be 100 units apart after 100 seconds.

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The distance between bug f and bug s after 30 seconds is: distance = 90 - 60 = 30 units.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas. It involves the study of variables, expressions, equations, and functions.

When bug s and bug f leave point 0, they are initially at the same location, which is at position 0 on the number line. After four seconds, bug s has traveled a distance of 4v_s units from point 0, and bug f has traveled a distance of 4v_f units from point 0. We know that bug f has traveled 12 units in this time, so:

4v_f = 12

Solving for v_f, we get:

v_f = 3 units per second

Similarly, we know that bug s has traveled a distance of 8 units in four seconds, so:

4v_s = 8

Solving for v_s, we get:

v_s = 2 units per second

Now we can find out how far apart the bugs are after 30 seconds. Bug f has traveled a distance of 30v_f units from point 0, which is:

30v_f = 30 x 3 = 90 units

Similarly, bug s has traveled a distance of 30v_s units from point 0, which is:

30v_s = 30 x 2 = 60 units

Therefore, the distance between bug f and bug s after 30 seconds is:

distance = 90 - 60 = 30 units.

So the bugs are 30 units apart after 30 seconds.

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Answer:

55 degrees angles on a rights angle triangle. 1 and 3 they are equal cause they are vertical opp angles 55 degrees

Answer: 4.5 litres

Step-by-step explanation:

If 1.5 liters of red paint is mixed with white paint to make 6 liters of pink paint, then the ratio of red paint to the total mixture is 1.5/6 = 0.25.

Since the pink paint is made by mixing red paint with white paint, the ratio of white paint to the total mixture is 1 - 0.25 = 0.75.

Therefore, to find the amount of white paint needed, we can set up the following proportion:

1.5/0.25 = x/0.75

Solving for x, we get:

x = 0.75 * 1.5 / 0.25 = 4.5

So, 4.5 liters of white paint is needed to make 6 liters of pink paint.

Hi!

If 6 liters were to be made, and 1.5 liters of red is needed, then we would subtract 1.5 from 6 to get your final answer
6 - 1.5 = 4.5.
So, 4.5 liters of white will be needed to make 6 liters of paint.

Hope this helps!

~~~PicklePoppers~~~

The answer of the given question based on the compound interest to find  total amount Nicole ended up paying for the machinery and the interest did Nicole pay on the loan is (A) the total amount Nicole ended up paying for the machinery is $14,342.52. (B) Nicole paid $2,342.52 in interest on the loan.

Compound interest is type of interest that is calculated not only on initial principal amount but also on accumulated interest from previous periods. In other words,  interest earned in each period is added to  principal amount, and  interest for the next period is calculated on  new, larger principal amount.

Compound interest can be thought of as "interest on interest" and is used in many financial transactions, like loans, investments, and savings accounts.

(a) The total amount Nicole ended up paying for the machinery is the sum of her down payment and all of her monthly loan payments over the 3-year period. We can calculate this as follows:

Total amount paid = Down payment + (Monthly payment x Number of payments)

Total amount paid = 1200 + (365.07 x 36)

Total amount paid = 1200 + 13142.52

Total amount paid = $14,342.52

Therefore, the total amount Nicole ended up paying for the machinery is $14,342.52.

(b) To calculate how much interest Nicole paid on the loan, we first need to calculate the total amount of the loan. We can do this by subtracting her down payment from the total cost of the machinery:

Total loan amount = Total cost of machinery - Down payment

Total loan amount = $13,200 - $1,200

Total loan amount = $12,000

Next, we can calculate the total amount of interest paid over the 3-year period by subtracting the total loan amount from the total amount paid:

Total interest paid = Total amount paid - Total loan amount

Total interest paid = $14,342.52 - $12,000

Total interest paid = $2,342.52

Therefore, Nicole paid $2,342.52 in interest on the loan.

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Step-by-step explanation:

Arithmetic sequences: a2 = a1 + n

Geometric sequences: a2 = a1 * n

a. geometric (2 = 1 * 2, 4 = 2 * 2, 8 = 4 * 2 ...)

b. arithmetic (8 = 5 + 3, 11 = 8 + 3 ...)

c. arithmetic (10 = 5 + 5)

d. geometric (100 = 10 * 10)

Answer:

Step-by-step explanation:

For Diane's account:

Year 1: Interest = $70,000 x 0.03 = $2,100

Year 2: Interest = ($70,000 + $2,100) x 0.03 = $2,163

Year 3: Interest = ($70,000 + $2,100 + $2,163) x 0.03 = $2,227.89

For Henry's account:

Year 1: Interest = $70,000 x 0.03 = $2,100

Year 2: Interest = $70,000 x 0.03 = $2,100

Year 3: Interest = $70,000 x 0.03 = $2,100

For the first year, both Diane and Henry earn the same interest of $2,100. However, for the second and third years, Diane earns more interest than Henry. Therefore, Diane earns more interest for each year after the first year

the maximum potential loss for this strategy is limited to the net cost of $3 if the stock price stays below the breakeven point of $63, but can be unlimited if the stock price rises significantly above the breakeven point

The maximum potential loss for this strategy can be calculated as the difference between the premiums received and paid. In this case, the customer pays a premium of $6 to buy the ABC May 60 call and receives a premium of $3 for selling the ABC May 17th call. Hence, the total cost for this strategy is $6 - $3 = $3.

The breakeven point for this strategy can be calculated as the strike price of the long call plus the net cost of the strategy, which is $60 + $3 = $63.

If the ABC stock price stays below the breakeven point of $63, both options will expire worthless, and the maximum loss for this strategy will be the net cost of $3.

However, if the ABC stock price rises above the breakeven point of $63, the short call option that was sold will be in the money, and the buyer of the option can exercise it, forcing the seller to sell the shares at the strike price of $17. This means that the maximum loss for this strategy will be unlimited if the stock price rises significantly above the breakeven point.

In summary, the maximum potential loss for this strategy is limited to the net cost of $3 if the stock price stays below the breakeven point of $63, but can be unlimited if the stock price rises significantly above the breakeven point. Therefore, it's important to have a risk management plan in place to mitigate potential losses in case the stock price moves against the expected direction.

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a customer buys one abc may 60 call at 6 and sells one abc may 17th call at 3 when abc stock is selling at 63% the maximum potential loss is?

Answer:

------------------------

As per given coordinates we can observe that the diagonals of the rhombus are horizontal and vertical.

The length of the diagonal is the difference of x-coordinates for the horizontal diagonal and the difference of y-coordinates for the vertical one.

The diagonals have the length:

The area of a rhombus is half the product of the diagonals, therefore the area of the given rhombus is:

The area οf the given rhοmbus is 22.5 square units. Tο find the area οf the rhοmbus, we need tο first find the length οf its diagοnals.

A rhοmbus is a type οf quadrilateral that has fοur sides οf equal length. It is alsο knοwn as a diamοnd οr a lοzenge. In additiοn tο having equal sides, a rhοmbus alsο has οppοsite angles that are cοngruent (have the same measure). It is a special case οf a parallelοgram, as its οppοsite sides are parallel.

Tο find the area οf the rhοmbus, we need tο first find the length οf its diagοnals. We can dο this using the distance fοrmula:

[tex]\rm d_1 = \sqrt{((4 - (-2))^2 + (-4 - (-1))^2)} = \sqrt{(6^2 + (-3)^2)} = \sqrt{(45)[/tex]

[tex]\rm d_2 = \sqrt{((-8 - (-2))^2 + (-4 - (-7))^2)} = \sqrt{((-6)^2 + 3^2)} = \sqrt{(45)[/tex]

Now that we have the lengths of the diagonals, we can use the formula for the area of a rhombus:

Area = [tex]\rm (d_1 \times d_2) / 2 =\dfrac{ (\sqrt{(45)} \times \sqrt{(45)}}{2}[/tex]

= (45/2) square units

Therefore, the area of the given rhombus is 22.5 square units.

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Answer:  Participant A

Step-by-step explanation:

if you divide 120 by 10 you would get 12 jumping jacks per minute and if you divide 140 by 14 you would get 10 jumping jacks per minute

Answer: 1.85

Step-by-step explanation:

For the given function, the critical point is (-1,2), relative extrema is is 2, and saddle points is zero.

To find the critical points of a function, we need to find where the partial derivatives of the function are equal to zero or do not exist. In other words, we need to find the points where the function is not changing with respect to x and y. The partial derivative of f(x,y) with respect to x is:

fx = 2x + 2

And the partial derivative of f(x,y) with respect to y is:

fy = 2y - 4

To find the critical points, we set both partial derivatives to zero and solve for x and y:

fx = 2x + 2 = 0

=> x = -1

fy = 2y - 4 = 0

=> y = 2

So, the critical point of the function is (-1, 2).

To determine whether this critical point is a relative maximum, minimum, or saddle point, we need to look at the second partial derivatives of the function. The second partial derivative of f(x,y) with respect to x is:

fx = 2

And the second partial derivative of f(x,y) with respect to y is:

fy = 2

The mixed partial derivative of f(x,y) with respect to x and y is:

fy = 0

To classify the critical point, we can use the second derivative test.

If fx and fy are both positive (or both negative) at the critical point, then the critical point is a relative minimum (or maximum), respectively.

If fx and fy have different signs, then the critical point is a saddle point. If the second derivative test is inconclusive, then we need to use additional methods to determine the nature of the critical point.

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Complete Question:

Find the critical points, relative extrema, and saddle points of the function. (If an answer does not exist, enter DNE.) f(x, y) = x² + y² + 2x - 4y + 2

The closed formula for this particular sequence is an = n² + 2.

Take note that the odd numbers 3, 5, 7, 9, and 11 are separate consecutive terms. This shows that the first n odd numbers can be added to the initial term, az, to get the nth term. Hence, the following is how we may represent the nth term a = az + 1 + 3 + 5 + ... + (2n-3) (2n-3). We may utilize the formula for the sum of an arithmetic series to make the sum of odd integers simpler that is 1 + 3 + 5 + ... + (2n-3) = n².

As a result, we get a = az + n^2 - 1. In conclusion, the equation for the series (an)n21, where a1 = az and an is the result of adding the first n odd numbers to az, is as a = az + n^2 - 1. We have the following for the given series where a1 = az = 3.

So, the closed formula for this particular sequence is an = n² + 2.

To learn more about arithmetic sequences, refer to:

Your question is incomplete. The complete question is:

Find the closed formula for the sequence (an)n21. Assume the first term given is az. an = 3, 6, 11, 18, 27... Hint: Think about the perfect squares.

Step-by-step explanation:

a probability is always the ratio

desired cases / totally possible cases

we have 2 possible cases for the coin and 6 possible cases for the die.

so, we have 2×6 = 12 combined possible cases :

heads, 1

heads, 2

heads, 3

heads, 4

heads, 5

heads, 6

tails, 1

tails, 2

tails, 3

tails, 4

tails, 5

tails, 6

out of these 12 cases, which ones (how many) are desired ?

all first 6 plus (tails, 3) = 7 cases

so, the correct probability is

7/12

formally that is calculated :

1/2 × 6/6 + 1/2 × 1/6 = 6/12 + 1/12 = 7/12

the probability to get heads combined with the probability to roll anything on the die, plus the probability to get tails combined with the probability to roll 3.

The given matrices are in the following form,

Reduced echelon form is Matrix A .

Only echelon form is Matrix B.

Neither echelon form nor reduced echelon form is Matrix C.

Matrix A is in reduced echelon form.

In matrix A,

Each row has a leading entry of 1

That is farther to the right than the leading entry of the row above it.

Additionally, all entries below a leading 1 are 0.

This meets the requirements for a matrix to be in reduced echelon form.

Matrix B is in echelon form only.

In matrix B,

Each row has a leading entry

That is farther to the right than the leading entry of the row above it.

However, not all entries below a leading entry are 0.

In the third row, there is a leading 1.

But the entries below it are not all 0.

Matrix is in echelon form only, but not in reduced echelon form.

Matrix C is in neither echelon form nor reduced echelon form.

In matrix C,

The first and third rows have leading entries.

But the second row does not.

In the first row, the leading 1 is not farther to the right than the leading entry of the row below it.

This matrix does not meet the requirements for echelon form or reduced echelon form.

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Answer:

The required probability = 0.144

Step-by-step explanation:

Since the probability of making money is 60%, then the probability of losing money will be 100-60% = 40%

Now the probability we want to calculate is the probability of making money in the first two days and losing money on the third day.

That would be;P(making money) * P(making money) * P(losing money)Kindly recollect;P(making money) = 60% = 60/100 = 0.6P(losing money) = 40% = 40/100 = 0.4The probability we want to calculate is thus;0.6 * 0.6 * 0.4 = 0.144

The graph of the linear function 4x + 6y = -12 is given by the image presented at the end of the answer.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

The function for this problem is given as follows:

4x + 6y = -12.

In slope-intercept form, the function is given as follows:

6y = -4x - 12.

y = -2x/3 - 2.

The slope and the intercept are given as follows:

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The rate of change of cost C with respect to the percent of particulate pollution that escapes when p = 5 (percent) is -190000.

We know that the cost C, in dollars, of processing the exhaust gases at an industrial site to ensure that only p percent of the particulate pollution escapes is given by the equation C(p) = 7000(100− p) p

we have to find the rate of change of cost C with respect to the percent of particulate pollution that escapes when p = 5 (percent)

a) c (p) = 7600 (100-p) / p

c (p) = 7600 [p(-1) - (100-p) (1)] / 2p

= 7600/2p = 760000/4

= -190000

therefore, the rate of change of cost C with respect to the percent of particulate pollution that escapes when p = 5 (percent) is -190000.

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When conducting course-based human research, Informing participants about what will happen to the data gathered is an essential aspect of ethical research practice and can contribute to the overall quality and credibility of the research. This includes explaining how the data will be collected, stored, and analyzed, as well as how it will be used and potentially shared with others.

By informing participants about the use of their data, researchers can build trust and transparency with their participants. Participants have the right to know how their data will be used and to provide informed consent to participate in the study. This also allows participants to make an informed decision about whether or not they want to participate in the study.

Furthermore, informing participants about the use of their data can help ensure that ethical guidelines are followed and that the study is conducted in a responsible and respectful manner. This can help to prevent any potential harm to participants and can contribute to the overall validity and reliability of the study.

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Answer: 1/12

Step-by-step explanation:

The triangle's other leg, side B, measures 12 cm in length.

When one of the interior angles is 90 degrees, or a right angle, the triangle is said to be a right triangle. The three internal angles of a triangle add up to 180 degrees in a right triangle because one angle must always be 90 degrees and the other two must always total to 90 degrees (they are complementary).

We can observe that the given triangle is a right triangle because angle A's measure is 90 degrees. The hypotenuse, which is represented by the letter "c," is the side that is opposite the right angle. The legs are the other two sides, and they are indicated by "a" and "b".

We are told that the hypotenuse (side c) is 13 cm long and that one leg (side a) is 5 cm long. The length of the other leg must be determined (side b).

The Pythagorean theorem, which asserts that in a right triangle, can be used.

a² + b² = c²

Inputting the values provided yields:

5² + b² = 13²

25 + b² = 169

b² = 144

b = 12

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a) The mean is 720 and the standard deviation for the distribution is approximately 28.87

b. The probability that X is less than 710 is 33%

a. To calculate the mean and standard deviation, we use the following formulas:

Mean (μ) = (lower limit + upper limit) / 2

Standard deviation (σ) = (upper limit - lower limit) / √12

Substituting the values, we get:

Mean (μ) = (670 + 770) / 2 = 720

Standard deviation (σ) = (770 - 670) / √12 ≈ 28.87

b. To find the probability that X is less than 710, we use the following formula:

Probability (X < 710) = (710 - lower limit) / (upper limit - lower limit)

Substituting the values, we get:

Probability (X < 710) = (710 - 670) / (770 - 670) ≈ 0.33

This means that there is a 33% chance that X will be less than 710.

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So, based on the resemblance between AA and SS, we can say: AEDC and AJKL

An enclosed triangle is a geometric shape with three sides and three angles in two dimensions. It is one of the fundamental geometric shapes and has several uses in both mathematics and daily life. Acute, obtuse, right, equilateral, isosceles, and scalene triangles are examples of popular types of triangles that can be categorized based on the size of their sides and angles. Triangle analysis is a crucial component of geometry and is used in disciplines including physics, engineering, and architecture.

given

Triangles in option (C) resemble those in (B).

If the matching sides and angles of two triangles are proportionate, then we can say that the triangles are comparable.

Triangle formed by AJKL and AEDC contains:

AED Equals AJK (both at 50 degrees)

ADS = ADE (both are right angles)

CDE = KLJ (both are right angles)

The triangles meet the angle-angle (AA) similarity requirement as a result.

Moreover, we have

DE/ JL = 52/39 AE/ AJ = 24/50 = 12/25

The triangles so also meet the side-side (SS) similarity requirement.

So, based on the resemblance between AA and SS, we can say: AEDC and AJKL

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The complete question is:-  State if the triangles in each pair are similar. If so, state how you know they are similar and complete the similarity statement.

AJKL~

A) not similar

B) similar; SSS similarity; ADCE C) similar; SAS similarity; AEDC D) similar; SSS similarity; ADEC