Which of the following explains how inlets are impacted by high tides?
A. High tides fill inlets with water so they become larger.
B. High tides cause the land to be more exposed.
C. High tides remove sand and seashells on the beach.
D. High tides erode the sediments from an inlet.
(pls help)

The pair of words or phrases that best completes the sentence "Isoelectronic species have radii that vary with ___even though they have the same number of ___." is "atomic number; electrons."

Explanation:

Isoelectronic species refers to atoms, molecules or ions having the same number of electrons but a different number of protons. They have identical electron configurations but different nuclear charges. As a result, they may have different ionic radii.

The ionization energy and electron affinity of isoelectronic species are identical, but the size of the atoms varies with the nuclear charge or atomic number. Atomic radius depends on the number of electrons and the nuclear charge. This is because the nuclear charge exerts an attractive force on the electrons in the outer shell that holds them in place.

The greater the nuclear charge, the smaller the atom.The pair of words or phrases that best completes the sentence is "atomic number; electrons." The number of electrons in the outermost shell of an atom determines its size. As we progress from left to right on a period, the number of electrons in the outer shell stays the same, but the nuclear charge increases.

This results in a decrease in size from left to right .Arranging isoelectronic species in a table shows that the radius of an ion is inversely proportional to the nuclear charge or atomic number.

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To shift the potential of the lead-zinc cell upward, toward 0.70 V, the following actions would give the desired result:

Add some concentrated Pb(C2H3O2)2 solution to the Pb2+/Pb couple

Adding some concentrated Zn(C2H3O2)2 solution to the Zn2+/Zn couple

Any action that makes [Zn2+] larger than [Pb2+]

A lead-zinc cell is a galvanic cell consisting of lead and zinc electrodes immersed in a suitable electrolyte. The potential of the lead-zinc cell is the difference in electrode potential between the lead and zinc electrodes, as determined by their concentration gradient.

Therefore, to shift the potential of the lead-zinc cell upward, toward 0.70 V, one should add some concentrated Pb(C2H3O2)2 solution to the Pb2+/Pb couple, add some concentrated Zn(C2H3O2)2 solution to the Zn2+/Zn couple, and any action that makes [Zn2+] larger than [Pb2+].

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Empirical formulae are the ratios of atoms in a compound that show the lowest possible ratio of atoms per mole of compound.

In this question, we are to find the empirical formulae for the following ions:

OCl³⁻, NH⁴⁺, CH₃CO₂⁻ and Pb⁴⁺

Empirical formula for OCl³⁻:Oxygen (O) forms an anion by gaining three electrons to form the oxide ion, O²⁻

The ClO₃⁻ ion has one O²⁻ and three Cl⁺ ions. Therefore, the empirical formula is OCl³⁻

Empirical formula for NH₄⁺ :Nitrogen (N) forms a cation by losing three electrons to form N₃⁺ while Hydrogen (H) forms a cation by losing an electron to form H⁺. Therefore, the empirical formula for NH₄⁺ is NH₄⁺

Empirical formula for CH₃CO₂⁻

The ion contains 2 Carbon atoms, 3 Oxygen atoms, and 4 Hydrogen atoms. Divide each number of atoms by the lowest number (2) to give the empirical formula: CH₃CO₂⁻

Empirical formula for Pb⁴⁺:Lead (Pb) forms a cation by losing four electrons to form Pb⁴⁺.Therefore, the empirical formula for Pb⁴⁺+ is Pb⁴⁺.

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There is a small gap left between the rails of a railway track Reason (R): Cooling of substances result in contraction. Both A and R are true but R is not the correct explanation of A,

When a substance is cooled, it means that the heat is removed from the substance. This results in fewer excited molecules and, as a result, less random motion. The force of attraction increases, resulting in fewer spaces between molecules, which causes contraction.

The gaps left between successive rails on a railway track as a result of the rails expanding in the summer. The gap exists to allow for this expansion. If no gap is left, the summer expansion will cause the rails to bend sideways. This will lead to train accidents.

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The standard reduction potential of the cathode half-reaction is -0.36V,

The standard reduction potential of the anode half-reaction is +0.34V,

and the standard potential of the cell is -0.02V.

The cathode half-reaction is the reduction of iron (Fe²⁺) to iron (Fe):

Fe²⁺ + 2e⁻ -> Fe; E°cathode = -0.36V.

The anode half-reaction is the oxidation of copper (Cu) to copper (Cu²⁺):

Cu -> Cu²⁺ + 2e⁻; E°anode = +0.34V.
The standard potential of the cell is determined by subtracting the standard reduction potential of the anode from the standard reduction potential of the cathode:

E°cell = E°cathode - E°anode

= -0.36V - (+0.34V)

= -0.02V.

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Dolostone is composed of the mineral dolomite, which is similar to calcite in limestone, except that dolomite contains magnesium.

Dolostone, also known as dolomite rock, is a sedimentary rock composed mainly of the mineral dolomite. Dolomite, a calcium magnesium carbonate mineral, is the primary component of dolostone, making up around 90-95 percent of the rock. Dolostone is a rock that is similar to limestone and is often mistaken for it.

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The coupling reaction of two radicals is b. exothermic and involves one arrow.

A radical is a chemical entity that contains an unpaired electron in its valence shell, which makes it highly reactive. Molecules that contain an unpaired electron are referred to as "free radicals." Coupling reactions between free radicals involve the interaction of two free radicals, both of which have an unpaired electron. A covalent bond is created when these two free radicals join together, effectively eliminating the unpaired electron. This coupling reaction can be exothermic or endothermic based on the number of arrows present.

For two radicals, only one arrow is needed for the exothermic coupling reaction. The reaction is exothermic, and heat is produced as a result of the reaction. The energy produced by the bond-forming reaction overcomes the energy of the starting materials. This energy that is generated raises the kinetic energy of the product's components. As a result, the temperature of the system increases. For two radicals, the endothermic coupling reaction requires two arrows. The reaction absorbs energy, causing the temperature of the system to decrease.

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The pH of a solution of ammonium-based buffer containing 0.175 M ammonium bromide and 0.0836 M acetic acid is 9.26.

What is the pH of this solution?

A buffer is a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid. It resists changes in pH when small amounts of acid or base are added to it.

For the buffer solution to work, its pH should be within the acid dissociation constant, Ka of the weak acid and the weak base, Kb. In this question, the buffer is made up of ammonium bromide and acetic acid. The Ka for the acetic acid, CH3COOH is 1.74 x 10-5. It is a weak acid. The buffer pH can be calculated using the Henderson Hassel-balch equation.

Henderson Hassel-balch equation pH = pKa + log ([A-] / [HA]) Where, A- is the conjugate base and HA is the weak acid, pKa is the negative logarithm of Ka, pKa = -log Ka = -log (1.74 x 10-5), pKa = 4.76. Ammonium bromide will act as a salt in this solution, and its conjugate base will be ammonia.

NH4Br → NH4+ + Br-NH4+ will combine with OH- to form ammonia, NH3 and water.NH4+ + OH- → NH3 + H2OIn this reaction, OH- will be added to the buffer.

To calculate the pH of the buffer, we need to know the concentration of NH4+ and NH3 at equilibrium. NH4+ will come from the ammonium bromide, and NH3 will come from the reaction above.The ammonium bromide dissociates as follows:

NH4Br → NH4+ + Br-

Therefore, [NH4+] = 0.175 M. The concentration of NH3 will depend on the OH- concentration, which will be used up in the reaction. We need to know the Kb of NH3 to calculate the concentration of NH3 at equilibrium.

Kb for NH3 is 1.8 x 10⁻⁵ NH3 + H2O ↔ NH4+ + OH

-Kb = [NH4+] [OH-] / [NH3]

Kb = [NH4+] [OH-] / [NH3]But [NH3] = [NH4+] as they are in equal amounts, so;

Kb = [OH-]

Kb = 1.8 x 10-5[OH-] = 1.8 x 10-5.

The pOH = - log (1.8 x 10-5) = 4.74.

The pH of the buffer = 14 - pOH = 9.26

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Answer:

1,2,1,2

Explanation:

The final concentration of DCMU in the locomotion chambers will be 0.1 mM. If 10mL of the Chlamydomonas, 100 microliters of sterile water, and 100 microliters of 10mM DCMU is added.

To Calculate the final concentration of Sodium Azide and DCMU in the locomotion chambers. The final concentration of Sodium Azide in the locomotion chambers will be 10mM (millimolar) if 10mL (milliliters) of the Chlamydomonas, 100 μL (microliters) of sterile water, and 100 μL of 1M (molar) Sodium Azide is added.

The final concentration of DCMU (3-(3,4-dichlorophenyl)-1,1-dimethylurea) in the locomotion chambers will be 0.1 mM (millimolar) if 10 mL (milliliters) of the Chlamydomonas, 100 μL (microliters) of sterile water, and 100 μL of 10 mM (millimolar) DCMU are added.

Calculating the final concentration of DCMU:

Formula: C1V1 = C2V2C1 = initial concentration of DCMU = 10 mMV1 = volume of DCMU added = 100 μL (microliters)C2 = final concentration of DCMU = ?V2 = final volume = 10 mL + 100 μL + 100 μL = 10.2 mL

(convert 100 μL to mL by dividing it by 1000)

Substituting the values in the formula:

C1V1 = C2V210 mM x 100 μL = C2 x 10.2 mL1000 (since 1 mL = 1000 μL)C2 = 0.098 mM (millimolar) = 0.1 mM (approx.)

Thus, the final concentration of DCMU in the locomotion chambers will be 0.1 mM if 10mL of the Chlamydomonas, 100 microliters of sterile water, and 100 microliters of 10mM DCMU is added.

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Answer: clear the area of anything flammable such as hair, chemicals, Ect.

The calculated molar mass of 32 g/mol is the same as the molar mass of oxygen. Thus, the gas is O2.

Let us determine the molar mass of this gas. We can begin with the density of the gas as follows:

Density = mass/volume
Density = 0.96 g/0.672 L

Density = 1.43 g/L

We know that at STP (standard temperature and pressure), temperature is 0°C and pressure is 1 atm. We can use these values to determine the molar volume of a gas, which is 22.4 L.

Molar volume = 22.4 L at STP
Thus,
1 mole of gas occupies 22.4 L at STP

We can determine the number of moles of the gas as follows:

Number of moles = volume/molar volume
Number of moles = 0.672 L/22.4 L/mol
Number of moles = 0.03 mol

The molar mass can be determined using the following formula:
molar mass = mass/number of moles
molar mass = 0.96 g/0.03 mol
molar mass = 32 g/mol

The calculated molar mass of the gas is 32 g/mol. Now let us compare this molar mass with the molar mass of the given gases.
Oxygen (O2) has a molar mass of 32 g/mol

The calculated molar mass of 32 g/mol is the same as the molar mass of oxygen. Therefore, the identity of the gas is O2.

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The volume of the gas will decrease from 20 cm³ to 13.08 cm³.

Boyle's law is a gas law that states that the product of the pressure and volume of a gas is constant at constant temperature.

Assuming no change in temperature is significant because it allows us to apply Boyle's law to solve the problem. If the temperature were to change, we would need to use a different gas law, such as Charles's law or the combined gas law, to account for the change in temperature.

We can use Boyle's law to solve this problem, which states that the product of the pressure and volume of a gas is constant at constant temperature. Mathematically, we can express this as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, respectively, and P₂ and V₂ are the final pressure and volume, respectively.

Using this equation, we can solve for V₂:

P₁V₁ = P₂V₂

V₂ = (P₁V₁)/P₂

Substituting the given values, we get:

V₂ = (510 mmHg x 20 cm³) / 780 mmHg

V₂ = 13.08 cm³

Therefore, if the pressure is increased from 510 mmHg to 780 mmHg at constant temperature, the volume of the gas will decrease from 20 cm³ to 13.08 cm³.

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The substance with the higher specific heat is Substance B. Specific heat is the amount of energy required to raise the temperature of a unit mass of a substance by one degree Celsius.

Since equal masses of two substances absorb the same amount of heat, the substance with the higher specific heat will require more energy to raise its temperature by one degree Celsius, meaning that it will experience a smaller increase in temperature when the same amount of heat is applied. In this case, since Substance A's temperature increased twice as much as Substance B's, Substance B has the higher specific heat.

When two substances have the same mass and absorb the same amount of heat energy, the substance with the lower specific heat will have a higher temperature increase. Therefore, if the temperature of substance A increases twice as much as the temperature of substance B, it means that the specific heat of substance A is lower than the specific heat of substance B.

The formula for specific heat is given as follows:

Q = mcΔT

where, Q is the amount of heat energy added or removed, m is the mass of the substance, c is the specific heat of the substanceΔT is the change in temperature.

Therefore, if Q and m are the same for both substances, then the ratio of their temperature changes is given by:

ΔTA/ΔTB = cB/cA

Since the temperature of substance A increased twice as much as substance B, it means that ΔTA = 2ΔTB. Therefore, we can substitute these values in the above formula and get:

2 = cB/cA⇒ cA = cB/2

Since the specific heat of substance A is half of the specific heat of substance B, it means that substance A has a lower specific heat as compared to substance B.

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At PH 1.2, the indicator will appear red.

Universal indicator- The universal indicator is a mixture of 4 common indicators allowing for a large pH range to be measured.

At pH 7, the indicator will appear yellow due to bromothymol blue. The universal indicator (or parts thereof) are in equilibrium and have an associated K value.

K value- The K value indicates the amount of products and reactants present in the reaction. It is an equilibrium ratio of the concentration of products and the reactants.

A universal indicator is made by mixing bromomethyl, methyl orange and phenolpthalein in alcohol.

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Generally, a literature review should aim to provide a comprehensive and up-to-date overview of the existing research and scholarly literature relevant to the research question or topic. This means that the number of studies or literatures included in a literature review will depend on factors such as the breadth and depth of the research question, the availability and relevance of existing research, and the scope of the research project.

It is important to ensure that the literature review is well-organized, critically analyzed, and clearly presented, regardless of the number of studies or literatures included. The focus should be on selecting high-quality and relevant sources, rather than simply aiming for a specific number of sources. A literature review should provide a thorough synthesis and analysis of the existing literature, and should demonstrate a clear understanding of the key debates, trends, and findings in the field.

The  molecule that is the main product of the Calvin cycle is glucose. The Calvin cycle is also known as the light-independent reactions.

It is a series of biochemical reactions that occur in the stroma of the chloroplast in photosynthetic organisms to produce glucose. The Calvin cycle is made up of three stages: Carbon fixation, Reduction and regeneration of ribulose bisphosphate. Here's a breakdown of each stage:

Carbon fixation: Carbon dioxide enters the Calvin cycle and is converted to organic molecules. During carbon fixation, Rubisco, which is a crucial enzyme in photosynthesis, catalyzes the reaction between carbon dioxide and ribulose bisphosphate, leading to the formation of a six-carbon molecule that splits into two three-carbon molecules. This three-carbon molecule is the starting material for the reduction process.

Reduction: The ATP and NADPH produced during the light-dependent reactions are used to convert the three-carbon molecule produced during carbon fixation into glyceraldehyde-3-phosphate. This process involves a series of biochemical reactions that require the use of energy from ATP and electrons from NADPH.

Regeneration of ribulose bisphosphate: Glyceraldehyde-3-phosphate, which is the main product of the Calvin cycle, is used to regenerate the starting material for carbon fixation, ribulose bisphosphate. During this stage, ATP is used to convert the remaining glyceraldehyde-3-phosphate molecules into ribulose bisphosphate. The Calvin cycle is an essential process in photosynthesis, as it produces glucose, which is the main source of energy for plants and other photosynthetic organisms.

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The density of the sample of a substance with a mass of 20 g and volume of 5 cm³ will be 4 g/cm³.

Density of a substance can be defined as the measure of the amount of mass which is contained in a unit of volume of that substance. The general trend is that most of the gases are less dense than that of liquids, which are in turn less dense than that of solids, but there are numerous exceptions also present in nature.

The density of a substance can be calculated with the help of the formula:

Density = mass/volume.

Given, Mass of substance = 20g

Volume of substance = 5cm³

Density of the sample = mass of substance/volume of substance = 20g/5cm³ = 4 g/cm³

Therefore, the density of the sample is 4 g/cm³.

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When the energy released by forming solvent-solute attractions is greater than the energy absorbed by overcoming solute-solute and solvent-solvent attractions, the dissolving process has a negative heat of solution. correct answer is option A

A negative heat of solution is created when the amount of energy required to dissolve a solute in a solvent is less than the amount of energy released when the solute and solvent combine. This generally occurs when the solute-solvent interactions are stronger than the solute-solute and solvent-solvent interactions.  

The magnitude of the heat of solution is determined by the magnitude of the change in enthalpy. The enthalpy change of the solvent-solute interaction is the heat change that occurs when one mole of solute is dissolved in a given solvent. A negative enthalpy change indicates an exothermic reaction, whereas a positive enthalpy change indicates an endothermic reaction.

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The protoliths for the displayed photos are: Quartzite - Sandstone, Schist and Phyllite - Mudstone or Shale, Marble - Limestone or Dolomite, and Metaconglomerate - Conglomerate.

Protoliths, or pre-existing rocks, undergo metamorphosis under extreme pressure, temperature, and/or chemical changes to become metamorphic rocks. The shown pictures show several kinds of metamorphic rocks with unique protoliths, textures, and mineral compositions. Sandstone may create quartzite, a hard, granular rock with a high quartz concentration. Both schist and phyllite, which are composed of mudstone or shale, have distinctive foliated textures, with schist having a coarser texture than phyllite. Marble is a crystal-like rock that is made from limestone or dolomite and has a wide range of hues and patterns. In addition, metaconglomerate, which is a layer of conglomerate with visible pebbles and cobbles, is a coarse-grained, layered rock.

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The balloon that is one size larger than the others serves to symbolise the area in a molecule inhabited by lone pairs of electrons, signifying unshared electron pairs in a particular region.

The Lewis structure is a chemical model that depicts how atoms and valence electrons are arranged in a molecule. The atoms are represented by symbols, and the valence electrons, which are the electrons at the highest energy level, are shown as dots or lines. In organic chemistry, the bigger balloon often designates a region of a molecule where electrons are not shared with any other atoms or groups. The structure and reactivity of the molecule are impacted by this region, which is referred to as a lone pair. The wider balloon makes it easier to see where these unshared electron pairs are located and how they affect the molecule's overall structure and behaviour.

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The factors that favor SN2 reactions are Strong nucleophile, good leaving group, polar aprotic solvent, methyl or primary halide.

SN2 reactions require a strong nucleophile, good leaving group, polar aprotic solvent, and a methyl or primary halide. The reason for this is that SN2 reactions occur in a single step, with the nucleophile attacking the substrate and the leaving group departing at the same time. When the nucleophile approaches the substrate, it must be in a good orientation to cause an SN2 reaction.The best orientation for SN2 reactions occurs when the substrate is methyl or primary, the solvent is polar aprotic, the nucleophile is strong, and the leaving group is good. When the leaving group departs, it must be able to do so quickly, so a good leaving group is required. Finally, the solvent must be polar aprotic, which means that it can stabilize negative charges while not inhibiting the reaction by solvating the substrate.

The nucleophile attacks the substrate from the rear in order for this reaction to continue. The angle of the nucleophile's approach to the supplied substrate with respect to the carbon-leaving group bond is 180o. Through a transition state, the carbon-nucleophile bond forms and the carbon-leaving group bond dissolves simultaneously.

The needed product is now created when the leaving group is forced out of the transition state on the other side of the carbon-nucleophile connection. It's crucial to remember that the product is created by inverting the tetrahedral geometry at the central atom.

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The salt which you would test if you wanted to observe how just anions affect pH is Na2CO3.

What is salt? Salts are inorganic compounds made up of a cation and an anion. Salts are formed by the neutralization of an acid with a base, for example, hydrochloric acid and sodium hydroxide form table salt: NaCl. The cation is typically a metal or a positively charged organic compound, whereas the anion is generally a non-metal or a negatively charged organic compound. The salt's properties are a function of the cation and anion and are hence unique.

Salt's effect on pH: Salts are made up of cations and anions, both of which can have an impact on pH. Cations and anions can both have an impact on the pH of the solution, but they can do it in different ways. The pH of a solution can be affected by the anion of the salt since it can act as a base or an acid. The pH of a solution can be affected by the cation of the salt since it can act as an acid or a base. For instance, if we dissolve copper sulfate in water, the pH of the solution will be acidic since the sulfate ion will be hydrolyzed to create sulfuric acid, H2SO4.

However, if we dissolve sodium carbonate in water, the pH of the solution will be basic because the carbonate ion acts as a base, picking up H+ ions from water molecules to generate HCO3- ions. Hence, Na2CO3 is the salt which you would test if you wanted to observe how just anions affect pH.

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The effect of low [s] is that the rate of the reaction will decrease and the effect of high [s] is that the rate of the reaction will increase. When Vo is one-half of Vmax, the effect is that the reaction has reached its half-maximum velocity, or that the reaction has reached its maximum efficiency.

The rate of the reaction will decrease in the case of low [s] as the substrate concentration is too low to support the reaction. On the other hand, the rate of reaction will increase in the case of high [s] as there is a greater amount of substrate to drive the reaction.

To understand these effects in a better way, we can use the Michaelis-Menten equation to calculate the rate of reaction at various substrate concentrations (Vo and Vmax) and also the reaction's maximum velocity (Vmax):-

V = Vmax[S]/(Km + [S])

Where Vmax is the maximum velocity of the reaction, Km is the Michaelis constant, and [S] is the concentration of the substrate.

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The statement that is true about the chemical equilibrium constant K eq is: A K eq larger than 1 means the reaction favors toward the product side.

When a chemical reaction occurs, it does not continue indefinitely; rather, it reaches a point at which the forward and reverse reactions occur at the same rate, and this is referred to as chemical equilibrium.

Chemical equilibrium refers to the point at which a reaction has reached a point at which the concentrations of the reactants and products no longer change over time,

implying that the forward and reverse reactions are occurring at the same rate.

K eq = ([C]^c[D]^d)/([A]^a[B]^b)

Where [A], [B], [C], and [D] represent the concentrations of the reactants and products, respectively, and a, b, c, and d represent the stoichiometric coefficients of the reactants and products.

The K eq value is a measure of the degree to which a reaction is likely to proceed.

The magnitude of the K eq value provides information about the position of the equilibrium, the extent of the reaction, and the relative concentration of reactants and products.

A K eq value greater than 1 indicates that the reaction is favored in the forward direction (product formation) at equilibrium,

whereas a K eq value less than 1 indicates that the reaction is favored in the reverse direction (reactant formation).

A K eq value of 1 indicates that the reactants and products are present in roughly equal proportions at equilibrium.

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Answer:

A gas with a constant volume had an original pressure of 1150 torr and a temperature of 75.0 ℃. Pressure was decreased to 760 torr. What is the final temperature of the gas?a. -43.0 ℃b. 49.6 ℃c. 230 ℃d. -251 ℃

When benzoquinone is treated with excess butadiene, the products obtained are 2,5-dimethylcyclohexadiene-1,4-dione and cyclohexene.

Benzoquinone is also known as 1,4-benzoquinone or cyclohexa-2,5-diene-1,4-dione, is a colorless organic compound. The presence of two carbonyl groups in its structure provides it its characteristic quinone chemistry.

Butadiene, also known as 1,3-butadiene, is a conjugated diene. The reaction between benzoquinone and butadiene is called a Diels-Alder reaction.

The Diels-Alder reaction is a conjugate addition reaction that joins a diene and a dienophile to create a new six-membered ring. The most important characteristic of the Diels-Alder reaction is its stereospecificity. This reaction occurs between a cyclic diene and an alkene or alkyne dienophile.

The products obtained when benzoquinone is treated with excess butadiene are:2,5-dimethylcyclohexadiene-1,4-dioneCyclohexeneThe reaction proceeds with the dienophile (benzoquinone) being attacked by the diene (butadiene) in the Diels-Alder reaction to produce a cyclic adduct. The product is 2,5-dimethylcyclohexadiene-1,4-dione. Cyclohexene is formed as a byproduct of the reaction.

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The correct answer is: In transpiration, because some of its properties change, water undergoes a physical change but keeps its identity.

Transpiration and photosynthesis are both processes that involve the use of water by plants.

Transpiration is the process by which water evaporates from the leaves of a plant and is released into the atmosphere. This occurs through tiny openings on the surface of leaves called stomata. The water that is lost through transpiration is replaced by water absorbed by the roots of the plant from the soil.

Photosynthesis, on the other hand, is the process by which plants use water, along with carbon dioxide and sunlight, to produce oxygen and glucose. During photosynthesis, water is split into hydrogen and oxygen, and the oxygen is released into the atmosphere as a byproduct. The glucose that is produced is used as a source of energy by the plant.

In transpiration, because some of its properties change, water undergoes a physical change but keeps its identity. In photosynthesis, because its identity changes, water undergoes a chemical change.

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Answer:

Its A

Explanation:

Got it right on the quiz

Answer: how many years does it take for plastic to decompose?

Well, it depends on the plastic,  regular plastic can take up to 20 years to decompose, however, plastic bottles can take up to 450 years to decompose.

Answer:

a) Acidified potassium dichromate solution is used to test for the presence of a primary or secondary alcohol.

b) The orange color of the potassium dichromate solution is reduced to green when it reacts with an alcohol.

c) The oxidation of a primary alcohol produces a carboxylic acid.

d) The oxidation of a secondary alcohol produces a ketone.

e) The dichromate test does not work for tertiary alcohols because they cannot be further oxidized. Methylpropan-2-ol is a tertiary alcohol with the chemical structure:

CH3

|

CH3—C—OH

|

CH3

Since there are no hydrogen atoms attached to the carbon atom bearing the hydroxyl group, it cannot be oxidized.

a) A simple test for the presence of a carboxylic acid group is the addition of sodium hydrogencarbonate solution to the compound. The reagent reacts with the carboxylic acid to produce carbon dioxide gas.

Reagent: Sodium hydrogencarbonate solution

Observation: Effervescence (bubbling) due to the release of carbon dioxide gas.

b) To confirm that the gas produced in the hydrogencarbonate test is carbon dioxide, it can be tested with limewater. Carbon dioxide turns limewater milky/cloudy due to the formation of calcium carbonate.

c) The hydrogencarbonate test is not conclusive proof that a carboxylic acid group is present in a completely unknown compound because some other functional groups such as phenols and alcohols can also react with the reagent and produce carbon dioxide. Therefore, additional tests such as the dichromate test or Tollens' test may be needed to confirm the presence of a carboxylic acid group.

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