Answer:
(4,5)
Step-by-step explanation:
Hi there!
We are given the system of equations:
5x+2y=30
-5x+4y=0
and we need to find the solution
there are 3 ways to solve a system of equations, but let's use the elimination method, where we will add the systems together to clear one variable out, solve for the other variable, and use the value of the solved variable to find the other variable
When we clear a variable, the coefficients need to be opposites (ex. 2 and -2). In this case, the coefficients in front of x are 5 and -5 in the first and second equation respectively
5x+2y=30
-5x+4y=0
add the equations together
6y=30
divide both sides by 6
y=5
we found the value of y
now we need to find the value of x
substitute 5 as y into either one of the equations (ex. the first one) to solve for x
5x+2(5)=30
multiply
5x+10=30
subtract 10 from both sides
5x=20
divide both sides by 5
x=4
so the answer is x=4, y=5; as a point, it's (4,5)
Hope this helps! :)
b(1)=−7
b(n)=b(n−1)+12
Find the 4th term in the sequence.
Answer:
4th term = 29
to generate the terms, substitute n = 2, 3, 4 into the rule
noting that b(1) = - 7
b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5
b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17
b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29
Please help I’ll give brainliest
Answer:
The answer for this question is 3
Answer:
i believe its 2 but i could be wrong
Step-by-step explanation:
im sorry if i am
ASAP 30 POINTS BRAINLIEST IF RIGHT
Answer:
answer in the link below if you have any questions let me know
Answer:
≈ 0.14
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [a, b ] = [ - 1, 3 ] , then
f(b) = f(3) = [tex]\sqrt[3]{3+3}[/tex] = [tex]\sqrt[3]{6}[/tex] ≈ 1.817
f(a) = f(- 1) = [tex]\sqrt[3]{-1+3}[/tex] = [tex]\sqrt[3]{2}[/tex] ≈ 1.260 , then
average rate of change = [tex]\frac{1.817-1.260}{3-(-1)}[/tex] = [tex]\frac{0.557}{4}[/tex] ≈ 0.14 ( to the nearest hundredth )
32% of the days in a year the wind blows south.About how many days does the wind blows south?
Answer:
116 days because 32 percent of 365 is 116
how to solve 3^8 times 3^2
Answer:
3072 that what I known as a 10th grader
The radius of a cylinder of volume 2970cm³ is 30mm. Find the volume of a similar cylinder of radius 40mm.
34.3 cm3
if you use formula
30mm 2970cm3
x-x un^3
What is the value of [tex]\frac{81^4}{3^5}[/tex]? (Express your answer in exponential form.)
Answer:[tex]3^1^1\\[/tex]
Step-by-step explanation:
[tex]\frac{81^4}{3^5}[/tex]
[tex]\frac{3^1^6}{3^5}[/tex]
The base is same power can be add or subtract
[tex]3^1^6^-^5[/tex]
[tex]3^1^1[/tex]
Find a third-degree polynomial equation with rational coefficients that has roots –5 and 6 + i.
The coefficients of the polynomial are rational, which means that any non-real roots occur alongside their complex conjugates. In this case, 6+i is a root, so 6-i is also a root.
So the simplest polynomial you can build with these roots is
(x - (-5)) (x - (6 + i )) (x - (6 - i )) = x ^3 - 7x ^2 - 23x + 185
(first choice)
Josie is purchasing a $75 appliance for her kitchen. She has three coupons to the store that she can choose from. Which is a true statement about Josie’s options?
Answer:
where are the answer choices?
Step-by-step explanation:
How do you graph x ≤ 5 on a number line? pls help!
Answer:
From 5, the arrow would be facing left and the dot on 5 would be closed
Step-by-step explanation:
Hope this helps
What is the value of 2 + (-2/3) ^2 ÷1/3 ?
16
3
-2
0
.
Answer:
Doing the test rn got 3 1/3 i dont know if u should trust me but just try
Step-by-step explanation:
Cameron drives a semi-truck for Haulin' Harry's Trucking Company. He earns $0.45 for every mile he drives. If Cameron drove 827.4 miles on his last route, how much money did he earn?
Answer:
$372.33
Step-by-step explanation:
For 1 mile= $0.45
For 827.4 miles = $0.45 x 827.4
= $372.33
harleys house has a value of £160000 correct to 2 significant figures
write down the least possible value of the house
write down the greatest possible value of the house
Answer:
155,000
159,999
Step-by-step explanation:
In order to correct to 2 significant figures, look at the third figure, if the number is greater or equal to 5, add 1 to the ten thousand figure. If this is not the case, add zero. Replace all the figures before the thousand figure with zero. i.e. the hundred ten, unit
e.g. Rounding off 10,999 to the nearest thousand is 11,000
In this example, the least figure, the thousand figure should have to be rounded off to 2 significant figures is 5 and the greatest figure it can have is 9
Identify the coefficients in this expression 4+3×+5×
Answer:
8Step-by-step explanation:
4 + 3x + 5x
= 4 + 8x
Hence, coefficient of x is 8 (Ans)
Geometric stuff and please explain
Perimeter = Sum of the sides measures
Perimeter = | AB | + | AT | + | BT |
Perimeter = ( x + 3 ) + ( 4x ) + ( 2x + 2 )
40 = x + 4x + 2x + 3 + 2
Colect like terms
40 = ( 1 + 4 + 2 )x + ( 3 + 2 )
40 = 7x + 5
Subtract both sides - 5
40 - 5 = 7x + 5 - 5
35 = 7x
Switch sides
7x = 35
Divide both sides by 7
7x ÷ 7 = 35 ÷ 7
x = 5
_____________________________
AB = x + 3 = 5 + 3 ======》 AB = 8
AT = 4x = 4 × 5 =========》 AT = 20
BT = 2x + 2 = 2(5) + 2 ===》 BT = 12
According to the law of inequality in a triangle, the sum of any two random sides must be greater than the size of the other side which means :
AB + AT > BT
&
AB + BT > AT
&
AT + BT > AB
If the sides is true in the above inequalities, then those sides are able to form a triangle ;
But if even one of the above inequalities is violated, those sides will not be able to form a triangle.
8 + 20 > 12 ( Check )
8 + 12 > 20 ( Nope this inequlity violated )
Thus the measures of the sides can not represent the measures of the sides of a triangle .
And we're done ...
Graph a line with y- intercept of 5 and gradient of -10/3
Step-by-step explanation:
the equation is:
y= -10/3 x +5
the graph as attached
y is proportional
to x
y = 72 when x = 12
Write a direct
proportion
equation.
A. y = 12x
B. y = 6x
C. 72x = 12
D. 7 x 12 = y
Answer:
B :) (im sure btw)
Step-by-step explanation:
Pls don’t have much time
Answer:
the answer is b
Step-by-step explanation:
35 occurs the most on the graph meaning that it's the mode
Express 60g as a percentage of 3kg?
Answer:
2%
60/3000g= ?/100
60×100/3000=2
Flying against the wind, an airplane travels 3800 kilometers in 4 hours. Flying with the wind, the same plane travels 3750 kilometers in 3 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer:
[tex]V_w =1100[/tex] ---- velocity of wind
[tex]V_a = 150[/tex] --- velocity of airplane
Step-by-step explanation:
Given
[tex]V_a \to[/tex] velocity of airplane
[tex]V_w \to[/tex] velocity of wind
Flying with the wind, the distance (d) is:
[tex]d = (V_w + V_a) * t[/tex]
Where d and t are distance travel and time spent with the wind
So:
[tex]3750 = (V_w + V_a) * 3[/tex]
Divide by 3
[tex]1250 = (V_w + V_a)[/tex]
Flying against the wind, the distance (d) is:
[tex]d = (V_w - V_a) * t[/tex]
Where d and t are distance travel and time against with the wind
So:
[tex]3800 = (V_w - V_a) * 4[/tex]
Divide by 4
[tex]950 = (V_w - V_a)[/tex]
Make [tex]V_w[/tex] the subject
[tex]V_w= 950 + V_a[/tex]
Substitute: [tex]V_w= 950 + V_a[/tex] in [tex]1250 = (V_w + V_a)[/tex]
[tex]1250 = 950 + V_a + V_a[/tex]
[tex]1250 = 950 + 2V_a[/tex]
Collect like terms
[tex]2V_a = 1250 -950[/tex]
[tex]2V_a = 300[/tex]
Divide by 2
[tex]V_a = 150[/tex]
Substitute [tex]V_a = 150[/tex] in [tex]V_w= 950 + V_a[/tex]
[tex]V_w =950 +150[/tex]
[tex]V_w =1100[/tex]
10 points!!!!! Do 14 and 15 only hurry please.
Answer:
8. x = 16
9. x = 10
14.
m ∠RSU = 130°
m ∠UST = 50°
15.
m ∠RSU = 124°
m ∠UST = 56°
Step-by-step explanation:
8.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is , (x + 15)° = 31°
x = 31 - 15 = 16
9.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is ,
(6x - 4)° = 56°
6x = 56 + 4
6x = 60
x = 10
14.
13x + 5x = 180° [straight line angles ]
18x = 180
x = 10
m ∠RSU = 130°
m ∠UST = 50°
15.
4x + 12 + 2x = 180° [ straight line angles]
6x = 180 - 12
6x = 168
x = 28
m ∠RSU = 4(28) + 12 = 112 + 12 = 124°
m ∠UST = 2(28) = 56°
Answer:
14. 13x+5x
=18x
180(angles on a st. line)= 18x
180/18
=10
RSU=13*10=130
UST=5*10=50
HELP I HAVE 10 MINS
If AB and CD have endpoints at A(- 1,3), B(6,8), C(4, 10) and D(9,3), are AB and CD parallel,
perpendicular, or neither? Explain.
Answer:
perpendicular
Bari Jay, a gown manufacturer, received an order for prom dresses from China. Her cost is $32 a gown. If her markup based on selling price is 76%, what is the selling price of each gown? (Round your answer to the nearest cent.)
Answer:
$56.32
Step-by-step explanation:
Find the selling price by multiplying the original cost by 1.76:
32(1.76)
= 56.32
So, the selling price is $56.32
Equation of a line is y = 2x + 5
a) what is the gradient?
b)what is y- intercepted?
c) if the gradient is -3 and y-intercept is 1,then what is the equation of the line?
Answer:
Step-by-step explanation:
Generally, we have the equation of a straight line as;
y = mx + b
where m is the slope and g is y intercept
a) The gradient is the slope and we have the value as 2
b) The y-intercept here is 5
c) for slope -3 and intercept 1, the equation becomes
y = -3x + 1
What is the product?
(-20d^2+s)(5d^2-6s)
Answer:
-100d⁴ + 125d²s - 6s²
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsExpand by FOILStep-by-step explanation:
Step 1: Define
Identify
(-20d² + s)(5d² - 6s)
Step 2: Expand
FOIL: -100d⁴ + 120d²s + 5d²s - 6s²[Addition] Combine like terms: -100d⁴ + 125d²s - 6s²You kick a 3.2 kg ball with a Force of 61 N. Find the acceleration of the
ball in m/s2. Round your answer to 1 decimal place.
Answer:
[tex]19.4 ms^{-2}[/tex]
Step-by-step explanation:
Newton second law: [tex]\vec F= m\vec a[/tex] We know the force, we know the mass, we can substitute and find the acceleration, which is [tex]61/3.2 = 19.4 ms^{-2}[/tex]
Find the distance between the points (-6, -8) and (6, -3).
Write your answer as a whole number or a fully simplified radical expression. Do not round.
units
Answer:
[tex]\displaystyle d = 13[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Identify
Point (-6, -8)
Point (6, -3)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(6- -6)^2+(-3- -8)^2}[/tex][√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{12^2+5^2}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{144+25}[/tex][√Radical] Add: [tex]\displaystyle d = \sqrt{169}[/tex][√Radical] Evaluate: [tex]\displaystyle d = 13[/tex]What is the answer for this
Answer:
A
Step-by-step explanation:
The green is the starting place, when you move from a point on the green triangle to the blue one, you go 5 to the left and 3 down.
Solve for x.
3x +13
6x + 5
x = [?]
Answer:
nessa resposta da 10 beijos
Answer:
x = 18
Step-by-step explanation:
The given angles are same- side exterior angles and sum to 180°, that is
6x + 5 + 3x + 13 = 180
9x + 18 = 180 ( subtract 18 from both sides )
9x = 162 ( divide both sides by 9 )
x = 18
help please asap just the answers
a = 2 ; b = −1 and c = −3
The values are :
[tex]a = 2[/tex][tex]b = - 1[/tex][tex]c = - 3[/tex]let's plug the values :
[tex] {c}^{2} + 5ab[/tex][tex]( - 3) {}^{2} + (5 \times 2 \times - 1)[/tex][tex]9 - 10[/tex][tex]-1[/tex]Therfore, correct answer is :
[tex] \large - 1[/tex][tex]\mathfrak{good \: \: luck \: \: for \: \: your \: \: assignment}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]
9.) Detemine the value of [tex] \sf{ {c}^{2} + 5ab.}[/tex][tex] \huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]
[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]
[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{c}^{2} + 5ab}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶{( - 3)}^{2} + 5( 2)( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9+ 5( 2)( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9+ 10( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9 - 10 }[/tex]
[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ -1}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-1}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]