Answer:
Water
Explanation:
Given the specific heat of oxygen is 918J/kg °C and the specific heat of water is 4181 J/kg °C.
Consider 1Kg mass of each substance.
Now 1 Kg of oxygen needs 918 J of energy to raise its temperature by 1 °C
Also, 1 Kg of water needs 4181 J of energy to raise its temperature by 1 °C.
Clearly water requires more energy when compared to oxygen.
Basically, specific heat capacity is the amount of energy required to raise the temperature of a 1 kg body by 1 °C.
why trucks are made to have many tires?
Answer: Load carrying heavy vehicles have large number of wheels in order to reduce pressure on the contact patch on road. With large number of wheels, it becomes easy to distribute the entire pressure of loads in an even manner.
Explanation:
Name the two types of vaporization and explain the difference between them. Give one example of each
Evaporation and Boiling are the two vaporizations.
Evaporation is the type of vaporization that occurs at temperatures below the boiling point, whereas boiling is the type of vaporization that occurs at temperatures above the boiling point. The other type of vaporization is boiling, which occurs when a liquid is heated to the point where its vapor pressure equals the external pressure surrounding the liquid. When the liquid is heated, bubbles form within the liquid.
Hope this helps and if it does, don't be afraid to give my answer a "Thanks" and maybe a Brainliest if it's correct?
Answer:
sample respond: Vaporization is the process by which a liquid becomes a gas. The two types of vaporization are evaporation and boiling. Evaporation takes place at the surface of a liquid, such as a puddle drying up. Boiling takes place below the surface of a liquid and causes bubbling, like a pot of water on a hot stove. Explanation:
Complete the equation to show the radioactive decay of carbon-14 to nitrogen-14
Answer:
The beta decay takes place.
Explanation:
The reaction of radioactivity of carbon 14 to nitrogen 14 is
There is a beta decay.
The reaction is
[tex]C_{6}^{14}\rightarrow N_{7}^{14}+\beta _{-1}^{0}+ energy[/tex]
Here some energy is released in form of neutrino.
When starting an exercise program, shrinking your goals down to realistic and attainable goals like just moving for 10 minutes a day, is better than setting a lofty goal of losing 10 pounds a week.
TRUE OR FALSE
Answer: True
Explanation:
In Part l, the independent variable was
Answer:
The independent variable is the variable the experimenter manipulates or changes, and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.
Subject: science 41. A device used to stop flow of electric current A) open plug key B)Closed plug key C)Both A and B D) Rio start
Answer:
Circuit Breaker - a protective device used to automatically blows and cuts the current when trouble in the circuit such as short circuit or overload occurs
Two uniform bars of the same dimensions are constructed from the same material. One bar has five evenly spaced holes through it and the second bar has only two holes. In these cases, the bars are slid over vertical pegs and rest on a horizontal surface, where friction between the bar and the surface is negligible. The two bars are each pulled by
horizontal forces of equal magnitude F from their right end as shown above. The bars' resulting angular accelerations are recorded.
Is the magnitude of the initial angular acceleration of the bar in case 1 larger than, smaller than or equal to the magnitude of the initial angular acceleration of the bar in Case 2? Explain your reasoning.
Solution :
The angular acceleration, [tex]$\alpha$[/tex] is obtained from the equation of the [tex]$\text{Newton's second law}$[/tex] of rotational motion,
Thus,
[tex]$\tau = F \times d$[/tex]
or [tex]$\tau = I \times \alpha$[/tex]
where [tex]$\tau$[/tex] is torque, F is force, d is moment arm distance, I is the moment of inertia
Thus, [tex]$\alpha=\frac{(F\times d)}{I}$[/tex]
Now if the force and the moment arm distance are constant, then the [tex]\text{angular acceleration is inversely proportional to the moment of inertia.}[/tex]
That is when, F = d = constant, then [tex]$\alpha \propto \frac{1}{I}$[/tex] .
Thus, moment of inertia, I is proportional to mass of the bar.
The mass is less for the bar in case (1) in comparison with that with the bar in case (2) due to the holes that is made in the bar.
Therefore, the bar in case (1), has less moment of inertia and a greater angular acceleration.
A person skateboards at 3.25 m/s for 55.0 s. How far did he travel?
18. Magnesium is a silvery-grey metal. When heated in air it reacts with oxygen burning with a bright flame to form a white powder called magnesium oxide. From the paragraph identity a) TWO elements (2 marks)
Answer:Magnesium and OXYGENNNN
Explanation:
Magnesium Oxide is still technically Magnesium
the length of second hand of clock is 14cm, an ant sits on the top of second hand. find the following
i) speed of ant
ii) distance covered by ant in 150 seconds
iii) displacement in 150 seconds
Answer:
The answer is below
Explanation:
i) Since the length of the second clock (radius) is 14 cm = 0.14 m, the distance covered by the second hand in one revelution is:
Distance covered = 2πr = 2π(0.14) = 0.88 m
The time taking to complete one revolution = 60 seconds, hence;
Speed = distance covered in one revolution / time take o complete a revolution
Speed = 0.88 m / 60 s = 0.0147 m/s
ii) Distance covered in 150 s = speed * 150 s = 0.0147 * 150 = 2.2 m
iii) Displacement in 150 seconds = distance from initial position to final position
At 150 s, the hand has covered 2 revolutions and moved 30 s. Hence:
Displacement in 150 seconds = speed * 30 s = 0.0147 * 30 = 0.44 m
Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg
Answer:
a) [tex]q=4.92*10^{-8} C[/tex]
b) [tex]m=4.026*10^{-6} kg[/tex]
Explanation:
From the question we are told that:
Separation distance [tex]d=2.65*10^{-2} m[/tex]
Acceleration 1 [tex]a_1=5.00*10^3 m/s^2,[/tex]
Acceleration 2 [tex]a_2=7.70*10^3 m/s^2,[/tex]
Mass 1 [tex]m_1=6.20*10^{-6}[/tex]
Generally the equation for Force is mathematically given by
[tex]F=ma[/tex]
For Particle 1
[tex]F=6.2*10^{-6} *5*10^3[/tex]
[tex]F=0.031 N[/tex]
Also
[tex]F=\frac{kq_1*q2}{r^2}[/tex]
Where
[tex]q_1=q_2[/tex]
Therefore
[tex]0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}[/tex]
[tex]q=4.92*10^{-8} C[/tex]
b)
Generally the equation for Force is mathematically given by
[tex]F=ma[/tex]
[tex]0.031=7.7*10^3[/tex]
[tex]m=4.026*10^{-6} kg[/tex]
The Statue of Liberty is made of Copper that has turned on Says has WAGNE Bongo Wantse
said about this change?
The change is a physical change because the owner in the same is still there,
The change is a physical change beave a new chemical is was on the outside of the sale,
The change is not a physical change beans the plos at the stanje na dana),
The change is nga physical change because a new chemical istmes on the outside of the stalye
Complete Question:
The Statue of Liberty is made of copper that has turned green because it has undergone a change. What can be said about this change?
Group of answer choices.
A. The change is a physical change because the copper in the statue is still there.
B. The change is a physical change because a new chemical is formed on the outside of the statue.
C. The change is not a physical change because the color of the statue has changed.
D. The change is not a physical change because a new chemical is formed on the outside of the statue.
Answer:
D. The change is not a physical change because a new chemical is formed on the outside of the statue.
Explanation:
A physical change can be defined as a type of change that only affects the physical form of a chemical substance (matter) without having any effect on its chemical properties. Thus, a physical change would only affect the physical appearance and properties of a chemical substance (matter) but not its chemical properties.
This ultimately implies that, a physical change result in a change of matter from one form or phase (liquid, solid or gas) to another without a corresponding change in chemical composition.
Additionally, a physical change is a type of change that involves an increase or decrease in the volume of a physical object (object). Also, this change can be reversed to the original state under certain conditions.
Since the Statue of Liberty which is made of copper turned green, the change is not a physical change because a new chemical is formed on the outside of the statue.
A ship anchored at sea is rocked by waves that have crests Lim apart the waves travel at 70m/S, at what frequency do the waves reach the ship?
Question: A ship anchored at sea is rocked by waves that have crests 100 m apart the waves travel at 70m/S, at what frequency do the waves reach the ship?
Answer:
0.7 Hz
Explanation:
Applying,
v = λf............... Equation 1
Where v = velocity of the wave, f = frequency fo the wave, λ = wavelength of the wave
make f the subject of the equation
f = v/λ................. Equation 2
From the question,
Given: v = 70 m/s, λ = 100 m ( distance between successive crest)
Substitute these values into equation 2
f = 70/100
f = 0.7 Hz
Hence the frequency at which the wave reach the ship is 0.7 Hz
A circuit diagram with a power source labeled 12 V is connected to 3 resistors in series. The resistors are labeled 1.0 Ohms, 2.0 Ohms, and 3 Ohms. Calculate the equivalent resistance in the circuit shown.
0.55 Ω
1.8 Ω
2.0 Ω
Its A "0.55" I guessed and got it right
Answer:
there it is fella u were right with ur answer
An elevator of 3 × 10^4N is raised to a height of 100m in 20s . The work done by electric motor is equivalent to ?
Answer:
we neglect the time data
Page
A car is moving at a rate of 72 km/ hr. How far
does the moves stop after 4 seconds
Answer:
Distance = 80 meters
Explanation:
Given the following data;
Speed = 72 km/hr
Time = 4 seconds
Conversion:
72 km/hr to meters per seconds = 72*1000/3600 = 72000/3600 = 20 m/s
To find the distance covered by the car;
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the formula;
[tex]Speed = \frac{distance}{time}[/tex]
Making distance the subject of formula, we have;
[tex] Distance = speed * time [/tex]
Substituting into the above formula, we have;
[tex] Distance = 20 * 4 [/tex]
Distance = 80 meters
who is the father of computer but not Charles Babbage can anyone guess
Answer:
It's Obusively charles Babbage I guess
ssooeorkgogogoogkrorooror
Answer:
ssooeorkgogogoogkrorooror
Explanation:
HELP, SCIENCE QUESTION I AM STUCK
6. Which of the following is NOT part of a circuit?
A. rim B. load C. power source D. conductor
Which instrument changes kinetic energy into electrical energy?
electric motor
hair drier
electric bell
dynamo
Answer:
Dynamo
Explanation:
Dynamo started to rotate which is known as kinetic energy.When dynamo is in running it produces electricity.dynamo specially used for generating electricity.
please help me..im begging you
Answer: The equations in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
Explanation:
(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.
So, PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant
T = temperature
Boyle's law: At constant temperature, the pressure of a gas is inversely proportional to volume.So, [tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Charles' law: At constant pressure, the volume of a gas is directly proportional to temperature. So,[tex]V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}[/tex]
Gay-Lussac's law: At constant volume, the pressure of a gas is directly proportional to temperature.So, [tex]P_{1}T_{2} = P_{2}T_{1}[/tex]
Avogadro's law: At same temperature and pressure, the volume of gas is directly proportional to moles of gas.So, [tex]V_{1}n_{2} = V_{2}n_{1}[/tex]
Combined gas law: When Boyle's law, Charles' law, and Gay-lussac's law are combined together then it is called combined gas law. So,[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex]
Graham's law of effusion: It states that the rate of effusion of a gas is inversely proportional to the square root of mass of its particles.[tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex]
Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
2. In a chemical reaction
a) The atoms of the reactants always stay together to form the products
b) The atoms of the reactants unbond, rearrange, and then rebond to form the products
c) New atoms are formed which combine to make the products
d) Some atoms disappear while others multiply to form the products
Answer:
what I think in my opinion is B
A meter 0.0525 m from a wire measures a magnetic field of 7.14 x 10-6 T. How much current flows through the wire?
Answer:
[tex]I=1.9A[/tex]
Explanation:
From the question we are told that:
Meter distance [tex]d=0.0525[/tex]
Magnetic field [tex]B=7.14*19^{-6}T[/tex]
Generally the equation for Magnetic field B is mathematically given by
[tex]B =\frac{\mu *I }{2* \pi r}[/tex]
[tex]7.14*19^{-6}T =\frac{ 1.26 *10^{-6} *I }{2* 3.142*0.0525}[/tex]
Where
Constant[tex]\mu=1.26 *10^{-6}[/tex]
[tex]I=1.9A[/tex]
Therefore
The Current through the wire is
[tex]I=1.9A[/tex]
Answer: 1.87
Explanation:
acellus
A parallel network consist of three resistors 4 ohm, 8 ohm and 16 ohm .If the current in 8 ohm resistor is 3 A then what are the currents in other resistors
Answer:
If the resistors are in parallel they must all experience the same voltage drop.
R * I = V
8 * 3 = 24 V (if i is 3 amps)
24V / 4 ohm = 6 amps
24V / 16 ohm = 1.5 amps
an object that is 15 cm tall is placed 44 cm in front of a diverging lens. A virtual image appears -14cm in front of the lens. determine the focal length of the lens .
SHOW YOUR WORK.
A) 0.09cm
B)-20.53cm
C)10.6cm
D)-0.04cm
Answer:
The correct option is (b).
Explanation:
Given that,
The height of the object, h = 15 cm
Object distance, u = -44 cm
Image distance, v = -14 cm
We need to find the focal length of the lens. Using the lens formula.
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{f}=\dfrac{1}{(-14)}-\dfrac{1}{(-44)}\\\\f=-20.53\ cm[/tex]
So, the focal length of the lens (-20.53 cm).
A long straight wire is parallel to one edge and is in the plane of a single-turn rectangular loop as shown. If the loop is moving in the plane shown so that the distance x changes at a constant rate of 20 cm/s, what is the magnitude of the emf induced in the loop at the instant x = 5.0 cm? Let / = 50 A, a = 50 cm, b = 6.0 cm.
Answer:
The magnitude of the emf induced in the loop is 2.4 × 10⁻⁵ V
Explanation:
The magnitude of the induced emf of a loop moving relative to a wire is given as follows;
The given parameters are;
I = 50 A, a = 50 cm, and b = 6.0 cm
The constant rate of change of x, v = 20 cm/s
Motional emf formula
The magnetic field due to the straight wire, B = μ₀·i/(2·π·x)
The flux given by the rectangular loop, Ф = BA = μ₀·i/(2·π·x) × a × b
Therefore, we get;
[tex]e = \dfrac{-d\phi}{dt} = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \dfrac{d}{dt} \left (\dfrac{1}{x} \right ) = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \left (\dfrac{1}{x^2} \right ) \dfrac{dx}{dt}[/tex]
[tex]\because \dfrac{dx}{dt} = v[/tex]
Therefore;
[tex]e = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \left (\dfrac{1}{x^2} \right ) \dfrac{dx}{dt} = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \left (\dfrac{1}{x^2} \right ) \times v \left(\because \dfrac{dx}{dt} = v \right)[/tex]
μ₀ = 4·π × 10⁻⁷ H/m
We get;
[tex]e = \dfrac{4\cdot \pi \times 10^{-7} \, H/m\times50 \, A \times 0.5 \, m\times 0.06 \, m}{2 \cdot \pi} \times \left (\dfrac{1}{(0.05 \, m)^2} \right ) \times 0.2 \ m/s = 2.4 \times 10^{-5} \, V[/tex]
The induced emf, e = 2.4 × 10⁻⁵ V
A 90kg football receiver named Reggie is running at 6.7m/s to catch a pass. A defensive back (103kg) named
Julio is waiting in position to hit him (standing still). They fall to the ground together after the tackle. How fast
are they going after the collision?
Answer: reciever is going to be going the momentum which is 90 times 6.7, so defensive back who is 103 KG and standing still therefore has no momentum, so the collision is 6.7 m/s against the defense
Explanation:
zero momentum
newton's 1st law of motion, when something is acted upon by an unbalanced force.
id really appreciate it if you helped (I'll give you brainlist)
Explanation:
answer is in the picture above
a current of 12 A flows through a fan for 30 minutes.How many charge flows through then fan during this time?
Answer:
Q=21600C
Explanation:
Q=It.
Data
I=12A
t=30min
convert time from minutes to second
t=60*30
=1800s
Q=?
Q=It
=(12A)*(1800s)
Q=21600C
A cubic box has a 0.6 cubic decimetre side. Find the mass of air in the box in gram. (1 Liter of air has a mass of 1.3 g).
Answer:
The mass of air in the box is 0.78 grams.
Explanation:
A litre equals a cubic decimetre. By definition of density ([tex]\rho[/tex]), in grams per litre, we calculate the mass of air inside the cube ([tex]m[/tex]), in grams:
[tex]m = \rho \cdot V[/tex] (1)
Where [tex]V[/tex] is the volume occupied by air within the cube, in litres.
If we know that [tex]V = 0.6\,L[/tex] and [tex]\rho = 1.3\,\frac{g}{L}[/tex], then the mass of air is:
[tex]m = \left(1.3\,\frac{g}{L} \right)\cdot (0.6\,L)[/tex]
[tex]m = 0.78\,g[/tex]
The mass of air in the box is 0.78 grams.