The first five terms of a sequence are 34, 35, 36, 37, 38.
Write down the general term of the sequence

Answers

Answer 1

33+n

Hope it helps you...

The First Five Terms Of A Sequence Are 34, 35, 36, 37, 38. Write Down The General Term Of The Sequence
The First Five Terms Of A Sequence Are 34, 35, 36, 37, 38. Write Down The General Term Of The Sequence

Related Questions

VIVIAN: My friend Sharon told me today that she will be driving back to Victorville, her hometown, this weekend for the first time in almost two years. NATALIE: You must not have been listening very carefully to what Sharon was saying, because I know for sure that Sharon's hometown is Vacaville, not Victorville.

Is dispute C a verbal dispute or a factual dispute?
a. Factual
b. Verbal

Answers

Answer:

The answer is "Option a".

Step-by-step explanation:

Dispute C comes under factual dispute because the words Vacaville or Victorville are two different places and they are arguing about the fact that's why option a is correct.

in an examination 45% students passed in science only 25% passed in english only and 5% students failed in both subjects if 200 students passed in english find the total number of students by using venn diagram​

Answers

Step-by-step explanation:

[tex]\huge\mathfrak\pink{Answer}[/tex]

Total number of students= y

(25/100) xy= 200

25 xy = 200 x 100

25y 20000

y = 20000/25

y 800

total number of students = 800

Step-by-step explanation:

[tex]\mathfrak\pink{Answer}[/tex]

Total number of students= y

(25/100) xy= 200

25 xy = 200 x 100

25y 20000

y = 20000/25

y 800

total number of students = 800

calculate the surface area and show work :) please help me no links!!

Answers

Answer:

294 in.²

Step-by-step explanation:

I believe this figure is a rectangular prism.

------------------------------------------------------------------------------------

Explain:

To find the surface area of a rectangular prism, use this formula:

[tex]SA=2lw+2lh+2wh[/tex]

              or

[tex]SA=2(lw+lh+wh)[/tex]

[tex]l-length[/tex]

[tex]w-width[/tex]

[tex]h-height[/tex]

A phrase I use to help remember this formula is:

LISA WILSON LOST HER WITCH HAT TWICE (2)

------------------------------------------------------------------------------------

Solve:

The length of this rectangular prism is 9 in.

This width is 10 in.

The height is 3 in.

Now, I will plug the numbers into the first formula.

[tex]SA=(2*9*10)+(2*9*3)+(2*10*3)=294 in.^2[/tex]

------------------------------------------------------------------------------------

Conclude:

I, therefore, believe the area of this rectangular prism is 294 in.²

PLEASE HELP ME PLEASE DUE IN 30 MINUTES

Answers

Answer:

x = 82.1º

Step-by-step explanation:

tan = opp/adj

tan75 = x/22

multiply both sides by 22

22 * tan75 = x

use calculator

82.1051177665153 = x

Rounded

x = 82.1º

D

Do tan75 * 22 because tan75 = x/22

Mrs. Brown, Mrs. White, and Mrs. Gray are a teacher, a doctor, and a lawyer, not necessarily in that order. Each has a horse. One horse is white, one is brown, and one is gray. From the following clues, determine the occupation of each woman and the color of her horse. No one’s name is the same as the color of her horse. The teacher owns a brown horse. Mrs. Gray is a doctor.

Answers

Answers:

Mrs. Brown ( lawyer ) owns the gray horse.Mrs. White ( teacher ) owns the brown horseMrs Gray ( doctor ) owns the white horse

===========================================================

Explanation:

We're given these three clues

Clue 1: No one's name is the same as the color of her horseClue 2: The teacher owns a brown horseClue 3: Mrs. Gray is a doctor.

Clue 3 is what we'll start with. Since Mrs. Gray is a doctor, this means that the doctor owns either a white horse or a brown horse. The doctor can't own a gray horse because the names can't match up (eg: the last name Gray with gray horse), due to clue 1.

If Mrs. Gray owned a brown horse, then she'd be a teacher (clue 2). But clue 3 says she's a doctor. We have a contradiction if Mrs. Gray owns the brown horse. Therefore, Mrs. Gray owns the white horse.

----------------

After we concluded the last section, we now know the following:

The horses that are left are the brown and gray horse.The professions left are the teacher and lawyer.The people left are Mrs. Brown and Mrs. White.

In short, we've just crossed "Mrs. Gray", "doctor", and "white horse" from the list.

Based on clue 1, we know that Mrs. Brown cannot possibly own the brown horse. Therefore, she must own the gray horse. So Mrs. White must own the brown horse.

Since Mrs. White owns the brown horse, she must be the teacher (clue 2). That leaves "lawyer" as the last profession, and that's assigned to Mrs. Brown.

----------------

Side note: I apologize for being a bit wordy, but I wanted to be very careful in the logical sense as to approach this problem. There's probably a much quicker efficient way to do this.

Jim and his dad are building a rectangular flower bed. They have a total of 35 feet of landscaping timber to use, and they want to use all of it. However, they are not sure what width and length they want the flower bed to be. In this activity, you will write a function in which the width of the flower bed, w, is the input, and the length, l, is the output. The perimeter of a rectangle is given by the equation 2l + 2w = p.If the width of the flower bed is 15 feet, what is its length? Write your answer as an evaluation of a function.

Answers

Step-by-step explanation:

the answer is in the image above

What is the nearest quarter hour to 10:40

Answers

[tex]\Huge \bf \over \rightarrow\mid\mathcal {\underline{ \orange{12 \: : \: 00}}} \mid[/tex]

Answer:

I think 10:45 is the nearest quarter hour.

The run scored in a cricket match by 11 players is as follows: 7, 16, 121, 51,101, 81, 1, 16, 9, 11, and 16. Find the mean of this data​

Answers

The mean is 39.1


7 + 16 + 121 + 51 + 101 + 81 + 1 + 16 + 9 + 11 + 16 = 430

430/11 = 39.0909

Simplify the expression.

33 · 32 + 12 ÷ 4

Answers

Answer:

1059

Step-by-step explanation:

33 · 32 + 12 ÷ 4

PEMDAS

Multiply and divide first from left to right

1056 + 3

Then add

1059

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{33\times32+12\div4}\\\\\mathsf{33\times32= \boxed{\bf 1,056}}\\\\\mathsf{\bold{1,056}+12\div4}\\\\\mathsf{12\div4=\boxed{\bf 3}}\\\\\mathsf{1,056+\bf 3}\\\mathsf{= \boxed{\bf 1,059}}\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 1,059}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite40:)}[/tex]

In the triangle below, which is equivalent to sinA?

Right triangle A B C is shown. B is the right angle and side A C is the hypotenuse.
sinC
sinB
cosA
cosC

Answers

you forgot to show the triangle

Answer:

CosC

Step-by-step explanation:

EDG

√25 + √ 81 = ? Heheeh

Answers

Answer:

14

Step-by-step explanation:

sqrt(25) = 5

sqrt(81) = 9

5 + 9 = 14

Answer:

5.83095189485

Step-by-step explanation:

Its so long

Flying against the wind a jet travels 1590 miles in 3 hours flying with the wind the same jet travels 8240 miles in 8 hours. What is the rate of the j et in still air and what is the rate of the wind?

Answers

Answer: See explanation

Step-by-step explanation:

From the information given, the following can be deduced:

Let rate of jet in still air be J

Let rate of wind be W

The formula for distance:

d = rt

Therefore, r = d/t

When, flying against the wind, then the Jet flies at a rate of J - W which will be:

= 1590mi/3hrs

= 530mph

When flying with the wind the jet will fly at a rate of J+W which will be:

= 8240mi/8hrs

= 1030 mph

Their average rate will be:

J = (530+1030)/2

= 1560/2

J = 780 mph

Since J - W = 530

Therefore, so

780 - W = 530

W = 780 - 530

W = 250 mph

The Jet in still air flies at a rate of 780 mph and the wind speed is 250 mph

The sum of two numbers is 50 and the difference is 18. What are the numbers?

Answers

set up 2 systems of equations: x+y=50 and x-y=18. Solve the second one for x to get x=y+18. Then plug y+18 in for x in the first equation to get y+18+y=50. Solve that for y to get y=16. Then plug that in the second equation to get x-16=18, solve for x to get 34. So, the numbers are 34 and 16.

Equations:

x + y = 50

x = y - 18

-------------------

Add and solve for "x"::

2x = 32

x = 16

-----

Solve for "y"::

16 + y = 50

y = 34

ANSWERS ARE IN BOLD

► What is the mean of the following data set? 98, 208, 189, 94, 117 ​

Answers

Answer:

mean of data is 141.2

Step-by-step explanation:

mean of data = sum of data / no of data

=98 + 208 + 189 + 94 + 117 / 5

=706 / 5

=141.2

Answer:

141.2

Step-by-step explanation:

98 + 208 +189 +94 +1117 =709

706/5 = 141.2

Hope this helps!

Find the whole using the percent proportion. 70% of what number of hay bales is
63 hay bales?

Answers

Answer:

90

Step-by-step explanation:

Let the whole number be x.

100% is to x as 70% is to 63

100/x = 70/63

10/x = 10/9

10x = 90 * 10

x = 90

Answer: 90

Step-by-step explanation:

0.7x = 63, x = 63/0.7 = 90

What is the vertex of the quadratic function below?
(-4, 0)

There is no y-intercept

(0, -1)

(-2, 3)

Answers

Answer:

(-2, 3)

Step-by-step explanation:

HELPPPPPPPPPPPPPPPP!!!


Which of the following is the product of the complex numbers below?
(6+ i)(2+91)


A. 3+56i
B. 3+52i
C. 21+56i
D. 21+52i

Answers

Answer:

It's answer is 93i +558....

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 8.1 minutes and a standard deviation of 2.0 minutes. For a randomly received emergency call, find the following probabilities.

a. between 5 and 10 min
b. less than 5 min
c. more than 10 min

Answers

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that [tex]\mu = 8.1, \sigma = 2[/tex]

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10 - 8.1}{2}[/tex]

[tex]Z = 0.95[/tex]

[tex]Z = 0.95[/tex] has a p-value of 0.8289

X = 5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5 - 8.1}{2}[/tex]

[tex]Z = -1.55[/tex]

[tex]Z = -1.55[/tex] has a p-value of  0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

The equation of the line passing through (2, 3) with a slope of 5 is y = [] x - []
what are the answers to []​

Answers

Answer:

y = 5x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 5, then

y = 5x + c ← is the partial equation

To find c substitute (2, 3) into the partial equation

3 = 10 + c ⇒ c = 3 - 10 = - 7

y = 5x - 7 ← equation of line

f(x) = 4x² + 3x - 2 g(x) = 6x³ - 3x²-4 Find (f +g) (x)​

Answers

Answer:

6x^3+x^2+3x-6

Step-by-step explanation:

f(x) = 4x² + 3x - 2

g(x) = 6x³ - 3x²-4

(f +g) (x)​ =4x² + 3x - 2+6x³ - 3x²-4

Combine like terms

             =6x^3+4x^2-3x^2+3x-2-4

             =6x^3+x^2+3x-6

The sum of 5 times a number and -2, added to 8 times the number.
The algebraic expression (simplify your answer)

Answers

Step-by-step explanation:

sum of 5 times a number and -2, + 8n

becomes:

5n + (-2) + 8n, or

5n -2 +8n, or. 13n - 2

which of the following nets does not make a triangular prism?​

Answers

Diagram A and Diagram B do not form a triangular prism

The manufacturer claims the mean bursting pressure for a certain type and size of PVC irrigation pipe to be at least 350 psi. A sample of 10 such pipes were experimentally determined to have the following bursting pressures: 401 359 383 427 414 415 389 463 394 428 State the null and alternative hypotheses:

Answers

Answer:

H0 : μ ≥ 350

H1 : μ < 350

Step-by-step explanation:

It is claimed that the mean is atleast 350 psi ;

10 such pipes were experimentally sampled ;

Here, the null hypothesis is the claim ; this means that the alternative hypothesis will be the opposite of the claim.

The hypothesis

H0 : μ ≥ 350

H1 : μ < 350

. A population of rabbits oscillates 25 above and below an average of 129 during the year, hitting the lowest value in January (t = 0). a. Find an equation for the population, P, in terms of the months since January, t. b. What if the lowest value of the rabbit population occurred in April instead?

Answers

Answer:

Because we know that here we have an oscillation, we can model this with a sine or cosine function.

P = A*cos(k*t) + M

where:

k is the frequency

A is the amplitude

M is the midline

We know that at t = 0, we have the lowest population.

We know that the mean is 129, so this is the midline.

We know that the population oscillates 25 above and below this midline,

And we know that for t = 0 we have the lowest population, so:

P = A*cos(k*0) + 129 = 129 - 25

P = A + 129 = 129 - 25

A = -25

So, for now, our equation is

P = -25*cos(k*t) + 129

Because this is a yearly period, we should expect to see the same thing for t = 12 (because there are 12 months in one year).

And remember that the period of a cosine function is 2*pi

Then:

k*12 = 2*pi

k = (2*pi)/12 = pi/6

Finally, the equation is:

P = -25*cos(t*pi/6) + 129

Now we want to find the lowest population was in April instead:

if January is t = 0, then:

February is t = 2

March is t = 3

April is t = 4

Then we would have that the minimum is at t = 4

If we want to still use a cosine equation, we need to use a phase p, such that now our equation is:

P = -25*cos(k*t + p) + 129

Such that:

cos(k*4 + p) = 1

Then:

k*4 + p = 0

p =  -k*4

So our equation now is:

P = -25*cos(k*t  - 4*k) + 129

And for the periodicity, after 12 months, in t = 4 + 12 = 16, we should have the same population.

Then, also remembering that the period of the cosine function is 2*pi:

k*12 - 4*k = 2*pi

k*8 = 2*pi

k = 2*pi/8 = pi/4

And remember that we got:

p = -4*k = -4*(pi/4) = -pi

Then the equation for the population in this case is:

P = -25*cos( t*pi/4 - pi) + 129

Polygon ABCD is a rectangle. What is its area? Round your answer to the
nearest tenth.
(2,4)
(4,1)
(-4,0)
4
(-2, -3)

Answers

9514 1404 393

Answer:

  26 square units

Step-by-step explanation:

Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...

  AB = √(2²+3²) = √13

We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.

  AC = √(6² +4²) = √52 = 2√13

Then the area is ...

  A = LW

  A = (2√13)(√13) = 2·13 = 26 . . . square units

Which graph represents the solution set of the compound inequality -4 s 3x-1 and 2x+4 518?
-10
-5
0
10
O
+
-10
-5
0
5
10
5
-10
0
5
10
+
-10
-5
0
10

Answers

Answer:

it's the first one where X is greater or equals to -1 and X is less or equals to positive 7

The compound inequality in x : -1 ≤ x ≤ 7

The correct graph is A .

Given, inequality: -4 ≤ 3x -1 and 2x + 4 ≤ 18 .

First inequality:

-4 ≤ 3x -1

Take -2 from RHS to LHS .

-4 + 1 ≤ 3x

-3 ≤ 3x

x ≥ -1

X will have values greater than equal to -1 .

Second inequality:

2x + 4 ≤ 18

take 4 from LHS to RHS.

2x ≤ 18 - 4

2x ≤ 14

x ≤ 7

x will have values less than equals to 7.

Combined result of both inequalities: -1 ≤ x ≤ 7 .Thus graph A is correct.

Know more about inequality,

https://brainly.com/question/28823603

#SPJ3


HW HELP ASAP PLZZZZZ

Answers

Answer:

last step is (2x + 5)(2x + 1)

Step-by-step explanation:

4x^2 + 12x + 5

4x^2 + (10 + 2)x + 5

4x^2 + 10x + 2x + 5

2x(2x + 5) +1(2x + 5)

(2x + 5)(2x + 1)

The height of a square pyramid where the lateral area equals 240 cm sq. and the edges of the base are 12cm

Answers

Answer:

The height is 8cm

Step-by-step explanation:

Given

[tex]L_A = 240cm^2[/tex] --- lateral area

[tex]a = 12cm[/tex] --- base lengths

Required

The height of the pyramid

The lateral area of a square pyramid is:

[tex]L_A = a\sqrt{a^2 + 4h^2[/tex]

So, we have:

[tex]240 = 12\sqrt{12^2 + 4h^2[/tex]

[tex]240 = 12\sqrt{144 + 4h^2[/tex]

Divide both sides by 12

[tex]20 = \sqrt{144 + 4h^2[/tex]

Square both sides

[tex]400 = 144 + 4h^2[/tex]

Collect like terms

[tex]4h^2 = 400 - 144[/tex]

[tex]4h^2 = 256[/tex]

Divide by 4

[tex]h^2 = 64[/tex]

Take square roots

[tex]h = 8[/tex]

Solve this asap for me

Answers

Answer:

by using middle term break method

Step-by-step explanation:

9x^2 + 12x + 4

9x^2+ (6 + 6)x + 4

9x^2 + 6x + 6x + 4

3x(3x + 2) + 2(3x + 2)

(3x + 2)(3x + 2)

(3x + 2)^2


What is the area of the triangle formed from (0,-3), (0,4), and (4,-3)?
O A. 14 square units
O B. 6 square units
O c. 48 square units
O D. 24 square units

Answers

24 units/C 48 units square units
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