[tex]\large \rm \sum \limits_{n = 0}^ \infty \frac{( { - 1)}^{1 + 2 + 3 + \dots + n} }{(2n + 1 {)}^{2} }[/tex]​

Answers

Answer 1

The sum we want is

[tex]\displaystyle \sum_{n=0}^\infty \frac{(-1)^{T_n}}{(2n+1)^2} = 1 - \frac1{3^2} - \frac1{5^2} + \frac1{7^2} + \cdots[/tex]

where [tex]T_n=\frac{n(n+1)}2[/tex] is the n-th triangular number, with a repeating sign pattern (+, -, -, +). We can rewrite this sum as

[tex]\displaystyle \sum_{k=0}^\infty \left(\frac1{(8k+1)^2} - \frac1{(8k+3)^2} - \frac1{(8k+7)^2} + \frac1{(8k+7)^2}\right)[/tex]

For convenience, I'll use the abbreviations

[tex]S_m = \displaystyle \sum_{k=0}^\infty \frac1{(8k+m)^2}[/tex]

[tex]{S_m}' = \displaystyle \sum_{k=0}^\infty \frac{(-1)^k}{(8k+m)^2}[/tex]

for m ∈ {1, 2, 3, …, 7}, as well as the well-known series

[tex]\displaystyle \sum_{k=1}^\infty \frac{(-1)^k}{k^2} = -\frac{\pi^2}{12}[/tex]

We want to find [tex]S_1-S_3-S_5+S_7[/tex].

Consider the periodic function [tex]f(x) = \left(x-\frac12\right)^2[/tex] on the interval [0, 1], which has the Fourier expansion

[tex]f(x) = \frac1{12} + \frac1{\pi^2} \sum_{n=1}^\infty \frac{\cos(2\pi nx)}{n^2}[/tex]

That is, since f(x) is even,

[tex]f(x) = a_0 + \displaystyle \sum_{n=1}^\infty a_n \cos(2\pi nx)[/tex]

where

[tex]a_0 = \displaystyle \int_0^1 f(x) \, dx = \frac1{12}[/tex]

[tex]a_n = \displaystyle 2 \int_0^1 f(x) \cos(2\pi nx) \, dx = \frac1{n^2\pi^2}[/tex]

(See attached for a plot of f(x) along with its Fourier expansion up to order n = 10.)

Expand the Fourier series to get sums resembling the [tex]S'[/tex]-s :

[tex]\displaystyle f(x) = \frac1{12} + \frac1{\pi^2} \left(\sum_{k=0}^\infty \frac{\cos(2\pi(8k+1) x)}{(8k+1)^2} + \sum_{k=0}^\infty \frac{\cos(2\pi(8k+2) x)}{(8k+2)^2} + \cdots \right. \\ \,\,\,\, \left. + \sum_{k=0}^\infty \frac{\cos(2\pi(8k+7) x)}{(8k+7)^2} + \sum_{k=1}^\infty \frac{\cos(2\pi(8k) x)}{(8k)^2}\right)[/tex]

which reduces to the identity

[tex]\pi^2\left(\left(x-\dfrac12\right)^2-\dfrac{21}{256}\right) = \\\\ \cos(2\pi x) {S_1}' + \cos(4\pi x) {S_2}' + \cos(6\pi x) {S_3}' + \cos(8\pi x) {S_4}' \\\\ \,\,\,\, + \cos(10\pi x) {S_5}' + \cos(12\pi x) {S_6}' + \cos(14\pi x) {S_7}'[/tex]

Evaluating both sides at x for x ∈ {1/8, 3/8, 5/8, 7/8} and solving the system of equations yields the dependent solution

[tex]\begin{cases}{S_4}' = \dfrac{\pi^2}{256} \\\\ {S_1}' - {S_3}' - {S_5}' + {S_7}' = \dfrac{\pi^2}{8\sqrt 2}\end{cases}[/tex]

It turns out that

[tex]{S_1}' - {S_3}' - {S_5}' + {S_7}' = S_1 - S_3 - S_5 + S_7[/tex]

so we're done, and the sum's value is [tex]\boxed{\dfrac{\pi^2}{8\sqrt2}}[/tex].

[tex]\large \rm \sum \limits_{n = 0}^ \infty \frac{( { - 1)}^{1 + 2 + 3 + \dots + N} }{(2n + 1 {)}^{2}

Related Questions

16+32 as a product of two factors using gif and distributive property

Answers

16 + 32 = 16 x 1 + 16 x 2 = 16 x (1 + 2)

Find the missing information for the triangle.
*not drawn to scale
• Make sure to find the missing angle measure and the 2 missing side
lengths.

Answers

missing angle:

180° - 90° - 30°

180° - 120°

60°

missing sides:

(a)

[tex]\rightarrow \sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

[tex]\rightarrow \sf tan(30)= \dfrac{4}{adjacent}[/tex]

[tex]\rightarrow \sf adjacent= \dfrac{4}{tan(30)}[/tex]

[tex]\rightarrow \sf adjacent= 4\sqrt{3}[/tex]

[tex]\rightarrow \sf adjacent= 6.93 \ cm[/tex]

(b)

[tex]\sf \rightarrow sin(x)= \dfrac{opposite}{hypotensue}[/tex]

[tex]\sf \rightarrow sin(30)= \dfrac{4}{hypotensue}[/tex]

[tex]\sf \rightarrow hypotensue= \dfrac{4}{ sin(30)}[/tex]

[tex]\sf \rightarrow hypotensue= 8 \ cm[/tex]

Answer:

m∠X = 60°

BX = 8 cm

BM = 4√3 cm

Step-by-step explanation:

The sum of the interior angles of a triangle is 180°

Given:

m∠B = 30°m∠M = 90°

⇒ m∠B + m∠M + m∠X = 180°

⇒ 30° + 90° + m∠X = 180°

⇒ 120° + m∠X = 180°

⇒  m∠X = 180° - 120°

⇒  m∠X = 60°

Using the sine rule to find the side lengths:

[tex]\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}[/tex]

(where A, B and C are the angles, and a, b and c are the sides opposites the angles)

Given:

m∠X = 60°m∠B = 30°m∠M = 90°MX = 4 cm

[tex]\implies \dfrac{4}{\sin 30\textdegree}=\dfrac{BX}{\sin 90\textdegree}=\dfrac{BM}{\sin 60\textdegree}[/tex]

[tex]\implies BX=\sin 90\textdegree \cdot\dfrac{4}{\sin 30\textdegree}[/tex]

              [tex]=1 \cdot \dfrac{4}{\frac12}[/tex]

              [tex]=1 \cdot 4 \cdot 2[/tex]

              [tex]=8 \textsf{ cm}[/tex]

[tex]\implies BM=\sin 60\textdegree \cdot\dfrac{4}{\sin 30\textdegree}[/tex]

              [tex]=\dfrac{\sqrt{3}}{2}\cdot \dfrac{4}{\frac12}[/tex]

              [tex]=\dfrac{\sqrt{3}}{2}\cdot 4 \cdot 2[/tex]

              [tex]=4\sqrt{3} \textsf{ cm}[/tex]

A can of soda can be modeled as a right cylinder. Aubrey measures its height as 10.1
cm and its circumference as 14 cm. Find the volume of the can in cubic centimeters.
Round your answer to the nearest tenth if necessary.

Answers

The volume of the cylinder is the amount of space in the cylinder

The volume of the cylinder is 218.4 cubic centimeter

How to determine the volume of the cylinder?

The given parameters are:

Circumference (C) = 14 cm

Height (h) = 10.1 cm

Start by calculating the radius (r) using:

[tex]C = 2\pi r[/tex]

So, we have:

[tex]2\pi r = 14[/tex]

Make r the subject

[tex]r =\frac 7\pi[/tex]

The volume of the cylinder is then calculated as:

[tex]V =\pi r^2h[/tex]

This gives

[tex]V =\pi * (\frac{7}{\pi})^2 * 14[/tex]

Evaluate

[tex]V =218.4[/tex]

Hence, the volume of the cylinder is 218.4 cubic centimeter

Read more about volumes at:

https://brainly.com/question/10171109

How to solve x + y[tex]\frac{dy}{dx}[/tex] = 0

Given that solution goes to (2,0) Neither x nor y can exceed 2

Answers

Answer:

The answer is {D}

Step-by-step explanation:

jack had m math problems to complete during his vacation. he solved the same number of problems every day and finished them all in 5 days. how many problems did jack solve per day.

Answers

If Jack finish them all in 5 days, then he can solve m/5 math problem in just one day.

Word problems leading to quadratic equation

From the given question, jack can only solve m math problems in 5 days, this can be expressed as:

m problems = 5 days

The number of questions he can solve per day is expressed as:

x = 1 day

Take the ratio

m/x = 5/1

5x = m

x = m/5 math problems

This shows that jack can solve m/5 math problem in just one day

Learn more on ratio here: https://brainly.com/question/2328454

A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card (king, queen, or jack).

Answers

6 red face cards

->in favour:

6/52

= 3/26

-> against:

52-6= 46

46/52

=23/26

?A bag contains red, blue, and green candies. Benjamin pour
out a handful and counted 10 red, 6 blue, and 14 green
candies. According to these ratios, if the bag contains a total of
400 candies, about how many of them are blue?

Answers

About 66 candies are blue.

What is the approximate volume of a cone with a height of 9 ft and radius of 3 ft? Use 3.14 to approximate pi, and express your final answer to the nearest hundredth Enter your answer as a decimal in the box. ft3​

Answers

Answer:
84.78 ft3

Steps:
Take note.
V = Volume
r = radius
h = height

V = (Pi) * (r^2 ) * (h/3)

V = (3.14) * (3^2) * (9/3)
V = (3.14) * (9) * (3)
V = 84.78

Can somebody help me pls!

Answers

Answer: C

Step-by-step explanation:

Just look at a z-score table and multiply by 100.

-> (0.308538)(100) is about 30.85%

Find the mean of the data.

8,14,22,7,2,11,25,7,5,9

Answers

Answer:

11

Step-by-step explanation:

Given:

8,14,22,7,2,11,25,7,5,9

Solve:

Put in order:

2, 5, 7, 7, 8, 9, 11, 14, 22, 25

Note:

Mean-

Add up all data values to get the sumCount the number of values in your data setDivide the sum by the count

2+ 5+7+7+8+9+11+ 14+22+25=110

110/10 = 11

Hence, the mean of the data is 11.

[RevyBreeze]

Answer:

The mean of the data given is 11

What is mean?
The mean is the arithmetic average of a set of given numbers. The median is the middle score in a set of given numbers. The mode is the most frequently occurring score in a set of given numbers.


Step-by-step explanation:

Have a great rest of your day
#TheWizzer

(pls give the person who answered before me braineist)

solve this question plss​ on number line

Answers

Answer:

3. 13/36, 14/36, 15/36, 16/36, 17/36

4.

-0.5 -0.25 0 0.25 0.5

5. 0.05

3.

between 1/2 and 1/3

five rational numbers:

0.35, 0.4, 0.42, 0.45, 0.46

4. Given in the graph below.

5. (-2/5 + 1/2)/2 = 0.05

9x9/16+12 whats the answer

Answers

Answer:

17.0625

Step-by-step explanation:

Due to order of operations the division and multiplication get done first and the we add the 12

Answer:

2.89285714

Step-by-step explanation:

9x9/16+12

81/16+12

5.0625 + 12 = 17.0625

Hope this helps :)

the equation is :
answer x:

Answers

Answer:

A) x would be 21 if i interpreted it right

Step-by-step explanation:

4x - 11 = 73

i think anyways

4x = 73 + 11

4x = 84

x = 21

i d k  what B means?

help for brainliest and 10 points

Answers

Answer:

-3

Step-by-step explanation:

[tex]0.002 = 2 \times {10}^{ - 3} \\ \implies \: x = - 3[/tex]

Help help math math math math math

Answers

Answer:

A

Step-by-step explanation:

You can think about it as an equation without the inequality:

y = 5 - x        OR       y = -x + 5

Slope = -1

Y-intercept = 5

Graph B is a horizontal line with a slope of zero and y-intercept of 2. Graph A is the only one that fits the above parameters.

Hope this helps!

Answer:

a

Step-by-step explanation:

3. For each triangle, find the length of the labeled side.

Answers

Answer:

see explanation for detailed analysis

4
Find the perimeter of a
Square with a side
length of 7 meters.

Answers

Answer: P=28 meters

Step-by-step explanation:

[tex]P=4[/tex] × a ⇒ a is the side length

[tex]P=4[/tex] × [tex]7[/tex]

[tex]P=28[/tex]

Answer:

28 m

Step-by-step explanation:

Given

Side length = 7 m

Perimeter of a square

4 x Side length4 x 728 m


Find the area of the following shape. (8 points)

what is the answer?

Answers

Answer:

72 square units

Step-by-step explanation:

Identify the heightIdentify the lengthMultiply those two togetherThat is your answer

H = 9 units

L = 8 units

A = H × L

A = 9 × 8

A = 72 square units

a thousand dollars is left in a bank savings account drawing 7% interest, compounded quarterly for 10 years. what is the balance at the end of that time​

Answers

Answer:  $2001.60

Work Shown:

A = P*(1+r/n)^(n*t)

A = 1000*(1+0.07/4)^(4*10)

A = 2001.59734318603

A = 2001.60

This assumes that you do not withdraw any of the money over the course of the 10 years. Also, the interest rate must stay the same at 7%.

A Ferris wheel is 20 meters in diameter and completes 1 full revolution in 8 minutes.



A round Ferris wheel

A Ferris wheel is 20 meters in diameter and boarded from a platform that is 1 meter above the ground. The six o’clock position on the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 8 minutes. The function h(t) gives a person’s height in meters above the ground t minutes after the wheel begins to turn.



a. Find the amplitude, midline, and period of h(t).



Enter the exact answers.



Amplitude: A= meters

Midline: h= meters

Period: P= minutes



b. Assume that a person has just boarded the Ferris wheel from the platform and that the Ferris wheel starts spinning at time t=0. Find a formula for the height function h(t).



Hints:

What is the value of h(0)?
Is this the maximum value of h(t), the minimum value of h(t), or a value between the two?
The function sin(t) has a value between its maximum and minimum at t=0 , so can h(t) be a straight sine function?
The function cos(t) has its maximum at t=0, so can h(t) be a straight cosine function?


c. If the Ferris wheel continues to turn, how high off the ground is a person after 30 minutes?

Answers

Given that the Ferris diameter is 20 meters, with a rate of rotation of 1 turn in 8 minutes, we have;

a. Amplitude: A = 10 meters

Midline: h = 11 meters

Period, P = 8 minutes

b. h(t) = 10•cos((π/4)•t + π) + 11

c. 11 meters

How can the Ferris wheel be evaluated?

The amplitude is the same as the radius of the Ferris wheel,

The radius of the Ferris wheel = 20 ÷ 2 = 10

Therefore;

Amplitude: A = 10 meters

[tex]the \: midline \: = \frac{max \: height \: + min \: height}{2} [/tex]

Therefore;

[tex]midline \: = \frac{10 + 10 + 1 + 1}{2} = 11[/tex]

Midline: h = 11 meters

The period is the time to complete one rotation, therefore;

Period, P = 8 minutes

b. h(t) = A•cos(B•t + C) + h

Where;

B = 2•π/P

When t = 0, h(t) = 1

Which gives;

h(0) = 1 = 10 × cos(B×0 + C) + 11

-10/10 = -1 = cos(C)

C = arcos(-1) = π

Therefore;

h(t) = 10•cos((π/4)•t + π) + 11

h(0) = 1

h(0) is the minimum value of h(t)

h(t) cannot be a straight sine function because of the vertical shift

h(t) cannot be a straight cosine function because at t = 0, is the minimum point

c. After 30 minutes, we have;

h(30) = 10•cos((π/4)×30 + π) + 11 = 11

The height of a person after 30 minutes is 11 meters

Learn more about the Ferris wheel here:

https://brainly.com/question/86214

WILL GIVE EXTRA POINTS FOR ANSWER ⭐️⭐️!! PLEASE EXPLAIN IF POSSIBLE

Answers

Answer:

B. (-3, 10)

Step-by-step explanation:

     I am going to graph the given equation. I then will see which of the points given are within the required area.

-> See attached.

-> I have explained in the image more in-depth as well.

Please the answer ... Integral

Answers

Answer:

[tex]\frac{dx^{2} (x+1)S^{2} }{2(x^{2} +6x+3)^{2} }+ C[/tex]

Step-by-step explanation:

Can somebody please help with this, I have been stuck on it for a while

Answers

Answer:

$2821.50

Step-by-step explanation:

value = 2700 (deposit) x 0.003 (rate) x 15 (time) + 2700

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$2700\\ r=rate\to 0.3\%\to \frac{0.3}{100}\dotfill &0.003\\ t=years\dotfill &15 \end{cases} \\\\\\ A=2700[1+(0.003)(15)]\implies A=2700(1.045)\implies A=2821.5[/tex]

Help solve for “q”
—————————————

Answers

Digram:-

[tex] \\ [/tex]

[tex]\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}[/tex]

[tex] \\ [/tex]

STEP :-

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

{Linear pair}

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ} - {117}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q =64{}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{64}{4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16 \times 4}{4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16}{1}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bf q = 16 \degree[/tex]

[tex] \\ \\ [/tex]

Verification:

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(4 \times 16- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(64- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt63^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt180^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

LHS = RHS

HENCE VERIFIED!

Answer:

Value of [tex]\sf\purple{q\: = \:16.}[/tex]

Step-by-step explanation:

[tex]\rightarrow[/tex]As we know that,

Sum all angles that lie on a straight line = [tex]\sf\blue{180°}[/tex]

So,

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)°+ 117°\: = \:180°}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:180-117}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:63}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{4q\: = \:63+1}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{q\: = \:\frac{64}{4}}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{q\: = \:16}[/tex]

Thus, [tex]\sf\purple{q\: = \:16.}[/tex]

_________________________________

Hope it helps you:)

A perfect score on a test with 25 questions is 100. Each question is worth the same number of points. How many points is each question on the test worth

Answers

Answer:

4

Step-by-step explanation:

100 divided by 25 equals 4.

Find the area of sector RST Enter your answer in terms of a fraction of it and rounded to the nearest
hundredth.

Answers

Fort nite battle pass is 8 dollars

Señora Cruz will use four triangles on the door decor. How many square centimeters of paper will Señora Cruz use to create the triangles?

Triangle has bases as 3.7 and height as 6.8

Square has length as 7.5 and width as 3.9

Answers

Answer:

  50.32 cm²

Step-by-step explanation:

The area of a triangle can be computed using the formula ...

  A = 1/2bh

For a triangle with base 3.7 cm and height 6.8 cm, the area is ...

  A = 1/2(3.7 cm)(6.8 cm) = 12.58 cm²

__

For four (4) triangles, Señora Cruz will need 4 times this area:

  4 × (12.58 cm²) = 50.32 cm²

Señora Cruz will need 50.32 cm² of paper to create her door decor.

The temperature at 1:00 p.m. on Tuesday was -13°C. There was an increase of 6º per
hour starting at 1:00 p.m. Which of the following best represents the Celsius
temperature n hours after 1:00 p.m. on Tuesday?
A. -13 + bn
B. -13 - 6n
C. -13n + 6
D. -13n - 6

Answers

At 1.00Pm the temperature was -13°C

No of hours be nIncrease rate=6°C/hour

So

The equation is

y=6n+(-13)y=6n-13y=-13+6n

y=5/2x-9 find the y intercept

Answers

Answer:

(0,-9) You have to substitute 0 for x and solve for y

1. For each diagram below, find the value of x

Answers

a. x = 10 + 90 = 100 °

b. x + 110 = 140
x = 140 - 110
x = 30

c. 3x + 7 = x + 35
2x = 28
Divide through by 2
x = 14
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