Studying a spectrum from a star can tell us a lot. All of the following statements are true except one. Which statement is not true?The total amount of light in the spectrum tells us the star's radius.We can identify chemical elements present in the star by recognizing patterns of spectral lines that correspond to particular chemicals.Shifts in the wavelengths of spectral lines compared to the wavelengths of those same lines measured in a laboratory on Earth can tell us the star's speed toward or away from us.The peak of the star's thermal emission tells us its temperature: hotter stars peak at shorter (bluer) wavelength

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Answer 1

All of the following statements are true about studying spectrum from a star except the statement that "The total amount of light in the spectrum tells us the star's radius."

It is possible to identify chemical elements present in the star by recognizing patterns of spectral lines that correspond to particular chemicals. In other words, we can determine which elements are present in a star by analyzing the spectrum of the light it emits. This is because every chemical element has a unique spectrum of energy that it emits.

The wavelength shifts of spectral lines compared to the wavelengths of those same lines measured in a laboratory on Earth can tell us the star's speed toward or away from us. This is known as the Doppler effect, and it enables astronomers to calculate how fast a star is moving relative to Earth. For example, if the spectral lines are shifted towards the blue end of the spectrum, it means that the star is moving towards us.

On the other hand, if the spectral lines are shifted towards the red end of the spectrum, it means that the star is moving away from us.The peak of the star's thermal emission tells us its temperature: hotter stars peak at shorter (bluer) wavelengths. This is because the hotter an object is, the more energy it radiates, and the shorter the wavelength of that radiation. Therefore, the peak of the thermal emission spectrum provides an indication of the star's temperature.

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Related Questions

what state of matter is rutherfordium in while at room temperature

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Rutherfordium is a synthetic element with the atomic number 104 and symbol Rf. As a synthetic element, it is not found naturally on Earth and is produced through nuclear reactions in laboratories.

Rutherfordium is a member of the transition metals group and is expected to have similar physical and chemical properties to its neighboring elements in the periodic table. However, due to its radioactive nature and short half-life, its physical properties are difficult to determine.

While there is no experimental data available on the state of matter of rutherfordium at room temperature, it is expected to be a solid metal, similar to other transition metals, such as copper or nickel.

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air enters the compressor of a simple gas turbine power plant at 708f, 1 atm, is compressed adiabatically to 40 lbf/in.2, and then enters the combustion chamber where it burns completely with propane gas (c3h8) entering at 778f, 40 lbf/in.2 and a molar flow rate of 1.7 lbmol/h. the combustion products at 13408f, 40 lbf/in.2 enter the turbine and expand adiabatically to a pressure of 1 atm. the isentropic compressor efficiency is 83.3% and the isentropic turbine efficiency is 90%. determine at steady state(a) the percent of theoretical air required.(b) the net power developed, in horsepower.

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In Isentropic turbine ,Net power developed = [(1/2.2) x (20,313 Btu/lbmol) x (1.7 lbmol/h)] / [(1.3558 x 10^5) x (0.903)] = 57.0 horsepower. Percent of theoretical air = 100 x [(1.7 lbmol/h)/(1.7 lbmol/h x [1/2.2])] = 77.3%

A) To determine the percent of theoretical air required, use the equation:


Percent of theoretical air = 100 x [(Actual mass of air used)/(Theoretical mass of air required)]


The theoretical mass of air required can be determined using the equation:


Theoretical mass of air = [(Mass of propane used)/(Combustion products of air-fuel ratio)]


The combustion products of air-fuel ratio can be determined by using the equation:


Air-fuel ratio = [Air/Fuel]


Using these equations, we can calculate the percent of theoretical air required:


Percent of theoretical air = 100 x [(1.7 lbmol/h)/(1.7 lbmol/h x [1/2.2])] = 77.3%


B) To determine the net power developed, in horsepower, use the equation:


Net power developed = [(Air-fuel ratio) x (Heat of combustion) x (Molar flow rate)] / [(1.3558 x 10^5) x (Thermal efficiency)]


Using these equations, we can calculate the net power developed:


Net power developed = [(1/2.2) x (20,313 Btu/lbmol) x (1.7 lbmol/h)] / [(1.3558 x 10^5) x (0.903)] = 57.0 horsepower.

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Suppose we can model a certain cyanine-type dye molecule as having 10 electrons confined to a one-dimensional box of length L. Imagine that we use an external source of light to illuminate a sample of this molecule with photons having just the right energy to excite electrons from the n= 5 level to the n=7 level of the box. (a) When such excited electrons decay back toward their lowest available energy state, in addition to reradiating photons of the same energy as those from the external source, they can radiate photons of two and only two other longer wavelengths (this is the phenomenon known as fluorescence). Using an energy-level diagram showing possible transitions, identify the two transitions that produce these photons and explain why others (say, from the n=7 to the n=1 level) are impossible.(b) Assume that, of the photons discussed in part (a), the ones with the longest wavelength have a wavelength of 600 nm (in the red-orange region of the spectrum). What is the wavelength of the original photons from the external source? Are the photons from the external source visible?

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(a) The two transitions that produce photons of longer wavelengths during fluorescence are from n=7 to n=5 and from n=6 to n=5.

These transitions are allowed because the energy difference between the n=7 and n=5 levels and between the n=6 and n=5 levels is equal to the energy of a photon with a longer wavelength than the excitation wavelength.

Transitions from n=7 to n=1 or from n=6 to n=1, for example, are not possible because the energy difference between these levels is greater than the energy of the excitation photon. Therefore, the excited electrons cannot decay to these lower energy levels by emitting a photon of lower energy than the excitation photon.

(b) The energy difference between the n=7 and n=5 levels is the same as the energy difference between the n=6 and n=5 levels. Therefore, the wavelength of the photon emitted during the n=7 to n=5 transition is the same as the wavelength of the photon emitted during the n=6 to n=5 transition.

If the longest wavelength of the fluorescence photons is 600 nm, we can use the following equation to calculate the energy of a photon with this wavelength:

E = hc/λ

where h is Planck's constant, c is the speed of light, and λ is the wavelength in meters.

Converting the wavelength to meters, we get:

λ = 600 nm = [tex]6.0 \times 10^{-7} m[/tex]

Substituting into the equation and solving for E, we get:

E = [tex](6.626 \times 10^{-34} Js)(3.00 \times 10^8 m/s)/(6.0 x 10^{-7} m) = 3.31 x 10^-19 J[/tex]

Since the energy of the excitation photon is equal to the energy difference between the n=5 and n=7 levels, we can use the following equation to calculate the wavelength of the excitation photon:

[tex]\Delta E = E_{n7} - E_{n5} = (h^2/8mL^2)(49-25) = 24h^2/(8mL^2)[/tex]

E_photon = hν = ΔE

ν = ΔE/h

λ = c/ν = hc/ΔE

Substituting the values, we get:

[tex]\lambda  = hc/(24h^2/(8mL^2)) = 8mL^2c/3h[/tex]

Hence the wavelength of the original photon is [tex]8mL^2c/3h[/tex].

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A ball is dropped from the top of a building. The height, y , of the ball above the ground (in feet) is given as a function of time, t (seconds) y = 1140 − 16 t 2 a) Find the velocity of the ball at time t . What is the sign of the velocity? Why is this to be expected? b) When does the ball hit the ground, how fast is it going at that time? Give answer in feet per second and in miles per hour.

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the velocity of the ball at time t is -32t.  And The negative sign indicates that the ball is moving downward at this speed, which makes sense because it is about to hit the ground.

How to find the velocity?

a) To find the velocity of the ball at time t, we need to take the derivative of the height function with respect to time:

y = 1140 - 16t²

v = dy/dt = -32t

So the velocity of the ball at time t is -32t. The negative sign indicates that the ball is moving downward. This is expected because the ball was dropped from the top of the building and is subject to the force of gravity, which pulls objects downward.

b) The ball will hit the ground when y = 0. We can use this fact to find the time when the ball hits the ground:

0 = 1140 - 16t²

16t²= 1140

t²= 71.25

t ≈ 8.43 seconds

So the ball will hit the ground after 8.43 seconds. To find the velocity of the ball at this time, we substitute t = 8.43 into the expression for velocity we found earlier:

v = -32t ≈ -269.76 feet per second

To convert this velocity to miles per hour, we can use the conversion factor 1 mile per hour = 1.46667 feet per second:

v ≈ -269.76 / 1.46667 ≈ -183.99 miles per hour

The negative sign indicates that the ball is moving downward at this speed, which makes sense because it is about to hit the ground.

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Approximately 85% of phosphorus in the body is found in the bones. The other 15% of phosphorus in the body serves mary impertari Durposes. Click to select the functions of phosphorus. Dairy foods are rich sources of calcium, but mary people with lactase intolerance cannot consume these foods without experiending g gestrointestinal discomfort. Fortunately, there are a number of nondairy sources of caiclum. Park the following nondairy foocs in order of calcium content. Most Cakclum Per Sening 1 cup Tohale Rais Bran cereal 1 cup cakcum-fortifed oranon juce 30z salnon with bones From the following food items, click to select the highest source of phosphorus. Click to select the organs that participate in vitamin D synthesis as a result of sunlight exposure.

Answers

Functions of phosphorus: Bone formation, ATP production, DNA and RNA synthesis, cell membrane structure.

Order of nondairy foods by calcium content: 1) 1 cup calcium-fortified orange juice, 2) 1 cup Total Raisin Bran cereal, 3) 3 oz salmon with bones.

Highest source of phosphorus: Salmon with bones.

Organs that participate in vitamin D synthesis: Skin (when exposed to sunlight), liver, and kidneys.

What is bone formation?

Bone formation is the process by which bones grow and develop, including the deposition of mineralized bone tissue by osteoblasts and the resorption of bone tissue by osteoclasts, resulting in changes to the shape and structure of bones.

What is RNA?

RNA (Ribonucleic acid) is a molecule that plays a vital role in various biological processes. It is a type of nucleic acid that is composed of a chain of nucleotides, which are the building blocks of the molecule.

RNA is similar to DNA (deoxyribonucleic acid) in terms of its structure, but it has some key differences. RNA is usually single-stranded, while DNA is double-stranded. RNA uses the sugar ribose, while DNA uses deoxyribose. RNA also contains the nitrogenous base uracil, while DNA contains thymine.

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Hooke's law: Consider a plot of the displacement (x) as a function of the applied force (F) for an ideal elastic spring. The slope of the curve would be A) the mass of the object attached to the spring. B) the reciprocal of the acceleration of gravity. C) the spring constant. D) the acceleration due to gravity. E) the reciprocal of the spring constant.

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Hooke's law: the slope of the curve would be the spring constant (C).

What is Hooke's law?

Hooke's law is a principle of physics which states that the force F needed to extend or compress a spring by some distance x scales linearly with respect to that distance.

F = kx

where k is the spring constant and x is the displacement of the spring.

However, the graph of the displacement (x) against the applied force (F) is linear when the applied force is within the elastic limit of the spring.

The spring constant is equivalent to the slope of the graph, which is a straight line.

Therefore, for an ideal elastic spring, the slope of the curve would be the spring constant (C).

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you know roughly the decrease in vo2max that occurs on the summit of mount everest vs. that at sea level. you have a client that weighs 198 lb and has a vo2 max of 4.2 l/min. provide the following information 1) what is this persons relative vo2 max at sea level (in ml/min/kg), 2) roughly, what would their vo2 max be at the top of everest (if they acclimated over time like in this study).

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The person's relative VO₂ max at the sea level is decreased approximately by 7% and the VO₂ max be at the top of the Everest is essentially 0.

What is the relative VO₂ max value?

To find out the person's relative VO₂ max at sea level, use the following formula:

Relative VO₂ max (ml/min/kg) = VO₂ max (ml/min) / body weight (kg)

So, relative VO₂ max at sea level (in ml/min/kg) is:

Relative VO₂ max = VO₂ max / body weight = 4.2 L/min × 1000 ml/L / (198 lb / 2.2 kg/lb) = 20.8 ml/min/kg².

It is believed that the VO2 max of a person can be decreased by approximately 7% for every 1,000 meters (3,281 feet) above sea level.

Everest's summit is at an altitude of 8,848 meters (29,029 feet), so the decrease in VO₂ max can be calculated as follows:

Decrease in VO₂ max = (altitude difference / 1000 m) × (7% VO₂ max loss per 1000 m)

So, the decrease in VO₂ max at the top of Everest is:

Decrease in VO₂ max = (8848 / 1000) × 7% = 619%

The person's VO₂ max at the top of Everest would be: VO₂ max at Everest = VO₂ max at sea level × (100 - decrease in VO₂ max) / 100 = 4.2 L/min x (100 - 619%) / 100= -22.6 L/minHowever, it is not possible for the VO₂ max to be negative, so the VO₂ max at the top of Everest is essentially 0.

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What do the dark lines in an absorption spectrum indicate?

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The dark lines in an absorption spectrum indicate that certain frequencies or wavelengths of light have been absorbed by the material that the light has passed through. Absorption occurs when an atom or molecule in the material absorbs a photon of a particular frequency, causing the electron in the atom or molecule to move to a higher energy level.

When white light is passed through a sample of a material, some of the frequencies of light are absorbed by the atoms or molecules in the material, causing dark lines to appear in the spectrum. The positions and intensities of these lines depend on the composition of the material and the conditions under which it is observed.

Absorption spectra are used in a wide range of fields, including astronomy, chemistry, and physics, to identify the composition of materials and study their properties. The dark lines in an absorption spectrum are sometimes called absorption lines or Fraunhofer lines, after the German physicist Joseph von Fraunhofer, who first discovered them in the 19th century.

The dark lines in an absorption spectrum indicate the wavelengths that have been absorbed by the substance.What is an absorption spectrum?An absorption spectrum is a graph that demonstrates the amount of light that is absorbed by a material as a function of wavelength. The graph depicts the amount of light that a sample absorbs at specific wavelengths. An absorption spectrum is created when a source of light is transmitted through a material, and certain wavelengths are absorbed and blocked by the material while others are not. The absorbed wavelengths appear as dark lines, whereas the non-absorbed wavelengths appear as bright lines on the graph. Absorption spectra are used to detect the presence of specific materials, as different substances absorb different wavelengths of light.

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a concave makeup mirror is designed so that a person 27.6 cm in front of it sees an upright image at a distance of 50.3 cm behind the mirror. a) what is the radius of curvature of the mirror?

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The radius of curvature of a concave makeup mirror that is designed so that a person 27.6 cm in front of it sees an upright image at a distance of 50.3 cm behind the mirror is 35.54 cm.

What is the radius of curvature?

The mirror formula is used to calculate this. When an object is placed in front of a concave mirror, a virtual image is formed behind it. The magnification of the virtual image is positive. Here's how to solve the problem:

1/f = 1/u + 1/v

where, f is the focal length of the mirror, u is the distance of the object from the mirror, v is the distance of the image from the mirror.

Given that , u = −27.6 cm (the negative sign indicates that the object is on the left-hand side of the mirror).

v = −50.3 cm (the negative sign indicates that the image is on the left-hand side of the mirror).

To calculate the radius of curvature, the focal length is required. The focal length can be calculated using the mirror formula.

1/f = 1/u + 1/v = (v + u)/uv = (-27.6 - 50.3)/(-27.6 × 50.3) = 77.9/1388.28 = 0.0562 cm. Therefore = 1/0.0562 = 17.77 cm.

The radius of curvature is twice the focal length.

2R = 2f = 2 × 17.77 = 35.54 cm

Thus, the radius of curvature of the mirror is 35.54 cm.

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what bias has been applied to a pn junction if the cathode is positive with respect to the anode?

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A forward biased has been applied to a P-N junction if the cathode is positive with respect to the anode.

A P-N junction is a type of semiconductor junction formed by joining together two types of semiconductors - P-type and N-type. P-type semiconductors have an excess of positively charged holes, while N-type semiconductors have an excess of negatively charged electrons.

When these two types of semiconductors are brought into contact, the electrons from the N-type material flow into the P-type material, filling some of the holes and creating a region with a net negative charge (the N-side), while the P-type material loses some of its holes and creates a region with a net positive charge (the P-side). This creates a potential difference between the P and N regions, which can be used to generate a current. P-N junctions are essential components in electronic devices such as diodes, transistors, and solar cells.

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An elevator that has descended from the 50th floor is coming to a halt at the 1st floor. As it does, your apparent weight is:a) less than your true weight
b) equal to your true weight
c) more than your true weight
d) zero

Answers

Option a. When the elevator reaches the 1st floor and comes to a halt, your apparent weight will be less than your true weight.

The apparent weight of an object in an elevator is affected by the force of gravity, the mass of the object, and the acceleration of the elevator. In this case, the elevator is decelerating from the 50th floor to the 1st floor, which means the acceleration is negative. When the elevator reaches the 1st floor and comes to a halt, your apparent weight will be less than your true weight.

To illustrate this concept, consider Newton's Second Law of Motion which states that

Force = Mass x Acceleration (F = ma).

In this case, the force exerted by gravity on the object remains the same (its true weight) but the acceleration changes as the elevator descends. As the acceleration decreases, the apparent weight decreases accordingly.

Therefore, option a is correct.

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when troubleshooting an hvac system, if no voltage is measured across any of the pairs of thermostat wiring terminals, the problem is most likely with the wire connected to terminal

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When troubleshooting an HVAC system, if no voltage is measured across any of the pairs of thermostat wiring terminals, the problem is most likely with the wire connected to terminal C.

What is an HVAC system?

HVAC stands for heating, ventilation, and air conditioning. An HVAC system is used to regulate indoor temperatures, humidity, and air quality. It may be used in residential, commercial, or industrial settings. HVAC systems can be complex, with various components and controls, and can require maintenance and repair from time to time.

When troubleshooting an HVAC system, there are several possible causes of a no-voltage problem, including: Tripped circuit breaker or blown fuse in the HVAC system or main electrical panel. Thermostat malfunction: faulty or damaged wiring or connections in the HVAC system, thermostat, or electrical panel.

Transformer failure or malfunction in this case, if no voltage is measured across any of the pairs of thermostat wiring terminals, the problem is most likely with the wire connected to terminal C. This could be due to a wiring or connection problem or a transformer failure or malfunction. A qualified HVAC technician should be consulted to diagnose and repair the problem.

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a microwave oven operates at 2.90 ghz . what is the wavelength of the radiation produced by this appliance?

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The given frequency of a microwave oven is 2.90 GHz. We have to find the wavelength of the radiation produced by this appliance. The speed of light is a constant value of 3 x 108 m/s. The relation between frequency and wavelength of electromagnetic radiation is given by:

c = fλ

Where,

c = speed of lightf = frequency of radiationλ = wavelength of radiation

We can rearrange this equation to get the formula for wavelength:

λ = c / f

Substituting the given values, we get:

λ = 3 x 108 / (2.90 x 109)λ = 0.1034 m or 10.34 cm

Therefore, the wavelength of the radiation produced by the microwave oven is 10.34 cm.

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which of the following electric charge doesn't exist in nature? a. 8.00 cross times 10 to the power of negative 17 end exponent c b. 4.80 cross times 10 to the power of negative 19 end exponent c c. negative 2.40 cross times 10 to the power of negative 19 end exponent space c d. negative 1.60 cross times 10 to the power of negative 18 end exponent c

Answers

The electric charge that does not exist in nature is d. - 1.60 × 10⁻¹⁸ C.

What is an electric charge?

An electric charge is a basic property of matter that results from the presence or absence of electrons. Electrons are subatomic particle that makes up atoms. They are negatively charged and have a very small mass. An atom is neutral in its electrical charge since the number of electrons and protons in its nucleus is the same.

There are two kinds of electric charge: positive and negative.

The net charge on an object is the sum of all the charges on it, and it is either positive, negative, or neutral.

What is the electric charge that does not exist in nature?

Negative 1.60 × 10⁻¹⁸ C does not exist in nature because an electric charge is quantized in nature, which means that electric charge is always a multiple of the smallest electric charge unit (charge of an electron or proton).

The electric charge on a proton is equal and opposite to the electric charge on an electron.

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Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods a)Find the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane (an axis through point O). b)Find the moment of inertia of the system about an axis bisecting two opposite sides of the square (an axis along the line AB). c)Find the moment of inertia of the system about an axis that passes through the centers of the upper left and lower right spheres and through point O.

Answers

The moment of inertia of the system  for the three situations are 0.026667 kg m2,0.04 kg m2,0.013333 kg .

Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods

a) The moment of inertia of the system about an axis

through the center of the square,

perpendicular to its plane (an axis through point O) is equal to

4 x 0.200 kg x (0.400 m)2/12

= 0.026667 kg m2.



b) The moment of inertia of the system about an axis

bisecting two opposite sides of the square (an axis along the line AB) is equal to

4 x 0.200 kg x (0.400 m)2/8

= 0.04 kg m2.



c) The moment of inertia of the system about an axis

that passes through the centers of the upper left and lower right spheres and

through point O is equal to

2 x 0.200 kg x (0.400 m)2/12

= 0.013333 kg m2.

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as a source of blackbody radiation becomes hotter, the peak in its radiation spectrum moves from the visible to the ultraviolet and beyond. does this imply that the object can no longer be seen by the unaided human eye

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Yes, it is correct that when the source of blackbody radiation becomes hotter, the peak in its radiation spectrum shifts from the visible to the ultraviolet and beyond. Blackbody radiation is electromagnetic radiation emitted from a blackbody or perfect absorber. This is due to the fact that hotter objects emit shorter wavelengths of electromagnetic radiation, which correspond to higher energy photons. Therefore, when an object gets hot enough to emit mostly ultraviolet or X-ray radiation, it will no longer be visible to the unaided human eye because the human eye can only detect radiation within the visible spectrum of about 400 nm (violet) and 700 nm (red). Therefore, a blackbody that emits radiation beyond this range will no longer be seen by the unaided human eye.

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the accumulation of excess electric charge on an object is called....static electricitychargeelectric chargeproton

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The accumulation of excess electric charge on an object is called Static electricity.

The excess electric charge remains on the surface of an object until it is discharged, creating a spark or a small electrical shock.

Electric charge is a fundamental property of matter. The total electric charge of a system is the algebraic sum of the charges of its constituents. Electric charge is measured in coulombs (C), which is a unit of electrical charge.

Static electricity is the accumulation of excess electric charge on an object. When two different materials are rubbed together, electrons can be transferred from one material to the other. This transfer of electrons causes one material to become positively charged, while the other becomes negatively charged.

The two materials will then have an electrostatic charge, and the charges will be attracted to each other. Static electricity is responsible for lightning, which is a natural phenomenon. Lightning is caused by the build-up of static electricity in clouds. When the build-up of static electricity is sufficient, it will discharge in the form of a lightning bolt.

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A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 6 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s2 (for the acceleration due to gravity.)x(t) = _____ ft

Answers

The equation of motion , x(t) = -6 cos (6.71t) ft

The equation of motion for a mass attached to a spring is given by x(t) = A cos (ωt) + B sin (ωt), where A and B are constants, ω is the angular frequency, and x(t) is the displacement of the mass from its equilibrium position at time t.

Mass attached to spring weighs 24 pounds

Spring is stretched 4 inches when the mass is attached

The mass is released from a point 6 inches below the equilibrium position

Acceleration due to gravity is 32 ft/s²

From the information, it can be concluded that a mass of 24/32 = 0.75 slugs is attached to the spring, which has a spring constant k = (mg)/x = (0.75 × 32)/4 = 6 lbf/inches.

The equation of motion is given by,x(t) = A cos (ωt) + B sin (ωt)

Since the mass is initially released from a point 6 inches below the equilibrium position, the displacement at time t = 0 is given by x(0) = -6. Therefore,

x(0) = A cos (ω × 0) + B sin (ω × 0) = A

From the initial condition of zero velocity, the derivative of the displacement function is given by,

v(t) = -Aω sin (ωt) + Bω cos (ωt)

Since the mass is initially released from rest, the velocity at time t = 0 is given by v(0) = 0. Therefore,

v(0) = -Aω sin (ω × 0) + Bω cos (ω × 0) = Bω

Equating x(0) = -6 and v(0) = 0, we get, A = -6 and Bω = 0.

Since ω cannot be zero, we get B = 0.

Thus, the equation of motion is, x(t) = -6 cos (ωt)

Substituting x = 4 inches and T = 2π/ω, we get,

4 = -6 cos (ωT/2)

Solving for T, we get,T = 2.094 s

Substituting T and the value of g, the value of ω is calculated as, ω = 6.71 rad/s

Therefore, the equation of motion is, x(t) = -6 cos (6.71t) ft

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A ford is traveling with a speed of 15m/s and is 200 meters ahead of a Chevy that is traveling in the same direction but at a speed of 20m/s. How far will the chevy travel before catching up to the Ford?

Answers

The Chevy will travel a distance f about 600m before catching up with the ford in the same direction of the motion.

The ford if travelling at 15m/s and it is 200 m ahead of the Chevy that is travelling in the same direction with a speed of 20m/s.

Now, we can use velocity = distance/time here,

Time of ford will be equal to the time of Chevy,

Time of ford = Distance/velocity of ford

Time of ford = S/15

Now, for the Chevy, the distance will be 200 more and the time will be same, so we will write,

Time of Chevy = (S+200)/20

(S+200)/20 = S/15

15S + 3000 = 20S

5S = -2000

S = -400m

Negative sign is showing the direction of the motion only, so we can ignore that.

So, the Chevy will travel 600 m before catching up with the ford.

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What do you think would happen if a solid were exposed to extremely cold temperatures, or if a gas were exposed to extremely hot temperatures? Is it possible that there are more than three states of matter?

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Solids can become Bose-Einstein condensates at very low temperatures, but gases may become plasmas at very high temperatures. There are further states of matter, such as quark-gluon plasma, and more states might be found.

Exposing a solid to extremely cold temperatures would cause its particles to slow down and reach minimal kinetic energy, resulting in a Bose-Einstein condensate. Conversely, exposing a gas to extremely hot temperatures would cause its particles to move faster, leading to dissociation into individual atoms and ionization into a plasma state. While solids, liquids, and gases are the most common forms of matter, there are other forms such as plasmas, Bose-Einstein condensates, and quark-gluon plasma that exist under extreme conditions. Ongoing research into potential new states of matter may lead to further discoveries in the future.

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if the variable capacitor in an fm receiver ranges from 10.9 pf to 16.4 pf , what inductor should be used to make an lc circuit whose resonant frequency spans the fm band?

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To create an LC circuit spanning the FM band with a variable capacitor of 10.9-16.4 pF, use the formula L = 1/(4π²f²C).

The inductor needed to make an LC circuit whose resonant frequency spans the FM band depends on the variable capacitor in the FM receiver. In your case, the variable capacitor ranges from 10.9 pF to 16.4 pF. To determine the inductor needed for the LC circuit, you can use the following formula:

L = (1/ (4π² * f² * C))

Where:

"L" is the inductor. "f" is the frequency of the LC circuit. "C" is the capacitor.

For example, if you set the variable capacitor to 10.9 pF, the inductor needed to make an LC circuit whose resonant frequency spans the FM band would be:

L = (1/ (4π² * f² * 10.9 pF))

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After the switch has been closed for a very long time, it is then opened. What is Q(topen), the charge on the capacitor at a time topen = 623 us after the switch was opened?

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After the switch has been closed for a very long time, it is then opened. What is Q(open), the charge on the capacitor at a time open = 623 us after the switch was opened.

After a very long time, a capacitor is completely charged, and when the switch is turned on, the capacitor discharges in the form of an electric current, and the capacitor charges up again when the switch is turned off. Thus, the capacitor's charge Q is calculated using the formula:

Q(t) = C×V(t),

where t is the time,

C is the capacitance of the capacitor,

and V(t) is the voltage across the capacitor at time t.

In this case, the time is open = 623 us after the switch was opened.

The voltage across the capacitor at this moment, V(open), can be obtained using the formula:

[tex]V_{o} = V e^{-t_o/RC}[/tex]

where V0 is the initial voltage across the capacitor, R is the resistance of the circuit, and C is the capacitance of the capacitor.

Substituting the given values,

we have [tex]V_o= 15 V*e^{-623*10^{-6} )/(15*10^{3} *10^{-6})[/tex]

= 13.61 V

The charge on the capacitor at the time open can now be obtained by multiplying the capacitance of the capacitor by the voltage across it at this time:

Q(topen) = C × V(topen)

[tex]= 12*10^{-6} F *13.61 V[/tex]

= 0.1633 mC (or 163.3 µC)

Thus, the charge on the capacitor at the time open = 623 us

after the switch was opened is 0.1633 mC or 163.3 µC.

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water is reabsorbed through specialized water channels called ______.

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Water is reabsorbed through specialized water channels called aquaporins. Aquaporins are transmembrane proteins that are found in the plasma membrane of many types of cells, including those in the kidney, lungs, and salivary glands.

Aquaporins are specialized water channels that allow for the reabsorption of water. The plasma membranes of many different types of cells, including those in the kidneys, liver, lungs, and brain, include integral membrane proteins called aquaporins. By obstructing the passage of other molecules like ions and solutes, they give water molecules a chance to cross the membrane. Aquaporins are necessary for numerous physiological activities, including the concentration of urine and the preservation of cell volume and shape, and help control the body's water balance.

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A bike accelerate uniformly from rest to a speed of 7.10m/s over a distance of 35.4m. Determine the acceleration of the bike

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Answer: A

Explanation:

which of the following eliminated the extensive loopholes of the general agreement on tariffs and trade (gatt)?

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The World Trade Organization eliminated the extensive loopholes of the General Agreement on Tariffs and Trade (GATT).

What is the General Agreement on Tariffs and Trade (GATT)? The General Agreement on Tariffs and Trade (GATT) was a treaty that was signed in 1948 in order to help in the liberalization of international trade. The General Agreement on Tariffs and Trade (GATT) aimed at reducing tariffs and trade barriers in order to increase international trade and economic development. It established the basic principles of non-discrimination, most-favored-nation status, and transparency. The GATT's principles and rules were integrated into the World Trade Organization (WTO), which was established in 1995 after the conclusion of the Uruguay Round. The World Trade Organization (WTO) eliminated the extensive loopholes of the General Agreement on Tariffs and Trade (GATT). The WTO replaced GATT, which was a provisional system for international trade. It was a forum for member countries to negotiate and adopt trade policies. The World Trade Organization (WTO) was established to support the multilateral trading system and to ensure that member countries comply with trade agreements. It has a more effective and impartial dispute settlement process, which makes it easier for countries to resolve trade disputes. A significant distinction between the GATT and the WTO is the latter's commitment to global economic cooperation. The WTO provides a more inclusive and efficient method for conducting global trade negotiations. In addition, the WTO has the capacity to cover all aspects of trade policy and to provide binding and enforceable rules.

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in the heliocentric model of the solar system, one planet passing another in its orbit gives rise to ...

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In the heliocentric model of the solar system, one planet passing another in its orbit gives rise to gravitational forces.

It can also lead to an alteration in the planets' orbits. This is due to the gravitational forces produced by the interaction between the planets. A heliocentric model is a model of the solar system in which the sun is at the center and the planets orbit it. This model was first proposed by Nicolaus Copernicus, a Polish astronomer in the 16th century. He proposed this model after observing that it better explained the motions of the planets than the previous geocentric model, in which Earth was at the center and everything else revolved around it. An orbit gives rise to the gravitational force that causes a planet to continue to travel in a circle around the sun. It is also responsible for the gravitational pull between planets, which affects their orbits. A planet passing another planet in its orbit can also cause some gravitational perturbations in its orbit. This can lead to an alteration in the planets' orbits or cause their orbits to change slightly over time. The heliocentric model is currently the widely accepted theory of how our solar system is arranged. It states that the planets orbit the sun, which is a massive ball of hot gas at the center of the solar system. The sun's gravity is what keeps the planets in their orbits.

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put the processes that occur when oceanic plates spread apart at the mid-ocean ridge in order, from the first event at the top to the last event at the bottom.
a. Basaltic lava erupts from the rift.
b. Blocks of oceanic crust are downdropped in normal faults.
c. Sediment settles onto new basalt.
d. Oceanic crust has a smooth surface covered by layered sediment.

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The following is the order of events that take place when oceanic plates spread apart at the mid-ocean ridge:

1. Basaltic lava erupts from the rift.

2. Blocks of oceanic crust are down-dropped in normal faults.

3. Sediment settles onto new basalt.

4. Oceanic crust has a smooth surface covered by layered sediment.

When an oceanic plate diverges from another oceanic plate or diverges from a continental plate, a mid-ocean ridge is created.

The mid-ocean ridge system is formed as magma rises from the mantle and is injected into the crustal rocks above.

The injection of magma creates a rift and extrusion of basaltic lava along the crest of the ridge.

The lava flows out from the crest of the ridge and cools and solidifies to form new crustal rock.

Thus, the first event that occurs when oceanic plates spread apart at the mid-ocean ridge is that basaltic lava erupts from the rift, and blocks of oceanic crust are down-dropped in normal faults.

As the new basaltic rock cools and solidifies, the sediment settles onto it. Finally, the oceanic crust has a smooth surface covered by layered sediment.

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Explain how a thermal cycler help the process of PCR can be used in the identification of a disease pathogen?

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A thermal cycler is used in the process of PCR to amplify DNA samples, which can then be used to identify disease pathogens through genetic testing.

PCR, or polymerase chain reaction, is a laboratory technique used to amplify and copy DNA samples. It involves the use of a thermal cycler, which rapidly cycles through different temperatures to facilitate the various steps of the PCR process. The thermal cycler heats and cools the reaction mixture containing the DNA sample and other reagents, causing the DNA to denature, anneal, and elongate in a repeating cycle. Once the DNA has been amplified, it can be used in genetic testing to identify the presence of specific disease pathogens, such as viruses or bacteria, by comparing the amplified DNA sequence to known pathogen sequences.

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The diffraction limit of a 4-meter telescope is _________ than that of a 2-meter telescope.
a) two times larger
b) four times larger
c) four times smaller
d) two times smaller
e) It depends on the type of telescope.

Answers

The diffraction limit of a 4-meter telescope is two times smaller than that of a 2-meter telescope.

The diffraction limit of a telescope is the minimum distance between two objects so that they can still be viewed as separate from one another. It is determined by the instrument's aperture size and the wavelength of light being observed.

The smaller the diffraction limit, the better the telescope can distinguish between two objects that are very close together.

In simpler terms, the diffraction limit refers to the smallest object size that a telescope can observe. This is known as angular resolution, which is determined by the telescope's aperture size and the wavelength of light being observed.

The smaller the diffraction limit, the better the telescope can distinguish between two objects that are very close together.

Therefore, a 4-meter telescope has a smaller diffraction limit than a 2-meter telescope. Hence, the answer is two times smaller.

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A bus engine transfers chemical potential energy into ___ so that the bus moves.
a. kinetic energy
b. thermal energy
c. gravitational potential energy
d. electrical energy

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the answer is “A” !!!!
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