Quadrilateral ABCD has coordinates A(3,-5), B(5,-2), C(10,-4), D(8,-7). Quadrilateral is a

Answer:

Area = 97.4 cm²

Step-by-step explanation:

a = 15 cm

        [tex]Area = \frac{ \sqrt 3}{4} a^2\\[/tex]

                 [tex]=\frac{\sqrt 3}{ 4 } \times 15^2\\\\=\frac{\sqrt 3}{ 4 } \times 225\\\\= 97.4 \ cm^2[/tex]

Answer:

it's can be anything from 1 to infinite.

Answer:

-4+8+-16+32+-64+128 = 84

Step-by-step explanation:

The fifth and sixth terms are -64 and 128

Answer:

0, 0.5, 8/3, root 5, 3.1

Answer:

[tex]6 \sqrt{5} [/tex]

Step-by-step explanation:

Take out Square root 5 as common and then add numbers

[tex]4 \sqrt{5} + 2 \sqrt{5} \\ 6 \sqrt{5} [/tex]

Answer:

90=30+(x+10). remove blanket

90=30+x+10. correct like terms

90=30+10+x

90=40+x. 40 will cross the = and change from +ve to -ve sign

90-40=x.

therefore

x=40

Answer:

x = 50

Step-by-step explanation:

The 2 angles sum to 90° , that is

x + 10 + 30 = 90

x + 40 = 90 ( subtract 40 from both sides )

x = 50

Answer:

We reach at 8.

Step-by-step explanation:

The starting point is 2 .

Jump at the six places, the final point reaches at 8, so the point is 8.

Answer:

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Answer:

i)

Odd numbers:

P(odd and odd) = 3/6*3/6 = 1/4

ii)

Total outcomes:

Sum of 8:

Sum of 12:

P(8 or 12) = 5/36 + 1/36 = 6/36 = 1/6

iii)

Prime numbers:

Odd numbers:

P(prime or odd) = 3/6*3/6 + 3/6*3/6 = 1/4 + 1/4 = 1/2

Step-by-step explanation:

everything can be found in the picture

Answer: one solution

this is all i know

Answer:

D

Step-by-step explanation:

Given

1 - [tex]\frac{1}{2}[/tex] (6x - 4) = 3(1 - x) ← distribute parenthesis on both sides

1 - 3x + 2 = 3 - 3x

3 - 3x = 3 - 3x

Since both sides of the equation are the same , then

This indicates the equation has infinitely many solutions.

Answer:

[tex]a_{n}[/tex] = 2n + 5

Step-by-step explanation:

There is a common difference between consecutive terms, that is

9 - 7 = 11 - 9 = 13 - 11 = 15 - 13 = 2

This indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 7 and d = 2 , then

[tex]a_{n}[/tex] = 7 + 2(n - 1) = 7 + 2n - 2 = 2n + 5

Answer:

3.78 × [tex]10^{2}[/tex] = 378

Step-by-step explanation:

Answer:

D   (0, 3)

Step-by-step explanation:

To go from B (8, 3) to C (3, 8)

subtract 5 from x, add 5 to y

A (5, -2)

subtract 5 from x,   x = 0

add 5 to y,   y = 3

D (0, 3)

Answer:

Hope this helps.

Answer:

4

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

she burns 250 calories per hour .to burn 3500 calories and shed 1 pound she has to work 14 hours and to shed 5 pounds she has to work 14×5=70 hours

Answer:

The minimum is -4

Step-by-step explanation:

The minimum is the lowest point on the parabola

It is at (-3,-4)

The y value is the minimum of the function

The minimum is -4

Step-by-step explanation:

I cannot see all the answer options.

square garden, side length x.

area = x² (or x×x)

new area r = (x-p)(x+q) = x² - px + qx - pq =

= x² + (q - p)x - pq

3D printer. costs p in general.

makes x figurines.

material per figurine costs q.

costs per figurine r = q + p/x

as the printer costs themselves need to be distributed equally across all produced figurines.

investment account. q% pretty year.

p dollars starting balance.

letting it sit for x years.

a0 = p

a1 = a0 + a0×q/100 = a0 × (1 + q/100)

a2 = a1 + a1×q/100 = a1×(1 + q/100) = a0×(1 + q/100)²

a3 = a2 + a2×q/100 = a2×(1 + q/100) = a0×(1 + q/100)³

...

ax = a0×(1 + q/100) to the power of x =

= p × (1 + q/100) to the power of x

account without interest. p dollars are already in it.

adding q dollars every month for x months.

balance after these x months

r = x×q + p = q×x + p

Answer:

Area = 4600m

explanation: I worked it out in the image attached if that helps let me know if you need a more in depth explanation step by step

Answer:

244280

Step-by-step explanation:

you divide it into three rectangles so you have three diffenet products of 6480+57800+180000 to get 244280

Answer:

sinC = [tex]\frac{4\sqrt{41} }{41}[/tex]

Step-by-step explanation:

We require to find the side DE before finding sinC

Using Pythagoras' identity in the right triangle

DE² + CE² = CD²

DE² + 5² = ([tex]\sqrt{41}[/tex] )²

DE² + 25 = 41 ( subtract 25 from both sides )

DE² = 16 ( take the square root of both sides )

DE = [tex]\sqrt{16}[/tex] = 4 , then

sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{DE}{CD}[/tex] = [tex]\frac{4}{\sqrt{41} }[/tex] , rationalise the denominator

sinC = [tex]\frac{4}{\sqrt{41} }[/tex] × [tex]\frac{\sqrt{41} }{\sqrt{41} }[/tex] = [tex]\frac{4\sqrt{41} }{41}[/tex]

Answer:

Step-by-step explanation:

The diagonals of a rhombus divides it into four congruent right triangles.  Each triangle is a mirror image of the adjacent.

Therefore angle 2 is the alternate interior angle of 57°, and angle 3 is the mirror image, so also 57°.

Angles 1 is the complement of angle 3, and angle 4 is equal to the complement of angle 2 , so both equal 90-57 = 33°.

To summarize,

angle 1 = 33°

angle 2 = 57°

angle 3 = 57°

angle 4 = 33°

Answer:

use the pythagorean theorem

Step-by-step explanation:

a²+b²=c²

Answer:

[tex]\Delta y = A[/tex] (Amplitude) (Correct answer: 1)

[tex]\omega = B[/tex] (Angular frequency) (Correct answer: 2)

[tex]x_{o} = C[/tex] (Phase shift) (Correct answer: 3)

[tex]y_{o} = D[/tex] (Vertical shift) (Correct answer: 4)

[tex]\frac{2\pi}{\omega} = \frac{2\pi}{B}[/tex] (Period) (Correct answer: 5)

Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

[tex]y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o}[/tex] (1)

Where:

[tex]\Delta y[/tex] - Amplitude.

[tex]\omega[/tex] - Angular frequency.

[tex]x_{o}[/tex] - Phase shift.

[tex]y_{o}[/tex] - Vertical shift.

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

In addition, we know that the period associated with the sinusoidal function ([tex]T[/tex]) is:

[tex]T = \frac{2\pi}{\omega}[/tex]

By direct comparison, we get the following conclusions:

[tex]\Delta y = A[/tex] (Amplitude) (Correct answer: 1)

[tex]\omega = B[/tex] (Angular frequency) (Correct answer: 2)

[tex]x_{o} = C[/tex] (Phase shift) (Correct answer: 3)

[tex]y_{o} = D[/tex] (Vertical shift) (Correct answer: 4)

[tex]\frac{2\pi}{\omega} = \frac{2\pi}{B}[/tex] (Period) (Correct answer: 5)

Answer:

Circumference! it's the major arc whose starting and ending point coincide.

Answer:

5 dollors i just tookthe test 4

Step-by-step explanation:

Arianna bought 0 bags of oranges. It's possible that she may have bought other items along with the oranges or there might be a pricing discrepancy.

To find out how many oranges Arianna bought, we can use the given price of a bag of 4 oranges and the total amount she spent on oranges.

Let's set up a proportion:

Price of a bag of 4 oranges = $2.84

Amount Arianna spent on oranges = $3.55

Let "x" be the number of bags of oranges Arianna bought.

Since each bag contains 4 oranges, the total number of oranges she bought is 4 times the number of bags (4x).

Now, we can set up the proportion:

(Price of a bag of 4 oranges) / (Amount spent on oranges) = (Number of bags bought) / 4x

$2.84 / $3.55 = 1 / 4x

To solve for "x," cross-multiply:

$2.84 * 4x = $3.55 * 1

11.36x = 3.55

Now, solve for "x":

x = 3.55 / 11.36

x ≈ 0.3125

Since we can't buy a fraction of a bag, we round the value of "x" to the nearest whole number:

x ≈ 0 (rounded to the nearest whole number)

So, Arianna bought 0 bags of oranges. It's possible that she may have bought other items along with the oranges or there might be a pricing discrepancy.

To know more about oranges:

https://brainly.com/question/28969541

#SPJ3

Answer:

False

Step-by-step explanation:

3(2x - 1) = 6(1 + 1)

Distribute

6x -3 = 6(2)

6x -3 = 12

Add 3 to each side

6x  =15

x = 15/6

There is one solution

Answer:

False.

Step-by-step explanation:

3(2x - 1) = 6 (1+1)

3*2x - 3*1 = 6*2

6x - 3 = 12

Add 3 to both side

6x = 12+ 3

6x = 15

Divide both sides by 6

x = 15/6

x = 2.5

This equation has one solution

Answer:

[tex] { ({x}^{2}. {y}^{6} )}^{ \frac{1}{8} } \\ {x}^{2 \times \frac{1}{8} } . {y}^{6 \times \frac{1}{8} } \\ = {x}^{ \frac{2}{8} } . {y}^{ \frac{6}{8} } \\ = {x}^{ \frac{1}{4} } . {y}^{ \frac{3}{4} } [/tex]

Answer:

positive charge...............