pls answer this if you do I mark brainlest​

Answer:

The factored difference is: [tex]2x(7x^3 - 10x + 5)[/tex]

Step-by-step explanation:

Difference in non factored form:

To find the difference in non-factored form, we subtract the common terms. So

[tex]24x^4 - 15x^2 + 6x - (10x^4 + 5x^2 - 4x) = 24x^4 - 10x^4 - 15x^2 - 5x^2 + 6x + 4x = 14x^4 - 20x^2 + 10x[/tex]

Greatest common factor:

Of the exponents: Between [tex]x^4, x^2[/tex] and [tex]x[/tex], it is the one with the lowest exponent, so x.

Between 14, 20 and 10:

14 - 20 - 10|2

7 - 10 - 5

So 2

The gcf is 2x, which means that the factored expression is:

[tex]2x(\frac{14x^4}{2x} - \frac{20x^2}{2x} + \frac{10x}{2x}) = 2x(7x^3 - 10x + 5)[/tex]

The factored difference is: [tex]2x(7x^3 - 10x + 5)[/tex]

Answer:

C.

Step-by-step explanation:

Given

[tex]A =(x_1,y_1)[/tex]

[tex]B =(x_2,y_2)[/tex]

[tex]C =(x_3,y_3)[/tex]

[tex]D =(x_4,y_4)[/tex]

Required:

Which condition proves that AB is perpendicular to CD

First, calculate the slopes of both.

For AB

[tex]m_1 = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

For CD

[tex]m_2 = \frac{y_4 -y_3}{x_4 - x_2}[/tex]

The condition of perpendicularity is:

[tex]m_1 * m_2 = -1[/tex]

Substitute values for m1 and m2

[tex]\frac{y_2 -y_1}{x_2 - x_1} * \frac{y_4 -y_3}{x_4 - x_2} = -1[/tex]

Option (c) is correct

Answer:

x=1 must satisfy both equations.

Step-by-step explanation:

1)Y=X+4

2)Y=3X+2

IT Means x+4=3x+2

3x-x=4-2;

2x=2 ;  x=1 must satisfy both equations

Answer:

1/8

1/4

1/8

1/8

1/8

1/4

Step-by-step explanation:

Probability a letter would be picked = total number of the letter in the bag /sum of letters in the bag

1. v,r,y,w appear once. the numerator would be 1 and the denominator would be 8 = 1/8

e and l would appear twice in the bag, so the numerator would be 2 and the denominator would be 8 = 2/8 convert to its simplest form = 1/4

Answer:

[tex]Area = 3500[/tex]

Step-by-step explanation:

Given

[tex]Length : Breadth = 7 : 5[/tex]

[tex]Perimeter = 240m\\[/tex]

Required

Determine the area

The perimeter is:

[tex]Perimeter = 2(Length + Breadth)[/tex]

This is then represented as:

[tex]240 = 2(7x + 5x)[/tex]

[tex]240 = 2 * 12x[/tex]

[tex]240 = 24x[/tex]

[tex]10 = x[/tex]

[tex]x = 10[/tex]

So, the area is:

[tex]Area = Length * Width[/tex]

[tex]Area = 7x * 5x[/tex]

[tex]Area = 7*10 * 5*10[/tex]

[tex]Area = 3500[/tex]

Answer:

[tex](a)[/tex] [tex]Denominator= (x - 10)(x+5)(x-4)[/tex]

[tex](b)[/tex] [tex]M = \frac{(7x - 5)(x-4)}{(x+5)(x - 10)(x-4)}[/tex]

[tex](c)[/tex] [tex]N = \frac{(3x - 8)(x + 5)}{(x-4)(x-10)(x + 5)}[/tex]

[tex](d)[/tex] [tex]M + N = \frac{10x^2-26x -20}{(x+5)(x - 10)(x-4)}[/tex]

Step-by-step explanation:

Given

[tex]M = \frac{7x - 5}{x^2 -5x - 50}[/tex]

[tex]N = \frac{3x - 8}{x^2 -14x+ 40}[/tex]

Solving (a): A common denominator of M and N.

To do this, we simply get the LCM of both denominators

[tex]M = x^2 - 5x - 50[/tex]

[tex]N = x^2 - 14x + 40[/tex]

Factorize both:

[tex]M = (x - 10)(x + 5)[/tex]

[tex]N = (x- 10)(x - 4)[/tex]

The LCM is

[tex]LCM= (x - 10)(x+5)(x-4)[/tex]

Hence, the common denominator is:

[tex]Denominator= (x - 10)(x+5)(x-4)[/tex]

Solving (b): Rewrite M

[tex]M = \frac{7x - 5}{x^2 -5x - 50}[/tex]

Factor the denominator:

[tex]M = \frac{7x - 5}{(x+5)(x - 10)}[/tex]

The LCM calculated in (a) above is:

[tex]LCM= (x - 10)(x+5)(x-4)[/tex]

So, we have to multiply the numerator and denominator of M by (x - 4)

The expression becomes:

[tex]M = \frac{7x - 5}{(x+5)(x - 10)} * \frac{x - 4}{x-4}[/tex]

[tex]M = \frac{(7x - 5)(x-4)}{(x+5)(x - 10)(x-4)}[/tex]

Solving (c): Rewrite N

[tex]N = \frac{3x - 8}{x^2 -14x+ 40}[/tex]

Factor the denominator:

[tex]N = \frac{3x - 8}{(x-4)(x-10)}[/tex]

The LCM calculated in (a) above is:

[tex]LCM= (x - 10)(x+5)(x-4)[/tex]

So, we have to multiply the numerator and denominator of N by (x + 5)

The expression becomes:

[tex]N = \frac{3x - 8}{(x-4)(x-10)} * \frac{x + 5}{x + 5}[/tex]

[tex]N = \frac{(3x - 8)(x + 5)}{(x-4)(x-10)(x + 5)}[/tex]

(d) Solve M + N

[tex]M + N = \frac{(7x - 5)(x-4)}{(x+5)(x - 10)(x-4)} + \frac{(3x - 8)(x + 5)}{(x-4)(x-10)(x + 5)}[/tex]

Take LCM

[tex]M + N = \frac{(7x - 5)(x-4) + (3x - 8)(x + 5)}{(x+5)(x - 10)(x-4)}[/tex]

Open brackets

[tex]M + N = \frac{7x^2 - 28x - 5x + 20 + 3x^2 + 15x - 8x - 40}{(x+5)(x - 10)(x-4)}[/tex]

Collect Like Terms

[tex]M + N = \frac{7x^2 + 3x^2- 28x - 5x + 15x - 8x + 20 - 40}{(x+5)(x - 10)(x-4)}[/tex]

[tex]M + N = \frac{10x^2-26x -20}{(x+5)(x - 10)(x-4)}[/tex]

Answer:

The profit is 300.

Step-by-step explanation:

x = 0

y = 6

P = 30(0) + 50(6)

P = 0 + 300

P = 300

Hope I helped! Have a nice day! Plz mark as brainliest!!! :D

-XxDeathshotxX

The required profit is 300.

Profit in Math is considered as the gain amount from any business activity.

Now the given function of profit is,

P = 30x + 50y

The Corner that maximizes profit is (0, 6)

Thus, At (0, 6) the given function is given as,

Put x = 0 and y = 6 in the given function.

P(0, 6) = 30*0 + 50*6

⇒ P(0, 6) = 0 + 300

P(0, 6) = 300

this is the required profit.

Thus, the required profit is 300.

To learn more about the profit visit:

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Answer:

0.5

Step-by-step explanation:

Answer:

the surface area of the cube is 150 inches squared

Step-by-step explanation:

The computation of the surface area of the cube is shown below:

As we know that

The surface area of the cube is

= 6s^2

= 6(5)^2

= 150 inches squared

hence, the surface area of the cube is 150 inches squared

2+7x=747 X83                 83(2)=83             83(7)= 581

Step-by-step explanation:

Answer:

a) 10

b) 3

c) 16

Step-by-step explanation:

Count the squares and the half ones match them with each other to get a full square... so so sorry if im wrong i did this a while ago! Currently Yr 9 x

Answer: 256

Step-by-step explanation:

Answer:

256cm² is the correct answer

Answer: (0,4)

Step-by-step explanation:

Answer:

x = -7/2........y = -11/2

Step-by-step explanation:

..….................

Forgive me if wrong

Answer:

[tex]1-8x-2x^2[/tex]

Step-by-step explanation:

(-4x^3-14x^2+10x-1)÷(2x-1)

Factor the expressions that are not already factored.

[tex]\frac{(2x-1)(2x^2-8x+1)}{2x-1}[/tex]

Cancel out 2x−1 in both numerator and denominator.

[tex]2x^2-8x+1[/tex]

Swap terms to the left side.

[tex]1-8x-2x^2[/tex]

Graph if needed:

Answer:

Step-by-step explanation:

∠1 = 180° - ∠2 - ∠3 = 38°

∠5 = ∠1 = 38°

Answer:

h = -25

Step-by-step explanation:

h - 5 = - 30

   +5     +5

h = -25

Answer:

A two-sided alternative hypothesis would be more appropriate in this case

Step-by-step explanation:

A one-sided hypothesis is one that asserts that a given parameter is either smaller than the null hypothesis value or larger than the value presented by the null hypothesis.

However in a two sided hypothesis, the claim is made that a given parameter is not equal to the parameter given in the null hypothesis, such that the parameter can be either larger than than or lesser than the value of the null hypothesis and still satisfy the condition of the hypothesis

Therefore, given for that for there to be a conclusion, the test should be weather the number of people that think of an odd number are equal to the number of people that think of an even number, or weather the number of people that think of an odd number are not equal to the number of people that think of an even number

Therefore, a two-sided hypothesis should be used since the claim (that the numbers are not equal) is not equal to the value of the parameter in the null hypothesis (that the numbers are equal)

Answer:

Quadratic (I took the test)

Step-by-step explanation:

y=t+2 equals y-2=t

put t in for x=t^1/2. this is x=(y-2)^1/2, which equals x^2=y-2.

add 2 to both sides, which is y=x^2+2 . This is an example of a quadratic equation (you kinda just need to know the format of different types of equations for the last part. It isn't cubic because it has a number added to it, isn't linear because the x is squared, and tbh I have no clue what quartic is.)

This is an example of a quadratic equation.

We have given that the equation

y=t+2 equals y-2=t

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax^2 + bx + c = 0, where a,b are and c represents the constant.

put t in for x=t^1/2. this is x=(y-2)^1/2,

Squaring both sides we get,

x^2=y-2.

add 2 to both sides, which is y=x^2+2.

This is an example of a quadratic equation.

To learn more about the quadratic equation visit:

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Answer:

8

Step-by-step explanation:

3 times 4 is 12 and 2 times 4 is 8

Answer:

y=-16

Step-by-step explanation:

Answer:

y = -16

Step-by-step explanation:

−10y+4(3y−8)=−64

Step 1: Simplify both sides of the equation.

−10y+4(3y−8)=−64

−10y+(4)(3y)+(4)(−8)=−64(Distribute)

−10y+12y+−32=−64

(−10y+12y)+(−32)=−64(Combine Like Terms)

2y+−32=−64

2y−32=−64

Step 2: Add 32 to both sides.

2y−32+32=−64+32

2y=−32

Step 3: Divide both sides by 2.

2y

2

=

−32

2

y=−16

Answer:

y=−16

Answer:

x = 32

Step-by-step explanation:

180 - 42 - 106 = x

x = 32