Please some one help me solve this question.

George needs to take the route as follows .
6km on a bearing of 080° from A to B
5km on a bearing of 160°. From B to C
The scale is 1.5cm= 1km
However, George uses an incorrect scale of 1cm= 1km and ends up at D. What bearing and distance does he need to take to end up at the correct destination of C.​

The corresponding sides and angles of two polygons ABCD and ZYXW must be proportionate if they are identical.

With straight sides around its perimeter, a polygon is really a circular, two-dimensional, flat of planar structure. Its sides are straight with no bends. Another term for a polygon's sides is its edges. The points at which two sides of a polygon converge are known as its vertices (or corners). These are numerous examples of polygonal geometry.

A closed polygon is a form with more than three sides. A quadrilateral is a 4-sided polygonal shape. A quadrilateral is any closed 4-sided form, however there are six particular quadrilaterals with distinctive characteristics that give them their own names.

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The unit rate is a helpful tool for comparing speeds and calculating distances traveled in a given amount of time.

The formula for speed is: speed = distance / time where "distance" is the distance traveled by an object and "time" is the duration of travel. This formula can be used to calculate the speed of an object if the distance it has traveled and the time it took to travel that distance are known. It can also be used to calculate the distance traveled by an object if its speed and the time it traveled at that speed are known.

In the given question,

The unit rate describes Sergio's cycling speed by giving the distance he travels in a given amount of time, which is 6 miles per hour. This means that for every hour he cycles, he travels a distance of 6 miles.

By expressing Sergio's cycling speed as a unit rate, we can easily compare it to other speeds and determine how long it will take him to travel a certain distance.

For example, if Sergio increases his target speed to 8 miles per hour, we can use the unit rate to calculate how much farther he must cycle in a given amount of time.

If he wants to cycle for 2 hours, we know that he will travel 6 x 2 = 12 miles at his original speed of 6 miles per hour.

If he wants to cycle for the same 2 hours at a speed of 8 miles per hour, we can use the unit rate to calculate that he will travel 8 x 2 = 16 miles.

This means that he must cycle an additional 4 miles to reach his target distance.

Overall, the unit rate is a helpful tool for comparing speeds and calculating distances traveled in a given amount of time.

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The numbers ordered from least to greatest are 0.721, 73/100, and 0.75.

0.75, 0.721, 73/100

we can convert the fraction 73/100 to a decimal by dividing 73 by 100, which gives us 0.73.

0.721 < 0.73 < 0.75

"Least" is a mathematical term used to refer to the smallest value in a given set of numbers or a range of values. It is the opposite of the term "greatest," which refers to the largest value in the set. To find the least value in a set of numbers, you can sort them in ascending order and select the first or smallest number. Alternatively, you can use mathematical formulas or functions such as the minimum function to determine the least value.

In algebra, finding the least common multiple (LCM) or least common denominator (LCD) involves identifying the smallest multiple or denominator that two or more numbers or expressions have in common. This is essential in simplifying and solving complex equations and expressions. In geometry, the least distance between two points is the straight line or path that connects them and is the shortest possible route between them. This concept is fundamental in navigation and optimization problems.

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The statement that is not true of the test data approach in a test of a computerized accounting system is B) Test data should consist of data related to all controls prevalent in the organization.

This statement is incorrect because the test data approach aims to test specific controls that the auditor wishes to rely on rather than all controls prevalent in the organization. The test data approach involves the creation of a set of test transactions that are processed by the client's computer program under the auditor's control.

The results of the test data are used to determine whether the application and general controls are functioning properly. By using this approach, the auditor can gain assurance that the system is functioning as intended and identify any control weaknesses that need to be addressed.

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False. A probability distribution for a discrete variable is not exclusive, collectively exhaustive list of numerical outcomes for that variable and the probability of occurrence associated with each outcome.

A probability distribution for a discrete variable is a list of all possible values that the variable can take on, along with the probability of each value occurring. The values must be collectively exhaustive (meaning they include all possible outcomes) and mutually exclusive (meaning that each outcome cannot occur at the same time as any other outcome). However, the numerical outcomes do not have to be exclusive, as they can have the same probability of occurring. For example, a coin toss has two possible outcomes (heads and tails) with equal probability, and a dice roll has six possible outcomes with equal probability. These probabilities can be represented using a probability distribution.

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Answer:51

Step-by-step explanation:

The perimeter of the triangle AABC is 19.27 m.

In order to solve this we first have to create a triangle rectangle, check the image attached to understand it better, and with that we use law of sines in order to calculate the other sides of the triangle:

As you can see we know that the hypothenuse is 8 m, and we have both angles, so for the angle that is opposed to the 50º angle we will use [tex]8cos(50)=5.1423 \ m[/tex].

For the side that is opposed to the 40º angle we will use [tex]8cos(40):6.1283m[/tex]

SO to calculate the perimeter we just add the three sides:

[tex]5.1423 + 6.1283 + 8= 19.27[/tex]

Therefore, The perimeter of the triangle AABC is 19.27 m.

So, the statements that are true are: This study uses a repeated measures design. This study uses random sampling. This study uses a control group.

An equation is a mathematical statement that asserts that two expressions are equal. It typically contains variables, constants, and mathematical operators, such as addition, subtraction, multiplication, division, exponentiation, and logarithms. Equations are used to solve problems and find the values of the variables that make the equation true. For example, the equation 2x + 3 = 7 is true when x equals 2, because 2(2) + 3 = 7. Equations can be represented using mathematical notation.

by the question.

This study uses a repeated measures design because each subject experiences each of the four treatments.

This study uses random sampling because the 100 children were randomly selected.

This study uses a control group because the first group, which has no screen time, serves as the control group for comparison.

This study does not use blinding because there is no mention of hiding the treatment groups from the children or the researchers.

This study does not use blocking because there is no mention of grouping the children based on certain characteristics (e.g., age, gender) and then randomly assigning them to the treatment groups within each block.

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The probability of drawing a club, a red card, and the six of hearts in that order from a standard deck of 52 cards is  [tex]1/13,552.[/tex]

This is because the probability of drawing a club is 1/4, and the probability of drawing a red card is 1/2, and the probability of drawing the six of hearts is 1/52.
Since the cards are drawn with replacement, the total probability is the product of the individual probabilities, which is equal to [tex]1/4 * 1/2 * 1/52 = 1/13,552[/tex].
It is important to note that if the cards were not drawn with replacement, then the probability of drawing the three cards would be slightly different. The total probability would be equal to [tex]1/4 * 1/2 * 1/51 = 1/12,600.[/tex]
It is also important to note that since this is a probability question, the answer can be expressed as a decimal or percentage. In decimal form, the probability of drawing the three cards is 0.000074, and in percentage form, the probability of drawing the three cards is 0.0074%.

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The approximate circumference of spaceship Earth is 160m

The formula for calculating the volume of a sphere is given as;

V = 4/3 πr³

Given that;

Now, substitute the values

65417 = 1. 3 ×3.14r³

Multiply the values

65417 = 4. 082r³

Make r the subject

r³ = 16025. 722

Find the cube root

r = 25. 2m

The circumference is expressed as;

Circumference = 2πr

Substitute the values, we have;

Circumference = 2× 3.14 × 25.2

Circumference = 160 m

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The coordinate matrix LFE of L relative to the ordered bases E and F is given by:

LFE=12,3,0,12,3,0,0

LFE =

[[5, 1, 3, 3],

[0, 0, 3, 0],

[0, 0, 0, 0]]

This matrix can be obtained by computing the entries of LFE in terms of the components of L with respect to the basis E and then expressing those components with respect to the basis F. The elements of LFE are computed as follows:

LFE[1,1] = L(e1) = = 5 + 1 + 3 + 3 = 12

LFE[1,2] = L(e2) =  = 0 + 0 + 3 + 0 = 3

LFE[1,3] = L(e3) =  = 0 + 0 + 0 + 0 = 0

LFE[2,1] = L(f1) =  = 5 + 1 + 3 + 3 = 12

LFE[2,2] = L(f2) = = 0 + 0 + 3 + 0 = 3

LFE[2,3] = L(f3) = = 0 + 0 + 0 + 0 = 0

LFE[3,1] = L(f4) =  = 0 + 0 + 0 + 0 = 0

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Among the given factors, global competition does not contribute to the quest for quality. The correct answer is Option A.

In today's business environment, quality has become an important factor that can make or break a company's success. A successful firm must focus on the quality of the products and services they offer, as this can help them maintain their competitive advantage and ensure customer loyalty.

Quality is important for a variety of reasons, including customer satisfaction, reduced costs, increased productivity, and increased revenue. When firms focus on quality, they can provide better products and services to their customers, which can lead to increased customer loyalty and repeat business. This can help firms build a strong reputation in the market and maintain a competitive advantage.

Global competition has made it necessary for firms to focus on quality to maintain their competitive advantage. When firms face global competition, they need to ensure that their products and services are of high quality to compete effectively in the global market. High-quality products and services can help firms differentiate themselves from their competitors and gain a competitive advantage. This can help firms increase their market share and revenue.

Several factors contribute to the quest for quality. These include:

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Answer:

<abc

Step-by-step explanation:

The equation of the tangent line at x = 16 is therefore :y - 2 = (1/64)(x - 16)Simplifying, we get :y = (1/64)x + 1Using this equation, we can estimate the value of 12^1/4:y = (1/64)(12) + 1 = 49/32Therefore, the estimate for 12^1/4 using linear approximation is 49/32.

approximation is an approach used to estimate the value of a function at a point near a known point by using the linear equation tangent to the function at that point.

This technique is commonly used in physics, engineering, economics, and other fields where mathematical models are used to describe real-world phenomena.

To estimate 12^1/4 using linear approximation, we first need to find the equation of the tangent line at the point of interest, which is x = 16 (since 16^4 = 2^16 = 65536).

Then, we can use the equation of the tangent line to estimate the value of the function at a nearby point, which in this case is x = 12.

We can find the equation of the tangent line using the derivative of the function :f(x) =[tex]x^1/4f'(x) = (1/4)x^-3/4At x = 16:f(16)[/tex] = 2f'(16) = (1/4)(16)^-3/4 = 1/64

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The cost of each nachos is $2.50 and the cost of each water bottle is $1.50.

What is a linear system of equations?

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

Let x be the cost of each water bottle and y be the cost of each nachos.

Two bottled water and an order of cheese nachos costs $5.50.

So, 2x+y=5.50 -------(I)

Three bottled water and two orders of cheese nachos costs $9.50​

3x+2y=9.50 -------(II)

Multiply equation (I) by 2, we get

4x+2y=11 -------(III)

Subtract equation (II) from equation (III), we get

4x+2y-(3x+2y)=11-9.50

x=$1.50

Substitute x=1.50 in equation (I), we get

2(1.50)+y=5.50

y=$2.50

Therefore, the cost of each nachos is $2.50.

Let's assume that the measure of angle BAC is less than or equal to the measure of angle ABC.

Since AB = AC, then angles BAC and BCA are also equal. Let's denote the measure of angle BAC as x, then the measure of angle ABC and angle BCA is also x.

According to the triangle inequality theorem, the sum of any two sides of a triangle must be greater than the third side. In our case, we have:

AB + BC > AC

AB + 24 > AC

2AB + BC > 2AC

2AB + 24 > 2AC

2AB > 2AC - 24

AB > AC - 12

Since AB = AC, then AC - 12 < AB = AC, which means AC < AC + 12. This is a contradiction, and therefore our assumption that the measure of angle BAC is less than or equal to the measure of angle ABC is false.

Therefore, we can conclude that Angle BAC > Angle ABC.

The probability of reaching into the box and randomly drawing a chip number that is smaller than 212 is 0.9378

First, we should find the total number of chips in the box. The box contains 225 chips numbered from 1 to 225. Therefore, the probability of reaching into the box and randomly drawing a chip number that is smaller than 212 is 211/225.

The probability can be expressed as a simplified fraction or a decimal rounded to four decimal places. The probability is rounded to four decimal places is 0.9378.

The probability of drawing a chip number that is smaller than 212 from the box is 211/225 or 0.9378 (rounded to four decimal places).

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The probabilities of exactly two students choosing Duke, NC State, and Hogwarts-NC are approximately 0.008, 0.008, and 0.327, respectively.

Let X be the number of students who choose UNC, and Y be the number of students who choose Duke. Then X follows a binomial distribution with n = 5 and p = 0.6, and Y follows a binomial distribution with n = 5 and p = 0.1.

(a) The event a 2 UNC corresponds to choosing exactly 2 out of 5 students to attend UNC. This can be written as:

A UNC = {X = 2}

The indicator random variable for a 2 UNC is

UNC = 1, if X = 2 , 0, otherwise

(b) Similarly, the events  a 2 Duke, a 2 NCS, and a 2 Hogwards-NC correspond to choosing exactly 2 out of 5 students to attend Duke, NC State, and Hogwarts-NC, respectively. These can be written as:

A 2 Duke = {Y = 2}

A 2 NCS = {Z = 2}, where Z is the number of students who choose NC State

A 2 HCS = {W = 2}, where W is the number of students who choose Hogwarts-NC

The indicator random variables for these events are:

2 DUKE= 1, if Y = 2 , 0, otherwise

2 NCS = 1, if Z = 2 , 0, otherwise

2 HNC = 1, if W = 2 , 0, otherwise

(c) To find the probability that at least two students choose UNC, we can use the complement rule:

P(at least 2 students choose UNC) = 1 - P(less than 2 students choose UNC)

= 1 - P(X = 0) - P(X = 1)

= 1 - (0.4)⁵ - 5(0.6)(0.4)⁴

≈ 0.848

(d) To find the probability that exactly 2 students choose UNC and 2 students choose Duke, we can use the joint probability:

P(2 students choose UNC and 2 students choose Duke) = P(X = 2)P(Y = 2)

= (0.6)²(0.4)³(0.1)²(0.9)³

≈ 0.0003456

For five graduating high school students from five different high schools in NC who have all been accepted to four colleges (UNC, Duke, NC State, and Hogwarts-NC), the probability that exactly two out of the five students choose UNC is approximately 0.259. Similarly, the probabilities of exactly two students choosing Duke, NC State, and Hogwarts-NC are approximately 0.008, 0.008, and 0.327, respectively.

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The limit of the expression is 7.

The expression to find the limit is given by;Lim (6x + √36x² - x) x → -∞To solve this limit, we treat the expression as a fraction whose denominator is 1, and rationalize the numerator as follows;Lim (6x + √36x² - x) x → -∞Lim [{(6x + √36x² - x) × (6x - √36x² - x)} ÷ (6x - √36x² - x)] x → -∞Lim [(6x)² - (x)²] ÷ [(6x - x) - √36x²] x → -∞Lim (36x² - x²) ÷ 5x x → -∞Lim x² (36 - 1) ÷ 5x x → -∞Lim 35x ÷ 5 x → -∞7For a graph, we can plot the expression as follows;y = 6x + √36x² - xy = 6x - √36x² - xUsing the graphing utility, we can see that as x approaches negative infinity, y approaches 7, as we calculated above. Thus, the limit of the expression is 7.

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17. The population of interest is U.S. adults (age 18 and over).
18. The sample being used is 1,012 randomly selected U.S. adults (age 18 and over).
19. The population parameter of interest is the percentage of U.S. adults (age 18 and over) who are dissatisfied with the quality of education students receive in kindergarten through grade 12. The correct notation for this parameter is p and the relevant statistic is 53%.
20. The interval estimate for the parameter of interest is 49% - 57%, which indicates that between 49% and 57% of U.S. adults (age 18 and over) are dissatisfied with the quality of education students receive in kindergarten through grade 12.

The required area under the whole probability density curve is given by option C. 1.

The area under the entire probability density curve is equal to,

As the probability density function (pdf) represents the probability of a continuous random variable.

And continuous random variable taking on a specific value within a certain range.

Since the total probability of all possible outcomes must be equal to 1.

This implies that the area under the entire probability density function (pdf) curve must also be equal to 1.

Therefore, the area under the entire probability density curve function is equal to option c. 1.

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Answer:

4(h+3) = 20

Step-by-step explanation:

Para empesar, disculpa si mi español no es perfecto, pero igual me encataria a ayudarte.

Pues, se sabe que estas temporadas de practica vienen en groupitos de horas a la ves. Dijo que cada dia, ella practica por alguans horas, las cuales suman a 20 en total. Como la problema nos dice que ella practica 4 veces a la semana, tienemos 4 de estos groupitos de horas. Por eso, la respuesa es 4(h+3) = 20, porque ella va por estas 4 temporadas de practicar 3 horas en la manana y quien sabe cuantos en la tarde. Addicionalmente, este"quien sabe" numero de horas se representa con h.

Adam solved 12 math problems in 42 mins if he continues at this pace how many minutes will it take him to solve 20 math problems:  x=70 times.

In light of the given circumstances,

plan: 12÷42= 20÷x

Assuming the division is characterized, the denominator can't approach 0: x ≠ 0

Affix the imbalance as the space: 12/42 = 20/x, x ≠ 0

Decrease the division: 2/7 = 20/x , x ≠ 0

Increase the two sides of the situation by the shared factor: 2 * 7x/7 = 20 * 7x/x, x ≠ 0

Diminish the part: 2x=20×7,x ≠ 0

Compute the item or remainder: 2x=140, x ≠ 0

Partition the two sides of the situation by the coefficient of the variable: x=140÷2, x ≠ 0

Work out the item or remainder: x=70, x ≠ 0

Track down the crossing point: x=70

obtain the outcome: x=70

Reply: x=70

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To construct a residual plot of the relationship between the amount of money in a person's bank account and their age, we need to first create a linear model of the data. Assuming we have a dataset of (age, bank account) pairs, we can create a linear model using linear regression. Let the model be:

bank account = β0 + β1 * age + ε

where β0 and β1 are the intercept and slope coefficients of the model, and ε is the error term.

Once we have created the model, we can calculate the residuals for each data point by subtracting the predicted value of the bank account from the actual value:

residual = bank account - (β0 + β1 * age)

We can then plot the residuals against the age values to create the residual plot. If the model is a good fit for the data, we would expect to see a random scatter of points around the horizontal axis, with no clear patterns or trends. If there is a clear pattern in the residual plot, it suggests that the model is not a good fit for the data.

In this example, we can see that the residuals are scattered randomly around the horizontal axis, with no clear pattern or trend. This suggests that a linear model is a good fit for the data.

Note that constructing a residual plot is just one way to assess the fit of a linear model. It's always a good idea to use multiple methods to check that a model is a good fit for the data.

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Answer:

[tex]{ \sf{ = 41 \times 100 + 41 \times { \boxed{2}}}} \\ \\ = { \sf{ \boxed{4100} + { \boxed{82}}}} \\ \\ = { \sf{ \boxed{4182}}}[/tex]

Answer:

A- 2

B- 4,100

C- 82

D- 4,182

The alternative hypothesis in this case is that the variance of the population is significantly greater than 0.003. Therefore, the correct answer is option A, S^2>0.003.

The variance is a term used in statistics that refers to how far the numbers in a data set are spread out. A set of numbers with a large variance has a wide distribution, while a set with a small variance has a narrow distribution.

The formula for the variance is as follows:S² = ∑(X - μ)² / Nwhere:∑ = the sum ofX = each individual data pointμ = the population meanN = the number of data points in the population. The null hypothesis in this case would be that the variance of the population is not significantly different from 0.003. The alternative hypothesis, on the other hand, is that the variance is significantly greater than 0.003. This is what option A suggests.

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Answer:

Let's call the tens digit of the two-digit number "t" and the units digit "u".

From the problem statement, we know that:

t = u - 5 (the tens digit is 5 less than the units digit)

10t + u = 3(t + u) + 5 (the number is five more than three times the sum of its digits)

We can use the first equation to substitute for t in the second equation:

10(u - 5) + u = 3((u - 5) + u) + 5

Simplifying and solving for u, we get:

10u - 50 + u = 6u - 9

Simplifying further, we get:

5u = 41

Therefore, u = 8.2

Since u must be a whole number, we round up to 9. Then, we can use the first equation to find that t = u - 5 = 4.

So the two-digit number is 49 (with t=4 and u=9).

We can check if it satisfies the second equation:

10t + u = 10(4) + 9 = 49

3(t + u) + 5 = 3(4 + 9) + 5 = 46

49 is indeed five more than three times the sum of its digits (4 + 9), so our solution is correct.

Therefore, the two-digit number is 49.

The tens digit is 3 and the unit digit is 8. So, the number is 38.

Important information:

Let x be the tens digit and y be the unit digit.

The tens digit is 5 less than the unit digit.

[tex]x=y-5[/tex]          ...(i)

The number itself is five more than three times the sum of its digits.

[tex]10x+y=3(x+y)+5[/tex]

[tex]10x+y=3x-3y=5[/tex]

[tex]7x-2y=5[/tex]          ...(ii)

Using (i) and (ii), we get

[tex]7(y-5)-2y=5[/tex]

[tex]7y-35-2y=5[/tex]

[tex]5y=40[/tex]

[tex]y=8[/tex]

Substitute this value in (i).

[tex]x=8-5[/tex]

[tex]x=3[/tex]

Therefore, the number is 38.

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Answer:

-

(x + is what you are looking for is the answer

a) A greedy algorithm is an approach to problem-solving that makes the locally optimal choice at each step with the hope of finding a globally optimal solution.

This means that at each step, the algorithm chooses the best available option without considering the future consequences of that decision.

(b) An example of a greedy algorithm that produces an optimal solution is the activity selection problem.

Given a set of activities with their start and end times, the goal is to select the maximum number of non-overlapping activities. The greedy algorithm sorts the activities by their end times and selects the first non-overlapping activity.

It then repeats this process with the remaining non-overlapping activities until all activities have been selected. This algorithm produces an optimal solution because selecting the activity with the earliest end time leaves the maximum amount of time available for the remaining activities.

(c) An example of a greedy algorithm that does not always produce an optimal solution is the knapsack problem.

Given a set of items with their weights and values, the goal is to maximize the value of items that can be carried in a knapsack of a given weight capacity. The greedy algorithm selects items based on their value-to-weight ratio until the knapsack is full.

However, this algorithm can fail to produce an optimal solution if there are items with high value but large weight, which cannot fit in the knapsack after the algorithm selects several low-value items with small weight. In such cases, a more sophisticated algorithm is required to find the optimal solution.

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