PLEASE HELP! The AHS football team did a weigh-in at the start of training camp. The weights of the players were distributed normally with a mean of 98kg and a standard deviation of 6kg. What percentage of players are under 86kg?

PLEASE HELP! The AHS Football Team Did A Weigh-in At The Start Of Training Camp. The Weights Of The Players

Answers

Answer 1
Answer:  2.5%

=============================================================

Explanation:

Notice how 98-2*6 = 98-12 = 86. So we're 2 standard deviations below the mean.

Start at the center, which is where the highest point is located. The value 98 is at the center. Then move 2 spots to the left, which has us move 2 standard deviations lower than the mean, and we arrive at 86. Refer to the diagram below.

From here, we add up the percentages in that diagram that are below the 86 mark. Those percentages are the 0.15% and 2.35%

So we get (0.15%) + (2.35%) = 2.5% which is the answer

Side note: This diagram is using the Empirical Rule. Some textbooks call it the "68-95-99.7 rule", but that's more clunky of a name in my opinion. The three values 68, 95 and 99.7 refer to the approximate percentage values within 1, 2 and 3 standard deviations of the mean.

PLEASE HELP! The AHS Football Team Did A Weigh-in At The Start Of Training Camp. The Weights Of The Players

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Step-by-step explanation:

The complete question is

In a random sample of 60 shoppers chosen from the shoppers at a large suburban mall, 36 indicated that they had been to a movie in the past

month. In an independent random sample of 50 shoppers chosen from the shoppers in a large downtown shopping area, 31 indicated that

they had been to a movie in the past month. What significance test should be used to determine whether these data provide sufficient

evidence to reject the hypothesis that the proportion of shoppers at the suburban mall who had been to a movie in the past month is the same

as the proportion of shoppers in a large downtown shopping area who had been to a movie in the past month?

A one-proportion z interval B two-proportion z interval

B two-proportion z interval

C two-sample t test D one-proportion z test

D one-proportion z test

E two-proportion z test

Solution

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