please answer these quickly i need this

Answer:

1km=1000m... thats basically the answer so the nearest mail box is 3000M

Answer:

D

Step-by-step explanation:

X must be positive as you cannot have a negative amount of people and neither X and Y could be 0. (In this case (7, 0) could have been viable but the choice says non-viable.) This means the answer is (12,3).

The ordered pair (12, 3) is viable  is correct answer.

"Ordered pair is defined as the two numbers or variables which is written in form of  pair using parenthesis."

According to the question,

Number of visitors = x

Number of winners = y

Relationship given,

Number of visitors and hole in one winners.

Negative value cannot  be part of number of visitors or winners.

Therefore,

(-3,7) is not the correct ordered pair.

'x' and 'y' value cannot be equals to zero as per the condition given.

(7,0) is non viable.

Therefore,

(0,4) and (7,0) is not the correct ordered pair.

(12,3) represent both positive value as per the condition.

Hence, the ordered pair (12, 3) is viable is correct answer.

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Answer:

Step-by-step explanation:

3 * 1/2 * 5 * 4.5

= 33.75 fT^2.

Step-by-step explanation:

the first graph

0=|x+2| f(0)=|0+2|

|x+2|=0 f(0)=|2|

x+2=0 f(0)=2

x=-2

Answer:

First graph X=-2

Answer: 1/4 .!

Step-by-step explanation: hope this helped :).

Answer:

7,854,000

because the 308 people would have to be at least 500 to round up to 7,855,000

Answer:

19

Step-by-step explanation:

Do what is in parenthesis first.

(4 - 3) = 1

(27 - 2 * 3) = (27 - 6) = 21

Now the equation looks like this:

1 - 3 (1) + (21) =

1 - 3 + 21 =

19

Answer:

99

Step-by-step explanation:

Triangles GJH and IJH are congruent, so GJ=IJ=99.

Answer:

a) 12x + 22   b) 17[tex]x^{2}[/tex] - x

Step-by-step explanation:

Perimeter is the sum of the each side length.

The first example is a rectangle so the (4x+8) and the (2x+3) are doubled.

(4x+8) x 2 = 8x+16

(2x+3) x 2 = 4x + 6

12x+22

(6[tex]x^{2}[/tex] - 12x) + (2[tex]x^{2}[/tex] + x) + (9[tex]x^{2}[/tex] + 10x)

combine like-terms.

17[tex]x^{2}[/tex] - x

Answer:

12x + 22 for the rectangle, 17x^2 - x for the triangle

Step-by-step explanation:

The perimeter of a square/rectangle is equal to 2*width + 2*length

So for the rectangle, it would be 2*(4x + 8) + 2*(2x + 3)

This can be further simplified as 8x + 16 + 4x + 6

Which can be further simplified as 12x + 22

The perimeter of a triangle is equal to length if side one + length of side two + length of base

That would be (6x^2 - 12x) + (2x^2 + x) + (9x^2 + 10x)

Which becomes 8x^2 - 11x + (9x^2 + 10x)

17x^2 - x

Answer:

Option B

Step-by-step explanation:

Given the following question:

In order to find the answer, we need to convert the scientific notation into standard notation and then simplify by subtracting the decimals. Then we convert the standard notation back into scientific notation.

[tex]0.0007 - (4.9\times 10^{-7} )[/tex]
[tex]4.9\times10^{-7} =0.00000049[/tex]
[tex]0.0007-0.00000049[/tex]
[tex]0.0007-0.00000049=0.00069951[/tex]
[tex]=0.00069951[/tex]
[tex]0.00069951=6.9951 \times10^{-7}[/tex]
[tex]=6.9951 \times10^{-7}[/tex]

Your answer is "6.9951 × 10^-7" or option B.

Hope this helps.

Answer: Yes

Step-by-step explanation:

If you draw the altitude of an isosceles triangle from the vertex angle, then the two triangles formed are congruent, meaning the base angles are congruent  by CPCTC.

Yes, the base angles of an isosceles triangle are congruent because in n isosceles triangle two of its sides are always congruent, and also angles opposite to congruent sides are congruent.

An isosceles triangle is a triangle that has at least two sides of equal length.

When an altitude is drawn to the base of the isosceles triangle, it bisects the vertex angle. As it bisects the base, the two congruent triangles are created.

Hence, Yes, the base angles of an isosceles triangle are congruent because in n isosceles triangle two of its sides are always congruent, and also angles opposite to congruent sides are congruent.

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Answer:

40/3

Step-by-step explanation: If you have a calculator type in (5 2/3)^2-(4 1/3)^2. To get 40/3. So in short, square (5 2/3)^2 to get 289/9 and square (4 1/3)^2 to get 169/9. Then subtract the two 289/9-169/9 to get 40/3.

Answer:

1. a) SR = 23

b) QV = 25

c) QT = 20

d) PQ = 40

e) VS = 4·√6

2. a) LH = 16

b) EL = 2·√185

c) JG = 30

d) EK = 22

e) KG = 30

3. a) XT = 37

b) TZ = 34

c) ZW = 17

d) XZ = 21

e) SY = 69

Step-by-step explanation:

The circumcenter ΔPQR is the center of the circle that circumscribes ΔPQR

The length of the radius of the circle ≡ VR = VP = QV = 25

a) Given that VR ≅ VP - Radius of circumcircle

VS ≅ VS Reflective property

∠VPS ≅ ∠VRS - Base angles of an isosceles triangle

Right triangle VPS ≅ Right triangle VRS -Hypotenuse and one Leg HL congruency

Therefore, SR ≅ PS -Corresponding parts of congruent triangles are congruent CPCTC

SR + PS = PR = 46

SR + PS = SR + SR = 2·SR = 46

∴ SR = 46/2 = 23

b) QV = VR = 25 = Radius of circumcircle of ΔPQR -Given V = center and Q = vertices of the triangle circumscribed by the circle referred to in the question

c) QT = √(QV² - TV²) = √(25² - 15²) = √400 = 20

d) TV ≅ TV - Reflexive property of congruency

ΔTQV ≅ ΔTVP - Hypotenuse and one Leg (HL) congruency

QT ≅ TP -Corresponding parts of congruent triangles are congruent CPCTC

PQ = QT + TP Given

∴ PQ = QT + QT since QT = TP

PQ = 2·QT = 2 × 20 = 40

e) VS = √(VR² - SR²) = √(25² - 23²) = √96 = 4·√6

2.  The incenter is the center of the incircle of ΔEFG

 a) LH = LK = JL = 16 -Radius of incircle of ΔEFG

b) EL = Hypotenuse of right triangle LHE = √(LH² + EH²) = √(16² + 22²) = √740 = 2·√185

c) JG = Leg length of right triangle JGL = √(LG² - JL²) = √(34² - 16²) = √900 = 30

d) EK = Leg length of right triangle LKE = √(EL² - LK²) = √(740 - 256) = 22

e) KG = Leg length of right triangle LKG = √(LG² - LK²) = √(34²- 16²) = √900 = 30

3. Point Z id the centroid of ΔRST

a) XT = XS - point X on ST bisected by median line RX

ST = XT + XS = XT + XT = 2.XT = 74

XT = 74/2 = 37

b) TZ = 2/3×TW  - Length from a vertex to the centroid on a median line is equal to two third the length of the median line

TZ = 2/3×51 = 34

c) TZ + ZW = TW

∴ ZW = TW - TZ = 51 - 34 = 17

d) RZ = 42 = 2/3×RX - Length from a vertex to the centroid on a median line is equal to two third the length of the median line

∴ RX = 3/2×42 = 63

RZ + XZ = RX - Given

XZ = RX - RZ = 63 - 42 = 21

e) SZ = 2/3×SY - Length from a vertex to the centroid on a median line is equal to two third the length of the median line

SZ + ZY = SY

∴ ZY = SY - SZ = SY - 2/3×SY = 1/3×SY = 23

Which gives;

SY = 3 × 23 = 69.

it is just still 5 I believe :P hope this helps

Answer:

V≈220.89cm³

Step-by-step explanation:

Answer: 220.9

4/3 π(3.75)^3=220.9

Answer:

Answer: 1.4

Step-by-step explanation:

P(Northern pike) = 0.7

P(walleye) = 0.3

If 2 fishes are caught :

Number of northern pike (x) :

X = 0

P(walleye 1 st) * p(walleye 2nd) = (0.3 * 0.3) = 0.09

X = 1

P(walleye 1st)*P(Northern pike 2nd) OR P(Northern pike 1st)*P(Walleye 2nd)

= (0.3 * 0.7) + (0.7 * 0.3)

= 0.21 + 0.21

= 0.42

P(x = 2)

P(northern pike 1st) * P(northen pike 2nd)

0.7 *0.7 = 0.49

X: _ 0 _ 1 __ 2

P(x): ___ 0.09 ___ 0.42 ____ 0.49

Expected value of northern pikes :

(0* 0.09) + (1 * 0.42) + (2 * 0.49)

0 + 0.42 + 0.98

= 1.4

Expected value of the number of walleye is 0.5.

The expected value exists as a long-run average value of random variables. It also demonstrates the probability-weighted average of all possible values. Expected value exists as a generally utilized financial concept.

W = # of walleye 0, 1, 2

P(W) 0. 49, 0. 42, 0. 09

To estimate the expected value of the number of walleye.

E(X) =  number of walleye

E(X) = (0 [tex]\times[/tex] 0.49) + (1 [tex]\times[/tex] 0.42) + (2 [tex]\times[/tex] 0.09)

E(X) = 0 + 0.42 + 0.08

E(X) = 0.5

Therefore, the number of walleye expected value = 0.5.

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Answer:

[tex]\sf 3x(3x+y)(2x-1)[/tex]

Step-by-step explanation:

Given expression:

[tex]\sf 18x^3 + 6x^2y - 9x^2 - 3xy[/tex]

Factor out common term [tex]\sf 3x[/tex]:

[tex]\sf \implies 3x(6x^2 + 2xy - 3x - y)[/tex]

Factor [tex]\sf (6x^2 + 2xy - 3x - y)[/tex]

Rearrange:

[tex]\sf \implies 6x^2 - 3x+ 2xy - y[/tex]

Factor pairs of terms:

[tex]\sf \implies 3x(2x-1)+ y(2x - 1)[/tex]

Factor out common term (2x - 1):

[tex]\sf \implies (3x+y)(2x-1)[/tex]

Final solution:

[tex]\sf \implies 3x(3x+y)(2x-1)[/tex]

Answer:

6x2y(3xy2 − 1)

Step-by-step explanation:

i got it right on my quiz :D

Answer:

9 packages of beads

Step-by-step explanation:

volume of cuboid = area of base × height

⇒ volume of jewelry box = (15 × 12) × 6

                                          = 180 × 6

                                          = 1080 in³

Given:

Number of packages of beads = volume of box ÷ volume of 1 package of beads

⇒ Number of packages of beads = 1080 ÷ 120

                                                        = 9

Considering the margin of error of a confidence interval, it is found that the correct option is:

It would be half as wide.

It is modeled by:

[tex]M = z\frac{s}{\sqrt{n}}[/tex]

In which:

From this, we get that the margin of error is inversely proportional to the square root of the sample size. Then, multiplying the sample size by 4, when it changes from 50 to 200, cuts the margin of error in half, making the interval half as wide.

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Answer: It would be half as wide

Step-by-step explanation:

If the principal had used a sample size of 200 students rather than 50 students, the length of the second interval would be half as wide compared to the original interval.

The width of a confidence interval is inversely proportional to the square root of the sample size. In this case, the sample size is multiplied by 4 (from 50 to 200), so the square root of the sample size is doubled. As a result, the width of the confidence interval is divided by 2, making it half as wide.

Therefore, the correct answer is: It would be half as wide.

The solution set -18 and 0 are the true values of the absolute value equation

The absolute value equation that has the a solution set of -18 and 0 is |x + 9| = 9

From the figure, the solution sets of the absolute value equation are given as:

x = {-18, 0}

Calculate the mean of the solution set

Mean = 0.5 * (-18 + 0)

Mean = -9

Calculate the difference of the solution set divided by 2

Difference = (0 + 18)/2

Difference = 9

The absolute value equation is the represented as:

|x - Mean| = Difference

Substitute known values

|x + 9| = 9

Hence, the absolute value equation that has the a solution set of -18 and 0 is |x + 9| = 9

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Answer:

|x+9|=9

Step-by-step explanation:

Answer:

  (c)  (15, -30)

Step-by-step explanation:

A proportional relationship has the equation ...

  y = kx

The value of the constant of proportionality is the ratio of y to x:

  k = y/x = 40/-20 = -2

__

The point that is on the line y = -2x is the point (15, -30).

Answer: [tex]12\pi[/tex]

Step-by-step explanation:

The formula for area of a circle is [tex]\pi r^2=A[/tex]

The formula for circumference of a circle is [tex]2r\pi=C[/tex]

Where r is the radius

A is area

C is circumference

Knowing this we can sub our values in and solve for r in the formula for area

Divide both sides by [tex]\pi[/tex] to isolate r

[tex]\pi r^2=A\\\pi r^2=36\pi \\\frac{\pi r^2}{\pi } =\frac{36\pi }{\pi } \\r^2=36[/tex]

Take the square root of both sides

[tex]r^2=36\\\sqrt{r^2} =\sqrt{36} \\r=6[/tex]

Now sub the value of r into the formula for circumference

[tex]2r\pi =C\\2(6)\pi =C\\12\pi[/tex]

Answer:

[tex]12\pi \: c \: m[/tex]

step by step explanation:

[tex]area \: of \: a \: cirle = \pi \: r {}^{2} \\ circmferene \: of \: a \: circle = 2 \:\pi \: r \\ 36\pi = \pi \: r {}^{2} \\ 36 = r {}^{2} \\ r = 6 \\ for \: circmference \\ 2 \times \pi \: \times 6 = 12\ \: \pi \: cm [/tex]

Wheres the ? n answers at for #3 n #4

Answer: A

Step-by-step explanation:

The three statements truly define the conditions are 1,3 and 4.

The number of individuals of a species in a certain geographic location is known as population density.

Data on population size may be used to quantify demographic information as well as to analyze links with habitats, people's health, and transportation.

The population density is given as  the ratio of population per unit area;

[tex]\rm population \ density= \frac{population}{Area}[/tex]

For the different cities the population density is found as;

For city a

[tex]\rm P_A = \frac{2,19514}{1553} \\\\ \rm P_A = 1413.98[/tex]

For city b

[tex]\rm P_B =\frac{48,592 }{26} \\\\ \rm P_B =1868.15[/tex]

For city c

[tex]\rm P_C = \frac{ 1,257,676}{999} \\\\ \rm P_C = 999[/tex]

For city d

[tex]\rm P_D = \frac{196,429}{258} \\\\ \rm P_A = 761.35[/tex]

The three statements defining the condition will be;

The population density for city b would be 48,592:26.  

The population density for city b is more than city c.

The city d contains the lowest population density

Hence the three statements true will be 1,3 and 4.

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Answer:

12 shirts

Step-by-step explanation:

   First, we need to write our equations. Let x be the number of shirts and y be the cost. We will multiply the number of shirts bought (x) by the price and then add the setup fee.

   To answer the overall question, we will graph the two equations we create. Their point of intersection is the solution, or where the number of shirts bought would cost the same.

   "One website" - 9.65 per shirt, plus a set up fee for $43

y = 9.65x + $43

   "Another company" - 8.40 per shirt plus a $58 fee

y = 8.4x + $58

   See attached for the graph.

They intersect at point (12, 158.8) meaning that both websites will charge $158.80 for 12 shirts.