Answer:
The chemical compound Mg(NO3)2, also known as magnesium nitrate, is very soluble, especially in water.
You have 0.531 L of gas in a container. What is the volume in mL?
Answer:
531 mL is the volume in mL
Answer:
Hi there!
I hope you are having an outstanding day.
I believe the answer to your question is 531!
Please adress me if I am incorrect. :)
Much love,
Pandora
Explanation:
Help me with my homework plzy
Answer:
the second answer choice i think
Explanation:
2. What is one effect of convection currents in the mantle?
A. forming deep-water currents in oceans B. cooling the rocks of the crust
C. providing energy to drive the water cycle
D. transferring heat from Earth's interior to the crust
Answer:
D no. is the answer of your question
HELP PLEASE I NEED HELP THANKS I LOVE U
How many moles of potassium nitrate (KNO3) are there in 0.300 L of a 2 molar solution?
Answer:
0.500-Molarity solution
Explanation:
The moles of the compound is given as the number of atomic mass unit in the compound. The moles of potassium nitrate in the solution are 0.6 mol
What is molarity?The molarity is the concentration unit, and it can be defined as the moles of compound present in the liter of solution.
The molarity can be expressed as:
[tex]\rm Molarity=\dfrac{Moles}{Volume(L)}[/tex]
The given potassium nitrate solution has, molarity = 2 M
The volume of the solution is 0.3 L.
Substituting the values for the moles of the compound:
[tex]\rm 2\;M=\dfrac{Moles}{0.3\;L} \\\\Moles=2\;\times\;0.3\;mol\\Moles=0.6\;mol[/tex]
The moles of potassium nitrate in 2 M solution is 0.6 mol.
Learn more about moles, here:
https://brainly.com/question/15209553
How many moles of hydrogen are in a 200. mg tablet of naproxen sodium, C14H13NaO3, the active ingredient in Aleve? Please show your work to receive full credit. MM = 252
Answer:
0.0103 mol
Explanation:
Step 1: Given data
Mass of the naproxen sodium tablet (m): 200. mgMolar mass of naproxen sodium (M): 252 g/molStep 2: Convert "m" to grams
We will use the conversion factor 1 g = 1000 mg.
200. mg × 1 g/1000 mg = 0.200 g
Step 3: Calculate the moles (n) of naproxen sodium
We will use the following expression.
n = m/M = 0.200 g / (252 g/mol) = 7.94 × 10⁻⁴ mol
Step 4: Calculate the moles of hydrogen in 7.94 × 10⁻⁴ moles of naproxen sodium
According to the chemical formula, the molar ratio of naproxen sodium to H is 1:13. The moles of H are 13/1 × 7.94 × 10⁻⁴ mol = 0.0103 mol.
I guess this is free:)))): ((((
Answer:
tysm!!!! :D <<<33333
Explanation:
What is the formula of A^4 +b^4
Answer:
A^4 +b^4
(a²)²+(b²)²
(a²+b²)²-2a²b²
or
(a²-b²)²+2a²b²
Which of these elements has the lowest ionization energy?
A. Si
B. CI
C. S
D. Na
Answer:
D . Na
Explanation:
Joan wants to test if salt lowers the temperature at which water boils. In two or more complete sentences, describe the best way for Joan to develop a hypothesis for this situation. Write your answer in the essay box below.
Answer:
Joan's hypothesis should make a prediction about the answer to the question. A hypothesis is just an educated guess on what you think the outcome will be on the experiment. The prediction must be testable and stated in if-then form. For example, a good hypothesis for Joan's experiment could be, I think that 1/2 cup of salt will make the water boil quicker, than water without salt.
Explanation:
Hope it helped!
Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many milliliters of 1.00 M sodium acetate solution would you need to add? The pKa for acetate buffer is 4.75.
Answer:
Explanation:
Molarity of NaOAc needed
Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.
pH = pKa + log [NaOAc]/[HOAc]
5.00 = 4.75 + log[NaOAc]/[1.00M]
5.00 - 4.75 = log [NaOAc] - log[1.00M]
log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78
Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.
Determine Volume of Base Needed
(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base
Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.
Checking Results:
5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00 QED.
The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.
We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:
[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex] (1)
Where:
[CH₃COOH] = 1.00 M
[CH₃COONa] =?
pH = 5.00
pKa = 4.75
From equation (1), we have:
[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]
[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]
[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]
Now, the volume of the acetate solution is:
[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]
Since the total volume is the same, we have:
[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]
[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]
Solving for Vb
[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]
Therefore, we need to add 17.8 mL of sodium acetate solution.
Find more here:
https://brainly.com/question/24188850?referrer=searchResults
I hope it helps you!
Use the balanced equation in the image below. How many moles of
ammonia (NH3) will be produced if 2.22 moles of nitrogen (N2) are used?
(Assume there is excess hydrogen gas.) SHOW YOUR WORK TO RECEIVE
CREDIT. *
N2 + 3H2 → 2 NH3
Since there is excess hydrogen, that means that the concentration of hydrogen is not limiting.
According to the balanced chemical equation:
every mole of N2 and every 3 moles of H2 we obtain 2 moles of NH3. Since we have the amount of N2 and excess of hydrogen, we only need to work with the amount of N2.
1 mol of N2 will produce 2 moles of NH3
so now we can get a conversation tool :
moles of N2 * (2 moles of NH3/ 1 mole of N2) = moles of NH3
(2.22 mol of N2 x 2) ÷ 1 = 4.44 mol of NH3
How much does the Earth weigh?
5.972 × 10^24 kg
hope it helps
Answer:
5.972 × 10^24 kg
hope this helps
What is the IUPAC name for the following compound?
CH3-CH2-CH2-CH2-CH2-CH2 -CH2-CH3
Enter the name of the molecule.
A student plans a two-step synthesis of 1-ethyl-3-nitrobenzene from benzene. The first step is nitration of benzene to give nitrobenzene, and the second step is a Friedel-Crafts alkylation using CH3CH2Cl and AlCl3. The plan is flawed because: A : When the alkyl halide interacts with AlCl3, the resulting carbocation can rearrange before it has a chance to react with the aromatic ring. B : Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation. C : The nitro group will direct the incoming alkyl group para position, rather than to the meta position. D : A blocking group is required to achieve this synthesis.
Answer:
Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Explanation:
The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.
-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.
This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Which resulted from the study of chemistry?
Answer:
I'm confused I think you're suppose to put a picture if you want someone to answer your question just saying.
Explanation:
Answer:
The understanding of the earth, air, fire, and water as the basic components of matter.
Explanation:
______ occur between molecules that have permanent intramolecular differences in elecronegativity.
A. Dipole-dipole interactions
B. Dispersion forces
C. Hydrogen bonds
Answer:
Dipole-dipole interactions
Explanation:
The equivalence point in a titration refers to the point when
A. the mł of the acid equals the mL of the base.
B. the molarity of the acid used in the reaction equals the molarity of the base used in the reaction.
C. the number of moles of one reactant reacts completely with the moles of the other reactant.
D. the acid in the flask turns clear.
Answer:
C) the number of moles of one reactant reacts completely with the moles of the other reactant.
Explanation:
it's right put it
Answer:
C
Explanation:
What unit of time is based on the revolution of Earth around the sun?
A. month
B. year
C. day
D. hour
What is N for ClO3, the
chlorate ion?
Answer:
Explanation: There is no molecule or ion as ClO3. The correct formula of chlorate ion is ClO3-. bolivianouft and 4 more users found this answer helpful.
Explanation:
2) Calculate the percent composition of each element in Mgso,
3) Calculate the percentage of each element in Ag,o.
Answer:
2)
[tex]\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%[/tex]
3)
[tex]\% Ag=93.1\%\\\\\% O=6.9\%[/tex]
Explanation:
Hello!
2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:
[tex]\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%[/tex]
3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:
[tex]\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%[/tex]
Best regards!
Five different substances added breakers of water. Each substance begins as a white, solid powder. Which substances do not dissolve in water? Salt,sugar,starch,chalk, and bakeing powder
Answer:
Chalk is does not dissolve in water
Explanation:
i had the same question as you
What is the mole ratio of iron (III) chloride (FeCl3) to zinc chloride (ZnCl2) ?
2 FeCl3 + 3 Zn → 2 Fe + 3 ZnCl2
a.2:2
b.2:3
c.3:3
d.3:2
Answer:C
Explanation:
what is the structure of methane
Answer:
CH4
Explanation:
if it is wrong, i blame my brain
What is the mole fraction of KCI in a
mixture of 0.564 g NaCl, 1.52 g KCI,
and 0.857 g LiCl?
Molar Mass
NaCl: 58.44 g/mol
KCI: 74.55 g/mol
Lici: 42.39 g/mol
Answer:
Mole fraction of KCl = 0.4056
Explanation:
We'll begin by calculating the number of mole of each compound. This can be obtained as follow:
For NaCl:
Mass NaCl = 0.564 g
Molar mass of NaCl = 58.44 g/mol
Mole of NaCl =?
Mole = mass /Molar mass
Mole of NaCl = 0.564 / 58.44
Mole of NaCl = 0.0097 mole
For KCl:
Mass KCl = 1.52 g
Molar mass of KCl = 74.55 g/mol
Mole of KCl =?
Mole = mass /Molar mass
Mole of KCl = 1.52 / 74.55
Mole of KCl = 0.0204 mole
For LiCl:
Mass LiCl = 0.857 g
Molar mass of LiCl = 42.39 g/mol
Mole of LiCl =?
Mole = mass /Molar mass
Mole of LiCl = 0.857 / 42.39
Mole of LiCl = 0.0202 mole
Next, we shall determine the total mole in the mixture. This can be obtained as follow:
Mole of NaCl = 0.0097 mole
Mole of KCl = 0.0204 mole
Mole of LiCl = 0.0202 mole
Total mole =?
Total mole = Mole of NaCl + Mole of KCl + Mole of LiCl
Total mole = 0.0097 + 0.0204 + 0.0202
Total mole = 0.0503 mole
Finally, we shall determine the mole fraction of KCl in the mixture. This can be obtained as follow:
Mole of KCl = 0.0204 mole
Total mole = 0.0503 mole
Mole fraction of KCl =?
Mole fraction of KCl = Mole of KCl /Total mole
Mole fraction of KCl = 0.0204 / 0.0503
Mole fraction of KCl = 0.4056
Answer:
.4 is correct
Explanation:
PLEASE HELP ME! I beg you :(
"A 4.75-kg cell phone is dropped from your second floor balcony (from rest). It hits the
ground at a speed of 40 m/s. Assuming air resistance can be ignored, calculate the
gravitational potential energy of the cell phone before it was dropped."
Help pls ASAP thank you!!
Answer:
Deer, Eagle, Raccoon, frog, turtle, fish, dragonfly.
Explanation:
They interact from the life cycle they eat each other...
How do the causes of surface and deep water currents differ?
A. Surface currents are caused by wind deep water currents are caused by difference in water density
B. Surface currents are caused by the Coriolis effect deep water currents are caused by differences in water density
C. Surface currents are caused by differences in water salinity deep water currents are caused by differences in water temperature
D. Surface currents are caused by differences in water density deep water currents are caused by wind
Answer:
The answer is A. Surface currents are caused by wind deep water currents are caused by difference in water density.
when comparing ethanol and acetic acid, which one has the most polar bond? and what is that bond?
Answer:
Ethanol is another alcohol, and since there are less carbons in its chain, it will be more polar. So Ethanol is the most polar bond, it has two different types of bonding between its constituent atoms. The bonds between the hydrogen and carbon atoms are nonpolar covalent bonds. The hydrogen-oxygen and carbon-oxygen bonds are polar covalent bonds.
Explanation:
All forms of energy can be traced back to