In a recent election 65% of eligible voters actually voted. A simple random sample of 1000 people is taken from the population of eligible voters. Which of the following represents the probability that less than 70% of the people sampled voted?

Answer:

[tex]{ \sf{a = { \blue{ \boxed{{53 \: \: \: \: \: \: \: \: }}}}} \: cm}[/tex]

Step-by-step explanation:

[tex] { \mathfrak{formular}}\dashrightarrow{ \rm{4 \times side \: length}}[/tex]

Each side has length of a?

[tex]{ \tt{perimeter = a + a + a + a}} \\ \dashrightarrow{ \tt{ \: 212 = 4a}} \\ \\ \dashrightarrow{ \tt{4a = 212}} \: \\ \\ \dashrightarrow{ \tt{a = \frac{212}{4} }} \: \: \\ \\ { \tt{a = 53 \: cm}}[/tex]

The required fraction of socks that Bobo the clown has used can be[tex]$\frac{\frac{1}{5}W+\frac{5}{8}B}{W+B}[/tex]

Bobo likes to wear one white sock and one black sock.

Let the number of white socks be W and the number of black socks be B. Bobo changes his socks every day. At the end of several days, he finds that he has used exactly [tex]\frac15[/tex] of his white socks.

So, the number of white socks he has used [tex]=\frac{1}{5}W[/tex]

Also, he has used [tex]\frac58[/tex] of his black socks. So, the number of black socks he has used [tex]=\frac{5}{8}B[/tex]

The total number of socks Bobo has used = number of white socks used + number of black socks used

                                                                [tex]=\frac{1}{5}W+\frac{5}{8}B[/tex]

The fraction of all of Bobo's socks he has used [tex]=\frac{\text{Total number of socks used}}{\text{Total number of socks}}[/tex]

So, we need to find the total number of socks.

Total number of white socks = W

Total number of black socks = B

The total number of socks Bobo has is = Total number of white socks + Total number of black socks [tex]= W + B[/tex]

The fraction of all of Bobo's socks he has used [tex]= \frac{\frac{1}{5}W+\frac{5}{8}B}{W+B}[/tex]

Hence, the required fraction of socks that Bobo the clown has used can be calculated as [tex]$\frac{\frac{1}{5}W+\frac{5}{8}B}{W+B}[/tex]

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Answer:

we bought 12 $3 clearance mystery books and 5 $8 regular-priced science fiction books.

Step-by-step explanation:

From the graphing utility, we get the value of the integral as, Integral = 0.7206 Comparing the values of the integrals obtained from Trapezoidal rule, Simpson's rule and graphing utility, we find that the integral value obtained from the graphing utility is closest to the Simpson's rule.

We are given the definite integral ∫31ln(x)dx and we are required to approximate the integral using the trapezoidal rule and Simpson's rule. Also, we are supposed to compare these results with the approximation of the integral using a graphing utility using n=4.Trapezoidal Rule. The trapezoidal rule for numerical integration is a method to approximate the definite integral using linear interpolation.

This rule approximates the definite integral by dividing the total area into trapezoids. The formula for trapezoidal rule is given by:(Image attached)Here, a = 3 and b = 1The value of h can be calculated as follows;h=(b−a)/nh=(3−1)/4=0.5We need to calculate the values of f(1), f(1.5), f(2), f(2.5), f(3) using n = 4(Image attached)The value of integral using the trapezoidal rule is,Integral = 0.7201.

Simpson's rule is used to approximate the value of definite integral. Simpson's rule involves approximating the integral under the curve using the parabolic shape. This is done by dividing the area under the curve into small sections and then approximating each section with a parabolic shape. The formula for Simpson's rule is given as:(Image attached)Here, a = 3 and b = 1

The value of h can be calculated as follows;h=(b−a)/nh=(3−1)/4=0.5We need to calculate the values of f(1), f(1.5), f(2), f(2.5), f(3) using n = 4(Image attached)The value of integral using the Simpson's rule is,Integral = 0.7200Comparing with Graphing UtilityIntegral = 0.7201 (from Trapezoidal rule)Integral = 0.7200 (from Simpson's rule).

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The equation has two distinct real roots if 64 - 4c > 0, one real root if 64 - 4c = 0, and no real roots if 64 - 4c < 0.

The discriminant of a quadratic equation of the form [tex]ax^2 + bx + c = 0[/tex] is given by [tex]b^2 - 4ac[/tex]. In the given quadratic equation, a = 1, b = 8, and c = c. Therefore, the discriminant is:

[tex]b^2 - 4ac[/tex]

[tex]= 8^2 - 4(1)(c)[/tex]

[tex]= 64 - 4c[/tex]

Now, we can use the discriminant to determine the nature of the solutions of the quadratic equation. If the discriminant is positive, the equation has two distinct real roots. If the discriminant is zero, the equation has one real root (a double root). If the discriminant is negative, the equation has no real roots (two complex conjugate roots).

In this case, we do not have enough information about the value of c to determine the nature of the roots of the equation. All we know is that the discriminant is 64 - 4c.

Hence, if 64 - 4c > 0, we can state that the equation has two separate real roots, one real root if 64 - 4c = 0, and no real roots if 64 - 4c < 0.

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we have to add 7775000 to make 7800000 from 25000 which is calculated by using Substraction method.

Subtraction in mathematics is the process of subtracting one integer from another. In other terms, the result of subtracting two from five is three. After addition, subtraction is usually the second process you learn in math class.Subtraction is the action or procedure of determining the difference between two quantities or figures. The phrase "taking away one number from another" is also used to describe the process of subtracting one number from another.

Distance to be covered altogether= 7800000 m
THE distance has covered= 25000 m.

We can calculate the thousands needs to be added in 25000 to make it 7800000 by using Substraction method:-

7800000-25000= 7775000m

hence, to make 7800000 from 25000 we have to add 7775000.

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Answer:

112°

Step-by-step explanation:

Finding the unknown angle in a quadrilateral:

        Sum of all angles of a quadrilateral = 360

                                      a + 49 + 72 + 127 = 360

                                                     a + 248  = 360

                                                                a = 360 - 248

                                                                a = 112°

The composite function -11-x^2 can be written in terms of the standard domain for the sine function as sin[−11−x2]. This function can be evaluated by substituting the value of x into the expression.

To do this, simply substitute the value of x into the equation:[tex]sin[-11-x^2][/tex]and evaluate the result. For example, if x=5, the equation would be sin[-11-5^2], which would evaluate to sin(-26).

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Therefore , the solution of the given problem of mean comes out to be  15 is the solution.

The sum of all values divided by all of the values constitutes the result from a collection, also referred to as the arithmetic mean. It is often referred to be known as "mean" as well as is one of the most frequency used main trend indicators. To find the answer, multiply the collection's overall amount of numbers by all of its values. Either the original data or data which has been combined into frequency charts can be used for calculations.

Here,

We can use linear interpolation between the two closest latitude numbers in the table, 45 and 50, to determine the typical temperature for a city with a latitude of 48.

Let T(45) and T(50) represent the typical temperatures at respective latitudes of 45 and 50, respectively. The following algorithm can be used to determine the temperature at 48 degrees latitude:

=> T(48) = T(45) + (T(50) - T(45)) * (48 - 45)/(50 - 45)

Using the numbers from the table as inputs, we obtain:

=> T(48) = 14 + (16 - 14) * (48 - 45)/(50 - 45)

=> T(48) = 14 + 2 * 3/5

=> T(48) = 14 + 1.2

=> T(48) = 15.2

The estimated average temperature for a city with a latitude of 48 is 15, rounded to the closest whole number.

Consequently, 15 is the solution.

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An interpretation of the IQR and median in the context of the data set include the following: D. The range of the middle 50% of the lengths of garter snakes is 4 inches.

Based on the information provided about the given box-and-whisker plot (see attachment), the five-number summary for the given data set include the following:

In Mathematics, the range of a data set can be calculated by using this mathematical expression;

Range = Highest number - Lowest number

Range = 30 - 10

Range = 20

Interquartile range (IQR) = Q₃ - Q₁

Interquartile range (IQR) = 29 - 24

Interquartile range (IQR) = 5

Middle 50% of the lengths = 20/5 = 4 inches.

In conclusion, the median is the middle of the data set and it means 50 percent of the lengths of the garter snakes are greater and 50 percent are less than 27 inches.

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Answer: 96

Step-by-step explanation:

M = 180 - 84 = 96

m<k = 96

Simplifying the algebraic expression ab + 3a² - 7a + ab + a² = a(4a + 2b - 7)

An algebraic expression is a mathematical expression in which letters are used to represent the variables.

Since we have the algebraic expression ab + 3a² - 7a + ab + a², and we want to simplify it. We proceed as follows

ab + 3a² - 7a + ab + a²

First, we collect the like terms together

ab + 3a² - 7a + ab + a² = 3a² + a²- 7a + ab + ab

Adding the similar terms together, we have

= 3a² + a²- 7a + ab + ab

= 4a²- 7a + 2ab

=  4a²- 7a + 2ab

Factorizing out a, we have that

= a(4a - 7 + 2b)

= a(4a + 2b - 7)

So, ab + 3a² - 7a + ab + a² = a(4a + 2b - 7)

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The value of x= 10.2.

This is the boundary or contour length of a 2D geometric shape.

Depending on their size, multiple shapes may have the same circumference. For example, imagine a triangle made up of wires of length L.

The same wire can be used to create a square if all sides are the same length.

The length covered by the perimeter of the shape is called the perimeter. Therefore, the units of circumference are the same as the units of length.

As we can say, the surroundings are one-dimensional. As a result, you can measure in meters, kilometers, millimeters, etc.

Inches, feet, yards, and miles are other globally recognized units of circumference measurement.

Hence, The value of x= 10.2.

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0, which is less than 0.01.

Suppose that X is a uniformly distributed random variable, scaled so that it has zero mean and unit variance. (1) What is P{|X|> ox}? (2) What is P{[X] > 30x}? (3) Is X spiky? Be sure to consider both positive and negative values of X.

For a uniformly distributed random variable with mean 0 and variance 1, P{|X|> ox} is equal to 0.5. (2) For a uniformly distributed random variable with mean 0 and variance 1, P{[X] > 30x} is equal to 0. (3) X is not spiky since P{|X| > 30x}

0.000045, which is greater than 0.01.
Suppose that Y is a Laplacian random variable with a pdf given by: fy(u) 2 e 2 -Au-hel, -  Oy}? (2) What is P{İY| > 30y}? (3) Is Y spiky? Be sure to consider both positive and negative values of Y.
Answer: (1) For a Laplacian random variable with mean 0 and variance 1, P{|Y|> oy} is equal to 0.5. (2) For a Laplacian random variable with mean 0 and variance 1, P{[Y] > 30y} is equal to 0.000045. (3) Y is spiky since P{|Y| > 30y}

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The Answer: The first step is Rearranging the Equation

v=9

v=-5

Step-by-step explanation:

STEP

1

:

Rearrange this Absolute Value Equation

Absolute value equalitiy entered

     4|-v+2|-3 = 25

Another term is moved / added to the right hand side.

     4|-v+2| = 28

STEP

2

:

Clear the Absolute Value Bars

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is 4|-v+2|

For the Negative case we'll use -4(-v+2)

For the Positive case we'll use 4(-v+2)

STEP

3

:

Solve the Negative Case

     -4(-v+2) = 28

    Multiply

     4v-8 = 28

    Rearrange and Add up

     4v = 36

    Divide both sides by 4

     v = 9

STEP

4

:

Solve the Positive Case

     4(-v+2) = 28

    Multiply

     -4v+8 = 28

    Rearrange and Add up

     -4v = 20

    Divide both sides by 4

     -v = 5

    Multiply both sides by (-1)

     v = -5

    Which is the solution for the Positive Case

STEP

5

:

Wrap up the solution

v=9

v=-5

The probability of rolling one of these five numbers is 5/37.

Suppose you roll a special 37-sided die. The probability that one of the following numbers is rolled is as follows:

35 | 25 | 33 | 9 | 19.

The total number of sides of a die is 37. As a result, there are 37 numbers in the die.

Rolling one of the 5 given numbers implies that you can select either 35 or 25 or 33 or 9 or 19.

Therefore, the probability of rolling any of these numbers is:

1 / 37 + 1 / 37 + 1 / 37 + 1 / 37 + 1 / 37 = 5 / 37

So, the probability of rolling one of these five numbers is 5/37.

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Answer:D

Step-by-step explanation:

The formula for sine is opposite/hypotenuse. This is the only formula that you can use with the given information.

False. A mean difference of zero does not necessarily indicate that the peppers are well distributed between the two groups.

Number is a mathematical object used to count, measure, and label. It is one of the most fundamental concepts in mathematics and is used to describe a wide variety of physical, logical, and abstract objects. Numbers are used to represent quantities, lengths, temperatures, money, and many other measurements. They are also used to represent abstract ideas, such as the number of days in a year or the number of colors in a rainbow.

Although the mean may be equal between the two groups, the distribution of the peppers could be skewed and not evenly distributed. For example, one group could have all large peppers and the other all small peppers and the mean would be equal. This would not be considered well distributed. To ensure the peppers are evenly distributed, one should check the standard deviation or range of the data to see if the peppers are spread across both groups.

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Answer:  A mean difference of zero indicates the peppers

are not well distributed between the two groups.

Why: Part B Answers

What do large differences of the means of each group indicate? Select the correct answer.

The peppers with different weights aren’t properly distributed between the two groups.

So they arent distributed well

The probability of getting tails in the three coins would be 0.125 or 12.5%.

To calculate the probability of an event happening, first, we need to identify the rate of the desired outcome versus the total possible outcomes. Moreover, to determine the total probability of two or more events happening we need to calculate the probability of each event and then multiply the results.

Probability of getting tails in any of the three coins:

1 / 2 = 0.5

Total probabilityy:

0.5 x 0.5 x 0.5 = 0.125 or 12.5%

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The sample size is 12 with an error calculation of 5 if 97% of the confidence interval is around a sample mean of 31. 3.

Percent confidence = 97

Sample mean =  31. 3

Standard deviation = 7. 6

Sample size = 40

Error calculation = 5

The formula for a confidence interval using the t-distribution is:

CI = x ± tα/2 * (s/√n)

CI = 31.3 ± 2.423 * (7.6/√40)

CI = 31.3 ± 3.940

CI = (27.36, 35.24)

The population mean with an error of 5,

n = (Zα/2 * σ / E)^2

Assuming a 95% confidence level, the sample size is,

n = (1.96 * 7.6 / 5)^2

n = 11.69

Therefore we can conclude that the sample size is 12 with an error calculation of 5.

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The amount that each type would be 11.87 lbs of cashews and 15.13 lbs of brazil nuts

1. First, find the total cost of 27 lbs of the mixture: 27 lbs x $6.41/lb = $171.07.
2. Next, find the cost of cashews and brazil nuts in the mixture. Cashews cost $7.70/lb and brazil nuts cost $4.80/lb.
3. Subtract the cost of the brazil nuts from the total cost of the mixture: $171.07 - (27 lbs x $4.80/lb) = $105.27.
4. Divide the cost of the cashews ($105.27) by the cost of one pound of cashews ($7.70): $105.27/$7.70 = 13.66 lbs.
5. Subtract the number of pounds of cashews (13.66) from the total pounds of the mixture (27) to find the number of pounds of brazil nuts: 27 - 13.66 = 15.13 lbs.
6. Therefore, the mixture should contain 11.87 lbs of cashews and 15.13 lbs of brazil nuts.

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In order to have an average speed of 4 mph for the entire trip, you would need to run at a speed of 7 mph for the next 0.5 hours after walking for 1.5 hours at 3 mph.

Let's begin by calculating the total distance covered during the entire trip, which is:

distance = (time walked) x (walking speed) + (time ran) x (running speed)

We know that the time walked is 1.5 hours and the walking speed is 3 mph, so the distance covered during walking is:

distance walked = (time walked) x (walking speed) = 1.5 x 3 = 4.5 miles

We also know that the average speed for the entire trip is 4 mph, and that the total time for the trip is 2 hours. Therefore, the distance covered during the entire trip is:

distance = (average speed) x (total time) = 4 x 2 = 8 miles

So the distance covered during running is:

distance ran = distance - distance walked = 8 - 4.5 = 3.5 miles

Now we can use the formula for average speed:

average speed = total distance / total time

To find the running speed, we need to solve for the running time, which is:

time ran = distance ran / running speed

Substituting this expression into the average speed formula, we get:

4 = (distance walked + distance ran) / (1.5 + time ran)

4 = (4.5 + 3.5) / (1.5 + distance ran / running speed)

Simplifying this expression, we get:

1.5 + distance ran / running speed = 2

distance ran / running speed = 0.5

Substituting the values we calculated, we get:

3.5 / running speed = 0.5

Solving for the running speed, we get:

running speed = 3.5 / 0.5 = 7 mph

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[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ \theta =42\\ r=2.8 \end{cases}\implies s=\cfrac{(42)\pi (2.8)}{180}\implies s=\cfrac{49\pi }{75}\implies s\approx 2.05 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{Perimeter of the sector} }{2.8~~ + ~~2.8~~ + ~~2.05} ~~ \approx ~~ \text{\LARGE 7.65}[/tex]

let's recall that the sector's perimeter includes the arc plust the radii.

The star Proxima Centauri is 4.2 light-years away from Earth, making it the sun's nearest rival. The word "nearest" means "nearest" in Spanish.

"A method to find a single unit value from a multiple unit value and to find a multiple unit value from a single unit value."

We always count the unit or amount value first and then calculate the more or less amount value.

For this reason, this procedure is called a unified procedure.

Many set values ​​are found by multiplying the set value by the number of sets.

A set value is obtained by dividing many set values ​​by the number of sets.

Hence, The star Proxima Centauri is 4.2 light-years away from Earth, making it the sun's nearest rival. The word "nearest" means "nearest" in Spanish.

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1. The area of the base, B, of the prism is: B = 12 ft².

2. The volume, V, of the prism is: V = 72 ft²

A prism is a transparent object with flat, polished surfaces that refract or bend light as it passes through. The most common type of prism is a triangular prism, which has two triangular faces and three rectangular faces. When light enters the prism at an angle, it is refracted or bent as it passes through the first surface of the prism.

Area of the base, B:

As given in the question, we can see that the prism is a rectangular prism. Thus, the shape of the base is rectangle.

∴ Length of the base of a rectangular prism = 4 ft

   Width of the base of a rectangular prism = 3ft

⇒ Area of the base of a rectangular prism is  = ( length of the base ) × ( Width of the base)

= ( 4 × 3 ) ft²

= 12 ft²

∴ B = 12 ft²

Volume of a prism: V = BH

Where B = Base of the prism =  12 ft²

H = Height of the prism = 6 ft²

∴ 12 × 6 = 72 ft²

Thus, V = 72 ft²

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Each pair of children gets to bat for 7.5 minutes.

To find out how much time each pair gets to bat, we need to divide the total session time by the number of pairs of children who bat.

Number of pairs of children who bat = 6 groups x 1 pair/group = 6 pairs

Total time for the session = 45 minutes

Time per pair of children who bat = Total time / Number of pairs of children who bat

= 45 minutes / 6 pairs

= 7.5 minutes per pair

Therefore, each pair of children gets to bat for 7.5 minutes.

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