The number of seconds that the dive will take if peregrine falcon dove at its maximum speed for half a mile is 9 seconds.
How to calculate the time?From the complete information, it was stated that the peregrine falcon can reach speed of up to 200 miles per hour.
Therefore, the number of seconds that the dice would take for half a mile will be calculated thus:
1 hour = 200 miles
3600 seconds = 200 miles
1 second will be: = (200/3600) = 0.056 miles
Therefore, the time will be:
200miles / 1 hour = 0.x
x = 0.0025 hours
Therefore, 0.0025 hours will be:
= 0.0025 × 3600
= 9 seconds.
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What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
Answer:
ν = E/h = 4.56x10-19 J / 6.626x10-34 Jsec-1
ν = 6.88x1014 s-1
Explanation:
The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
What is a frequency?The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.
Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,
[tex]\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma = 6.88 \times 10^{14}\ s^{-1}[/tex]
Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
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A skateboarder initially has 5 kJ of kinetic energy. As she freewheels along a flat section of path, she does 400 J of work against friction and air resistance. Calculate her final kinetic energy.
The final kinetic energy of the skateboarder after she freewheels and did work against friction on the flat section of the path is 4,600 J.
Conservation of energyThe final kinetic energy of the stakeboarder is determined by applying the principle of conservation of energy as shown below;
ΔK.E = -W
K.Ef - K.Ei = -W
where;
K.Ef is the final kinetic energyK.Ei is the initial kinetic energyW is work doneK.Ef = K.Ei - W
K.Ef = 5,000 J - 400 J
K.Ef = 4,600 J
Thus, the final kinetic energy of the skateboarder is 4,600 J.
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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0. Consider the moment when the current is 2. 50 a
For a flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω, the rate of energy being delivered is mathematically given as
P= 53 W
What rate is energy being delivered by the battery?Generally, the equation for the Battery power is mathematically given as
P = I (dt)V
Therefore
P= 2.50 A * 21.2V
P= 53 W
In conclusion, rate of energy being delivered
P= 53 W
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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0.The power developed will be 53 Watt.
What is electric power?Electric power is the product of the voltage and current. Its unit is the watt. It is the rate of the electric work done.
The given data in the problem is;
V is the voltage = 21.2 volt (V)
I is the electric current = 2.50 ampere (A)
The formula for the power is given as;
[tex]\rm P= V I \\\\\ P= 2.50 \times 21.2 \\\\ P=53 \ watt[/tex]
Hence electric power developed will be 53 Watts.
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What is the wavelength in nm of a light whose first order brightband forms a diffraction angle of 19.0°, and the diffraction grating has 600.0 lines per mm? round to the nearest whole number. nm
The wavelength of light will be 195.34 nm.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The wavelength from the diffraction grating formula is found as;
[tex]\rm m \lambda= d sin\theta \\\\ \lambda= \frac{dsin \theta }{m}\\\\ \lambda= \frac{600 \times sin 19^0 }{1} \\\\ \lambda= 195.34\ nm[/tex]
Hence the wavelength of light will be 195.34 nm.
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Answer:543nm
Explanation:
becuase
Consider the following processes: The temperature of two identical gases are increased from the same initial temperature to the same final temperature. Reversible processes are used. For gas A the process is carried out at constant volume while for gas B it is carried out at constant pressure. The change in entropy:_________.
i. is greater for B
ii. is the same for A and B
iii. is greater for A only if the initial temperature is high
iv. is greater for A
v. is greater for A only if the initial temperature is low
The entropy at constant pressure is always greater than that at constant volume and the change in entropy for the two processes is greater for gas B.
Second law of thermodynamicsAccording to the second law of thermodynamics, entropy in the isolated system always stays the same or increases.
Since gas does work in isobaric (constant pressure) change processes, the entropy at constant pressure will be greater than that at constant volume.
Thus, for gas A the process is carried out at constant volume while for gas B that is carried out at constant pressure. The change in entropy is greater for gas B.
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One billiard ball strikes another billiard ball, and they move away from each other
at a 90° angle. The momentums involved include (blank) of the velocity before and after the collision.
(A) only the direction
(C) the magnitude and direction
(B) only the magnitude
(D) the square of the magnitude
Answer:
C) The magnitude and direction
Explanation:
Velocity is a vector quantity, meaning that it has both magnitude and direction.
For the momentum, we look at both the direction of the ball (negative, positive) and the magnitude of the velocity (5 m/s, 10 m/s) when figuring out what to use for "v" in p = mv.
What type of charge is acquired when a rubber is rubbed with a fur
Answer:
The triboelectic charging process (a.k.a., charging by friction) results in a transfer of electrons between the two objects that are rubbed together. Rubber has a much greater attraction for electrons than animal fur.
Explanation:
HOPE IT HELP^_^
THANKS^_^
Electromagnets project student guide
y’all i need helppppo
Answer:
I don't know
Explanation:
you need then search here
if a solution contains 30 g of
potassium chloride (KCI) per 100 mL of water at 60°C, the
solution would be considered saturated.
true
false
A pair of opposite electric charges of equal magnitude is called a(n)
Answer:
Dipole
Explanation:
A pair of opposite electric charges of equal magnitude is called a(n)
Answer:
Dipole
Explanation:
A mass m on a frictionless plane, inclined at an angle θ with respect to the horizontal, is connected by a cord that runs parallel to the inclined plane and is wrapped around a flywheel of radius r and moment of inertia
[tex]i=\frac{3mr^{2}}{4}[/tex]
what is the acceleration of the mass down
the plane?
The acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).
Conservation of angular momentumThe acceleration of the mass down the plane is determined by applying the principle of conservation of angular momentum.
Fr = Iα
where;
F is weight of the object parallel to the planer is the radius of the flywheelI is moment of inertiaα is angular acceleration(mg sinθ)r = Iα
(mg sinθ)r = I(ar)
(mg sinθ) = I(a)
[tex]a = \frac{mg \times sin(\theta)}{I} \\\\a = \frac{mg \times sin(\theta)}{3mr^2/4} \\\\a = \frac{4mg \times sin(\theta)}{3mr^2}[/tex]
Thus, the acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).
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WILL GIVE BRAINLEST!!! What is the magnification of a virtual image if the image is 10.0 cm from a mirror and the object is 20.0 cm from the mirror?
a. -2.0
b. 0.50
c. 2.0
d. -0.50
option D
hope it helps...!!!
Answer:
B.
Explanation:
You have to divide.
10.0/20.0 = 0.50
I apologize if it is incorrect-
I hope it helps! Have a great day!
Anygays-
Explain diffraction at a single slit (light)
Answer:
At some point on say, the receiving screen, light emanating from the left side of the slit will be out of phase (a difference of 1/2 wavelengths) from light coming from the center of the slit.
Thus for every point that is left of the center of the slit, there will be a point on the right side of the slit that is out of phase,
There will be no light on the screen at that particular point and thus there will be a dark fringe there.
That is the basic explanation for the appearance of dark and bright fringes on the receiving screen.
Part B
At your sink, turn on your faucet slowly, until you have achieved a steady drip, drip, drip of lukewarm water. Make sure you can visually see and count the drips. Align the center of the bar of soap with the dripping water and set it down. Make sure the soap is in a sturdy location and does not move during the experiment. The soap represents a rock, and the dripping faucet represents precipitation.
While the soap is being weathered, calculate the number of drips that hit it in a minute. Do this by using your stopwatch to count the number of drips that occur in 10 seconds, and then multiply that number by 6 (because there are 60 seconds in a minute, 6 × 10 = 60). What is the number of drips hitting your bar of soap per minute?
The experiment was conducted in my toilet wash hand sink with a bar soap 30 centimeter away from the faucet, the number of drips record per minute is 120 drips
Control ExperimentationData
Number of Drips Recorded = 20 drips per 10 secondsIn one minute(60 seconds), the number of drips recorded will beCalculation for the number of drips per minute
= 20*6
= 120 drips
What is Control Experiment
Control experiment are carried out to minimize the effects of variables other than the independent variable
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You calibrate a set of automobile springs using a 25 kg car battery, attached to a rope that runs over a pulley, as shown in the diagram.
You find that the spring is pulled out by 0.06 meters. Compute the spring constant, k, in N/m.
Just type in the numeric part of your answer, to the nearest 0.1 N/m.
For an automobile spring using a 25 kg car battery, the spring constant is mathematically given as
K=4.08.3N/m
What is the spring constant?Question Parameter(s):
a 25 kg car battery
The springs are pulled out by 0.06 meters
Generally, the equation for the Force is mathematically given as
F=mg
Therefore
F=(25*9.8)
(25*9.8)=K(0.06)
K=4.08.3N/m
In conclusion, the spring constant
K=4.08.3N/m
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A body of mass 5kg is ejected vertically from the ground when a force of 600N acts on it for 0.1s.Calculate the velocity with which the body leaves the ground.
1200
Explanation:
F = m x (v / t)
v / t = F / m
v = (F / m) / t
v = (600 / 5) / 0.1
v = 120 / 0.1
v = 1200 m / s
Calculate the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule. Answer in units of K.
The temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 10,684.4 K.
Conservation of energyThe temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is determined by applying principle of conservation of energy as shown below;
E = K + U
E = K - GmM/R
0 = K - GmM/R
K = mgR
When the minimum escape energy is 15 times average kinetic energy;
15K = mgR
[tex]15 \times \frac{3}{2} kT = mgR[/tex]
where;
m is mass of oxygen per atom = (0.032 kg)/(6.02 x 10²³) = 5.316 x 10⁻²⁶ kg/atomg is acceleration due gravity = 9.8 m/s²R is radius of Earth = 6.371 x 10⁶ m.k is Boltzmanns’ constant = 1.38066 x 10⁻²³ J/K.[tex]T = \frac{2mgR}{15 \times 3k} \\\\T = \frac{(2)(5.316 \times 10^{-26})(9.8)(6.371 \times 10^6)}{45(1.38066 \times 10^{-23})} \\\\T = 10,684.4 \ K[/tex]
Thus, the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 10,684.4 K.
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_____ is a measure of how closely packed particles of matter are in certain amount of space
Answer:
Density
Explanation:
The more dense something is, the more packed the particles are. The equation for density is m/v.
After hearing about an accident on his normal route, mr. gujral checks for alternate routes to get to work. what type of circuit does this traffic situation model? a series circuit because there is more than one path a series circuit because there is only one path a parallel circuit because there is more than one path a parallel circuit because there is only one path
The type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.
What is a parallel circuit?A parallel circuit has branches that split the current such that just a portion of it passes through each branch.
The voltage or potential difference between each branch of a parallel circuit is the same, but the currents might differ.
A parallel circuit is having more than one path in order to reach it on time he has to take a different path.
Hence the type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.
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Answer:
C) a parallel circuit because there is more than one path
Explanation:
C) a parallel circuit because there is more than one path
A small car with mass of 0.800 kg travels at a constant speed
on the inside of a track that is a vertical circle with radius 5.00
m. If the normal force exerted by the track on the car when it
is at the bottom of the track is 25 N,
a) What is the normal force on the car when it is at the (i)
top, (ii) rightmost and (iii) leftmost point of the track?
b) What is the speed of the car as it travels around the
vertical circle?
Answer:
The equation of equilibrium at the top of the vertical circle is:
\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}
The speed experimented by the car is:
\frac{N}{m}+g=\frac{v^{2}}{R}
v = \sqrt{R\cdot (\frac{N}{m}+g) }
v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}
v\approx 9.302\,\frac{m}{s}
The equation of equilibrium at the bottom of the vertical circle is:
\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}
The normal force on the car when it is at the bottom of the track is:
N=m\cdot (\frac{v^{2}}{R}+g )
N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)
N=21.690\,N
The kinetic energy of a javelin is 81 J, and its speed is 9.0 m/s. What is its mass?
A. 0.5 kg
В. 1.0 kg
C. 2.0 kg
D 9.0 kg
help asap
Explanation:
[tex]kinetic \: energy = \frac{1}{2} m {v}^{2} [/tex]
[tex]81 = \frac{1}{2}m {(9)}^{2} [/tex]
[tex] \frac{81 \times 2}{81} = m[/tex]
[tex]m = 2kg[/tex]
What do we call objects that form like a star (from a contracting gas cloud), but do not have enough mass to ignite hydrogen fusion in their centers
A brown dwarf is a starlike body that do do not have enough mass to ignite hydrogen fusion in their centers.
What is a brown dwarf?Brown dwarf refer to a body of substellar that is not huge or big enough to undergo nuclear fusion of o hydrogen into helium in their cores. This formed when there is contraction of gases in the intercellar spaces. The have a mass between 13 to 80 times that of Jupiter.
Therefore, brown dwarf is a starlike body that do don't not have enough mass to ignite hydrogen fusion in their centers.
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Two wave pulses move toward each other along a rope. two small triangular crests moving toward each other. which diagram shows the resulting wave when they cross at point x? a straight line. a triangular crest. a rectangular crest. a triangular trough.
The triangular crest. shows the resulting wave when they cross at a point x. The meeting point of two waves is known as wave interference ia x.
What is wave pulse?A wave pulse is a short, non-periodic wave that is formed by a single energy input rather than a continuous or repeated energy input.
Wave interference is the result of multiple waves interacting. There are two types of interference: constructive and destructive.
The relative displacement of the waves is the difference between the two. Wave beats are frequently caused by wave interference.
Hence the triangular crest. shows the resulting wave when they cross at a point x.
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Answer:
B
Explanation:
Got it right on edge
(please answer) It is better to jump on a smooth, flat surface than on thick carpeting.
Question 5 options:
True
False
I believe the answer to your question would be True
A distant star gives off a visible range of light whose color depends on its temperature. Which model of light does this example support? O A. The interference model B. The particle model O C. The diffraction model OD. The wave model
The statement 'a distant star gives off a visible range of light whose color depends on its temperature' is supported by the wave model.
What is wavelength?The wavelength can be defined as the periodic distance of a given wave that repeats in a constant way.
The emissivity of particles is a function of both wavelength and temperature of a given material/object. Visible wavelengths range from 700 nm to 400 nm (violet color).
Star temperature largely determines its color, blue stars are warmer than yellow and red stars, and red stars are cooler than yellow stars.
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A 10. 0 cm object is 5. 0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and the mirror? 3. 5 cm –3. 5 cm 8. 6 cm –8. 6 cm.
The distance between the image and the mirror is -8.6 cm
What is concave mirror?A concave mirror has a reflective surface that is curved inward and away from the light source. Concave mirrors reflect light inward to one focal point.
Unlike convex mirrors, the image formed by a concave mirror shows different image types depending on the distance between the object and the mirror.
Let's use the mirror equation to solve the problem:
[tex]\dfrac{1}{f}=\dfrac{1}{d_o}+\dfrac{1}{d_i}[/tex]
where f is the focal length of the mirror, the distance of the object from the mirror, and the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for by using the numbers given in the text of the problem:
[tex]\dfrac{1}{12}=\dfrac{1}{5}+\dfrac{1}{d_i}[/tex]
[tex]\dfrac{1}{d_i}=-\dfrac{7}{60}[/tex]
[tex]d_i=-8.6\ cm[/tex]
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
Hence the distance between the image and the mirror is -8.6 cm
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A hot tungsten filament emit electromagnetic radiation within
A hot tungsten filament emit electromagnetic radiation within the bulb because the tungsten is present within the bulb.
What temperature does a tungsten filament glow at?Due to its high melting point, tungsten can be heated to 3000°C where it glows white hot providing very good brightness due to the presence of argon.
So we can conclude that a hot tungsten filament emit electromagnetic radiation within the bulb.
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Electromagnetic radiation is made up of electromagnetic field waves. A hot tungsten filament emits electromagnetic radiation in the presence of Argon.
What is electromagnetic radiation?Electromagnetic radiation is made up of electromagnetic field waves that travel through space carrying electromagnetic radiant energy. Radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays are all examples of electromagnetic waves.
When tungsten is heated to a temperature of around 3000 °C, the tungsten starts to emit lights. Tungsten when used in a bulb as a filament then because of its high melting point when electricity is passed through it, it starts to shine white-hot and provides extremely good brightness due to the presence of argon.
Hence, A hot tungsten filament emits electromagnetic radiation in the presence of Argon.
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Why do comets only have tails when they are near the sun?.
A compression spring with a spring constant of 200 N/m catches a ball that's falling with
kinetic energy of 0.5 J. How far will the spring compress to stop the ball?
Pls help It would be great if someone can show the steps too thank u
Answer:
distance of compression: 0.07071 m
Explanation:
[tex]\sf energy = \dfrac{1}{2} kx^2[/tex]
[tex]\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2[/tex]
[tex]\rightarrow \sf 0.5= (100)x^2[/tex]
[tex]\rightarrow \sf 5\ *\ 10^{-3}= x^2[/tex]
[tex]\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}[/tex]
[tex]\rightarrow \sf x =0.07071 \ m[/tex]
A 0. 5 kg mass on a 1-m-long string swings in a circle on a horizontal, frictionless table at a steady speed of 2 m/s. How much work does the tension in the string do on the mass during one revolution?
The tension does no (zero) work
F· S = W
Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.