how many positive integers are less than or equal to 200 are relatively prime to either 15 or 24 but not both

Part A. The probability pf drawing a purple card out of the hat is 28%.

Part B. The experimental probability is 2% greater than the theoretical probability.

The probability that a specific event will occur is known as probability. The ratio of favourable outcomes to all other possible outcomes serves as a stand-in for the likelihood that an event will occur.

In numerous disciplines, including mathematics, statistics, physics, economics, and computer science, uncertain events are described and understood using probability theory. It is used to analyse risks, make decisions, and forecast events.

Now in the given question,

Total cards in the hat = 12 + 17 + 14 + 7 = 50 cards

Total purple cards in the hat = 14

Probability of getting a purple card from the hat = 14/50

= 0.28

= 28%

Now similarly for the experiment,

Probability = 324/1080

= 0.3

= 30%

Therefore, the experimental probability is 30% - 28% = 2% greater than the theoretical probability.

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The equation of the bird's height above the water as a function of time can be expressed as:

H(t) = A * sin (B * t + C) + D

Where:

A is the amplitude, which is the difference between the maximum and minimum

B is angular frequency (2πf)

C is the phase shift

D is the midline

The maximum height is 112 ft and the minimum height is 14 ft, so A = 98ft.

The frequency of the cycle is 4 seconds (1 cycle every 4 seconds).

Therefore, the angular frequency is 2π/4 = π/2

The bird was at maximum height of 112 ft at t=4s, so the phase shift C = 0.

The midline is the average of the maximum and minimum, so D = (112+14)/2 = 63 ft.

Therefore, the equation of the bird's height above the water as a function of time is:

H(t) = 98 * sin (π/2 * t + 0) + 63

Hence, at the end οf year 2, the machine's bοοk value is $70,000.

Example οf Calculating Residual Value fοr a Business-Owned Vehicle. Hence, if the cοrpοratiοn sells the car after 6 years, 60% οf the οriginal cοst οf the car is depreciated οver 6 years, and the residual value is 40%. Remaining Value Befοre Tax is anοther name fοr this value.

The cοst οf an asset is evenly dispersed acrοss the asset's useful life with the straight-line technique οf depreciatiοn. Cοmpute the annual depreciatiοn cοsts and deduct it frοm the machine's οriginal cοst tο arrive at the machine's bοοk value at the end οf year twο.

Yοu can cοmpute the yearly depreciatiοn expense as fοllοws:

Cοst οf Asset - Residual Value / Useful Life = Depreciatiοn Cοsts

Inputting the values prοvided yields:

Depreciatiοn Expense = ($86,000 - $6,000) / 10 = $8,000 per year

The machine's οriginal cοst must be subtracted frοm the bοοk value at the end οf year twο in οrder tο determine the machine's value:

Bοοk Value at End οf Year 2 = Cοst οf Asset - (Depreciatiοn Expense x Number οf Years)

Bοοk Value at End οf Year 2 = $86,000 - ($8,000 x 2) = $70,000

Thus, the machine's bοοk value at the end οf year twο is $70,000.

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Answer:

Integral

Step-by-step explanation:

explain integral calculus

Answer:

It looks like there might be a typo in the expression given. Assuming that "J" and "K" are just placeholders, we can write the expression as:

f(n) = 45 * |4 - 5(n-1)|

To find the recursive formula for this sequence, we need to determine how each term relates to the previous term. We can start by looking at the first few terms of the sequence:

f(1) = 45 * |4 - 5(1-1)| = 45 * |4 - 5(0)| = 45 * |4| = 180

f(2) = 45 * |4 - 5(2-1)| = 45 * |4 - 5(1)| = 45 * |-1| = 45

f(3) = 45 * |4 - 5(3-1)| = 45 * |4 - 5(2)| = 45 * |-6| = 270

From this, we can see that the sign of the expression inside the absolute value changes with each term, alternating between positive and negative. Furthermore, the magnitude of this expression increases by 5 with each term. We can use these observations to write the recursive formula:

f(1) = 180

f(n) = f(n-1) + (-1)^(n-1) * 5 * 45 for n >= 2

This formula says that the first term in the sequence is 180, and each subsequent term is found by adding or subtracting 225 (5 * 45) from the previous term, depending on whether n is odd or even.

(please mark my answer as brainliest)

Answer:

We can solve for the unknown whole number by using the formula:

Dividend = Divisor × Quotient + Remainder

In this case, the dividend is z, the divisor is 19, the quotient is the unknown whole number, and the remainder is 16. We can substitute these values into the formula and solve for the unknown whole number:

z = 19 × Quotient + 16

To isolate the variable (Quotient), we can subtract 16 from both sides:

z - 16 = 19 × Quotient

Then, we can divide both sides by 19 to solve for Quotient:

Quotient = (z - 16) ÷ 19

Therefore, the unknown whole number is (z - 16) ÷ 19.

The value of length of side g using the  similar triangles is found as 20 ft.

In the given figures:

DC || EA

So,

∠D = ∠A

∠C = ∠E

By Angle -Angle similarity both triangles are similar.

Thus,

Taking the ratios of their side, it will be also equal.

EA / DC = EB / BC

5 / 10 = g / 10

g = 10*10 / 5

g = 100 / 5

g = 20

Thus, the value of length of side g using the  similar triangles is found as 20 ft.

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Answer: It's a 80% increase

Step-by-step explanation:

Answer:

Let's start by setting up an equation to represent the problem. Let x be the cost of the meal:

x + 0.1x = 126.50

Simplifying the left side of the equation:

1.1x = 126.50

Dividing both sides by 1.1:

x = 115

Therefore, the cost of the meal was £115.

The value of expression 40 divided by 160000 would be equal to 0.00025

When 'a' is divided by 'b', then the result we get from the division is part of 'a' that each one of 'b' items will get. Division can be interpreted as equally dividing the number that is being divided into total x parts, where x is the number of parts the given number is divided.

We need to find the expression of 40 divided by 160000

A negative divided by a negative is positive, then

40÷160000 = 0.00025

Therefore, The value of 40 divided by 160000 is; 0.00025

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The equation of the tangent line to the curve at the point (2,4) is y = (-1/2)x + 5.

To use implicit differentiation to find an equation of the tangent line to the curve at the given point (2,4), we need an implicit equation of the curve. Let's assume the curve is given by the equation:

x² + y² = 16

We can use implicit differentiation to find the slope of the tangent line at any point on this curve. Taking the derivative of both sides with respect to x, we get:

2x + 2y (dy/dx) = 0

Simplifying for (dy/dx), we get:

dy/dx = -x/y

Now we can substitute the given point (2,4) into this equation to find the slope of the tangent line at that point:

dy/dx = -2/4 = -1/2

So the slope of the tangent line at (2,4) is -1/2. We can use this slope and the point-slope form of the equation of a line to find an equation of the tangent line. The point-slope form is:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the given point. Substituting the values, we get:

y - 4 = (-1/2)(x - 2)

Simplifying, we get:

y = (-1/2)x + 5

Therefore, the equation of the tangent line to the curve at the point (2,4) is y = (-1/2)x + 5.

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Complete question:

Use implicit differentiation to find an equation of the tangent line to the curve at the given point (2,4)

Answer:

Step-by-step explanation:

x= 0.45

Answer: 0.45 L of sparkling water

Step-by-step explanation:

1.65 - 0.2 = 1.45  

1.9 - 1.45 = 0.45

0.45 L of sparkling water

Answer:

the answer is 12/13 simplified

Step-by-step explanation:

simplified

10√10 is the dimensions of a rectangle with area 1,000 m² whose perimeter is as small as possible.

a. The smaller value is 10√10 m.

b. The larger value is 10√10 m.

We have to determine the dimensions of a rectangle with area 1,000 m² whose perimeter is as small as possible.

P = 2w + 2L

1000 = Lw

P = 2w + 2(1000/w)

P = 2w + 2000/w

P-prime = 2 -2000/w²

0 = 2 - 2000/w²

Add 2000/w² on both side, we get

2000/w² = 2

Multiply by w² on both side, we get

2000 = 2w²

Divide by 2 on both side

w² = 2000/2

w² = 1000

Taking square root on both side, we get

w = 10√10

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The new estimated value of the trust funds in 2038 would be $2.5 trillion.

Funds are resources of monetary value that can be used to acquire goods, services, or to meet financial obligations. They are usually obtained through the sale of goods and services or by borrowing. Funds can come from a variety of sources, including individuals, businesses, governments, and other organizations. Funds can be used to purchase assets such as stocks, bonds, real estate, or other forms of investments.

This is because a 10% relative increase over the original estimated 7.6% rate of decline means that the actual rate of decline is 8.36% (7.6% x 1.10 = 8.36%). Applying this rate to the original starting value of $4 trillion, the value of the trust funds in 2038 would be $4 trillion x 0.9164 (which is the equivalent of 1 - 0.0836) = $2.5 trillion.

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The new estimated value of the trust funds in 2038 would be $2.4 trillion.

A trust fund is a legal arrangement in which a person or organization (the trustor) transfers assets to another person or organization (the trustee) to be managed and distributed for the benefit of a third party (the beneficiary). The trustor sets out a set of instructions (the trust deed) on how the trust funds should be handled, managed, and distributed. The trustee is legally bound to abide by these instructions, and is responsible for the management and distribution of the trust funds according to the trust deed. Trust funds can be used for a variety of purposes, such as providing for a beneficiary's education, medical care, or retirement.

This is because a 10% increase in the rate of decline would result in a rate of decline of 8.36% (7.6% plus 10% of 7.6%).
Using this new rate of decline, the value of the trust funds in 2038 would be $4 trillion multiplied by (1 - 0.0836)⁵,
which is equal to $2.4 trillion.

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The required area of the irregular quadrilateral as given in the attached diagram is equal to 37.5 square units.

In the attached diagram,

Area of each square grid is equal to 1 square units.

Area of the irregular quadrilateral

= Area of the triangle A + Area of the triangle B + Area of the triangle C + Area of the rectangle D  ___(1)

Area of triangle A = ( 1/2 ) × Base × height

                              = ( 1/2 ) × 4 × 8

                              = 16 square units

Area of triangle B = ( 1/2 ) × Base × height

                              = ( 1/2 ) × 5 × 5

                              = 12.5 square units

Area of triangle C = ( 1/2 ) × Base × height

                              = ( 1/2 ) × 3 × 4

                              = 6 square units

Area of rectangle D = length × width

                                 = 3 × 1

                                 = 3 square units

Substitute all the values in (1 ) we have,

Area of the irregular quadrilateral

= 16 + 12.5 + 6 + 3

= 37.5 square units.

Therefore, the area of irregular quadrilateral is equal to 37.5 square units.

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The above question is incomplete, the complete question is:

Each square in the grid below has area 1. Find the area of the irregular quadrilateral below.

Diagram is attached.

The position of the particle moving in the x-y plane is given by the parametric functions x(t) and y(t), where = t sin(n t'') and (3t+1). The position of the particle is (2) , 7) at time t = 3.

In mathematics, a parametric equation defines a set of quantities as a function of one or more independent variables called parameters. [1] Parametric equations are often used to represent the coordinates of points that constitute geometric objects such as curves or surfaces, called respectively parametric curves and parametric surfaces. In this case, the equations are collectively referred to as the object's parametric representation or parameter system or parametrization (or orthographic parametrization)

The velocity of the particle is zero at t = 1 second

v(x) = dx/dt

     = d/dt (3t²- 6t)

     = 6t−6.

At t = 1, v(x) = 0

v(y) =dy/dt

     = d/dt (t²−2t)

     =2t−2.

At t=1,

v(y) = 0

Hence v = [tex]\sqrt{v_x^2 + v_y^2}[/tex]  = 0

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Angle PLE is measured at 90°. The options supplied do not contain the solution.

The acute angle is defined as being less than 90 degrees. Right angles are 90 degrees in length. Angles that are obtuse have a greater angle than 90 degrees. Discover the various sorts of angles and examples of each.

As complementary angles, ZPLA and ZELA, we can infer that:

ZPLA + ZELA = 90°

Using the following expressions in place of ZPLA and ZELA, we obtain:

5x-2 + x+8 = 90

When we simplify the equation, we obtain:

6x + 6 = 90

6 is subtracted from both sides to yield:

6x = 84

Dividing by 6, we get:

x = 14

With the knowledge of x, we can determine the dimensions of ZPLA and ZELA:

ZPLA = 5x-2 = 5(14)-2 = 68°

ZELA = x+8 = 14+8 = 22°

Therefore, we can find the measure of angle PLE by subtracting the measures of ZPLA and ZELA from 180°:

PLE = 180 - ZPLA - ZELA

PLE = 180 - 68 - 22

PLE = 90

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Therefore, the expression [tex]\frac{7}{Tanb} +7Tanb[/tex] is equivalent to function. [tex]7*secb*cscb[/tex].

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It includes the study of trigonometric functions such as sine, cosine, tangent, cotangent, secant, and cosecant, as well as their properties and applications.

Trigonometry is useful in a wide range of fields, including engineering, physics, navigation, astronomy, and surveying. It is often used to solve problems involving triangles, such as determining the height of a tall object, finding the distance between two points, or calculating the trajectory of a moving object.

The origins of trigonometry can be traced back to ancient civilizations such as the Babylonians, Greeks, and Indians, who developed various methods for calculating angles and distances. Today, trigonometry is an important part of mathematics education and continues to be used extensively in many fields of study.

Given by the question.

To simplify the expression 7/tan b + 7 tan b, we need to first recall the following trigonometric identity:

tan(x) * cot(x) = 1

Using this identity, we can rewrite the expression as:

[tex]\frac{7}{Tanb} +7Tanb[/tex]

= [tex]\frac{7}{Tanb} +7Tan^{2} b*cotb\\[/tex]

=[tex]\frac{7}{Tanb} +7*(sin^{2}/cos^{2}b)*(cosb/sinb)[/tex]

= [tex]\frac{7}{Tanb} +7*(cosb/sinb)[/tex]

= [tex]7*(1/tanb+sinb/cosb[/tex]

[tex]=7*(cosb/sinb+sinb/cosb)\\=7*((cos^{2}b+sin^{2}b)/(sinb/cosb))\\ =7*(1/(sinb/cosb))\\=7*secb*cscb[/tex]

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Answer:

3/4 of a bag of dog food will last 3 days.

The derivative of S(t)= 1+e −t is  S'(t) = S(t)(1 - S(t)). So, the correct answer is (iii).

To find S'(t), we can use the chain rule:

S'(t) = (d/dt) [1 + e^(-t/2)]^-2 * d/dt [1 + e^(-t/2)]

Using the chain rule again for the second derivative:

d/dt [1 + e^(-t/2)] = (-1/2)e^(-t/2)

d/dt [1 + e^(-t/2)]^-2 = -2(1 + e^(-t/2))^-3 * (-1/2)e^(-t/2) = (1/2) e^(-t/2) / (1 + e^(-t/2))^3

Substituting into the expression for S'(t), we have:

S'(t) = [(1/2) e^(-t/2) / (1 + e^(-t/2))^3] * [1 - (1/2)e^(-t/2)]

S'(t) = (1/2) e^(-t/2) / (1 + e^(-t/2))^3 * [2 - e^(-t/2)]

S'(t) = e^(-t/2) / (1 + e^(-t/2))^3 * [2 - e^(-t/2)]

Taking the derivative of S(t), we have:

S'(t) = e^(-t/2) / (1 + e^(-t/2))^2

Comparing this to the given choices, we can see that:

S'(t) = S(t) is not true, since S(t) = 1 + e^(-t/2) and S'(t) is a different function.

S'(t) = (S(t))^2 is not true, since (S(t))^2 = (1 + e^(-t/2))^2 is a different function from S'(t).

S'(t) = S(t)(1 - S(t)) is true, since we can substitute S(t) and S'(t) from above and simplify:

S'(t) = e^(-t/2) / (1 + e^(-t/2))^3 * [2 - e^(-t/2)]

S(t)(1 - S(t)) = [1 + e^(-t/2)] * [1 - (1 + e^(-t/2))] = e^(-t/2) / (1 + e^(-t/2))

Therefore, S'(t) = S(t)(1 - S(t)) is true.

S'(t) = -S(-t) is not true, since S(-t) = 1 + e^(t/2) and -S(-t) is a different function from S'(t).

So the correct choice is (iii): S'(t) = S(t)(1 - S(t)).

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The Dcpromo wizard will guide you through e. All of the above installation scenarios

A utility in Active Directory called DCPromo (Domain Controller Promoter) installs and uninstalls Active Directory Domain Services and promotes domain controllers. Since Windows 2000, every version of Windows Server contains DCPromo, which creates forests and domains in Active Directory. It works with Windows Server and houses all network resources as a centralised security management solution.

The functionality aids in building a completely new forest structure. It allows for both the addition of a new domain tree to an existing forest and the addition of a child domain to an existing domain. Additionally, it degrades the domain controllers and ultimately deletes a domain or forest.

Complete Question:

The dcpromo wizard will guide you through which of the following installation scenarios? [check all that apply]

Creating an entirely new forest structure.

Adding a child domain to an existing domain.

Adding a new domain tree to an existing forest.

Demoting domain controllers and eventually removing a domain or forest

All of the above

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Answer:

Equation: [tex]P=10n[/tex]

[tex]P=40[/tex] when n = 4

Step-by-step explanation:

Given

Direct Variation: P ∝ n

When n = 15, P = 150

Required

Determine the equation

Her earnings if she sold 4 necklaces

P ∝ n

Convert variation to equation

[tex]P=kn[/tex]

When P = 150, n = 15 (Substitute these values in the given equation)

[tex]150=k\times15[/tex]

Divide both sides by 15

[tex]\dfrac{150}{15} =\dfrac{k\times15}{15}[/tex]

[tex]10=k[/tex]

[tex]k=10[/tex]

Substitute k = 10 in [tex]P=kn[/tex]

[tex]P=10\times n[/tex]

[tex]P=10n[/tex] ------- Equation that relates P and n

When she sold 4 necklaces, n = 4

Substitute n = 4 in the formula above

[tex]P=10\times4[/tex]

[tex]P=40[/tex]

Step-by-step explanation:

i)

A = {2, 3, 5, 7}

as "1" can only be divided by one number (instead of the usual 2 numbers for prime numbers), if it's not part of that set.

out of U = {1, 2, 3, 4, 5, 6, 7, 8}

B = {1, 3, 5}

I am not sure what you mean by "y E 7".

I don't think you mean the E7 algebraic group.

I decided you mean y <> 7 (not equal to 7).

ii)

A u B (united) = {1, 2, 3, 5, 7}

A n B (elements in common) = {3, 5}

iii)

a set with n elements has 2^n subsets and (2^n) - 1 proper subsets (all subsets minus the equal one).

our U here has 8 elements, so the number of subsets is

2⁸ = 256.

the number of relations from A to B is 2^|A×B| = 2^(|A|·|B|).

|A| = 4

|B| = 3

so the number of relations from A to B are

2^(4×3) = 2¹² = 4096

remember, for the number of possible relations we have 4×3 = 12 possible combinations of elements of A and engender of B.

each of these combinations can be in the set of relations or not, which gives us 2 options per combination.

that gives us 2¹² relations.

Answer:

(a) Find (f + g)(x)

To find (f + g)(x), we add the two functions f(x) and g(x):

(f + g)(x) = f(x) + g(x) = (4x + 9) + (9x - 5) = 13x + 4

The domain of (f + g)(x) is all real numbers, since there are no restrictions on x that would make (f + g)(x) undefined.

(b) Find (f - g)(x)

To find (f - g)(x), we subtract the function g(x) from f(x):

(f - g)(x) = f(x) - g(x) = (4x + 9) - (9x - 5) = -5x + 14

The domain of (f - g)(x) is all real numbers, since there are no restrictions on x that would make (f - g)(x) undefined.

(c) Find (f * g)(x)

To find (f * g)(x), we multiply the two functions f(x) and g(x):

(f * g)(x) = f(x) * g(x) = (4x + 9)(9x - 5) = 36x^2 + 11x - 45

The domain of (f * g)(x) is all real numbers, since there are no restrictions on x that would make (f * g)(x) undefined.

(d) Find (f / g)(x)

To find (f / g)(x), we divide the function f(x) by g(x):

(f / g)(x) = f(x) / g(x) = (4x + 9) / (9x - 5)

The domain of (f / g)(x) is all real numbers except x = 5/9, since this value would make the denominator of (f / g)(x) equal to zero, resulting in division by zero, which is undefined.

(e) Find f(g(x))

To find f(g(x)), we substitute g(x) into the expression for f(x):

f(g(x)) = 4g(x) + 9

Substituting the expression for g(x), we get:

f(g(x)) = 4(9x - 5) + 9 = 36x - 11

The domain of f(g(x)) is all real numbers, since there are no restrictions on x that would make f(g(x)) undefined.

(f) Find g(f(x))

To find g(f(x)), we substitute f(x) into the expression for g(x):

g(f(x)) = 9f(x) - 5

Substituting the expression for f(x), we get:

g(f(x)) = 9(4x + 9) - 5 = 36x + 76

The domain of g(f(x)) is all real numbers, since there are no restrictions on x that would make g(f(x)) undefined.

(g) Find f(f(x))

To find f(f(x)), we substitute f(x) into the expression for f(x):

f(f(x)) = 4f(x) + 9

Substituting the expression for f(x), we get:

f(f(x)) = 4(4x + 9) + 9 = 16x + 45

The domain of f(f(x)) is all real numbers, since there are no restrictions on x that would make f(f(x)) undefined.

(h) Find g(g(x))

To find g(g(x)), we substitute g(x) into the expression for g(x):

g(g(x)) = 9

Step-by-step explanation:

Answer:

Step-by-step explanation:

(a) Find f(g(x)).

To find f(g(x)), we first need to find g(x) and then substitute it into f(x).

g(x) = 9x - 5

f(g(x)) = f(9x - 5) = 4(9x - 5) + 9 = 36x - 11

Therefore, f(g(x)) = 36x - 11.

(b) Find g(f(x)).

To find g(f(x)), we first need to find f(x) and then substitute it into g(x).

f(x) = 4x + 9

g(f(x)) = g(4x + 9) = 9(4x + 9) - 5 = 36x + 76

Therefore, g(f(x)) = 36x + 76.

(c) Find f(f(x)).

To find f(f(x)), we need to substitute f(x) into f(x).

f(f(x)) = 4(4x + 9) + 9 = 16x + 45

Therefore, f(f(x)) = 16x + 45.

(d) Find g(g(x)).

To find g(g(x)), we need to substitute g(x) into g(x).

g(g(x)) = 9(9x - 5) - 5 = 81x - 50

Therefore, g(g(x)) = 81x - 50.

Domain of f(x) and g(x): Since both f(x) and g(x) are linear functions, their domains are all real numbers.

(e) Find the inverse of f(x).

To find the inverse of f(x), we need to switch the roles of x and f(x) and solve for f(x).

y = 4x + 9

x = 4y + 9

x - 9 = 4y

y = (x - 9) / 4

Therefore, the inverse of f(x) is f^(-1)(x) = (x - 9) / 4.

(f) Find the inverse of g(x).

To find the inverse of g(x), we need to switch the roles of x and g(x) and solve for g(x).

y = 9x - 5

x = 9y - 5

x + 5 = 9y

y = (x + 5) / 9

Therefore, the inverse of g(x) is g^(-1)(x) = (x + 5) / 9.

(g) Find the domain of f^(-1)(x).

The domain of f^(-1)(x) is the range of f(x). Since f(x) is a linear function, its range is all real numbers. Therefore, the domain of f^(-1)(x) is also all real numbers.

(h) Find the domain of g^(-1)(x).

The domain of g^(-1)(x) is the range of g(x). Since g(x) is a linear function, its range is all real numbers. Therefore, the domain of g^(-1)(x) is also all real numbers.

The constant k that makes f(x) continuous everywhere is k = 49/41.

If a function's limit at a given position exists and is the same as the function's value there, the function is said to be continuous at that location. If a function is continuous over its whole domain, then it is continuous everywhere. As the name implies, a continuous function is one whose graph is continuous throughout without any pauses or leaps. To put it another way, we say that a function is continuous if we can draw the curve (graph) of the function without ever picking up the pencil.

For f(x) to be continuous everywhere, it must be continuous at x = 7.

Using the left limit we have:

k(7)² = 49k

Using the right limit we have:

(7x + k) = 49 + k

Setting the limits equal we have:

49k = 49 + k = 8k

49k = 8k + 49

41k = 49

k = 49/41

Hence, the constant k that makes f(x) continuous everywhere is k = 49/41.

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The percent of people that own at most 4 T-Shirts costing more than $19 each is 76%.

The number of people who own at most four T-Shirts costing more than $19 is ⇒ n = N(1) + N(2) + N(3) + N(4),

where , N(i) represents the number of people who own "i" T-Shirts costing more than $19 each.

From the frequency histogram , we substitute the values and get;

⇒ n = 5 + 17 + 23 + 39

⇒ n = 84.

So, percentage of people who own at most four T-Shirts costing more than $19 each is calculated as :

⇒ (n/111) × 100% ;

⇒ (84/111) × 100% = 75.68% ≈ 76%.

Therefore, 76% of people that own at most 4 t-Shirts costing more than $19 each.

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The given question is incomplete, the complete question is

Suppose 111 people who shopped in a special t-shirt store were asked the number of t-shirts they own costing more than $19 each. The following relative frequency histogram shows the results of the survey.

The percent of people who own at most four T-Shirts costing more than $19 each is ?

The quadrilaterals which have both line and rotational symmetry of order more than 1 are square, and rhombus

Symmetry is a fundamental concept in mathematics and geometry. It refers to the property of a shape that remains unchanged when it is transformed in a certain way.

Now, let's talk about quadrilaterals that have both line and rotational symmetry of order more than 1. One example of such a quadrilateral is a square.

Another example of a quadrilateral with both line and rotational symmetry of order more than 1 is a rhombus. A rhombus is a type of quadrilateral where all four sides are equal in length, and opposite angles are equal.

In summary, a square and a rhombus are examples of quadrilaterals that have both line and rotational symmetry of order more than 1.

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Complete Question:

Name the quadrilaterals which have both line and rotational symmetry of order more than 1.

The value of Zeff for a valence electron in carbon using slater's rule is equals to 3.60.

Effective nuclear charge (Zeff) for a valence electron in carbon using Slater's rules,

Consider the shielding effect of the inner electrons.

Slater's rules state that the effective nuclear charge felt by an electron in an atom = the actual nuclear charge minus the shielding constant for that electron.

The shielding constant for an electron in a particular shell is determined by summing the contributions of all the electrons in inner shells.

Slater assigned the following shielding constants for each shell,

Electrons in the same shell contribute 0.35

Electrons in the next inner shell contribute 0.85

Electrons in all inner shells beyond that contribute 1.00

Carbon has an atomic number of 6, so it has six electrons.

The first two electrons are in the inner shell, leaving four valence electrons in the outer shell.

Zeff for a valence electron in carbon,

Consider the contributions of the inner electrons.

Two electrons in the 1s orbital contribute

2× 0.35 = 0.70 to the shielding constant.

The two electrons in the 2s orbital contribute

2 × 0.85 = 1.70 to the shielding constant.

There are no electrons in the 2p orbitals,

This implies,

They do not contribute to the shielding constant.

Thus, the effective nuclear charge felt by a valence electron in carbon is,

Zeff

= 6 - 0.70 - 1.70

= 3.60

Rounding to two decimal places, we get,

Zeff = 3.60

Therefore, the Zeff for a valence electron in carbon is equals to 3.60.

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