How can you use standard deviations to compare the spread of each data set?
Sample A: 2,5,1,2,3,3,4,3
Sample b: 10,5,1,2,3,7,4,3

Answer:

D.

Step-by-step explanation:

If She earns 80$ PER day + 8$ per phone sold and makes AT LEAST 176$ on Tuesday, You need to figure out how many phones she has sold by Tuesday.

Okay so now you need to set up your problem.

8x + 80 ≥ 176

Take away the 80, then take 80 from 176.

176 - 80 = 96

96 ÷ 8

x ≥ 12

Answer:

The scale factor is (2/3)

Step-by-step explanation:

[tex]9 \times \frac{2}{3} = 6 \\ 12 \times \frac{2}{3} = 8[/tex]

I hope that is useful for you :)

Answer: The system we need to use is:

A = T - 3

A = (2/3)*T

Solving this, we get:

In a bag, there are 9 tangerines and 6 apples.

Step-by-step explanation:

The question seems to be incomplete, by a quick online search i've found the complete question:

"A fruit stand sells bags of apples and tangerines. • Each bag has 3 fewer apples than tangerines. 2 • In each bag, the number of apples is 2/3 the number of tangerines..."

We know that:

A = number of apples in one bag

T = number of tangerines in one bag

We also know that:

"Each bag has 3 fewer apples than tangerines"

This can be written as:

A = T - 3

"In each bag, the number of apples is 2/3 the number of tangerines"

This can be written as:

A = (2/3)*T

Then we have a system of equations:

A = T - 3

A = (2/3)*T

This is the system of equations that can be used to solve for A and T, now let's solve this.

Because A means the same thing in both equations, then we can write:

A = T - 3 = A = (2/3)*T

Then:

T - 3 = (2/3)*T

We can solve this for T.

T - 3 = (2/3)*T

T - (2/3)*T = 3

(1 - 2/3)*T = 3

(1/3)*T = 3

T = 3/(1/3) = 3*3 = 9

This means that in each bag we have 9 tangerines in a bag.

Now we can use any of the two equations in the system to find the value of A.

I will use the first one:

A = T - 3

Now let's replace T by 9, then:

A = 9 - 3 = 6

A = 6

So there are 6 apples in a bag.

Answer:

The correct option is (c).

Step-by-step explanation:

The given number is -0.904.

We need to represent the number in scientific notation.

Any number can be written in scientific notation as follows :

[tex]a\times 10^b[/tex]

Where

a is a real number and b is an integer

We can write it as follows :

[tex]-0.904=-9.04\times 10^{-1}[/tex]

Hence, the correct option is (c).

Answer: hi how are you i

Answer:

30 inches wide by 40 inches long

Step-by-step explanation:

27 inches rounds up to 30 inches and 42 inches rounds down to 40 inches

Answer:

Trapezoid, E, is the correct answer.

Answer: B

Step-by-step explanation:

Answer:

15 minutes it what we call it pretty sure its 10

Step-by-step explanation:

Answer:

15min or a quarter of an hour.

Step-by-step explanation:

Answer:

There is insufficient statistical evidence at 5% significant level to conclude that Brand B machines have a lower variance in quality

Step-by-step explanation:

The given parameters are;

The number of units of the sample from Brand A, n₁ = 12 units

The standard deviation of the quality characteristic of Brand A, s₁ = 15.2

The number of units of the sample from Brand A, n₂ = 20 units

The standard deviation of the quality characteristic of Brand B, s₂ = 10.1

The null Hypothesis; H₀; s₁² = s₂²

The alternative Hypothesis; H₀;  s₂²< s₁²

The difference of two variance formula;

The F test statistic is given as follows;

[tex]F = \dfrac{S_1^2}{S_2^2}[/tex]

Where;

S₁² = The variance of sample (1) = 15.2² =  231.04

S₂² = The variance sample (2) = 10.1² = 102.01

df₁ = n₁ -1 = 12 - 1 = 11

df₂ = n₂ - 1 = 20 - 1 = 19

From the F table, we have the critical value from the F table = 2.66

[tex]F = \dfrac{S_1^2}{S_2^2} = \dfrac{231.04}{102.01} \approx 2.265[/tex]

Therefore, given that F ≈ 2.265 is not larger than the critical F for α = 0.05, we do not reject the null hypothesis, and there is sufficient statistical evidence at 5% significance level to conclude that Brand B machines have the same variance in quality as Brand A machines

Answer:

I would probably choose warlock if my computer could handle it ;w;

Answer: plate tectonics

Step-by-step explanation:Most earthquakes and volcanic eruptions do not strike randomly but occur in specific areas, such as along plate boundaries. One such area is the circum-Pacific Ring of Fire, where the Pacific Plate meets many surrounding plates. The Ring of Fire is the most seismically and volcanically active zone in the world.

Earthquakes

Answer:

y = -3× + 1

Step-by-step explanation:

rise / run = 3 / -1 = -3

y intercept = 1

therefore y = -3× + 1

Answer: See the diagram below

There are infinitely many ways to do this. So there isn't one set answer. However, all of the answers have these properties in common.

In the diagram below, I've made distribution B wider and more spread out compared to distribution A. Distribution B has a higher standard deviation. The larger the standard deviation is, the more spread out the data values will be. Standard deviation is always some positive number.

Both distributions are centered at 0, which is the mean. You could change the center to whatever you want, but make sure both distributions have this same center value.

As the diagram shows, each curve is symmetric about the center point. The left half can be reflected over the center line to get the right half, and vice versa. The curves peak at the center because this is where the majority of the data values are located. As you move to either end, the curve levels off to indicate not as many individuals are found here.

Answer:

a) The line intersects with the circle once.

b) Tangent

Step-by-step explanation:

We are given the following equation for the circle:

[tex]x^2 + y^2 = 36[/tex]

How many times does the line y=-6 intersect with the circle?

We have to find the values of x when [tex]y = -6[/tex]

So

[tex]x^2 + y^2 = 36[/tex]

[tex]x^2 + (-6)^2 = 36[/tex]

[tex]x^2 + 36 = 36[/tex]

[tex]x^2 = 0[/tex]

[tex]x = 0[/tex]

Since the line intersects the circle at one point, it is tangent to the circle.

The line intersects with the circle once.

B. 448 square meters

Step-by-step explanation:

I cut it into two rectangles

12cm by 4 cm for the first rectangle = 48cm

22cm by 8 cm for the second = 176cm

add areas together = 224cm

convert to meters = 448 square meters

hope this helps comment for more

Answer:

the third angle of the triangle is 62°

62 grad

Step-by-step explanation:

Answer:$17.16

Step-by-step explanation:

do you have to start by subtracting the cost of the belt from the total budget: 80-28.5= 51.5. Then you can divide the remaining money by three because he’s buying three ties: 51.5/3≈ $17.16

The parabola x = ay^2 opens (a) left, if a is negative

The equation of the parabola is given as:

x = ay^2

From the question, we understand that a is negative

This means that

a < 0

When a is negative, then the parabola opens to the left

Hence, the parabola opens (a) left

Read more about parabolas at:

https://brainly.com/question/1480401

Answer:

4

Step-by-step explanation:

Answer:

6 square inches

Step-by-step explanation:

4x3=12

12/2=6

Answer:

It's 12 from what I can remember on finding the area.

Step-by-step explanation:

I'm pretty sure that you add them all together and don't quote me on this but if you add 5 and 4 you get 9 then add 3 and you get 12. Hope this helped!

Answer:y=x+0

Step-by-step explanation:

Answer:

693 apples

Step-by-step explanation:

126 x 8 = 1,008

1,008 - 126 (1 bushel) = 882

1,008 - 126 (another bushel) = 756

126/2 = 63

756 - 63 (1/2 bushel) = 693

sorry, the correct answer is 693 apples left

Answer:

a. (3x² - 2x - 5) units²

b. (x² - x) units²

c. (2x² - x - 5) units²

Step-by-step explanation:

a. Area of the frame = L*W

L = (x + 1) units

W = (3x - 5) units

Area of the frame = (x + 1)(3x - 5)

Apply distributive property

x(3x - 5) +1(3x - 5)

3x² - 5x + 3x - 5

Area of the frame = (3x² - 2x - 5) units²

b. Area of the picture = L*W

L = x units

W = (x - 1) units

Area of the picture = x(x - 1)

Apply distributive property

= x² - x

Area of picture = (x² - x) units²

c. Area of the frame that surrounds the picture = area of frame - area of picture

= (3x² - 2x - 5) - (x² - x)

= 3x² - 2x - 5 - x² + x (distributive property)

Add like terms

= 3x² - x² - 2x + x - 5

= 2x² - x - 5

Area of the frame that surrounds the picture = (2x² - x - 5) units²

Answer:

H=-6t^2+38t+1

Step-by-step explanation:

Answer:

1) no solution

2) no solution

Step-by-step explanation:

7(2 + 5v) = 3v +14

14 + 35v = 3v + 14

The 14s cancel each other out.

35v ≠ 3v

no solution

36 - 7p = -7(p - 5)

36 - 7p = -7p + 35

The -7s cancel each other out.

36 ≠ 35

no solution

Answer:

Step-by-step explanation:

Yes

Answer:

it's no

Step-by-step explanation:

6 = 5(2) - 4

7 = -1/2(2) + 8

they don't meet at (2,6)

Answer:

a) 0.0498 = 4.98% probability that the number of pieces of junk mail you receive next week will be none at all.

b) 0.1680 = 16.80% probability that the number of pieces of junk mail you receive next week will be exactly four.

c) 0.4232 = 42.32% probability that the number of pieces of junk mail you receive next week will be no more than two.

d) 0.5768 = 57.68% probability that the number of pieces of junk mail you receive next week will be more than two.

Step-by-step explanation:

We have only the mean, which means that we use the Poisson distribution to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

You find that you receive on average about 3 pieces of junk mail per week.

This means that [tex]\mu = 3[/tex]

(a) none at all.

This is P(X = 0).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498[/tex]

0.0498 = 4.98% probability that the number of pieces of junk mail you receive next week will be none at all.

(b) exactly four.

This is P(X = 4).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 4) = \frac{e^{-3}*3^{4}}{(4)!} = 0.1680[/tex]

0.1680 = 16.80% probability that the number of pieces of junk mail you receive next week will be exactly four.

(c) no more than two.

This is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498[/tex]

[tex]P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494[/tex]

[tex]P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.224[/tex]

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0498 + 0.1494 + 0.224 = 0.4232[/tex]

0.4232 = 42.32% probability that the number of pieces of junk mail you receive next week will be no more than two.

(d) more than two

[tex]P(X > 2) = 1 - P(X \leq 2) = 1 - 0.4232 = 0.5768[/tex]

0.5768 = 57.68% probability that the number of pieces of junk mail you receive next week will be more than two.