Answer:
9 sides
Step-by-step explanation:
180 - 140 = 40
360 ÷ 40 = 9
You have three dice in your pocket, one is 4 -sided and two are 6-sided. You randomly select two of the dice, roll them, and record the sum. a. What's the probability the sum is 7 ? b. Given that the sum of the dice is 7 , what's the probability both dice are 6 -sided?
The probability that sum of two randomly selected dice is 7 is 1/2. The given that the sum of the dice is 7, the probability that both dice are 6-sided is 1/3.
a. Each pair has a probability of being selected of 1/3 * 1/2 = 1/6. Now sum of the probabilities of the three pairs that have a sum of 7: P = P(4-6) + P(6-4) + P(6-6) = 1/6 + 1/6 + 1/6 = 1/2
b. Given that the sum of the dice is 7, there are three possible pairs that could have been rolled: (1-6), (2-5), or (3-4). Of these, only one pair has both dice as 6-sided.
P = (1/3 * 1/2) / (1/2) = 1/3
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Please answer these questions correctly :)
Find the percent of each number :-
1.) 64% of 75 tiles :
[tex] \implies \sf \: \dfrac{64}{100} \times 75 \\ \\\implies \sf \:0.64 \times 75 \\ \\ \implies \sf \: 48 \\ [/tex]
Hence, 64% of 75 tiles is 48 tiles.
2.) 20% of 70 plants.
[tex] \implies \sf \: \dfrac{20}{100} \times 70 \\ \\\implies \sf \:0.2 \times 70 \\ \\ \implies \sf \: 14 \\ [/tex]
Hence, 20% of 70 plants is 14 plants.
3.) 32% of 25 pages .
[tex] \implies \sf \: \dfrac{32}{100} \times 25 \\ \\\implies \sf \: 0.32 \times 25 \\ \\ \implies \sf \: 8 \\ [/tex]
Hence, 32% of 25 pages is 8 pages.
4.) 85% of 40 e -mails.
[tex] \implies \sf \: \dfrac{85}{100} \times 40 \\ \\\implies \sf \:0.85 \times 40 \\ \\ \implies \sf \: 34 \\ [/tex]
Hence, 85% of 40 e -mails is 34 e-mails.
5.) 72% of 350 friends.
[tex] \implies \sf \: \dfrac{72}{100} \times 350 \\ \\\implies \sf \:0.72 \times 350 \\ \\ \implies \sf \: 252 \\ [/tex]
Hence, 72% of 350 friends is 252 friends.
6.) 5% of 220 files.
[tex] \implies \sf \: \dfrac{5}{100} \times 220 \\ \\\implies \sf \:0.05 \times 220 \\ \\ \implies \sf \: 11 \\ [/tex]
Hence, 5% of 220 files is 11 files.
In a particular class of 24 students, 16 are men. What fraction of the students in the class are women?
The fraction of the students in the class are women is one-third (1/3)
How to calculate he fraction of the students in the class are womenIf there are 16 men in the class of 24 students, we can find the number of women by subtracting the number of men from the total number of students:
Number of women = Total number of students - Number of men
Number of women = 24 - 16
Number of women = 8
Therefore, there are 8 women in the class.
To find the fraction of students in the class who are women, we divide the number of women by the total number of students:
Fraction of students who are women = Number of women / Total number of students
Fraction of students who are women = 8 / 24
Fraction of students who are women = 1/3
So, one-third (1/3) of the students in the class are women.
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A simple random sample of size n is drawn. The sample mean, x, is found to be 18.1, and the sample standard deviation, s, is found to be 4.1.
(a) Construct a 95% confidence interval about u if the sample size, n, is 34.
Lower bound: Upper bound:
(Use ascending order. Round to two decimal places as needed.)
In response to the stated question, we may state that Hence, the 95% CI function for u is (16.72, 19.48), rounded to two decimal places in increasing order.
what is function?In mathematics, a function is a connection between two sets of numbers in which each member of the first set (known as the domain) corresponds to a single element in the second set (called the range). In other words, a function takes inputs from one set and produces outputs from another. Inputs are commonly represented by the variable x, whereas outputs are represented by the variable y. A function can be described using an equation or a graph. The equation y = 2x + 1 represents a linear function in which each value of x yields a distinct value of y.v
We use the following formula to create a confidence interval around the population mean u:
CI = x ± z*(s/√n)
where x represents the sample mean, s represents the sample standard deviation, n represents the sample size, z represents the z-score associated with the desired degree of confidence, and CI represents the confidence interval.
Because the degree of confidence is 95%, we must calculate the z-score that corresponds to the standard normal distribution's middle 95%. This is roughly 1.96 and may be determined with a z-table or calculator.
CI = 18.1 ± 1.96*(4.1/√34)
CI = 18.1 ± 1.96*(0.704)
CI = 18.1 ± 1.38
Hence, the 95% CI for u is (16.72, 19.48), rounded to two decimal places in increasing order.
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A bag is filled with an equal number of red, yellow, green, blue, and purple socks. The theoretical probability of a child drawing 2 yellow socks from the bag with replacement is one fifth. If the experiment is repeated 175 times, what is a reasonable prediction of the number of times he will select 2 yellow socks?
one fifth
10
25
35
35 is a reasonable prediction of the number of times he will select 2 yellow socks?
what is probability?Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 indicates that an event is impossible, and 1 indicates that an event is certain to occur. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
What is event?In probability theory, an event is a set of outcomes or a subset of a sample space. In simpler terms, an event is anything that can happen, or any possible outcome of an experiment or observation. An event can be a single outcome, or it can consist of multiple outcomes.
In the given question,
The theoretical probability of drawing two yellow socks with replacement from a bag containing equal numbers of red, yellow, green, blue, and purple socks is:
P(drawing two yellow socks) = P(yellow) * P(yellow) = (1/5) * (1/5) = 1/25
So, the probability of drawing two yellow socks from the bag in any given trial is 1/25.
To predict the number of times the child will select two yellow socks in 175 trials, we can use the formula for the expected value of a discrete random variable:
E(X) = n * p
where E(X) is the expected number of times the event occurs, n is the number of trials, and p is the probability of the event occurring in a single trial.
In this case, n = 175 and p = 1/25. So,
E(X) = 175 * (1/25) = 7
Therefore, a reasonable prediction of the number of times the child will select two yellow socks in 175 trials is 7. Since this prediction is not one of the answer choices, the closest option is 35, which is more than five times the expected value. However, this is within the range of possible outcomes due to the random nature of the experiment.
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In a certain company, employees contribute to a welfare fund at the rate of 4% of the first $1000 earned, 3% of the next $1000, 2% of the next $1000 and 1% of any extra monies. How much will an employee who earned $20,000 contribute to the fund?
The employee will contribute 4% of the first $1000, which is $40. Then, the employee will contribute 3% of the next $1000, which is $30. Following that, the employee will contribute 2% of the next $1000, which is $20. Finally, the employee will contribute 1% of the remaining $17,000, which is $170. Therefore, the employee will contribute a total of $260 to the fund.
An employee who earned $20,000 will contribute $260 to the welfare fund.
To calculate the contribution to the welfare fund for an employee who earned $20,000, we can break down the earnings into different tiers based on the given rates.
The first $1000 will have a contribution rate of 4%.
Contribution for the first $1000 = 4% of $1000 = $40.
The next $1000 will have a contribution rate of 3%.
Contribution for the next $1000 = 3% of $1000 = $30.
The next $1000 will have a contribution rate of 2%.
Contribution for the next $1000 = 2% of $1000 = $20.
The remaining amount above $3000 ($20,000 - $3000 = $17,000) will have a contribution rate of 1%.
Contribution for the remaining amount = 1% of $17,000 = $170.
Now, let's sum up the contributions for each tier:
$40 + $30 + $20 + $170 = $260.
Therefore, an employee who earned $20,000 will contribute $260 to the welfare fund.
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We are working on a survey that shows what 100 insurance holders claim for that survey. We find that 40 are fire claims (FIRE), 16 of which are fraudulent (FRAUD). Also, there are a total of 40 fraudulent claims.
(a) Let us construct a contingency table summarizing the claims data. Use the pairs of Events FIRE and FIRE, FRAUD and FRAUD as shown below:
The probability of a claim being both fire and fraudulent is:
P(Fire and Fraud) = number of claims that are both fire and fraudulent/total number of claims
= 16 / 100
= 0.16
We can use the information given to construct a contingency table as follows:
Fraud No Fraud Total
Fire 16 24 40
No Fire 24 36 60
Total 40 60 100
This table shows the number of insurance claims that fall under each combination of the FIRE and FRAUD events. For example, 16 claims are both fire and fraudulent, and 24 claims are fire but not fraudulent.
We can also calculate some probabilities from this table. For example, the probability of a claim being fraudulent is:
P(Fraud) = number of fraudulent claims / total number of claims
= 40 / 100
= 0.4
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Question:-We are working on a survey that shows what 100 insurance holders claim for that survey. We find that 40 are fire claims (FIRE), 16 of which are fraudulent (FRAUD). Also, there are a total of 40 fraudulent claims.
(a) Let us construct a contingency table summarizing the claims data. Use the pairs of
Events FIRE and, FRAUD and as shown below:
Fraud No Fraud Total
Fire 16 24 40
No Fire 24 36 60
Total 40 60 100
A mail-order company business has six telephone lines. Let X denote the number of lines in use at a specified time. Suppose the pmf of X is as given in the accompanying table.
x 0 1 2 3 4 5 6
p(x) 0.10 0.15 0.20 0.25 0.20 0.05 0.05
Calculate the probability of each of the following events.
(a) {at most three lines are in use}
(b) {fewer than three lines are in use}
(c) {at least three lines are in use}
(d) {between two and five lines, inclusive, are in use}
(e) {between two and four lines, inclusive, are not in use}
(f) {at least four lines are not in use}
The probability of each of the events of {at most three lines are in use}, {fewer than three lines are in use}, {at least three lines are in use, {between two and five lines, inclusive, are in use}, {between two and four lines, inclusive, are not in use} and {at least four lines are not in use} are 0.70, 0.45, 0.55, 0.80, 0.35 and 0.40 respectively.
The problem involves finding probabilities of different events for a mail-order company with six telephone lines. The probability mass function (pmf) is given, and we use it to calculate the probabilities of different events such as "at most three lines are in use" or "between two and five lines, inclusive, are in use".
To calculate these probabilities, we use basic probability formulas such as the addition rule, subtraction rule, and the complement rule.
P(X ≤ 3) = 0.10 + 0.15 + 0.20 + 0.25 = 0.70
P(X < 3) = 0.10 + 0.15 + 0.20 = 0.45
P(X ≥ 3) = 1 - P(X < 3) = 1 - (0.10 + 0.15 + 0.20) = 0.55
P(2 ≤ X ≤ 5) = P(X ≤ 5) - P(X < 2) = (0.10 + 0.15 + 0.20 + 0.25 + 0.20) - 0.10 = 0.80
P(2 ≤ X ≤ 4) = 0.20 + 0.25 + 0.20 = 0.65, so P(2 ≤ X ≤ 4)ᶜ = 1 - 0.65 = 0.35
P(X ≥ 4) = 0.20 + 0.05 + 0.05 = 0.30, so P(X ≤ 3) = 1 - P(X ≥ 4) = 0.70 - 0.30 = 0.40
These formulas are applied based on the given events to determine the probabilities.
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Convert 555 into base five numberal system
The decimal number 555 is written as 4210 in base-5.
Answer: [tex]555_{10} =4210_{5}[/tex]
Step-by-step explanation:
Decimal to base five conversion
we divide the decimal number by 5 repeatedly until the quotient becomes 0here
We apply the rule to convert 555 into base five numeral.Divide the number 555 repeatedly by 5 until quotient becomes zero.D Q Remainders
5 |555 0
5 |111 1
5 |22 2
5 |4 4
0
here , Divisor = 5 , Quotient = [555,111,22,4,0] , Remainders = [4210]a string composed of positive integers, in which every prefix contains at least as many positive integers i as integers i 1.
Lattice permutation is a string composed of positive integers, in which every prefix contains at least as many positive integers i as integers i + 1.
In mathematics, a lattice permutation group is a type of permutation group, also known as a Coxeter group, which acts on a set of vectors in a lattice.
A lattice permutation group is a special type of finite group that can be used to generate symmetries in a lattice structure. They are related to Coxeter groups, which are groups that act on a set of points in a Euclidean space, and are generated by reflections.
Lattice permutation groups are generated by permutations of the lattice points, and can be used to study the symmetry of a lattice. These groups are important in the study of crystallography, and can be used to classify the symmetry of a lattice.
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The complete question is:
______ is a string composed of positive integers, in which every prefix contains at least as many positive integers i as integers i + 1.
Determine whether or not the given procedure results in a binomial distribution. If not, identify which condition is not met. Rolling a six-sided die 80 times and recording the number of l's rolled, Answer Tables Yes AN No There are more than two possible outcomes on each trial of the experiment. The experiment does not consist of n identical trials. The trials are dependent
Rolling a six-sided die 80 times and recording the number of l's rolled and it is a Binomial Distribution.
The binomial distribution is a probability distribution used in statistics that summarizes the probability that a value will take on one of two independent values given a set of parameters or assumptions. The binomial distribution is calculated by multiplying the probability of success by the power of the number of successes and by multiplying the probability of failure by the power of the difference between the number of successes and the number of trials. The product is then multiplied by the combination of trials and successes.
For example, suppose a casino develops a new game where participants bet on the number of heads or tails in a specified number of coin tosses. Suppose a contestant wants to bet $10 that 20 coin tosses will result in exactly 6 heads. The participants wanted to calculate the probability of this happening, so they used calculations from the binomial distribution.
The probability is calculated as :
(20! / (6! × (20 - 6)!)) × (0.50)⁶ × (1 - 0.50)⁽²⁰⁻⁶⁾. Therefore, the probability of getting exactly 6 heads out of 20 coin tosses is 0.037, or 3.7%.
In this case, the expected value is 10 heads, so the contestant made a bad bet.
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A sample of 245 high school students from grades 9-10 and 11-12 were asked to choose the kind of band to have play at a school dance
Let's break down this question. How many students were in each grade? In grades 9-10, there were 122 students, and in grades 11-12, there were 123 students. What kind of bands were the students asked to choose from? Were they given a list of bands to choose from, or were they simply asked to suggest a band they would like to see?
The retail price of a television set is $4,500. If the buyer pays by cash, the price is 10% below the retail price. If the set is bought on higher purchase, the buyer pays a down payment of $675 and 24 monthly installments of $212.50. Calculate for the television the:
cash price to the buyer, if he pays by cash.
amount payable.
outstanding balance.
hire purchase price.
interest.
difference between the hire purchase and the cash price.
percentage interest charged.
Cash price to the buyer, if he pays by cash:
The cash price would be 10% less than the retail price of $4,500:
Cash price = $4,500 - (10% * $4,500)
Cash price = $4,500 - $450
Cash price = $4,050
Amount payable:
If the buyer chooses to purchase the TV on higher purchase, the amount payable would be the sum of the down payment and the total amount of monthly installments:
Amount payable = Down payment + (24 * Monthly installment)
Amount payable = $675 + (24 * $212.50)
Amount payable = $5,175
Outstanding balance:
The outstanding balance would be the difference between the amount payable and the down payment:
Outstanding balance = Amount payable - Down payment
Outstanding balance = $5,175 - $675
Outstanding balance = $4,500
Hire purchase price:
The hire purchase price would be the sum of the down payment and the outstanding balance:
Hire purchase price = Down payment + Outstanding balance
Hire purchase price = $675 + $4,500
Hire purchase price = $5,175
Interest:
The interest charged on the hire purchase would be the difference between the hire purchase price and the cash price:
Interest = Hire purchase price - Cash price
Interest = $5,175 - $4,050
Interest = $1,125
Difference between the hire purchase and the cash price:
The difference between the hire purchase price and the cash price would be the interest charged:
Difference = Interest
Difference = $1,125
Percentage interest charged:
To calculate the percentage interest charged, we can divide the interest by the hire purchase price and multiply by 100:
Percentage interest charged = (Interest / Hire purchase price) * 100
Percentage interest charged = ($1,125 / $5,175) * 100
Percentage interest charged = 21.74%
Therefore, the cash price to the buyer is $4,050, the amount payable is $5,175, the outstanding balance is $4,500, the hire purchase price is $5,175, the interest charged is $1,125, the difference between the hire purchase and the cash price is $1,125, and the percentage interest charged is 21.74%.
solve the equation
x/2-2=4+1/2
Step-by-step explanation:
7eh8heusvush0wio0w92726 2is 3the world ydgugd8jd8djkd0jd9jd8hd7hd
Please refer to the photo for question
The equation of the line in slope-intercept form is y = 2.5x + 210.
What is slope intercept form?y = mx + b, where m is the line's slope and b is its y-intercept, is the equation of a line in slope-intercept form. This version of the equation is advantageous since it makes it simple to determine a line's slope and y-intercept and to utilise its equation to graph the line.
We may first apply the formula for the slope to get the slope of the line in order to calculate the equation of a line given two points. Next, we solve for the y-intercept using the slope-intercept version of the problem, substituting the slope and one of the supplied locations.
The given coordinates of the line are (46, 325) and (64, 370).
The slope is given by:
m = (y2 - y1) / (x2 - x1)
Substituting the values we have:
m = (370 - 325) / (64 - 46)
m = 45 / 18
m = 2.5
The slope intercept form of the line is given as:
y = mx + b
here, b is the y-intercept.
325 = 2.5(46) + b
b = 325 - 115
b = 210
Hence, the equation of the line in slope-intercept form is y = 2.5x + 210.
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The graph of triangle has coordinates E(1,4) F(-1,1) and G(2,-1). Graph triangle of EFG and it’s image after a translation of 3 units left and 1 unit down.
Answer:
Step-by-step explanation:1.4 -1, 1 2, -1
ASNSWER QUICKLY!! FIRST ANSWER GETS BRAINLIEST!!
What is the length of arc HI?
picture below
convert 49% to a fraction
Answer:
To convert 49% to a fraction, we can simply write it as 49/100. This is because a percentage is a way of expressing a number as a fraction of 100. So 49% means 49 out of 100, which can be written as the fraction 49/100.
Answer:
49/100
Step-by-step explanation:
Percent means out of 100.
49%
49/100
polygon trig is a quadrilateral. which of the following pieces of information would prove that trig is a parallelogram?
The pieces of information would prove that the polygon trig is a parallelogram is GI || TR (option b).
Now, suppose you have a quadrilateral named TRIG. The question asks which of the given information would prove that TRIG is a parallelogram. Let's examine each option to determine which one satisfies the conditions of a parallelogram.
a) GT || IR: This option tells us that GT is parallel to IR. However, we cannot conclude that TRIG is a parallelogram from this information alone.
b) GI || TR: This option states that GI is parallel to TR. Again, we cannot immediately conclude that TRIG is a parallelogram from this information.
c) GO ≅ OR, TO ≅ OI: This option tells us that GO is congruent to OR and TO is congruent to OI. However, this information alone does not prove that TRIG is a parallelogram.
d) GR ≅ TI: This option states that GR is congruent to TI. Similarly, we cannot conclude that TRIG is a parallelogram from this information.
e) GO ⊥ OI: This option tells us that GO is perpendicular to OI. Unfortunately, this information alone does not prove that TRIG is a parallelogram either.
f) GT ≅ TR: This option states that GT is congruent to TR. However, this information alone does not prove that TRIG is a parallelogram.
The answer is option (b) GI || TR. If GI is parallel to TR, then by definition, TRIG has opposite sides parallel, which means it is a parallelogram.
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Complete Question:
Polygon TRIG is a quadrilateral.
Which of the following pieces of information would prove that TRIG is a parallelogram?
a) GT || IR
b) GI || TR
c) GO ≅ OR, TO ≅ OI
d) GR ≅ TI
e) GO ⊥ OI
f) GT ≅ TR
[tex]y = ( \sqrt{47 + \sqrt{9 - \sqrt{25} } } )[/tex]
find the value of y ~
The simplification of the given expression
[tex]y = ( \sqrt{47 + \sqrt{9 - \sqrt{25)} } } [/tex]
is y = 7
How to simplify expressions?[tex]y = ( \sqrt{47 + \sqrt{9 - \sqrt{25)} } } [/tex]
find the square root of 25
[tex]y =( \sqrt{47 + \sqrt{9 - 5} } [/tex]
simplify root 9 - 5
[tex]y = ( \sqrt{47 + \sqrt{4} } [/tex]
find the square root of 4
[tex]y = ( \sqrt{47 + 2)} [/tex]
Add root 47 and 2
[tex]y = ( \sqrt{49} )[/tex]
Find the square root of 49
y = 7
Therefore, the solution to the given expression is y = 7
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I will mark you brainiest!
What is the measure of angle R?
A) 17 degrees
B) 25 degrees
C) 34 degrees
D) 65 degrees
Answer: D) Angle R is 65 degrees
Step-by-step explanation:
In the given figure, we have a right-angled triangle PQR.
Using the property of angles in a triangle, we know that the sum of angles in a triangle is 180 degrees. Therefore,
∠QRP + ∠QPR + ∠PRQ = 180 degrees
Since ∠PRQ is a right angle (90 degrees), we have:
∠QRP + ∠QPR = 90 degrees
Now, we are given that ∠QPR is 25 degrees. Substituting this in the above equation, we get:
∠QRP + 25 = 90 degrees
Solving for ∠QRP, we get:
∠QRP = 90 - 25 = 65 degrees
Therefore, the measure of angle R is 65 degrees, which is option (D).
Answer:
Answer is D
Step-by-step explanation:
SPiDerMom is so hot bTw
Venell put together a model train with 25 train cars. Each train car is 80 millimeters long. How many meters long is Venell's model train if there are no gaps between cars? (1 meter = 1,000 millimeters)
Answer: 2 meters
Step-by-step explanation:
The length of one train car is 80 millimeters. Therefore, the length of the entire train is:
25 cars × 80 mm per car = 2000 mm
To convert millimeters to meters, we need to divide by 1000:
2000 mm ÷ 1000 = 2 meters
Therefore, Venell's model train is 2 meters long.
What does the point (5, 10) represent on the
graph?
Answer:
It means the point x = 5 and y = 10
Answer: The place 5 units right and 10 units up from the center of the graph (the origin).
Step-by-step explanation:
Starting at the origin, the 5 represents moving right 5, and the 10 represents going up 5.
Which expression is equivalent to 14m2n2/ 7mn? Assume that the denominator does not equal to zero.
A. 7/mn
B.2mn/7
C.7mn
D.2mn
Answer: D: 2mn
Step-by-step explanation:
To simplify the expression 14m^2n^2 / 7mn, we can cancel out the common factors in the numerator and denominator.
We can cancel out 7 in both the numerator and denominator to get:
14m^2n^2 / 7mn = 2m * n / 1 = 2mn
Therefore, the expression 14m^2n^2 / 7mn is equivalent to 2mn. The answer is option D.
Help quick! Timed
Let f(x) = ex and g(x)=x-3. What are the domain and range of (fog)(x)?
domain: x > 0
range: y < 0
O domain: x>3
range: y > 0
O domain: all real numbers
range: y < 0
domain: all real numbers
range: y > 0
Answer:
To find the domain and range of (fog)(x), we need to first find (fog)(x):
(fog)(x) = f(g(x)) = f(x-3) = e^(x-3)
The domain of (fog)(x) is all real numbers because there are no restrictions on the input x that would make e^(x-3) undefined.
To find the range of (fog)(x), we need to determine the possible outputs of e^(x-3). Since e^x is always positive, e^(x-3) is positive for all x. Therefore, the range of (fog)(x) is y > 0.
So, the answer is: D. domain: all real numbers | range: y > 0
find the point(s) on the surface which are closest to the point . list points as a comma-separated list, (e.g., (1,1,-1), (2, 0, -1), (2,0, 3)).
The points on the surface z² = xy+ 1 which are closest to the point
(7, 11, 0) is x = 2 and y = 10.
The distance of any point on the surface from the point (7, 11, 0) is
D(x, y) = { [ x -7]2 + [ y -11 ]2 + [ z -0 ]2 } 1/2
D(x, y) = { [ x -7]2 + [ y -11 ]2 + z 2 } 1/2
D(x, y) = { [ x -7]2 + [ y -11 ]2 + z 2 } 1/2
D(x, y) = { [ x -7]2 + [ y -11 ]2 + x y +1 } 1/2
Now,
To minimize D suffices to minimize
d (x ,y ) = [ x -7]2 + [ y -11 ]2 + x y +1
∂ d / ∂ x =2 x + y - 14
∂ d / d y = 2 y +x - 22
Solving the system:
2x + y - 14 = 0 and 2y +x - 22 = 0 we get for
x = 2 and for y = 10
The Hessian being 3 > 0 and d²x and d²y positive makes sure that the points ( 2 , 10, √21 ) and ( 2 , 10, -√21 ) are the points of interest
Complete Question:
Find the point(s) on the surface z2=xy+1 which are closest to the point
(7, 11, 0). List points as a comma-separated list, (e.g., (1,1,-1), (2, 0, -1),
(2,0, 3)).
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A carpenter has a box of nails of various
different lengths. You decide to practice your
weighted averaging skills to figure out the
average length of a nail in the box. You grab
two handfuls of nails and count out the
number of each type of nail. You record your
data in the table below.
Sample
Type
Short nail
Medium nail
Long nail
Number Abundance
of Nails
(%)
67
18
10
[?]
Nail Length
(cm)
2.5
5.0
7.5
What is the percent abundance of the
medium nails in your sample?
The percent abundance of medium nails in the sample is approximately 18.95%.
What is weighted averaging?An average value for a collection of data is calculated statistically via weighted averaging, where each data point is assigned a weight based on its relative relevance or frequency. This method is frequently applied when certain data points are more important than others or when the sample sizes for several sets of data vary. Each data point is multiplied by its weight in weighted averaging, and the resulting products are added up and divided by the overall weight.
The number of each type of nail is:
Abundance = 67 + 18 + 10 = 95
The weighted average is:
Weighted Average = (Abundance1 x Value1 + Abundance2 x Value2 + ... + AbundanceN x ValueN) / Total Abundance
For different types of nails we have:
Short nail: Abundance1 = 67, Value1 = 2.5
Medium nail: Abundance2 = 18, Value2 = 5.0
Long nail: Abundance3 = 10, Value3 = 7.5
Substituting the values:
Weighted Average = (67 x 2.5 + 18 x 5.0 + 10 x 7.5) / 95
Weighted Average ≈ 3.53
The percent abundance is:
Percent Abundance = (Abundance2 / Total Abundance) x 100%
Substituting the values:
Percent Abundance = (18 / 95) x 100%
Percent Abundance ≈ 18.95%
Hence, the percent abundance of medium nails in the sample is approximately 18.95%.
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please identify from the following choices which has the shape of the resultant matrix of multiplication of a 2 by 4 and 4 by 3 matrices.
The shape of the resultant matrix of the multiplication of a "2 by 4" matrix and a "4 by 3" matrix will be a "2 by 3" matrix, the correct option is (d).
We know that the general rule for matrix multiplication, which is If matrix A is "m by n" matrix (it has m rows and n columns) and the matrix B is "n by k" matrix (it has n rows and k columns),
Then the product AB is an "m by k" matrix, which means, that the resulting matrix will have "m" rows and "k" columns.
In this case, the "2 by 4" matrix means that matrix has 2-rows and 4-columns, and
The "4 by 3" matrix means the matrix has 4-rows and 3-columns.
Since the number of columns in the first matrix (4) matches the number of rows in the second matrix (4), we can perform the multiplication.
The resulting matrix will have 2 rows and 3 columns,
Therefore, the shape of the resultant matrix is (d) 2 by 3.
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The given question is incomplete, the complete question is
Please identify from the following choices which has the shape of the resultant matrix of multiplication of a "2 by 4" and "4 by 3" matrices.
(a) 3 by 2
(b) 2 by 4
(c) 4 by 4
(d) 2 by 3
5. Which of the graphs below illustrates water boiling in Denver, Colorado?
Your question is incomplete. The complete question is: Which of the graphs below illustrates water boiling in Denver, Colorado? (Altitude 1,600 meters.)
Answer:
The graphs that come with this question are in the picture attached.The answer is graph identified with the letter A.Explanation:
The normal boiling point of water is 100°C. That is the temperature at which water boils when the atmospheric pressure is 1 atm, i.e. at sea level.
The liquids boil when its vapor pressure equals the atmospheric pressure; so the higher the atmospheric pressure the higher the boiling point, and the lower the atmospheric pressure the lower the boiling point.
Since, it is stated that the altitude of Denver, Colorado is 1,600 m, the atmospheric pressure (the pressure exerted by the column of air above the place) is lower than 1 atm (atmospheric pressure at sea level).
Hence, water boiling point in Denver is lower than 100°C.
The graphs shown represent the temperature (T °C) as water is heated. Since when liquids boil their temperature remains constant during all the phase change, the flat portion of the graph represents the time during which the substance is boiling.
In the graph A, the flat portion is below 100°C; in the graph B, the flat portion is at 100 °C; in the graph C the flat part is above 100ªC, and, in graph D, there is not flat part. Then, the only graph that can illustrate water boiling in Denver, Colorado is the graph A.
Find the 16th term of the arithmetic sequence described below.
ak = 3 + 4 (k − 1)
Show your work here
Answer: 63
Step-by-step explanation:
The given arithmetic sequence is defined by the formula:
ak = 3 + 4(k - 1)
To find the 16th term, we can substitute k = 16 into this formula and simplify:
a16 = 3 + 4(16 - 1)
a16 = 3 + 4(15)
a16 = 3 + 60
a16 = 63
Therefore, the 16th term of the arithmetic sequence is 63.