can you guys answer this?​

Answer:

The answer is G.

Step-by-step explanation:

Trust me.

Answer:

J is the answer

Step-by-step explanation:

I had given the explanation but brainly deleted it for having a link.

Just use this:

"What is a box and whisker plot?

A box and whisker plot—also called a box plot—displays the five-number summary of a set of data. The five-number summary is the minimum, first quartile, median, third quartile, and maximum.

In a box plot, we draw a box from the first quartile to the third quartile. A vertical line goes through the box at the median. The whiskers go from each quartile to the minimum or maximum.

Example: Finding the five-number summary

A sample of 101010 boxes of raisins has these weights (in grams):

252525, 282828, 292929, 292929, 303030, 343434, 353535, 353535, 373737, 383838

Make a box plot of the data.

Step 1: Order the data from smallest to largest.

Our data is already in order.

252525, 282828, 292929, 292929, 303030, 343434, 353535, 353535, 373737, 383838

Step 2: Find the median.

The median is the mean of the middle two numbers:

252525, 282828, 292929, 292929, \large{30}3030, \large{34}3434, 353535, 353535, 373737, 383838

\dfrac{30+34}{2}=32

2

30+34

​

=32start fraction, 30, plus, 34, divided by, 2, end fraction, equals, 32

The median is 323232.

Step 3: Find the quartiles.

The first quartile is the median of the data points to the left of the median.

252525, 282828, \large{29}2929, 292929, 303030

Q_1=29Q

1

​

=29Q, start subscript, 1, end subscript, equals, 29

The third quartile is the median of the data points to the right of the median.

343434, 353535, \large{35}3535, 373737, 383838

Q_3=35Q

3

​

=35Q, start subscript, 3, end subscript, equals, 35

Step 4: Complete the five-number summary by finding the min and the max.

The min is the smallest data point, which is 252525.

The max is the largest data point, which is 383838.

The five-number summary is 252525, 292929, 323232, 353535, 383838.

Example (continued): Making a box plot

Let's make a box plot for the same dataset from above.

Step 1: Scale and label an axis that fits the five-number summary.

Step 2: Draw a box from Q_1Q

1

​

Q, start subscript, 1, end subscript to Q_3Q

3

​

Q, start subscript, 3, end subscript with a vertical line through the median.

Recall that Q_1=29Q

1

​

=29Q, start subscript, 1, end subscript, equals, 29, the median is 323232, and Q_3=35.Q

3

​

=35.Q, start subscript, 3, end subscript, equals, 35, point

Step 3: Draw a whisker from Q_1Q

1

​

Q, start subscript, 1, end subscript to the min and from Q_3Q

3

​

Q, start subscript, 3, end subscript to the max.

Recall that the min is 252525 and the max is 383838.

We don't need the labels on the final product:

Want to learn more about making box and whisker plots? Check out this video.

Want to practice making box plots? Check out this exercise."

We see that 24 is split into 8q.

Therefore 8q equals 24 --> 8q = 24 --> q = 24/8 = 3.

So q = 3.

Hope it helped!

Answer:

[tex]5=5^{3x}[/tex]

Step-by-step explanation:

[tex]log_5(5)=3x\\\\5=5^{3x}[/tex]

Answer:

C

Step-by-step explanation:

0.081+6.18 =6.261

0.21+4.93 =5.14  

6.261 - 5.14 = 0.13

Answer:

58.50

Step-by-step explanation:

C.$58.50

|| ▼ Answer ▼ ||

|| ✪ Solution ✪ ||

Step 1:

In this question, we are given the following:

A teenager puts $50 into an investment account in January.

If by December the balance in the account increases by 17%,

what is the amount of money in the account in December?

Step 2:

In this case, we are going to use:

[tex]Amount=Principal~(~1+\frac{Rate}{100})^{n}[/tex]

Here, Principal = $ [tex]50[/tex]

Rate = 17%

[tex]^{n}(Time)=~From~January~to~December=12=months=1~year[/tex]

Then, we have that:

[tex]Amount=50~(~1+\frac{17}{100})^{1}[/tex]

[tex]Amount=50~(~1+0.17~)^{1}[/tex]

[tex]Amount=50~(~1.17)[/tex]

[tex]Amount=[/tex] $ 58.50 (Option B)

CONCLUSION:

The amount of money in the account in December = $ 58. 50 ( OPTION B )

Hope this helps!

If you have any queries please ask.

The correct probability distribution of the random variable tracking "yellow (Y)" color is given by: Option A:

Yellow:x    Probability

0               9/16 = 0.5625

1                6/16 = 0.375

2                1/16 = 0.0625

Probability distribution of a random variable is the collection of value and its probability pair for values of that considered random variable.

It might be a function, a table etc.

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}[/tex]

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

For this case, the experiment consists of a spinner with four color sections, and is spun twice.

The sample space is:

S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}

Let we take:

X = the number of times out of two spins the color yellow occurs in a pair of spin of the considered spinner.

Then, as there are only two spin going to happen, so the values X can take are:

Let we take:

Then, as there are four colors equally likely, so we get:
P(A) = 1/4 (yellow color can occur in 1 way in one spin, and total number of colors that can occur = 4).

Similarly, we get P(B) = 1/4

Also, as first and second spins are independent of each other's result, so both A and B are independent events.

Getting the probabilities for each value of X:

[tex]P(X = 0) = P(A' \cap B') = P(A')P(B') = (1-P(A))(1-P(B)) \\P(X = 0) = \dfrac{3}{4} \times \dfrac{3}{4}\\\\P(X = 0) = \dfrac{9}{16}[/tex]

(where A' and B' are complement of A and B, and as (A and B) are independent, so as (A' and B') and (A' and B) and (A and B') )

So either first spin had yellow color, or second, so we get:

[tex]P(X = 1) = P((A' \cap B) \cup (A \cap B'))\\ P(X=1) = P(A' \cap B) + P(A \cap B') - P((A' \cap B) \cap (A \cap B'))\\P(X=1) = P(A')P(B) + P(A)P(B') -0\\P(X=1) = \dfrac{3}{4} \times \dfrac{1}{4} + \dfrac{1}{4} \times \dfrac{3}{4} - 0\\\\P(X = 1) = \dfrac{6}{16}[/tex]

Both event A and B occured this time, so we get:

[tex]P(X = 2) = P(A \cap B) = P(A)P(B) \\P(X = 0) = \dfrac{1}{4} \times \dfrac{1}{4}\\\\P(X = 0) = \dfrac{1}{16}[/tex]

Thus, the probability distribution of X is:

X=x                P(X = x)

0               9/16 = 0.5625

1                6/16 = 0.375

2                1/16 = 0.0625

Learn more about probability here:

brainly.com/question/1210781

Answer:

A. y = 2x + 2

Step-by-step explanation:

For this function....

f(0) = 2

f(1) = 4

f(2) = 6

f(3) = 8

I hope this helps!

Answer:

c. infinotely msny solutions

Answer:

Step-by-step explanation:

y = 4x + 1

2y - 2 = 8x

2(4x + 1) - 2 = 8x

2x + 2 - 2 = 8x

2x + 0 = 8x

6x = 0

x = 0

y = 0 + 1

y = 1

(0, 1)

answer is b. one solution

Answer:

The coefficient of the quadratic term ,a,determines how wide or narrow the graphs are, and

weather the graph turns upward or downward

Step-by-step explanation:

this is your answer

the assumption being that "y" is encapsulating a function in "x" terms.

[tex]y+2=\cfrac{x^2}{2}-2sin(y)\implies \stackrel{\textit{taking the derivative to both sides}}{\cfrac{dy}{dx}+0=\cfrac{1}{2}(2x)\underset{chain~rule}{-2cos(y)\cdot \cfrac{dy}{dx}}} \\\\\\ \cfrac{dy}{dx}=x-2cos(y)\cfrac{dy}{dx}\implies \cfrac{dy}{dx}+2cos(y)\cfrac{dy}{dx}=x \\\\\\ \cfrac{dy}{dx}\left[ 1+2cos(y) \right]=x\implies \cfrac{dy}{dx}=\cfrac{x}{1+2cos(y)}[/tex]

Answer:

26.8

Step-by-step explanation:

Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.

Total students that were divided into 4 classrooms :

33.5 × 4 = 134

So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.

134 ÷ 5 = 26.8

So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .

Hope this helped !

Answer:

Step-by-step explanation:

(-2, 8)

(-1, 6)

(0, 4)

(1, 2)

(2,0)

to "show work" just plug in each x value into that equation. you will never learn if all you do is copy down answers. i have given you all of the correct answers, and all you need to do is plug in the values for each x value into the equation, multiply then add. good luck man.

Answer: B. 24

Step-by-step explanation:

8 / 1/3 =

8 * 3 +

24

Answer:

24

Step-by-step explanation:

8 divided by 1/3=24

1/3x4=1 1/3

1/3x12=4

1/3x24=8

1/3x20=7 1/3

Answer:

I'm sorry but there isn't really any question to be answered

Answer:

102 dollars

Step-by-step explanation:

Answer:

a₅ = 1701

Step-by-step explanation:

[tex]a_1=7\\\\a_n=-4a_{n-1} + n\\\\a_2 = -4*a_1 + 2\\\\[/tex]

    = -4*7 + 2

    = -28 + 2

   = -26

a₃ = -4a₂ + 3

    = -4*(-26) + 3

    = 104 + 3

    = 107

a₄ = -4a₃ + 4

    = -4*107 + 4

   = -428 + 4

  = -424

a₅ = -4a₄ + 5

    = -4*(-424) + 5

    = 1696 + 5

   = 1701

Answer:

see explanation

Step-by-step explanation:

look at the photo

Answer:

a - 8

Step-by-step explanation:

1/2 a - 4

if we scale both numbers by the same factor, we will be creating an equivalent expression.

So, let's say we multiply the equation by 2.

1/2 a (2) = 1 a = a

-4 (2) = -8

One equivalent expression would be

a - 8

[If you want to test this out, try plugging in any number for a. For example, if you plug in 10...

1/2 of 10 = 5, 5 - 4 = 1

1 times 10 = 10, 10 - 8 = 2

These answers are the same scaled as the original equation, the answer for the first expression is multiplied by 2 to get the second expression]

Answer:

a = 6 , b = 5

Step-by-step explanation:

using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] = [tex]\sqrt{ab}[/tex]

then

[tex]\sqrt{180}[/tex]

= [tex]\sqrt{36(5)}[/tex]

= [tex]\sqrt{36}[/tex] × [tex]\sqrt{5}[/tex]

= 6[tex]\sqrt{5}[/tex]

with a = 6 and b = 5

Answer:

y-9=8

Step-by-step explanation:

Answer:

Third option

Step-by-step explanation:

Since our leading coeffeicent has a leading even degree, and a positive number,

The end behavior will as

as x approaches oo, and -oo, f(x) approaches oo.

Answer:

10 hours

Step-by-step explanation:

multiply b 2 then divided the miles and time and add to the total to get the time and miles you need

The total number of nickles that Alice has got for this case is 14. The total amount of money from those nickle and dimes that Alice hold is $1.9

A dollar is further divided into some majorly used parts as:

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

For this case, we're specified that:

Suppose that she has got 'x' nickles.

Then, as it is given that she has 2 more nickles than dimes, therefore, we get:

number of nickles = 2 + number of dimes

x = 2 + 12 = 14

Thus, Alice has got  12 dimes and 14 nickles.

Similarly, we have:

Thus, the total amount of money she got is $1.2 + $0.7 = $1.9

Thus, the total number of nickles that Alice has got for this case is 14. The total amount of money from those nickle and dimes that Alice hold is $1.9

Learn more about forming equations here:

https://brainly.com/question/11938672

#SPJ4

Answer:

X²-8x+308

Step-by-step explanation:

two negative integers -x and -x= +x²

8units apart=-8x

all equals 308

X²-8x=308

bring everything to the LHS

X²-8x-308=0

Answer:

80 oz

Step-by-step explanation:

20 portions times 4 oz is 80 oz

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's see ~

[tex]\qquad \sf  \dashrightarrow \:j + j + 2k[/tex]

[tex]\qquad \sf  \dashrightarrow \:2j + 2k[/tex]

[tex]\qquad \sf  \dashrightarrow \:2(j + k)[/tex]

・．━━━━━━━━━━†━━━━━━━━━━━━．・

The trigonometry identity sin(x + y) = sinx cosy + cosx siny.

sin(x + y) is one of the identities in trigonometry for compound angles.

The angle (x + y) represents the compound angles.

sin(x + y) = sinx cosy + cosx siny

To prove

sin(x + y) = sinx cosy + cosx siny

Consider OX as a rotating line anti-clockwise. Let angle XOY = a

the making of an acute angle b the rotation in the same direction is

angleYOZ = b , angle XOZ = a + b

From triangle PTR,

∠TPR = 90 - ∠PRT , ∠ROX = a

From the right-angled triangle PQO

sin(a + b) = PQ/OP

= (PT + TQ) / OP

= PT/OP + TQ/OP

= PT/PR × PR/OP + RS/OR × OR/OP

= cos (∠TPR ) sinb + sina cosb

= sina cosb + cosa sinb

if we replace a=x and b=y

Therefore, sin(x + y) = sinx cosy + cosx siny.

Learn more about trigonometry identity;

brainly.com/question/63577