Can somebody please help me thank you

Answer:

draw a square with a side length of 2.5 cm. label it CARL

Draw the circle with center A passing through C

draw SEGMENT CR

draw the straight line d passing through A and perpendicular to CR

Answer:

12 < x < 18

Step-by-step explanation:

Assuming these are 2 sides of a triangle, then

given 2 sides of a triangle , the 3rd side x is in the range

difference of 2 sides < x < sum of 2 sides , that is

15 - 3 < x <  15 + 3

12 < x < 18

Answer: 6/8 inch

Step-by-step explanation:

Answer:

The answer is c on edge or f(x) = 1 sqt x + 6 -2

Step-by-step explanation:

From the given two options, none of them has a function that has the same maximum value as f(x) = -|x+3|-2.

A function is a correspondence between input numbers (x-values) and output numbers (y-values). It is used to describe an equation.

Given that:

Suppose that x = c is a critical point of (x) then,

If f'(x) > 0 to the left of x = c and f'(x) < 0 to the right of x = c;

If f'(x) < 0 to the left of x = c and f'(x) > 0 to the right of x = c;

If f'(x) is the same sign on both sides of x = c;

From the given equation, the critical points: x = -3

If we put the point x = -3 into - |x+3|-2

We can therefore conclude that none of them has a function that has the same maximum value as f(x) = -|x+3|-2.

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The fact that the angles in a triangle add up to 180 indicates that it is actually a square). There are also four right triangles, each with a base and a height. The Pythagorean Theorem is reached when a2 + b2 = c2.

Answer:

  5 sets

Step-by-step explanation:

The average number of pieces per set is the ratio of the total number of pieces to the total number of sets.

Let x represent the number of 3-piece sets. Then the total number of pieces is ...

  3x +5(5) +10(2) = 3x +45

The total number of sets is ...

  x +5 +2 = x +7

We want the ratio of these numbers to be 5 pieces per set:

  (3x +45)/(x +7) = 5

  3x +45 = 5x +35 . . . . . multiply by (x+7)

  10 = 2x . . . . . . . . . . subtract (3x+35)

  5 = x . . . . . . . . . divide by 2

Divya owns 5 sets with 3 pieces.

_____

Alternate solution

Each 10-piece set has 5 more pieces than average, so the two of them total 10 more pieces than average.

Each 3-piece set has 2 fewer pieces than average. The total number of 3-piece sets must have a total of 10 fewer pieces than average in order to balance the excess of the 10-piece sets. That is, there must be 10/2 = 5 of the 3-piece sets to have a total lof 10 fewer pieces than average.

Altogether, the differences from average must total zero.

Answer:

688.19 inches

Step-by-step explanation:

The probability of not drawing C in neither draw is P = 0.5

All the cards have the same probability of being drawn, in this case, our set of cards is {F, D, C, G}

The probability of not drawing C is equal to the probability of drawing F, D or G. So we have 3 options out of 4, then the probability is:

p = 3/4.

Now we draw another, this time there are 3 cards, one of these is C, and the other two cards are not C. Then the probability of not drawing C again is equal to 2 over 3.

q = 2/3.

The joint probability (for both of these events to happen) is equal to the product of the individual probabilities:

P = p*q = (3/4)*(2/3) = 0.5

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Answer:

Step-by-step explanation:

. Volume: A measure of _space  occupied by a _three dimensional _ figure.

1. Base: The surface on which an object stands on.

1. Height: The _vertical distance from top to bottom, creates a _90° degree angle with the base.

1. Inverse Operation: The opposite of a math operation; the opposite of addition is subtraction and the opposite of multiplication is division.

1. Diameter: A straight line going from one side of a point on a circle to the other through the _center.

1. Radius: The distance from the center to the point of a circle;or half of the diameter.

Volume of a Cylinder

A cylinder is a three dimensional object with a circular base and top.

To find the volume of a cylinder we use the following formula:πr²h

Proof -

So, in the first part we'll verify by taking n = 1.

[tex] \implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6} [/tex]

[tex] \implies{ \frac{1(2)(3)}{6} }[/tex]

[tex]\implies{ 1}[/tex]

Therefore, it is true for the first part.

In the second part we will assume that,

[tex] \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }[/tex]

and we will prove that,

[tex]\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}[/tex]

[tex] \: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}[/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}[/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6} [/tex]

Henceforth, by using the principle of mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n.

_______________________________

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With the frequecy distribution shown in the 50 cities of pakistan,

= highest value - lowest value

= 26.5 - 8.5

= 18

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

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Answer:

Our Sun is a bright, hot ball of hydrogen and helium at the center of our solar system. It is 864,000 miles (1,392,000 km) in diameter, which makes it 109 times wider than Earth. It's 10,000 degrees Fahrenheit (5,500 degrees Celsius) at the surface, and 27 million degrees Fahrenheit (15,000,000 degrees Celsius) in the core.

Step-by-step explanation:

did this help

The Sun is the star at the center of the Solar System. It is a nearly perfect sphere of hot plasma, heated to incandescence by nuclear fusion reactions in its core, radiating the energy mainly as visible light and infrared radiation. It is by far the most important source of energy for life on Earth.                        maybe this will help a little

Answer:

226

Step-by-step explanation:

Given:

Simplify 6^3+5(4-2)

Note:

I think you meant 6^3 because if you solve 63+5(4-2):

63+5(4-2)

63+5 * 2

63 + 10

73
Solve:

6^3 + 5(4 - 2 )    

6^3 + 5 x 2

6 x 6 x 6 = 216

226 + 5 x 2

5 x 2 = 10

216 + 10 = 226

~Lenvy~

k must be greater than or equal to 22.75 to have two different zeros.

Second order polynomials are algebraic expressions that observe the following form:

[tex]p(x) = a\cdot x^2 + b\cdot x + c[/tex]   (1)

Where:

For polynomials of the form p(x) = 0, we can infer the nature of their roots by applying the following discriminant:

d = b² - 4 · a · c   (2)

According to (2), there are three cases:

Now we have the following discriminant case:

-(3 + 2 · k)² - 4 · (1) · (4) ≠ 0

-(9 + 6 · k + 4 · k²) - 16 ≠ 0

-9 - 6 · k - 4 · k² - 16 ≠ 0

4 · k²+ 6 · k +25 ≠ 0

This characteristic polynomial has two conjugated complex roots, then we conclude that all values of k must positive or negative, but never zero. By graphng tools we find that k must be greater than or equal to 22.75 to have two different zeros.

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Answer:

70 degrees

Step-by-step explanation:

We know that a straight line is 180 degrees so this equation can be used:

80 + x + 30 = 180
110 + x = 180
x = 70

Hope this helps :)

Answer:

Step-by-step explanation:

The given circle has equation

[tex] \sf \: x^2+y^2=16x[/tex]

The equation of a circle with center (h,k) and radius r units is

[tex] \sf(x-h)^2+(y-k)^2=r^2(x−h) [/tex]

[tex] \sf(x-7)^2+(y-5)^2=4^2(x−7)[/tex]

[tex] \sf(x-7)^2+(y-5)^2=16(x−7) [/tex]

This is the equation that has its center at the origin with radius 4 units.

When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).

Answer:

a.  up 1 unit

Step-by-step explanation:

f(x) + k will translate the function up k units

f(x) - k will translate the function down k units

f(x-h) will translate the function right h units

f(x+h) will translate the function left h units

It's 8/6

Because 6/8 × 8/6 = 1

Answer:

it's 8/6

I hope it's help u

The function L= 10 log(I/10^-16) is a logarithmic equation

The loudness of the whisper is 40 decibels

The function of the loudness is given as:

L= 10 log(I/10^-16)

When the intensity is 10^-12, the equation becomes

L= 10 log(10^-12/10^-16)

Evaluate the quotient

L= 10 log(10^4)

Apply the rule of logarithm

L= 10 * 4

Evaluate the product

L = 40

Hence, the loudness of the whisper is 40 decibels

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Answer:

water level is h=6.5 m, compute the time required to drain the tank to a level of h= 0.5m. Use the fourth-order Runge-Kutta method.

Step-by-step explanation:

water level is h=6.5 m, compute the time required to drain the tank to a level of h= 0.5m. Use the fourth-order Runge-Kutta method.

Answer:

Step-by-step explanation:

[tex]7 - 1 \frac{3}{5} = 6 \frac{2}{5}[/tex]

Answer:

The velocity of this particle is [tex]25\; {\rm m \cdot s^{-1}}[/tex] at [tex]t = 4\; {\rm s}[/tex].

Acceleration is constantly [tex]6\; {\rm m\cdot s^{-2}}[/tex] (and thus is never [tex]0[/tex].)

Step-by-step explanation:

The distance between the particle and the initial position is the displacement of this particle. Let [tex]x(t)[/tex] denote the displacement (in meters) of this particle at time [tex]t[/tex] (in seconds.) The question states that [tex]x(t) = 3\, t^{2} + t[/tex].

Differentiate displacement [tex]x(t)[/tex] with respect to time [tex]t[/tex] to find the velocity [tex]v(t)[/tex] (in [tex]{\rm m \cdot s^{-1}}[/tex]) of this particle:

[tex]\begin{aligned}v(t) &= \frac{d}{d t}\left[x(t)\right] \\ &= \frac{d}{d t}\left[3\, t^{2} + t\right] \\ &= 6\, t + 1 \end{aligned}[/tex].

Set velocity to [tex]25\; {\rm m\cdot s^{-1}}[/tex] and solve for time [tex]t[/tex] (in seconds):

[tex]v(t) = 25[/tex].

[tex]6\, t + 1 = 25[/tex].

[tex]t = 4[/tex].

Thus, the velocity of this particle is [tex]25\; {\rm m \cdot s^{-1}}[/tex] at [tex]t = 4\; {\rm s}[/tex].

Differentiate velocity [tex]v(t)[/tex] with respect to time [tex]t[/tex] to find the acceleration (in [tex]{\rm m\cdot s^{-2}}[/tex]) of this particle:

[tex]\begin{aligned}a(t) &= \frac{d}{d t}\left[v(t)\right] \\ &= \frac{d}{d t}\left[6\, t + 1\right] \\ &= 6\end{aligned}[/tex].

In other words, the acceleration of this particle is constantly equal to [tex]6\; {\rm m\cdot s^{-2}}[/tex]. Hence, the acceleration of this particle is never [tex]0[/tex].

Answer:145

Step-by-step explanation:

if h=33 and g=5 the expression would look like 33-4x5 frist 33-4=29 so now we imes by 5, 29x5=145 so 145 is your answer

Answer:

see explanation

Step-by-step explanation:

look photo

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

The given pair of angles form linear pair, therefore their sum is equal to 180°

that is :

[tex]\qquad \sf  \dashrightarrow \:2(x - 26) + 3x + 2 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:2x - 52 + 3x + 2 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:5x - 50 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:5x = 230[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 46 \degree[/tex]

Have a great day ~

Answer:

v = length x width x hight

Answer:

Rs. 32767

Step-by-step explanation:

Because the amount is doubling every day, we can use the expression 1*2^15-1 because there is 1 to start with. Also cool trick! if you need to do 2^1+2^2+2^3+....+2^x, it will be equal to 2^(x+1)-1. So:

2^15-1

32768-1

32767

Answer:

42 in²

Step-by-step explanation:

Total: Shape 1 + Shape 2

Area of a square: l x w, where l is the length and w is the width.

= 6 x 5

= 30

Area of a triangle: 1/2 x b x h, where b is the base and h is the height.

= 1/2 x 4 x 6

= 1/2 x 24

= 12

Total = 30 + 12

= 42 in²

Answer:

Step-by-step explanation:

This figure is trapezium

a and b are the parallel lines.

a = 5 +4 = 9 in  & b = 5 in   and h = 6 in

[tex]\boxed{\text{Area of trapezium =$\dfrac{(a+b)*h}{2}$}}[/tex]

                              [tex]\sf = \dfrac{(9+5)*6}{2}\\\\=\dfrac{14*6}{2}\\\\= 7*6\\\\= 42 \ in^{2}[/tex]

Answer:

See below, please

Step-by-step explanation:

[tex](2x + 9) + (4x - 3) = 90[/tex]

[tex]6x + 6 = 90[/tex]

[tex]6x = 90 - 6 = 84[/tex]

Hence

[tex]x = 14[/tex]

Answer:

sin C = 3/5

Step-by-step explanation:

see image.

It helps to draw a picture. Tan C is the ratio of the OPP/ADJ.

Pythagorean theorem or if you know Pythagorean triples are a shortcut to find the hypotenuse.

Once you know the hypotenuse, use the ratio for sine to solve the question. Sine is OPP/HYP.

see image.

Answer:

  840 km

Step-by-step explanation:

The speed expression ...

  840 kilometers per hour

means the plane files 840 kilometers in each hour.

In 1 hour, it will travel 840 km.