CAN ANYONE HELP ME WITH THIS QUICKKKKK!

Answer:

Step-by-step explanation:

length = Pi.radius.15degree/180degree

= Pi.2.15/180 = about 0,5 feet

The length of the arc that is subtended by 15° is: 0.5 ft.

Formula for the arc length in a circle with a radius of r and a central angle of ∅ is, ∅/360 × 2πr.

Given the following:

Arc length = 15/360 × 2π(2)

Arc length = 0.5 ft.

Thus, the length of the arc that is subtended by 15° is: 0.5 ft.

Learn more about the arc length on:

https://brainly.com/question/17329757

Answer:

275, 300, 450, 490, 675

Median: 450

Q1: 287

Step-by-step explanation:

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]

7.) Detemine the value of [tex] \sf{ {3a}^{2} -b.}[/tex]

[tex] \huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]

[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]

[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶12-( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶12 + 1 }[/tex]

[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}[/tex]

8.) Find the value of [tex] \sf{ {a}^{3} {b}^{3} - abc.}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}[/tex]

[tex]\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]

Answer:

9

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

A system of equations can be solved by Translating the system of equations into a matrix by following theses steps

write out the resulting answer in form of equations.

Answer:

[tex] \large{ 16.}[/tex]

[tex] \: \large{\tt{❃ \: m \: \angle \: 1 + m \: \angle \: 2 = 180 \degree \: ( \: SUM \: OF \: ANGLE \: IN \: LINEAR \: PAIR)}}[/tex]

[tex] \large{ \tt{⟶ \: 47 \degree + m \angle \: 2 = 180 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: m \angle \: 2 \: = 180 \degree - 47 \degree}}[/tex]

[tex] \large{ \boxed{ \tt{⟶ \: m \: \angle \: 2 = 133 \degree}}}[/tex]

–––––––––––––

[tex] \large{17}.[/tex]

[tex] \large{ \tt{↝ \: m \angle \: 6 = m \angle5 = \boxed{ 99.5\degree }\: ( \: BEING \: VOA)}}[/tex]

–––––––––––––

[tex] \large{18.}[/tex]

[tex] \large{ \tt{✻ \: m \angle \: JHL = m \angle \: JHK + m \: \angle \: KHL\: }}[/tex]

[tex] \large{ \tt{⤏ \: m \angle \: JHL= 60 \degree + 46 \degree}}[/tex]

[tex] \large{ \boxed{\tt{⤏ \: m \angle \: JHL = 106 \degree}}}[/tex]

–––––––––––––––

[tex] \large{ {19.}}[/tex]

[tex] \large{ \tt{❁ \: m \: \angle \: JHK + m \: \angle JHP+ m \: \angle PHN= 180 \degree \: ( \: sum \: of \: angle \: in \: straight \: line)}}[/tex]

[tex] \large{ \tt{↣ \: 60 \degree + m \angle \: JHP+ 46 \degree = 180 \degree}}[/tex]

[tex] \large{ \tt{↣ \: m \angle \: JHP = 74 \degree}}[/tex]

[tex] \large{ \tt{☂ \: m \angle \: JHN = m \angle \: JHP + m \angle \: PHN}}[/tex]

[tex] \large{ \tt{↦m \angle \: JHN = 74 \degree + 46 \degree}}[/tex]

[tex] \large{ \boxed{ \tt{ ↦m \angle \: JHN = 120 \degree}}}[/tex]

––––––––––––––––

[tex] \large{ 20.}[/tex]

[tex] \large{ \tt{✺ \: m \angle \: KHP = m \angle \: KHJ + m \angle \: JHP}}[/tex]

[tex] \large{ \tt{ ↬ \: \: m \angle \: KHP = 74 \degree + 60 \degree}}[/tex]

[tex] \large{ \boxed{\tt{↬ \: m \angle \: KHP = 134 \degree}}}[/tex]

––––––––––––––––

[tex] \large{ \tt{ \# \: StayInAndExplore \: !}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer/Step-by-step explanation:

The diagram of the circular track is missing, and so also its dimensions.

However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.

Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.

Circumference = πd

d = 20 m (we are assuming the diameter is 20 meters)

π = 3.14

Circumference of circular track = 3.14 × 20 = 62.8 m.

This means that 1 lap = 62.8 m that she would have to run.

Therefore,

6 laps would be = 6 × 62.8 = 376.8 m

Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.

a rule in quadratic equ states that

if summation of the roots should be -b/a of the equa

comparing the equ x² - 6x + y=0

with. ax² + bx +c =0

we see that in the equ, a= 1, b=-6

so the sum of the roots is -(-6)/1= +6

looking the the option the only one that agreed is option A

-2 + 8= 6

there fore the values of x are -2 or 8

Answer:

250

Step-by-step explanation:

4/16 = 1/4 = .25

When dividing exponents, subtract the bottom from the top, so [tex]10^{5}[/tex]÷[tex]10^{2}[/tex] = [tex]10^{3}[/tex]

So, .25 * [tex]10^{3}[/tex] = 250

Answer:

12.21

Step-by-step explanation:

Explanation:

This is a right triangle, so the Pythagorean Theorem applies.

The Pythagorean Theorem states that the sum of the squared legs of a triangle is equal to the squared hypotenuse.

The legs of a triangle are the sides that form the right angle.

The hypotenuse of a triangle is the longest side.

Formula/solve:

[tex]a^2+b^2=c^2[/tex]

[tex]a,b-legs[/tex]

[tex]c-hypotenuse[/tex]

Here, I am solving for the hypotenuse.

[tex]7^2+10^2=c^2[/tex]

[tex]49+100=c^2[/tex]

[tex]149=c^2[/tex]

Conclude:

The last step is the cancel out c² by finding the square root of 149.

149 is not a perfect square, so I must round the square root to the nearest hundredth.

[tex]12.2065556157[/tex] ≈ [tex]12.21[/tex]

I, therefore, believe the length of the hypotenuse is 12.21 feet.

Answer:

a

Step-by-step explanation:

Answer:

The answer would be D.

Step-by-step explanation: Hope this helps and gl :)

Answer:

Can I get the full question please

Step-by-step explanation:

x + y = 10 - - - 1

x=2y - - - - - 2

Putting the value of x in eqn 1,

2y+y=10

y=10/3

=3.33 yrs

Which i feel is incorrect

Answer:

x=4.34 seconds

Step-by-step explanation:

-16x^2+70x-2=0

[tex]x=\frac{35+\sqrt{1193}}{16}[/tex]

x=4.34

Answer:

See Explanation

Step-by-step explanation:

You posted an incomplete question with little and unclear details.

I will answer this question with a more complete version (see attachment)

Given that:

[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]

Required

The fraction that passed the test

Rearrange the score in ascending order:

[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

The total number of students is:

[tex]n =20[/tex]

Extract the students that passed (scored 70 and above)

[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

Their numbers are:

[tex]Passed: 14[/tex]

So, the fraction of those that passed is:

[tex]Fraction = \frac{Passed}{n}[/tex]

[tex]Fraction = \frac{14}{20}[/tex]

Reduce fraction

[tex]Fraction = \frac{7}{10}[/tex]

Answer:

I've attached the Answer

Answer:

a = - 2

Step-by-step explanation:

Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.

Find a :

Equation : 5x + 2y = - 4

                5 ( a ) + 2 ( 3) = - 4

                5a + 6 = - 4

                 5a + 6 - 6 = - 4 - 6               [ subtracting both sides by 6 ]

                 5a  + 0 = - 10

                   5a = - 10

                    a = - 2                               [ dividing both sides by 5]

[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4

                                                                    5(-2) + 2( 3 ) = - 4

                                                                   - 10 + 6 = - 4

                                                                         - 4 = - 4 ]

Answer:

total amount of sweets=230

Step-by-step explanation:

ratio=8:5:10

total ratio=8+5+10

=23

Adrian=x

Charlie= x+20

Ben=1/2×(x+20)

Charlie's share

10/23×(x+20+x+(1/2×x+20))=x+20

10/23×(x+20+x+(x+20/2))=x+20

10/23×(x+20+x+x+20/2)=x+20

10/23×(2(x+20)+(2×x)+(x+20/2)/2=x+20

10/23×(2x+40+2x+x+20)/2=x+20

10/23×(2x+2x+x+40+20)/2=x+20

10/23×(5x+60)/2=x+20

50x+600/46=x+20

50x+600=46(x+20)

50x+600=46x+920

50x-46x=920-600

4x=320

4x/4=320/4

x=80

Total amount of sweet

x+x+20+1/2(x+20)

80+80+20+1/2(80+20)

180+1/2(100)

180+50

230

Answer:

x = ±2

 x = ±i

Step-by-step explanation:

(x^2+4)^2 – 11(x^2+4) + 24 = 0

Let m = x^2 +4

(m)^2 – 11(m) + 24 = 0

Solving this quadratic

What two numbers multiply to 24 and add to -11

-8*-3 =24

-8-3 = -11

(m-8)(m-3) =0

m = 8   m=3

Now substitute back

x^2 +4 = 8    x^2 +4 = 3

x^2 +4-4 = 8-4    x^2+4-4 = 3-4

x^2 = 4                      x^2 = -1

Taking the square root

sqrt(x^2) = sqrt(4)                      sqrt(x^2) = sqrt(-1)

x = ±2                                           x = ±i

Answer:

one value of x = 2

Step-by-step explanation:

[tex](x^2 + 4 )^2 - 11(x^2 + 4 ) + 24 = 0\\\\x^4 + 16 + 8x^2 - 11x^2 -44 + 24 = 0\\\\x^4 - 3x^2 -4 = 0\\\\[/tex]   ------ ( 1 )

[tex]Let \ x^2 \ = \ u[/tex]

( 1 ) => [tex]u^2 - 3u - 4 = 0[/tex]

         [tex]u^2 -4u + u - 4 = 0\\\\u(u - 4) + 1 (u - 4) = 0\\\\(u + 1) (u - 4) = 0\\\\u = -1 \ , \ u = 4[/tex]

   [tex]=> x^2 = - 1 \ and \ x^2 = 4[/tex]

      [tex]x = \sqrt {-1} = i[/tex]

      [tex]x = \sqrt{4} = \pm 2[/tex]

Answer:

circumference of a circle =2 pi r

radius=14/2=7

2×3.14×7=43.96ft

The circumference of the circle is 43.96 ft.

Given,

Diameter of the circle = 14 ft

π = 3.14

We need to find the circumference of a circle.

The circumference is the total length of the surface of the circle.

The circumference is given by:

= 2πr

r = radius of the circle

Diameter = 2radius

Example:

We have,

Diameter = 14 ft

π = 3.14

Radius = diameter / 2 =  14/2 = 7 ft

Circumference:

= 2πr

= 2 x 3.14 x 7

= 43.96 ft

Thus the circumference of the circle is 43.96 ft.

Learn more about circles here:

https://brainly.com/question/16125353

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Answer:

Total Distance Michelle Covered is 26.14 miles

Step-by-step explanation:

According To the Question, We Have

Michelle First Ride Her bike In 12 miles South, then Changed her Direction & Ride Bike For A long While, and when she stopped she find Herself 2 miles south and 10 miles west from starting point. that shows she change direction and start walking in South-West Direction.  

(For Diagram, Please Find in attachment)

In Triangle ABC , Apply Phythagorus Theorem

AB² = BC² + AC²

AB² = 10² + 10²

AB² = 200

AB = √2×10 ⇔ 14.14 miles

Now The Total Distance Travelled by Michelle Would be

OA + AB = 26.14 miles

Answer:

C. 54

Step-by-step explanation:

1. Drop down the 1

2. Multiply 1 by 3, put that answer, 3, underneath the 5

3. Add 3+5, then put that answer, 8, below.

4. Multiply 8 by 3, put the answer, 24, under the -8

5. Add 24 and -8 to get 16, drop 16 underneath

6. Multiply 16 by 3, put the answer, 48, under the 6

7. Add 48 and 6 to get 54. Drop 54 below.

Now there are no more coefficients to add the 54 to, so 54 is the remainder!

I hope this helped, the explanation without writing it down is kind of confusing. :))

Answer:

Step-by-step explanation:

volume of reqd. figure=10×5×1+3×3×1=50+9=59 cm³

Answer:

Step-by-step explanation:

Answer:

x = 80

Step-by-step explanation:

x + .1x = 88

or

x(1+.1) = 88

which ever makes more sense to you

1.1 x = 88

x = 88/1.1

x = 80

QUESTION:- Given 3x+y=1

Write the equation in general form Ax+By+C =0

3x-y+1=0

-3x +y-1=0

3x-y=-1

[tex]3x + y - 1 = 0 \: \: ✔[/tex]

ANSWER:-

[tex]3x + y = 1 [/tex]

Form of the given equation->

[tex]Ax + By = C[/tex]

so we need to change the side of the C !

while changing side of C we need to change the sign of C !

[tex] \bold{ \red{SO :- }}[/tex]

[tex]3 x + y = 1 \\ 3x + y - 1 = 0[/tex]

FORM OF THE RESULTED EQUATION:-

[tex]Ax + By + C = 0 \\

A = 3 \\ B = 1 \\ C = - 1[/tex]

Answer:

x=0;y=2

Step-by-step explanation:

4(-x+2)=2x+8 -4x+8=2x+8 -4x-2x=8-8 -6x=0 x=0 y=-x+2 y=0+2 y=2

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]

[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

[tex]\huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{mass \: 1 \: = \: 6000 \: kg}[/tex]

[tex]\quad\quad\quad\quad\sf{velocity\: 1\: = \: 2.0\: m/s}[/tex]

[tex]\quad\quad\quad\quad\sf{mass \: 2\: = \: 3000 \: kg}[/tex]

[tex]\quad\quad\quad\quad\sf{velocity\: 2\: = \: 3.0\: m/s}[/tex]

[tex]\huge\underline{\sf{\red{Fomula:}}}[/tex]

[tex]\quad\quad\quad\quad\boxed{\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}}[/tex]

[tex]\huge\underline{\sf{\red{Solution:}}} [/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(6000 \: kg)(2.0\:m/s)+(3000\:kg)(3.0\:m/s)}{(6000\:kg)+(3000\:kg)}}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(12,000kgm/s)+(9,000\:kgm/s)}{(9,000kg)}}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \: kgm/s}{9000kg}}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \cancel{ \red{ kg}}m/s}{9000 \cancel{ \red{kg}}}}[/tex]

[tex]\quad\quad\quad\quad \sf{vf\: = \boxed{ \sf{ 2.33 \:m /s}}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad\quad \underline{ \sf{\boxed{ \sf{ \red{ 2.33 \:m /s}}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]

[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]

[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]

ฅ^•ﻌ•^ฅ