Using the bond dissociation energy approach, which entails deducting the total energy released when the bonds form in the products from the total energy released when the bonds are broken in the reactants, we may get the enthalpy change (H) for the given reaction.
The reaction's chemically balanced equation is as follows:
O2 (g) + 2H2(g) = 2H2O (g)
For the reaction, we may utilise the following bond dissociation energies (in kJ/mol):
436 kJ/mol H-H bond (reactant)
498 kJ/mol O=O bond (reactant)
463 kJ/mol H-O bond (product)
The energy needed to break the bonds in the reactants and the energy released when the bonds form in the products may both be calculated using these values::
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in fireworks, the heat of the reaction of an oxidizing agent, such as kclo4, with an organic compound excites certain salts, which emit specific colors. strontium salts have an intense emission at 641 nm. what is the energy (in kj) of this emission for 4.09 g of the chloride salt of strontium? assume that all the heat produced is converted to emitted light. enter to 2 decimal places. (mts 2/17/2018)
The energy emitted by 4.09 g of strontium chloride salt is 8.01 8.00 x 10⁻²⁴ kJ (rounded to 2 decimal places).
What is the emission energy?
To determine the energy of the emission at 641 nm, we can use the formula:
E = hc/λ
where;
E is the energy, h is Planck's constant (6.626 x 10⁻³⁴ J·s), c is the speed of light (3 x 10⁸ m/s), and λ is the wavelength in meters.First, we need to convert the wavelength from nanometers to meters:
641 nm = 641 x 10⁻⁹ m
Next, we can plug in the values and solve for E:
E = (6.626 x 10⁻³⁴J·s)(3 x 10⁸ m/s)/(641 x 10⁻⁹ m)
E = 3.10 x 10⁻¹⁹ J
To convert from joules to kilojoules, we divide by 1000:
E = 3.10 x 10⁻²² kJ
Now we can use the molar mass of the chloride salt of strontium to calculate the total energy released:
SrCl₂ has a molar mass of 158.53 g/mol, so 4.09 g is equivalent to:
n = 4.09 g / 158.53 g/mol
n = 0.0258 mol
The energy released by 0.0258 mol of strontium chloride at 100% efficiency is:
E_total = nE
E_total = (0.0258 mol)(3.10 x 10⁻²² kJ/mol)
E_total = 8.00 x 10⁻²⁴ kJ
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which one of the following salts, when dissolved in water, produces the solution with the highest ph?
a. LiClO4 b. KF c. KHSO4 d. Li3PO4 e. BaO.
The salt that produces the solution with the highest pH when dissolved in water is KF (Potassium Fluoride).The correct answer is b.
KF has a strong basic character and so it produces a highly basic solution. LiClO4 (Lithium Perchlorate), KHSO4 (Potassium Hydrogen Sulfate), Li3PO4 (Lithium Phosphate) and BaO (Barium Oxide) are all relatively weakly acidic and so produce solutions with lower pH.
The negative logarithm of the hydrogen ion concentration in a water-based solution is called pH. It represents the acidity or alkalinity of the solution. On a scale of 1 to 14, pH ranges from 0 to 14. The solutions with pH values less than 7 are acidic, those with pH values greater than 7 are alkaline, and those with pH values equal to 7 are neutral.
Salts are compounds made up of cations and anions that are ionically bonded. When they dissolve in water, they dissociate into their constituent ions. As a result, the pH of the solution may be affected. In the given salts, KF produces the solution with the highest pH when dissolved in water.
When dissolved in water, the pH of the solution is influenced by the salt.The negative logarithm of the hydrogen ion concentration in a water-based solution is called pH.pH represents the acidity or alkalinity of the solution.
Salts are compounds made up of cations and anions that are ionically bonded.KF produces the solution with the highest pH when dissolved in water.
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If some solid sodium solid hydroxide is added to a solution that is 0.010–molar in (CH3)3CCl and 0.10–molar in NaOH, which of the following is true? (Assume the temperature and volume remain constant.)answer choicesa. Both the reaction rate and k increase.b. Both the reaction rate and k decrease.c. Both the reaction rate and k remain the same.d. The reaction rate increases but k remains the same.e. The reaction rate decreases but k remains the same.
If some solid sodium hydroxide is added to a solution that is 0.010–molar in (CH₃)₃CCl and 0.10–molar in NaOH, the reaction rate increases but k remains the same. Therefore, option D is correct.
In this scenario, when solid sodium hydroxide (NaOH) is added to a solution containing (CH₃)₃CCl and NaOH, a reaction between (CH₃)₃CCl and NaOH takes place. The balanced chemical equation for this reaction is:
(CH₃)₃CCl + NaOH ⇒ (CH₃)₃COH + NaCl
The reaction rate is determined by the concentration of the reactants. In this case, the concentration of (CH₃)₃CCl remains constant because only solid NaOH is added.
The rate constant depends on the specific reaction and the conditions under which it occurs. Since the temperature and volume remain constant, the rate constant (k) will also remain constant.
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Arrange the following in the decreasing order of their basic strength in aqueous solutions. CH3NH2, (CH3)2NH, (CH3)3N, NH3
The decreasing order of basic strength in aqueous solutions is NH3 > (CH3)3N > (CH3)2NH > CH3NH2.
NH3 is the strongest base among the four because it is a proton acceptor, so it can easily accept protons from the water molecules. (CH3)3N is the second strongest base because it has three methyl groups which help stabilize the negative charge generated after accepting the proton from water. (CH3)2NH is weaker than (CH3)3N because it has two methyl groups and can accept a proton from water but the stability of the negative charge created is lower. CH3NH2 is the weakest base because it has one methyl group and its negative charge is not as stable as the other bases.
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How would the pKa of the unknown acid be affected (higher, lower, or no change) if the following errors occurred? Please explain.
a) The pH meter was incorrectly calibrated to read lower than the actual pH.
b) During the titration several drops of NaOH missed the reaction beaker and fell onto the bench top.
c) Acid was dissolved in 75 mL of distilled water rather than 50 mL of distilled water.
Also, the same question, but if it says: How would the molar mass of the unknown acid be affected (higher, lower, or no change) if the following errors occurred? Please explain.
Same things that are asked in part a,b, and c.
The pKa will be higher in the unknown acid solution. The pH of the unknown acids would not be affected by several drops of NaOH solution.
What is pKa and pH of solution?The pKa of the unknown acid would be higher if the pH meter was incorrectly calibrated to read lower than the actual pH. This is because if the pH meter reads lower than the actual pH, the measured pH would be lower than the actual pH.
As pKa is the negative logarithm of the acid dissociation constant, Ka, which is directly proportional to the hydrogen ion concentration, [H⁺], a decrease in the measured pH would lead to a decrease in the measured [H⁺]. Since:
pKa = -log Ka = -log [H⁺] + log [HA], a decrease in [H⁺] would lead to an increase in pKa.
The pKa of the unknown acid would not be affected if several drops of NaOH missed the reaction beaker and fell onto the bench top. This is because the number of moles of NaOH that react with the unknown acid is not affected by the drops that miss the beaker.
The number of moles of NaOH that react with the unknown acid is determined by the volume and the concentration of NaOH added to the beaker and the volume and the concentration of the unknown acid in the beaker. Therefore, the pKa would remain the same.
The pKa of the unknown acid would not be affected if acid was dissolved in 75 mL of distilled water rather than 50 mL of distilled water. This is because the pKa of an acid is an intrinsic property that is independent of the amount of the acid. The pKa is determined by the acid itself, not by the amount of acid. Therefore, the pKa would remain the same.
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write a list of rules for recognizing and naming binary molecular compounds from their chemical formulas
The following are the rules for recognizing and naming binary molecular compounds from their chemical formulas:
1. The first element in the chemical formula will be the name of the first element in the compound.
2. The second element in the chemical formula will be the name of the second element in the compound.
3. If the first element is a metal, the second element will end in “-ide”.
4. If the first element is a nonmetal, the second element will end in “-ate” or “-ite”.
5. The prefixes “mono-, di-, tri-, tetra-, penta-, and hexa-” are used to indicate the number of atoms of each element in the compound.
6. When the prefixes are not used, the number of atoms of each element is implied by the subscript.
7. If the subscript is written as a fraction, the fraction is changed to a whole number when forming the compound name.
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The rules for recognizing and naming binary molecular compounds are written focusing on the lower groups and the higher groups.
The rules for recognizing and naming binary molecular compounds from their chemical formulas are as follows:
1. The element with the lower group number is written first in the formula, and its full name is used.
2. The element with the higher group number is written second in the formula, and its stem name is used along with the suffix -ide.
3. The prefixes mono-, di-, tri-, tetra-, penta-, and so on are used to indicate the number of atoms present for each element in the molecule.
4. The prefix mono- is omitted for the first element in the formula.
5. The ending -a or -o in the prefix is omitted if the element name begins with a vowel, and only the vowel of the prefix is used in the compound name.
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make a prediction about the densities of the unknown solid and liquid. how will mass affect the volume of the solid, and how will volume affect the mass of the liquid?
When the mass of the solid increases, its volume will decrease, while when the volume of the liquid increases, its mass will increase. This is because the densities of these materials are determined by the amount of mass that can be held in a given volume.
What is the density?
The volume of the solid is directly proportional to its mass. It means, as the mass of the solid increases, its volume will also increase. Hence, we can predict that as the mass of the unknown solid increases, its density will also increase because the volume of the solid will increase, but the amount of space it occupies will not change.
The mass of the liquid is directly proportional to its volume. It means, as the volume of the liquid increases, its mass will also increase. Hence, we can predict that as the volume of the unknown liquid increases, its density will decrease because the mass of the liquid will increase, but the amount of space it occupies will also increase.
Therefore, we can conclude that the density of the unknown solid will increase with increasing mass, and the density of the unknown liquid will decrease with increasing volume.
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a. Show the complete dissociation of perchloric acid.
b. Show the complete dissociation of cesium hydroxide.
c. Show the partial dissociation of ammonia by reacting it with water.
a. Perchloric acid is a strong acid and completely dissociates into hydrogen ions and perchlorate ions
b. Cesium hydroxide is a strong base and completely dissociates into cesium ions and hydroxide ions
c. Ammonia is a weak base and partially dissociates in water to form ammonium ions and hydroxide ions
a. Perchloric acid dissociates completely in water to form hydrogen ions and perchlorate ions:
HClO₄ (aq) → H⁺ (aq) + ClO₄⁻ (aq)
b. Cesium hydroxide dissociates completely in water to form cesium ions and hydroxide ions:
CsOH (aq) → Cs⁺ (aq) + OH⁻ (aq)
c. Ammonia reacts with water to form ammonium ions and hydroxide ions through partial dissociation:
NH₃ (aq) + H₂O (l) ⇌ NH₄⁺ (aq) + OH⁻ (aq)
In this reaction, some ammonia molecules remain intact while others donate a proton to a water molecule to form ammonium ions and hydroxide ions.
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Please Help me with this question, No.2
124.61 grams of NH₃ form from 22 g of H₂.
What is molar mass?Molar mass is the mass of one mole of a substance. It is usually expressed in units of grams per mole (g/mol). For example, the molar mass of carbon is 12.01 g/mol, which means that one mole of carbon has a mass of 12.01 grams. Molar mass is useful in chemistry because it allows us to convert between mass and moles of a substance, which is important for many chemical calculations.
The balanced chemical equation is:
3H₂ + N₂ -----> 2NH₃
From the equation, we can see that 3 moles of H2 react to form 2 moles of NH₃.
The molar mass of H₂ is 2 g/mol, so 22 g of H₂ is:
22 g H2 x (1 mol H2/2 g H2) = 11 mol H2
Using the mole ratio from the balanced equation, we can calculate the number of moles of NH3 produced:
11 mol H2 x (2 mol NH3/3 mol H2) = 7.33 mol NH3
Finally, we can convert moles of NH3 to grams using its molar mass:
7.33 mol NH₃ x (17 g NH3/1 mol NH3) = 124.61 g NH₃
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What is the molar concentration (molarity) of a solution made by dissolving 0.340 moles of CaCl2 (s) in just enough water to form 1.7 liters of solution
a. 5.0 M b. 0.20 M c. 0.58 M d. 0.34 M
Option (b) is the correct answer. The molar concentration (molarity) of a solution made by dissolving 0.340 moles of CaCl₂ (s) in just enough water to form 1.7 liters of the solution is 0.20 M.
This can be determined using the formula:
Molarity = moles of solute/liters of solution.
In this case, 0.340 moles of CaCl₂ (s) is dissolved in 1.7 liters of solution, so the molarity is:
0.340 / 1.7 = 0.20 M.
Molarity is an important concept in chemistry. It is a measure of the number of moles of a substance dissolved in one liter of solution. In the case of this question, the molarity of the solution is 0.20 M, which means that there are 0.20 moles of CaCl₂ (s) dissolved in one liter of the solution.
In chemistry, molarity is often used to determine the concentration of a solution. The higher the molarity, the higher the concentration of the solute in the solution. For example, a 0.58 M solution of CaCl₂ (s) would be more concentrated than a 0.20 M solution.
To summarize, the molarity of the given solution is 0.20 M.
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Carbon reacts with zinc oxide (ZnO) to produce zinc and carbon dioxide
In this type of redox process, zinc oxide is reduced while carbon is oxidised.
The reaction between carbon and zinc oxide (ZnO) is a chemical reaction that results in the production of zinc and carbon dioxide. The reaction is a form of a redox reaction, where carbon is oxidized while zinc oxide is reduced.
The balanced chemical equation for the reaction is:
C + ZnO → Zn + CO2
In this reaction, solid carbon reacts with solid zinc oxide to form solid zinc and gaseous carbon dioxide. The reaction takes place at high temperatures, typically above 1200°C.
The reaction is important in metallurgy, where it is used to extract zinc metal from its ore, zinc oxide. The reaction is also used in the production of carbon dioxide gas, which is used in various industries such as food and beverage, as well as in fire extinguishers.
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Chlorate is an oxyanion. It contains a single covalent bond between oxygen and chlorine atoms. The ion also have an ovaral negative charge. Show by calculation that the percentage by mass of chlorate 1 in calcium chlorate 1 is greater than the percentage by mass of chlorate 1 ions in Sodium chlorate
Percentage by mass of chlorate 1 in calcium chlorate 1 is greater than the percentage by mass of chlorate 1 ions in Sodium chlorate.
What is an oxyanion? Give an example of an oxyanion.An oxyanion is a polyatomic ion that contains at least one oxygen atom and one or more other elements, typically nonmetals. Examples of oxyanions include nitrate (NO3-), sulfate (SO42-), and phosphate (PO43-).
The molecular formula for calcium chlorate is Ca(ClO3)2, and the molecular formula for sodium chlorate is NaClO3.
To calculate the percentage by mass of chlorate 1 in calcium chlorate 1, we need to calculate the molar mass of Ca(ClO3)2 and the molar mass of chlorate 1.
Molar mass of Ca(ClO3)2 = 1 mol Ca + 2 mol ClO3
= 40.08 g/mol Ca + 2(35.45 g/mol Cl + 3(16.00 g/mol O))
= 238.06 g/mol
Molar mass of chlorate 1 = 35.45 g/mol Cl + 3(16.00 g/mol O)
= 99.45 g/mol
Now, we can calculate the percentage by mass of chlorate 1 in calcium chlorate 1:
% by mass of chlorate 1 in calcium chlorate 1 = (2 mol ClO3 x 99.45 g/mol) / (1 mol Ca(ClO3)2 x 238.06 g/mol) x 100%
= 83.3%
To calculate the percentage by mass of chlorate 1 in sodium chlorate, we only need to calculate the molar mass of NaClO3 and the molar mass of chlorate 1.
Molar mass of NaClO3 = 22.99 g/mol Na + 35.45 g/mol Cl + 3(16.00 g/mol O)
= 106.99 g/mol
Molar mass of chlorate 1 = 35.45 g/mol Cl + 3(16.00 g/mol O)
= 99.45 g/mol
Now, we can calculate the percentage by mass of chlorate 1 in sodium chlorate:
% by mass of chlorate 1 in sodium chlorate = (1 mol ClO3 x 99.45 g/mol) / (1 mol NaClO3 x 106.99 g/mol) x 100%
= 92.9%
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A chemistry student is given 650. mL of a clear aqueous solution at 33.° C. He is told an unknown amount of a certain compound X is dissolved in the solution. The student allows the solution to cool to 17.9 C. At that point, the student sees that a precipitate has formed. He pours off the remaining liquid solution, throws away the precipitate, and evaporates the water from the remaining liquid solution under vacuum. More precipitate forms. The student washes dries and weighs the additional precipitate. It weighs 0.150 kg.-Using only the information solubility above, can you calculate solubility of X in water at 17.°cYes/ No.-If you said yes, calculate itBe sure your answer has a unit symbol and the right number of significant digits
Yes, the solubility of X in water at 17°C can be calculated using the given information. The solubility of X is 0.00118 kg/L.
What is the solubility of compound?To determine the solubility, we need to assume that all of the X is dissolved in the solution and use the solubility of X at 33°C.
Solubility of X at 33°C = 12.0 g/L = 0.012 kg/L
Volume of solution = 650 mL = 0.65 L
Therefore, the initial mass of X in the solution is: 0.012 kg/L × 0.65 L = 0.0078 kg
Now we need to determine the final mass of X in the solution after cooling. Since a precipitate has formed, we know that some of the X has come out of solution. Let's assume that all of the additional precipitate that formed came from X. Therefore, the final mass of X in the solution is: 0.0078 kg - 0.150 kg = 0.00765 kg = 7.65 g
Now we can use the final mass of X and the volume of the remaining liquid solution to calculate the solubility of X at 17°C.
Solubility of X at 17.9°C = mass of X / volume of solution at 17.9°C = 7.65 g / 0.65 L = 11.8 g/L = 0.0118 kg/L
Therefore, the solubility of X in water at 17°C is 0.0118 kg/L.
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any groups present on a benzene ring can impact the success and regioselectivity of an electrophilic aromatic substitution. determine which group from the list best fits each activation and directing description. moderately deactivating meta- director choose... strongly activating ortho-/para- director choose... weakly activating ortho-/para- director choose... strongly deactivating meta- director choose... weakly deactivating ortho-/para- director choose...
The groups present on a benzene ring can impact the success and regioselectivity of an electrophilic aromatic substitution
. The activation and directing effects of various groups present on a benzene ring are as follows: Moderately deactivating meta- director: Nitro (-NO2), Sulfonyl (-SO3H)Strongly activating ortho-/para- director: Amino (-NH2), Hydroxyl (-OH), Alkoxy (-OR), Aryl (-Ar), Alkyl (-R), Dialkylamino (-N (R) 2), Carboxyl (-COOH)Weakly activating ortho-/para- director: Chloro (-Cl), Bromo (-Br), Iodo (-I)Strongly deactivating meta- director: Carbonyl (-C (O) R), Cyano (-CN)Weakly deactivating ortho-/para- director: Methyl (-CH3), Ethyl (-C2H5), Phenyl (-C6H5)Therefore, the groups that best fit each activation and directing description are as follows: Moderately deactivating meta- director: Nitro (-NO2)Strongly activating ortho-/para- director: Amino (-NH2)Weakly activating ortho-/para- director: Chloro (-Cl)Strongly deactivating meta- director: Carbonyl (-C (O) R)Weakly deactivating ortho-/para- director: Methyl (-CH3)
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in a low pressure system wind moves in what direction
In a low pressure system, wind moves in a counterclockwise direction.
What is the effect of wind have in a low pressure system?The effect wind have in a low pressure system is the Coriolis effect, which is the apparent deflection of moving objects (including wind) caused by the rotation of the Earth.
In a low pressure system, air rises from the surface, creating a region of lower atmospheric pressure at the center of the system. The surrounding higher pressure air then flows inwards towards the center to replace the rising air, and is deflected to the right (in the Northern Hemisphere) or left (in the Southern Hemisphere) by the Coriolis effect, resulting in the counterclockwise or clockwise circulation.
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. a perchloric acid solution has a ph of 3.158. what is the concentration of perchlorate ion in this solution?
The concentration of perchlorate ion in a perchloric acid solution with a pH of 3.158 can be calculated using the Henderson-Hasselbalch equation.Therefore, the concentration of perchlorate ion in the solution is 4.7 x 10^{-4} M.
Perchloric acid (HClO4) is a strong acid. A strong acid is a substance that almost entirely dissociates into ions when it dissolves in water. As a result, perchloric acid can be thought of as a source of hydrogen ions (H+) in solution.The concentration of hydrogen ions in solution can be determined using the pH of the solution. pH is the negative logarithm of the hydrogen ion concentration in moles per liter (mol/L) of solution.A pH of 3.158 corresponds to a hydrogen ion concentration of:10^{-3.158} = 6.59 x 10^{-4} mol/LIn a perchloric acid solution, the perchlorate ion (ClO4) is the conjugate base of the acid. It can be concluded that the concentration of perchlorate ions (ClO4-) is equal to the concentration of hydrogen ions (H+) in the solution because the acid completely dissociates. Therefore, the concentration of perchlorate ions in a solution with a pH of 3.158 is 6.59 x 10^{-4} mol/L.Therefore, the answer is that the concentration of perchlorate ion in perchloric acid solution with a pH of 3.158 is 6.59 x 10^{-4 }mol/L.
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consider the following reaction. zn( s) 2agno 3( aq) --> 2ag( s) zn(no 3) 2( aq) when 16.2 g of silver was produced, g of zinc nitrate would be produced.
The given reaction is Zn + 2AgNO₃ → 2Ag + Zn(NO₃)₂. So 14.20 g of zinc nitrate would be produced when 16.2 g of silver was produced.
The Stoichiometry of the reactionLet us calculate the number of moles of silver using the given data:
Mass of silver produced = 16.2 gThe molar mass of silver = 107.87 g/molNumber of moles of silver produced = mass of silver produced / molar mass of silver= 16.2 / 107.87= 0.15 molThe number of moles of zinc nitrate produced = 2 mol of silver are produced when 1 mol of zinc nitrate is produced too. Therefore, 0.15 / 2= 0.075 molThe molar mass of zinc nitrate = 189.36 g/molMass of zinc nitrate produced = number of moles of zinc nitrate produced × molar mass of zinc nitrate= 0.075 × 189.36= 14.20 gHence, 14.20 g of zinc nitrate would be produced.
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the cage size of the zeolites is in the centimeters scale, True or false
The cage size of zeolites is in the centimeters scale. This statement is false.
Zeolites are microporous aluminosilicate minerals that have a framework structure composed of aluminosilicate tetrahedra. These tetrahedra are linked together to form a 3-dimensional pore structure with uniform size and shape. Zeolites are widely used as adsorbents, catalysts, and ion-exchangers due to their unique properties such as high surface area, thermal stability, and molecular sieving properties.Cage size of zeolitesZeolites are known for their uniform pore size and shape. The size of the pores in zeolites ranges from 2-10 Å (angstroms), which is too small to be measured in centimeters. Therefore, the cage size of zeolites is not in the centimeters scale, but rather in the angstroms scale.
This means that zeolites have a cage size that is much smaller than a nanometer. Their pore size makes them selective towards certain molecules based on their size and shape.Properties of zeolitesThe properties of zeolites are attributed to their pore structure, which is composed of channels and cages. These channels and cages provide a surface area that is accessible to molecules that can be adsorbed. The size and shape of the pores in zeolites allow them to be selective towards certain molecules based on their size and shape. The high surface area of zeolites also makes them an effective catalyst for a wide range of reactions, including the conversion of petroleum feedstocks to gasoline and diesel fuel.
SummaryIn conclusion, the statement "The cage size of zeolites is in the centimeters scale" is false. Zeolites have a uniform pore size and shape that ranges from 2-10 Å, which is much smaller than a nanometer. This size allows them to be selective towards certain molecules based on their size and shape, and makes them an effective adsorbent, catalyst, and ion-exchanger.
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3. Tick [✔] the correct statements and cross [x] the wrong ones. (a)Rain water is one of the major factors that brings changes on the earth's surface. (b)Mantle is the thickest layer of the earth. (c) Rivers erode rocks and deposit on the plain areas. (d) The terraces on the hills reduce soil erosion. (e) Land covers the major part of the earth.
Formerly weathered material is eroded by the power of the water. In addition, the rock it runs over is worn down and weathered. You now know that water can erode soil and weather rock. These processes alter the surface of the Planet.
The correct answer is :A.
What are the substances that the earth's surface is affected by?Wind, moisture, and ice break apart large rocks and transport surface sediments. Years are usually required for weathering, erosion, and deposition to cause changes that are visible. Yet certain things change the surface of the Planet far more quickly than others. These consist of volcanic eruptions, earthquakes, and landslides.
What changes to the Ground atmosphere may liquid bring about?By weathering and erosion, water flow modifies the properties of the terrain. The role of the ocean and other interactions determine region weather patterns and have an impact on climate. The unique properties of water, both physically and chemically, have a profound effect on the motions of the planet.
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some elements and/or ions are isoelectronic, which means that they have the same number of electrons in the same orbitals, albeit with different nuclei. Which of the following is not isoelectronic with the others?a. S2-b. Arc. Sc3+d. Ti4+e. Ga3+
Option B Ar is the correct answer, which is not isoelectronic with the others. Therefore, S2−, Sc3+, Ti4+, and Ga3+ are isoelectronic.
Elements are different from ions in that they have the same number of electrons and protons. It is said that some elements and/or ions are isoelectronic, implying that they have the same number of electrons in the same orbitals, although with different nuclei.What is the meaning of Isoelectronic? In the case of chemical elements, the term "isoelectronic" is used to describe atoms, ions, or molecules that have the same number of electrons. Two or more atomic species are said to be isoelectronic if they contain the same number of electrons in the same electronic configuration, despite the fact that their atomic numbers are different. In contrast, the term "isotonic" is used to describe two or more species having the same number of nucleons (i.e. the same total number of protons and neutrons).The correct answer is option B, as it is not isoelectronic with the others. Argon, denoted by the symbol "Ar," is a chemical element with the atomic number 18, indicating that it contains 18 electrons. Argon is a noble gas that has a completely filled outer shell with eight electrons in the n = 2 shell and eight electrons in the n = 3 shell. However, S2− has 18 electrons, which are present in the same electron configuration as Argon.Sc3+ has 18 electrons, which are present in the same electron configuration as Argon.Ti4+ has 18 electrons, which are present in the same electron configuration as Argon.Ga3+ has 18 electrons, which are present in the same electron configuration as Argon.As a result, option B Ar (Argon) is not isoelectronic with the others. Therefore, the correct option is B.Learn more about isoelectronic: https://brainly.com/question/1626090
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Which of these micronutrients is destroyed by exposure to light?
A) riboflavin
B) iron
C) iodine
D) vitamin D
The micronutrient that is destroyed by exposure to light is riboflavin, also known as vitamin B2. The correct answer is option: a.
Riboflavin is a water-soluble vitamin that is important for energy production, cellular function, and growth. When exposed to light, riboflavin undergoes photo-oxidation, which causes it to break down and lose its activity. This is why many products that contain riboflavin, such as milk and other dairy products, are packaged in opaque containers to prevent exposure to light. Iron and iodine are not affected by light, while vitamin D is synthesized by the body in response to sunlight, rather than being destroyed by it. Option a is correct.
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Rank the following items in order of decreasing radius: K, K^+, and K^-. Rank from largest to smallest radius. To rank items as equivalent, overlap them.
K, K^+, and K^-
Largest radius Smallest radius
______________ ______________
In isoelectronic species, the species that have the least number of electrons will have the smallest radius. Therefore, K+ has the smallest radius amongst K, K+ and K-.The order of the radius of the given species can be given as follows:
K > K⁻ > K⁺
The effective nuclear charge experienced by the K atom is +1, as it has one valence electron which can shield 18 electrons. Therefore, the attraction between the valence electron and the nucleus is weak which makes the atomic size larger than that of K- and K+.
The effective nuclear charge experienced by the K-atom is +1, as it has one valence electron which can shield 17 electrons. The attraction between the valence electron and the nucleus is stronger than in K due to less screening effect by electrons. Therefore, the atomic size is smaller than that of K.
The effective nuclear charge experienced by the K⁺ atom is +1, as it has one valence electron which can shield 19 electrons. The attraction between the valence electron and the nucleus is maximum in K+ due to the absence of one electron from the 4s orbital. Therefore, the atomic size is the smallest among the given species.
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Gold reacts with the elements in group 7 of the periodic table. 0. 175g of gold reacts with chlorine. The equation for the reaction is: 2Au+ 3Cl2 ------> 2AuCl3.
Calculate the mass of chlorine needed to react with 0. 175g of gold.
Give your answer in mg
Relative atomic masses(Ar): Cl=35. 5 Au=197
The mass of the chlorine needed to react with 0.175g of gold is 94.6mg. This is calculated with the help of Mole concept.
The mass of Au is 0.175g
The atomic mass of Au is 197g
Atomic mass of chlorine atom= 35.5 g
The number of moles of gold is calculated by the expression,
Number of moles= given mass/ molar mass
Putting all the values in the expression of moles we get,
number of moles of gold = 0.175 g/ 197 g/ mole
= 0.000888 mole
From the balanced equation 2Au + 3 → 2AuC, if 2 moles of gold readily react with 3 moles of Cl.
0.000888 moles of gold will react will be,
= 3/2 x 0.000888 x 35.5
Number of moles of Cl will be = 0.001332 moles
So, the mass of Cl that will react with Au is:
Mass of Cl = 0.01332 x 71
= 0.0946 g
we can convert the gram into milligram by multiplying 1000.
so it becomes, 0.0946 g x 1000= 94.6mg
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Which equimolar mixture would result in a buffer with a pH less than 7?a) HF with KFb) HBr with KBrc) NaOH with NaCld) NH3 with NH4NO3e) HClO with HClO2
NH₃ with NH₄NO₃ equimolar mixture would result in a buffer with a pH less than 7. The answer is (d) .
A buffer solution is made up of a weak acid and its conjugate base or a weak base and its conjugate acid. The pH of a buffer solution depends on the pKa of the weak acid or the weak base and the ratio of the concentrations of the weak acid and its conjugate base, or the weak base and its conjugate acid.
In this case, NH₃ is a weak base with a pKa of 9.25, and NH⁴⁺ is its conjugate acid. NH₄NO₃ is a salt of NH4+ and NO³⁻, and it will dissociate in water to form NH⁴⁺ and NO³⁻. Since NH⁴⁺ is the conjugate acid of NH₃, it will react with any added OH⁻ ions, preventing the pH from rising above 7. Therefore, NH₃ with NH₄NO₃ would result in a buffer with a pH less than 7.
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knowing that solid sodium acetate is soluble and that acetic acid dissociates into hydrogen ions and acetate ions, why will sodium acetate influence the equilibrium of acetic acid dissociation?
As sodium acetate is added to the solution, the sodium ions (Na+) will replace the hydrogen ions (H+) in the equation. This causes a shift in the equilibrium as the number of hydrogen ions (H+) decreases, while the number of acetate ions (CH3COO-) increases.
Sodium acetate is an ionic compound composed of Na⁺ and CH₃COO⁻ ions.
It dissociates in water to create these ions, which are then available to affect the dissociation of acetic acid.
The equilibrium of acetic acid dissociation is influenced by the addition of sodium acetate.
Acid dissociation equilibria are influenced by salt addition (usually sodium salts), particularly when the acid is weak.
This is due to the fact that the anion of the salt reacts with hydrogen ions from the acid's dissociation.
This decreases the concentration of hydrogen ions in the solution, causing the reaction to shift towards more dissociation.
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suppose you experimentally calculate the value of the density of co2 as 2.03 g/l. the known value is 1.98 g/l. what is the percent error of your experimentally determined density?
The percent error of your experimentally determined density is that is an error of 2.53%.
It can be calculated using the following equation: Error % = (Experimentally Determined Value - Known Value)/Known Value x 100. So in your case, the equation would look like: Error % = (2.03 g/l - 1.98 g/l)/1.98 g/l x 100
This gives us an error of 2.53%.
The given value of density of CO2 is 2.03 g/L and the actual value of density of CO2 is 1.98 g/L. The percent error can be calculated using the below formula: Percent error = (|experimental value - actual value|/actual value) × 100Therefore, the percent error of experimentally determined density is Percent error = (|2.03 g/L - 1.98 g/L|/1.98 g/L) × 100= (0.05 g/L/1.98 g/L) × 100= 2.53%Thus, the percent error of the experimentally determined density is 2.53%.
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According to avogadros law, how will the number of molecules in 2 liters of hydrogen gas compare with the number of molecules in 2 liters of oxygen gas at the same temperature and pressure?
A hydrogen will have more molecules in a volume of 2 liters
B oxygen will have more molecules in a volume of 2 liters
C they will have equal number of molecules
D there is no way to tell
Answer:
C - they will have equal number of molecules.
Explanation:
The number of molecules in 2 liters of hydrogen gas compare with the number of molecules in 2 liters of oxygen gas at the same temperature and pressure because while the equal volumes of the gases are at the same temperature and pressure, it still has the same number of molecules.
molecules that can absorb light in the visible range are called
The molecules that can absorb light in the visible range are called pigments.
What is a pigment?
Pigments are compounds that absorb light and reflect only some wavelengths, resulting in color production.
The molecules are capable of absorbing specific wavelengths of light, giving them the potential to interact with photons.
The visible range of light is absorbed by pigments.
The term "chromophore" is used to describe the light-absorbing portion of a pigment molecule.
The portion of the molecule that absorbs light in the visible region is the chromophore.
The pigments' physical and chemical properties affect the absorption spectrum.
Pigments have a characteristic absorption spectrum, which is the range of wavelengths they can absorb.
When pigments absorb light, they become excited, and this energy is used to fuel biological processes.
Pigments are an essential component of photosynthesis, which is the process by which plants use sunlight to make energy.
Chlorophyll a, chlorophyll b, and carotenoids are examples of pigments in plants that absorb light energy from the sun. In humans, pigments such as melanin and hemoglobin are involved in coloration and oxygen transportation, respectively.
In conclusion, molecules that can absorb light in the visible range are called pigments.
The term "chromophore" is used to describe the light-absorbing portion of a pigment molecule.
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Now suppose a reaction vessel is filled with 0.0406 atm of nitrogen (N_2) and 5.97 atm of ammonia (NH_3) at 1126. Degree C. Answer the following question this system: Under these conditions, will the pressure of N_2 tend to rise or fall? rise fall Is it possible to reverse this tendency by adding H_2? In other words, if you said the pressure of N_2 will tend to rise, can that be changed to a tendency to fall adding H_2? Similarly, if you said the pressure of N_2 will tend to fall, can that be changed to a tendency to rise by adding H_2? Yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of H_2 needed to reverse it. Round your answer to 2 significant digits. atm
The pressure of [tex]N_{2}[/tex] will rise under the given conditions. And, Yes, it is possible to reverse this tendency by adding [tex]H_{2}[/tex]. The minimum pressure of H2 required to reverse the tendency is 0.01 atm.
The reaction involved is: [tex]N_{2}[/tex](g) + 3[tex]H_{2}[/tex](g) ⇌ 2[tex]NH_{3}[/tex](g) Hence, when [tex]H_{2}[/tex] is added to the above system, the [tex]N_{2}[/tex] and [tex]H_{2}[/tex] will react to produce [tex]NH_{3}[/tex]. This reaction will reduce the amount of [tex]N_{2}[/tex] present in the system, causing the pressure of [tex]N_{2}[/tex] to decrease. Therefore, by adding [tex]H_{2}[/tex] , we can change the tendency of [tex]N_{2}[/tex] pressure from rise to fall.To calculate the minimum pressure of [tex]H_{2}[/tex] required to reverse the tendency, we have to use the equilibrium constant, Kp. The expression for Kp for the above reaction is: Kp =( [tex]NH_{3}[/tex]) / p([tex]N_{2}[/tex]) p3( [tex]H_{2}[/tex] )
At equilibrium, Kp = 1.7 × 104 at 1126 °C.Now, we will solve for the minimum pressure of [tex]H_{2}[/tex] needed to reverse the tendency. Let's assume that the pressure of [tex]N_{2}[/tex] has increased by x atm. Therefore, the new pressure of [tex]N_{2}[/tex] will be (0.0406 + x) atm. At equilibrium, we have:
p2([tex]NH_{3}[/tex] ) / p([tex]N_{2}[/tex]) p3( [tex]H_{2}[/tex] ) = 1.7 × 104
On substituting the given values and simplifying, we get:
p2([tex]NH_{3}[/tex]) / p(N2) = 6.39 × 10-5
Now, p2([tex]NH_{3}[/tex]) = 5.97 atm, and p([tex]N_{2}[/tex]) = (0.0406 + x) atm.
On substituting these values, we get:5.97 / (0.0406 + x) = 6.39 × 10-5
Solving for x, we get:x = 0.00579 atm ≈ 0.01 atm (rounded to 2 significant digits)Therefore, the minimum pressure of [tex]H_{2}[/tex] required to reverse the tendency is 0.01 atm.
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PLS HELP!!!
Match the terms to the appropriate definitions or descriptions
1. - c. Absolute dating
2. - k. Zircon
3. - m. Meteorites
4.- h. Compression melting
5. - e. Relative dating
6. - a. An igneous intrusion
7. - g. Unconformity
8. - d. Index fossils
9. - f. The Grand Canyon
10.- b. Iguazu Falls in Argentina
11. -h. Yosemite Valley
12.- i. Carbon 14 dating
13.-c. Radiometric dating
What is Carbon 14 dating?Carbon 14 dating, also known as radiocarbon dating, is a technique used to determine the age of organic materials based on their content of the radioactive isotope carbon-14. Carbon-14 is a naturally occurring isotope of carbon that is formed in the upper atmosphere by the interaction of cosmic rays with nitrogen atoms. This carbon-14 is incorporated into carbon dioxide molecules, which are then taken up by plants during photosynthesis and subsequently passed on to animals that eat those plants.
When an organism dies, it stops taking in carbon-14, and the carbon-14 in its tissues begins to decay into nitrogen-14 at a known rate. By measuring the amount of carbon-14 that remains in the sample, scientists can determine how long it has been since the organism died.
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