An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation x(t)=Acosωt . The maximum net force exerted on the object while it is oscillating has a magnitude F. Which of the following expressions is correct for the maximum speed of the object during its motion?

Answers

Answer 1

What the equation given?

x(t)=Acos[tex]\omega[/tex]t

Maximum velocity occurs at the equilibrium position

So

x=0

Now

x(0)=Acos0[/tex]x(0)=A

Now

As we know the formula

[tex]\\ \rm\rightarrowtail V_max=A\omega[/tex]

These expressions can be used

Answer 2

The maximum speed of the oscillating object will be given by [tex]V_{max}=Aw[/tex]

What is oscillation?

An oscillation is defined as the repitative periodic motion of any object about its mean or equilibrium position.

The given equation is as follows:

x(t)=Acost

Maximum velocity occurs at the equilibrium position x=0

x(0)=Acos0

x(0)=A

Hence the maximum velocity will be  [tex]V_{max}=Aw[/tex]

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Related Questions

Terry is walking down the street at 3 m/s. If he
has a mass of 70 kg, what is his momentum?

Answers

[tex]\text{Given that, mass m = 70 kg and velocity v = 3 m/s}\\\\\text{Momentum,}~ p = mv = 70 \times 3 = 210~ kg ~ms^{-1}[/tex]

Which of the following would NOT cause acceleration?
A. an object falling towards the earth
B. the wind catching the sail of a sailboat
C. a car traveling at a constant velocity
D. a pitcher throwing a baseball

Answers

I think the answer is C.


What’s the weight of a box w/ a mass of 150kg on earth?

Answers

[tex]\text{Weight ,} W = mg = 150 \times 9.8 =1470N[/tex]

Explanation:

f=ma

where force is weight. we know that a is the acceleration of gravity which is -9.8 m/s^2

so f is

-1471.5 N

2. A tennis ball machine launches balls horizontally with an initial speed of 5.3 m/s, from a height of 1.2 m.
a) What will the time of flight be for a tennis ball launched by the ball machine? (3)
b) What will the range of the tennis ball be? (2)
c) What will be the final velocity of the ball with which it reaches the ground? (3)

Answers

(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.

(b) The range of the tennis ball be is 1.01 m.

(c)  The final velocity of the ball with which it reaches the ground is 7.16 m/s.

Time of flight of tennis ball

The time of flight of the tennis ball is calculated as follows;

h = vt + ¹/₂gt²

1.2 = 5.3t + 0.5(9.8)t²

1.2 = 5.3t + 4.9t²

4.9t² + 5.3t - 1.2 = 0

a = 4.9, b = 5.3, c = 1.2

solve using quadratic formula

t = 0.19 s

Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.

Range of the tennis ball

The range of the tennis ball is calculated as follows;

R = vt

R = 5.3 x 0.19

R = 1.01 m

Final velocity of the ball

The final velocity of the ball with which it reaches the ground is calculated as follows;

vf = vo + gt

vf = 5.3 + 9.8(0.19)

vf = 7.16 m/s

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23) What is the magnitude of the electric field intensity at a point where a proton experiences an
electrostatic force of magnitude 2.30 x 10-25 newton?

Answers

Answer: I am so sorry i hadn't learned this Yet~!

Explanation:

Who is the father of the humans?

Answers

Answer:

Adam (Arabic:, romanized:dam) is said to be the first human person on Earth, as well as the first prophet (Arabic:, nab) of Islam. Muslims see Adam's role as the father of the human race with veneration.

Explanation:

Answer:

Adam is the name given to the first person in Genesis 1-5. Aside from being the name of the first man, Adam is also used as a pronoun in the Bible, both individually as "a human" and collectively as "mankind."

Explanation:

A spring-loaded ballistic cart measuring 0.68 kg is in contact with a second 0.80 kg
cart. The carts are initially at rest on a level surface. The spring is released and the
lighter cart is observed to move at +0.52 m/s afterward. What is the velocity of the
other cart?

Answers

Answer:

wait in comments.................

Which process describes the warm ocean that transfers heat to the air above it?
O conduction
O convection
O reflection
O radiation

Answers

Answer:

convection is the answer

The process that describes the warm ocean that transfers heat to the air above it is known as Convection. Thus, the correct option for this question is B.

What are some characteristics of heat?

Some characteristics of heat are as follows:

It has no mass, shape, color, odor, volume, and weight.It is one of the invisible forms of energy.It stimulates the presence of warmth.It gets remarkably transferred from one body to another.This form of energy has the capacity to flow in each and every direction.

The process of convection transfers heat with the help of the migration of a fluid (liquid or gas) between areas of different temperatures. It is an approach that signifies the transfer of heat between two bodies by involving currents of moving gas or fluid.

Therefore, convection is the process that describes the warm ocean that transfers heat to the air above it. Thus, the correct option for this question is B.

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#SPJ2

An unbalanced force acting on an object results in ______.
A. inertia
B. friction
C. acceleration
D. faster
E. slower

Answers

Answer:

friction

Explanation:

A student in the Biomechanics class has decided that she would like to make her arms
stronger. She has a mass of 63 kg, She chooses to complete some elbow flexion exercises
using a kettlebell. For this problem, consider the hand and forearm to be a single segment.
The distance from her elbow to her wrist is 22.86 cm.
The force from the kettlebell is applied to her hand, which is 30.48 cm from her elbow joint.
She knows that the moment arm of the elbow extensor muscles about the elbow axis is

Answers

Answer:

what is heat and transfer

Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water when it freezes?

Answers

There is no temperature change which drives heat flow, thus no heat will be released by the water.

Heat released by the water when it freezes

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

m is mass of waterc is specific heat capacity of waterΔФ is change in temperature = Фf - Фi

Initial temperature of water, Фi = 0 °C

when water freezes, the final temperature, Фf = 0 °C

Q = 22 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

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The magnetic field perpendicular to a single wire loop of diameter 10.0 cm decreases from 0.50 T to zero. The wire is made of copper and has a diameter of 2.0 mm and length 1.0 cm. How much charge moves through the wire while the field is changing?

I know how to do the calculations, but can someone please explain what is the 10cm diameter and 2mm diameter? Why is there one wire and two diameters? I understand this problem mathematically but not conceptually.

Answers

Hi there!

We can begin by using Lenz's Law:
[tex]\epsilon = -N\frac{d\Phi _B}{dt}[/tex]

N = Number of Loops

Ф = Magnetic Flux (Wb)
t = time (s)

Also, we can rewrite this as:
[tex]\epsilon = -NA\frac{dB}{dt}[/tex]

A = Area (m²)

Since the area is constant, we can take it out of the derivative.

This is a single wire loop, so N = 1.

Now, we can develop an expression for the induced emf.

We can begin by solving for the area:

[tex]A = \pi r^2 \\\\d = r/2 r = 0.05cm \\\\A = \pi (0.05^2) = 0.007854 m^2[/tex]

We can also express dB/dt as:
[tex]\frac{dB}{dt} = \frac{\Delta B}{t} = \frac{0-0.5}{t} = \frac{-0.5}{t}[/tex]

Now, we can create an equation.

[tex]\epsilon = -(1)(0.007854)\frac{-0.5}{t} = \frac{0.003927}{t}[/tex]

To solve the system, we must now develop an expression for current given an emf and resistance.

Begin by calculating the resistance of the copper wire:
[tex]R = \frac{\rho L}{A}[/tex]

ρ = Resistivity of copper (1.72 * 10⁻⁸ Ωm)
L = Length of wire (0.01 m)

A = cross section area (m²)

Solve:
[tex]R = \frac{(1.72*10^{-8})(0.01)}{\pi (0.001^2)} = 5.475 * 10^{-5} \Omega m[/tex]

Now, we can use the following relation (Ohm's Law):

[tex]\epsilon = iR\\\\\epsilon = \frac{Q}{t}R[/tex]

*Since current is equivalent to Q/t.

Plug in the value of R and set the two equations equal to each other.

[tex]\frac{Q}{t}(5.475 * 10^{-5}) = \frac{0.003927}{t}[/tex]

Cancel out 't'.

[tex]Q (5.475 * 10^{-5}) = 0.003927 \\\\Q = \frac{0.003927}{5.475*10^{-5}} = \boxed{71.73 C}[/tex]

Describe gravitational force in your own words. Which two factors affect the gravitational force between two objects?

Answers

Answer:

Gravitational force is the force that attracts objects towards each other. Two factors that affect the gravitational force between objects are the mass of the two objects and the distance between

Explanation:

Gravity is what pulls us towards the Earth if we were to jump into the air, so it is the force that pulls things towards other things. The bigger the objects are the more gravity they have, so a planet has more gravity than say, an apple. Distance between objects also makes their gravity change, so the Earth's pull on the moon is different than the Earth's pull on the sun.

Hopefully this helps- let me know if you have any questions!

Question :-

Describe gravitational force in your own words. Which two factors affect the gravitational force between two objects?

Answer :-

Gravitational Force :-

It is the attractive force between the two body having some mass.Example of gravitational force :- attraction between the human and earth . earth pulls the body towards it with the help of this This force helps the celestial bodies to revolve in there orbits

Factors effecting Gravitational force:-

Mass :- gravitational force directly proportional on the masses of the body between which it is acting [tex]gravitational \: force ∝m{ \tiny1}m{ \tiny2}[/tex]Distance between the masses :- Gravitational force is inversely proportional to the square of the distance between the masses [tex]gravitational \: force∝ \frac{1}{ {r}^{2} } [/tex]

Formula of the Gravitational force :-

[tex]F = \frac{G m{ \tiny1}m{ \tiny2} }{ {r}^{2} } [/tex]

where

F is gravitational force G is gravitational constant ( universal constant ) m 1 is mass of first body m2 is mass of second body r is the distance between the two bodies

Which of the following examples BEST describes the life characteristic of respiration?

A) A cheetah races across the plain.
B) Starfish cells divide and multiply as it gets larger.
C) Humans eliminate some wastes through urine and feces.
D) Humans breathe in oxygen and release carbon dioxide.

Answers

Answer:

D if I'm incorrect then sorry.

Explanation:

The answer is C. Sorry if I’m wrong, if I’m right please give me brainliest.

The ________ of an object is the same on the earth as it is on the moon.
A. mass
B. kilogram
C. newton
D. acceleration of gravity
E. weight

Answers

Answer:

mass

Explanation:

The mass of an object is the same on the earth as it is on the moon.

Mass always remains constant, it never changes with respect to place.

What is environmental?

Answers

Answer:

Environmental means relating to or caused by the surroundings in which someone lives or something exists. It protects against environmental hazards such as wind and sun. The form the human family takes is a response to environmental pressures.

Explanation:

I HOPE IT HELPS!!

THANX!!!

STAY SAFE!!!!

Predict the magnitude of the gravitational force....

Answers

Answer:

a=650.549

b=246.4819

c=38.5261

Explanation:

A rope is wrapped around a pulley many times. The pulley can be modeled as a solid disk of radius R and mass M, and a mass mA hangs vertically from the pulley. The mass is released from rest. show answer Incorrect Answer 25% Part (a) What is the magnitude of the tangential acceleration of the hanging mass?

Answers

The magnitude of the tangential acceleration of the hanging mass is 2mg/MR

Tangential acceleration of the hanging mass

The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;

τ = Iα

Where;

I is the moment of inertiaα is the angular velocity

[tex]\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}[/tex]

Where;

m is the hanging massM is the mass of solid disk

The tangential acceleration is calculated as follows;

[tex]a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}[/tex]

Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR

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Place the following in order, from closest to furthest away:
A) The scattered disc; B) The Kuiper Belt; C) The Oort cloud

Answers

The order from closest to furthest away include the following:

The  Kuiper BeltThe  scattered discThe Oort cloud.

What is Kuiper belt?

This is the region which ends around 50 AU from the Sun and has the presence of the scattered disc in its outer surface.

The  Oort cloud has a distance of between 2,000 and 10,000 thereby making it the farthest which is why the correct order is B, A and C.

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Calculate the average velocity of the cart for each fan speed. Round your answers to the nearest tenth. The cart with Low fan speed has an average velocity of cm/s. The cart with Medium fan speed has an average velocity of cm/s. The cart with High fan speed has an average velocity of cm/s.

A 4-column table with 3 rows. Column 1 has entries Elapsed time to finish line(s); Total distance (c m); Average velocity (c m/s). Column 2 is labeled Cart Speed (Low Fan Speed) (c m/s) with entries 7.4; 500; unknown. Column 3 is labeled Cart Speed (medium Fan Speed) (c m/s) with entries 6.4; 500; unknown. Column 4 is labeled Cart Speed (High Fan Speed) (c m/s) with entries 5.6; 500; unknown.

Answers

The velocity for column 1 is 67.57m/s.The velocity for column 2 is 78.13m/s.The velocity for column 3 is 89.29m/s.

What is Velocity?

This is defined as the rate of change of position of an object with respect to time. The unit is metres per second(m/s).

Velocity = distance/ time

The velocity for column 1 = 500m/7.4s = 67.57m/s.

The velocity for column 2  = 500m/6.4s = 78.13m/s.

The velocity for column 3  = 500m/5.6s = 89.29m/s.

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Answer:

67.6

78.1

89.3

Explanation:

The force of gravity on an object gives the object its _______.
A. mass
B. kilogram
C. acceleration of gravity
D. weight

Answers

Answer:

Weight

Explanation:

The force of gravity on a an object gives the object its weight.

What are the essential components of successfully competing in the field events:

Power, technique, and timing


Technique, flexibility, and speed


Power, speed, and strength


None of the above

Answers

Answer:

Power, technique, and timing

Explanation:

I took the test, hope it helps, dont forget to rate ⭐⭐⭐⭐

Answer:

A

Explanation:

I took the quiz

10 N
30 N
4 kg

what’s the net force & acceleration

Answers

Answer:

The question is not complete. Since force is a vector quantity we need to consider the direction of the two forces.

hence if they are acting opposite on the body . then the net force will be  30-10=20N20N

Acceleration=Force/mass

=20/4

=5m/s^2

Explanation:

The United States uses only 10% of the world's energy.
True
False

Answers

Answer:

False

Explanation:

17%

the answer to your question is false

The SI unit for force is the _________.
A. mass
B. kilogram
C. newton
D. acceleration of gravity
E. weight

Answers

Answer:

Newton

Explanation:

The SI unit for force is the newton.

Answer:

The SI unit of kilogram is Newton. It is denoted by n

define what is physics​

Answers

In my own words, I would say that physics is an area of science that seeks to explain and understand the fundamental nature of the dynamics of objects, essentially defining how objects can interact, in space and in time.

Physics is a branch of science that deals with the structure of matter and the fundamental constituents of the universe interact. It’s motion, and behaviour through space and time, and the related entities of energy and force. Physics is one of the most fundamental scientific disciplines, and it’s main goal is to understand how the universe behaves.

7. A 2.0 kg block, starting from rest, is pushed by a
constant force along a frictionless track. The
position of the block as a function of time is
recorded in the data above. The final momentum
of the block is
(A) 0.8 kgm/s
(B) 1.2 kgm/s
(C) 1.6 kgm/s
(D) 3.2 kgm/s

Answers

Answer:

(A) 0.8 kgm/s

Explanation:

because of the even ground it would only slow down

Why was the government in giving support to addressing and researching the HIV epidemic ?

Answers

Do you mind adding the picture?? It’ helps me answer the question better :)

Why would it be impractical to wire a home with a circuit in which all loads were connected in series.

Answers

For residences, series circuits are impracticable. Parallel circuits are practical because each appliance is controlled by its own switch, which prevents the other appliances from being turned off. A) The appliances are all turned on. The conductor wire is carrying a considerable quantity of current (arrow).

A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per meter of length. By constructing a suitable Gaussian surface around the wire, Find the magnitude and direction of the electric field at points

a)5.5m

b)2.5m

perpendicular from the center of the wire.​

Answers

(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

Electric field at a point on the Gaussian surface

The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;

E = λ/2πε₀r

where;

λ is linear charge densityε₀ is permitivity of free spacer is the position of the chargeAt a distance of 5.5 m

[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C[/tex]

At a distance of 2.5 m

[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C[/tex]

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

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