Answer:
We know that:
She needs 9/10 grams of flour for the cake (this quantity does not make a lot of sense, maybe is written incorrectly, but is the only info we have, so let's solve the problem with this)
She only has 1/3 of the amount she needs.
How much flour does she have?
Well, she needs 9/10 grams, and she has one-third of that.
Then she has (1/3) times (9/10) grams, this is:
F = (1/3)*(9/10) grams
F = (1*9)/(3*10) grams
F = 9/30 grams
That is the amount of flour that she has.
Divide the following polynomials. (hint; use long division)
(h³ - 4h + 12) / (h+3)
PLZ I NEED HELP!!!!!!!!!!!!!!!!
WILL GIVE BRAINEST!!!!!!!!!!!!!
Answer:
[tex]h^2-3h+5\:\text{remainder }3 \text{ or }h^2-3h+5-\frac{3}{h+3}[/tex]
Step-by-step explanation:
Question: [tex]\frac{h^3-4h+12}{h+3}[/tex] (divide using long division)
To start, our quotient must have a degree of 2, since [tex]h\cdot h^2=h^3[/tex].
From long division, multiply by the highest degree possible with appropriate constants to ride terms of the dividend when necessary. When you finish, the final term at the bottom will be your remainder and your quotient will be on top (in long division form).
The result is [tex]\frac{h^3-4h+12}{h+3}=h^2-3h+5\text{ with a remainder of } 3[/tex]. You can write it in quotient-remainder form, or as one long polynomial: [tex]\implies h^2-3h+5-\frac{3}{h+3}[/tex].
Verify:
[tex](h^2-3h+5)(h+3)=h^3-4h+15=\bold{h^3-4h+12}+\underline{3} \:\checkmark[/tex]
Show your work on how you got the answer
please helppp
Answer:
250
Step-by-step explanation:
4/16 = 1/4 = .25
When dividing exponents, subtract the bottom from the top, so [tex]10^{5}[/tex]÷[tex]10^{2}[/tex] = [tex]10^{3}[/tex]
So, .25 * [tex]10^{3}[/tex] = 250
Jacob has gained weight.
He now weighs 88kg, which is 10% higher than his normal weight.
What is Jacob's normal weight?
Answer:
x = 80
Step-by-step explanation:
x + .1x = 88
or
x(1+.1) = 88
which ever makes more sense to you
1.1 x = 88
x = 88/1.1
x = 80
All the whole numbers from 1 to 100 are written in a row next to each other. How many 7s are there in the formed number?
A circle has a radius of 2 feet. What is the length of the arc subtended by a 15 degree central angle?
Answer:
Step-by-step explanation:
length = Pi.radius.15degree/180degree
= Pi.2.15/180 = about 0,5 feet
The length of the arc that is subtended by 15° is: 0.5 ft.
What is the Arc Length in a Circle?Formula for the arc length in a circle with a radius of r and a central angle of ∅ is, ∅/360 × 2πr.
Given the following:
r = 2 ft∅ = 15°Arc length = 15/360 × 2π(2)
Arc length = 0.5 ft.
Thus, the length of the arc that is subtended by 15° is: 0.5 ft.
Learn more about the arc length on:
https://brainly.com/question/17329757
The scores from Dr. Wilhelm's students science fair project are shown below .
Dr wilhelm made a histogram for the data.
answer choices :
50
65
70
71
plsss help I appreciate it thank you so much
Answer:
See Explanation
Step-by-step explanation:
You posted an incomplete question with little and unclear details.
I will answer this question with a more complete version (see attachment)
Given that:
[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]
Required
The fraction that passed the test
Rearrange the score in ascending order:
[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
The total number of students is:
[tex]n =20[/tex]
Extract the students that passed (scored 70 and above)
[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
Their numbers are:
[tex]Passed: 14[/tex]
So, the fraction of those that passed is:
[tex]Fraction = \frac{Passed}{n}[/tex]
[tex]Fraction = \frac{14}{20}[/tex]
Reduce fraction
[tex]Fraction = \frac{7}{10}[/tex]
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
Line AB = line AC
Write down the size of
a) angle BAC
b) angle ABC
c) angle ADC
d) angle COB
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
The sum of 10 and twice Mai’s age
Answer:
Can I get the full question please
Step-by-step explanation:
x + y = 10 - - - 1
x=2y - - - - - 2
Putting the value of x in eqn 1,
2y+y=10
y=10/3
=3.33 yrs
Which i feel is incorrect
A baseball is hit with an initial upward philosophy of 70 ft./s from a height of 4 feet above the ground. The equation h= -16x^2+70t+4 models the height in feet , t, seconds after it is hit. After the ball gets to its maximum height it comes down in his caught by another player at a height of 6 feet above the ground. About how long after it was hit does it get caught
Answer:
x=4.34 seconds
Step-by-step explanation:
-16x^2+70x-2=0
[tex]x=\frac{35+\sqrt{1193}}{16}[/tex]
x=4.34
You can solve a system of equations by translating it into a matrix,manipulating the matrix until it has eliminated terms,and then translating it back to equations
Answer:
True
Step-by-step explanation:
A system of equations can be solved by Translating the system of equations into a matrix by following theses steps
list all coefficients in a single matrix multiply the coefficient matrix with the variables matrixenter answers into a new matrixwrite out the resulting answer in form of equations.
Please help me on this imagine math question!
Answer: the 24 oz hazelnuts
Step-by-step explanation:
Answer:
hazelnuts
Step-by-step explanation:
pecans = $15.2/16= .95
cashews = 5.60/8=.7
almonds = 20.48/32= .64
hazelnuts = 13.5/24 = .56
HELP PLEASEEEEE!!!!!!!
If (a,3) is the point lying on the graph of the equation 5x + 2y = -4, Then find a.
Answer:
I've attached the Answer
Answer:
a = - 2
Step-by-step explanation:
Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.
Find a :
Equation : 5x + 2y = - 4
5 ( a ) + 2 ( 3) = - 4
5a + 6 = - 4
5a + 6 - 6 = - 4 - 6 [ subtracting both sides by 6 ]
5a + 0 = - 10
5a = - 10
a = - 2 [ dividing both sides by 5]
[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4
5(-2) + 2( 3 ) = - 4
- 10 + 6 = - 4
- 4 = - 4 ]
What are the values of x in the equation x2 - 6x + y =
A)x= -2 or x = 8
B)x= -1 or x = -11
C)x= 1 or x = 11
D)x = 2 or x = -8
a rule in quadratic equ states that
if summation of the roots should be -b/a of the equa
comparing the equ x² - 6x + y=0
with. ax² + bx +c =0
we see that in the equ, a= 1, b=-6
so the sum of the roots is -(-6)/1= +6
looking the the option the only one that agreed is option A
-2 + 8= 6
there fore the values of x are -2 or 8
Michelle decides to ride her bike one day. First she rides her bike due south for 12 miles, then the direction of the bike trail changes and she rides in the new direction for a while longer. When she stops, Michelle is 2 miles south and 10 miles west from her starting point. Find the total distance that Michelle covered from her starting point.
Answer:
Total Distance Michelle Covered is 26.14 miles
Step-by-step explanation:
According To the Question, We Have
Michelle First Ride Her bike In 12 miles South, then Changed her Direction & Ride Bike For A long While, and when she stopped she find Herself 2 miles south and 10 miles west from starting point. that shows she change direction and start walking in South-West Direction.
(For Diagram, Please Find in attachment)
In Triangle ABC , Apply Phythagorus Theorem
AB² = BC² + AC²
AB² = 10² + 10²
AB² = 200
AB = √2×10 ⇔ 14.14 miles
Now The Total Distance Travelled by Michelle Would be
OA + AB = 26.14 miles
Find the circumference of this circle.
Use 3.14 to approximate a.
C=2ar
14 ft
C = [?] ft
Answer:
circumference of a circle =2 pi r
radius=14/2=7
2×3.14×7=43.96ft
The circumference of the circle is 43.96 ft.
Given,
Diameter of the circle = 14 ft
π = 3.14
We need to find the circumference of a circle.
What is the circumference of a circle?The circumference is the total length of the surface of the circle.
The circumference is given by:
= 2πr
r = radius of the circle
Diameter = 2radius
Example:
We have,
Diameter = 14 ft
π = 3.14
Radius = diameter / 2 = 14/2 = 7 ft
Circumference:
= 2πr
= 2 x 3.14 x 7
= 43.96 ft
Thus the circumference of the circle is 43.96 ft.
Learn more about circles here:
https://brainly.com/question/16125353
#SPJ2
A right triangle with the leg lengths of 7ft and 10ft. Using this information, find the length of the hypotenuse. Then round your answer to the nearest hundredth.
Answer:
12.21
Step-by-step explanation:
Explanation:
This is a right triangle, so the Pythagorean Theorem applies.
The Pythagorean Theorem states that the sum of the squared legs of a triangle is equal to the squared hypotenuse.
The legs of a triangle are the sides that form the right angle.
The hypotenuse of a triangle is the longest side.
Formula/solve:
[tex]a^2+b^2=c^2[/tex]
[tex]a,b-legs[/tex]
[tex]c-hypotenuse[/tex]
Here, I am solving for the hypotenuse.
[tex]7^2+10^2=c^2[/tex]
[tex]49+100=c^2[/tex]
[tex]149=c^2[/tex]
Conclude:
The last step is the cancel out c² by finding the square root of 149.
149 is not a perfect square, so I must round the square root to the nearest hundredth.
[tex]12.2065556157[/tex] ≈ [tex]12.21[/tex]
I, therefore, believe the length of the hypotenuse is 12.21 feet.
Write the expanded form of the expression.
y(0.5+6)
y(0.5+ 6) =
(Simplify your answer. Use integers or decimals for any numbers in the expression.)
help please asap just the answers
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]
7.) Detemine the value of [tex] \sf{ {3a}^{2} -b.}[/tex]
[tex] \huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]
[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]
[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶12-( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶12 + 1 }[/tex]
[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}[/tex]
8.) Find the value of [tex] \sf{ {a}^{3} {b}^{3} - abc.}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}[/tex]
[tex]\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]
Given 3x+y=1
Write the equation in general form Ax+By+C =0
3* -y+=0
-3x +y-1=0
3x-y=-1
QUESTION:- Given 3x+y=1
Write the equation in general form Ax+By+C =0
3x-y+1=0
-3x +y-1=0
3x-y=-1
[tex]3x + y - 1 = 0 \: \: ✔[/tex]
ANSWER:-
Equation-->[tex]3x + y = 1 [/tex]
Form of the given equation->
[tex]Ax + By = C[/tex]
so we need to change the side of the C !
while changing side of C we need to change the sign of C !
[tex] \bold{ \red{SO :- }}[/tex]
[tex]3 x + y = 1 \\ 3x + y - 1 = 0[/tex]
FORM OF THE RESULTED EQUATION:-
[tex]Ax + By + C = 0 \\
A = 3 \\ B = 1 \\ C = - 1[/tex]
Otis and his 2 brother went to their favorite restaurant. Their total bill was $22.42. They used a coupon for 20% off of the total bill. If they split the bill evenly, how much will each person owe, to the nearest cent?
Answer:
$ 5.98
Step-by-step explanation:
20/100 × 22.42/1 = $ 4.48
$ 22.42 - $ 4.48 = $ 17.94
If they split that bill in two each would pay $ 5.98
I hope this helps.
can someone help me with this maths question? workings would be appreciated :]
Adrian, Ben and Charlie share some sweets in the ratio 8:5:10
Charlie got 20 more sweets than Adrian.
Work out the total amount of sweets.
Answer:
total amount of sweets=230
Step-by-step explanation:
ratio=8:5:10
total ratio=8+5+10
=23
Adrian=x
Charlie= x+20
Ben=1/2×(x+20)
Charlie's share
10/23×(x+20+x+(1/2×x+20))=x+20
10/23×(x+20+x+(x+20/2))=x+20
10/23×(x+20+x+x+20/2)=x+20
10/23×(2(x+20)+(2×x)+(x+20/2)/2=x+20
10/23×(2x+40+2x+x+20)/2=x+20
10/23×(2x+2x+x+40+20)/2=x+20
10/23×(5x+60)/2=x+20
50x+600/46=x+20
50x+600=46(x+20)
50x+600=46x+920
50x-46x=920-600
4x=320
4x/4=320/4
x=80
Total amount of sweet
x+x+20+1/2(x+20)
80+80+20+1/2(80+20)
180+1/2(100)
180+50
230
3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]
3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex][tex]\huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 1 \: = \: 6000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 1\: = \: 2.0\: m/s}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 2\: = \: 3000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 2\: = \: 3.0\: m/s}[/tex]
[tex]\huge\underline{\sf{\red{Fomula:}}}[/tex]
[tex]\quad\quad\quad\quad\boxed{\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}}[/tex]
[tex]\huge\underline{\sf{\red{Solution:}}} [/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(6000 \: kg)(2.0\:m/s)+(3000\:kg)(3.0\:m/s)}{(6000\:kg)+(3000\:kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(12,000kgm/s)+(9,000\:kgm/s)}{(9,000kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \: kgm/s}{9000kg}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \cancel{ \red{ kg}}m/s}{9000 \cancel{ \red{kg}}}}[/tex]
[tex]\quad\quad\quad\quad \sf{vf\: = \boxed{ \sf{ 2.33 \:m /s}}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad\quad \underline{ \sf{\boxed{ \sf{ \red{ 2.33 \:m /s}}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]
[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]
ฅ^•ﻌ•^ฅ
Type the correct answer in each box.
Find the volume of the irregular
figure
1 cm
3 cm
?] cm3
3 cm
1 cm
10 cm
5 cm
Answer:
Step-by-step explanation:
volume of reqd. figure=10×5×1+3×3×1=50+9=59 cm³
What is the x value of the solution to the system of equations
4y=2x+8
Y=-x+2
Answer:
x=0;y=2
Step-by-step explanation:
4(-x+2)=2x+8 -4x+8=2x+8 -4x-2x=8-8 -6x=0 x=0 y=-x+2 y=0+2 y=2
A bicycle shop owner offers five styles of mountain bikes for $450, $275, $675, $490, and $300. He wants to increase the mean price but keep the median price and range of prices the same Suggest a new set of prices for the five styles. (Show All Work)
Answer:
275, 300, 450, 490, 675
Median: 450
Q1: 287
Step-by-step explanation:
Can someone helppppp and explain plsss:))
Answer:
Step-by-step explanation:
Find one value of x that is a solution to the equation:
(x^2+4)^2 – 11(x^2+4) + 24 = 0
Answer:
x = ±2
x = ±i
Step-by-step explanation:
(x^2+4)^2 – 11(x^2+4) + 24 = 0
Let m = x^2 +4
(m)^2 – 11(m) + 24 = 0
Solving this quadratic
What two numbers multiply to 24 and add to -11
-8*-3 =24
-8-3 = -11
(m-8)(m-3) =0
m = 8 m=3
Now substitute back
x^2 +4 = 8 x^2 +4 = 3
x^2 +4-4 = 8-4 x^2+4-4 = 3-4
x^2 = 4 x^2 = -1
Taking the square root
sqrt(x^2) = sqrt(4) sqrt(x^2) = sqrt(-1)
x = ±2 x = ±i
Answer:
one value of x = 2
Step-by-step explanation:
[tex](x^2 + 4 )^2 - 11(x^2 + 4 ) + 24 = 0\\\\x^4 + 16 + 8x^2 - 11x^2 -44 + 24 = 0\\\\x^4 - 3x^2 -4 = 0\\\\[/tex] ------ ( 1 )
[tex]Let \ x^2 \ = \ u[/tex]
( 1 ) => [tex]u^2 - 3u - 4 = 0[/tex]
[tex]u^2 -4u + u - 4 = 0\\\\u(u - 4) + 1 (u - 4) = 0\\\\(u + 1) (u - 4) = 0\\\\u = -1 \ , \ u = 4[/tex]
[tex]=> x^2 = - 1 \ and \ x^2 = 4[/tex]
[tex]x = \sqrt {-1} = i[/tex]
[tex]x = \sqrt{4} = \pm 2[/tex]
If sally completed 6 laps around a circular track with the dimensions shown below, how many meters will she have run? Use 3.14 for up and round your answer to the nearest tenth
Answer/Step-by-step explanation:
The diagram of the circular track is missing, and so also its dimensions.
However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.
Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.
Circumference = πd
d = 20 m (we are assuming the diameter is 20 meters)
π = 3.14
Circumference of circular track = 3.14 × 20 = 62.8 m.
This means that 1 lap = 62.8 m that she would have to run.
Therefore,
6 laps would be = 6 × 62.8 = 376.8 m
Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.