(a) The force the ground exerts on each set of rear wheels when the plane is at rest on the runway is 0.743 MN.
(b) The force the ground exerts on the front set of wheels is 0.239 MN.
Center mass of the airplaneThe concept of center mass of an object can be used to dtermine the mass distribution of the airplane along the line through the center.
Some assumptionsThe wheels under the wind do not pass through the center line.The position of the front wheel is constant and it is zero mark (origin).The rear wheels are at 21.7 m markPosition of the center mass of the plane is calculated as follows;
Let the position of the center mass, Xcm = y
the center mass is 3 m in front of rear wheels, that is
21.7 - y = 3
y = 21.7 - 3
y = 18.7 m
Xcm = 18.7 m
Mass of the plane at the position of the rear wheelsLet the mass of the plane at front wheels = M1
Let the mass of the plane at rear wheels = M2
[tex]X_{cm} = \frac{M_1x_1 + M_2x_2}{M_1 + M_2}[/tex]
[tex]18.7 = \frac{M_1(0) + M_2(21.7)}{177000} \\\\3,309,900 = 21.7M_2\\\\M_2 = \frac{3,309,900}{21.7} \\\\M_2 = 152,529.95 \ kg[/tex]
Force exerted by the ground on each rear wheelThere are two rear wheels, and the force exerted on each wheel due to mass of the airplane at this position is calculated as follows;
[tex]W = mg\\\\W_1 = W_2 = \frac{1}{2} (mg) = \frac{1}{2} (152,529.95 \times 9.8) = 743,396.76 \ N= 0.743 \ MN[/tex]
Mass of the plane at the position of the front wheelM1 + M2 = 177,000
M1 = 177,000 - M2
M1 = 177,000 - 152,529.95
M1 = 24,470.05 kg
Force exerted by the ground on the front wheelW = mg
W = 24,470.05 x 9.8
W = 239,806.5 N = 0.239 MN
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A student uses a motion detector to study the kinematics of a block suspended on a vertical spring that obeys Hooke’s law. The student pulls the block a distance y from equilibrium, releases it from rest, and records the speed v of the block as it passes the equilibrium position. The student repeats this process several times for different values of y. Which variables should be plotted on the horizontal and vertical axes to yield a linear graph?
When the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.
Hooke's lawHooke's law states that force or load applied to elastic material is directly proportional to the extension produced in the material. This law can be written as;
F = kx
where;
F is the applied forcek is spring constantx is extension of the materialVelocity of the blockThe speed of the block increases with decreasing displacement of the bock. This is because the kinetic energy of the block is maximum at zero displacement and minimum at maximum displacement of the block.
Thus, when the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.
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What is the magnitude of the electric field at the dot in the figure?
The magnitude of the electric field at the dot is : 10⁴ v/m
Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field
Determine the magnitude of the electric field at the dotchange in voltage = E .d
100 - 0 = E * ( 1 * 10⁻² m ) ----- ( 1 )
From equation ( 1 )
The magnitude of E = 100 v / ( 1 * 10⁻² m )
= 10⁴ v/m
Hence we can conclude that The magnitude of the electric field at the dot is : 10⁴ v/m
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A ball is dropped off of a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window what is the distance from the top of the building to the top of the window?
Answer:
oh what do you believe this one
While cruising on the high sea at speed of v = 22 km/hr, a cargo ship suddenly encounters a problem with its propeller shaft leading to the main engine being shut down. This causes the vessel to slow down to 12 km/hr over the next 14 minutes. Assuming that its deceleration profile is following a correlation of as a = -0.85ct², where c is the acceleration constant for any time t, determine; i) The magnitude for constant c from the two boundary limits of deceleration profile given above, and ii) Plot against the timescale for same interval above, a total distance covered by the vessel as it's slowing down from 22 km/hr to 12 km/hr. Also plot the speed profile for the vessel during that 14 minutes' span.
Answer:
how can you support to leprosy victims?
A crate of oranges is shoved across a grocery store floor with a force of 100 N for a distance of 1 meter. The crate travels an additional 1 meter after the shove and stops just short of the display. You can conclude: the magnitude of work done by frictional forces on the crate is 100 J the magnitude of work done by the applied force on the crate is 100 J the magnitude of the force of friction on the crate is 50 N all of the above conclusions are correct none of the above conclusions are correct
The statements that are true are;
the magnitude of work done by frictional forces on the crate is 100 Jthe magnitude of work done by the applied force on the crate is 100 JWhat is work done?Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.
Hence, the following are true;
the magnitude of work done by frictional forces on the crate is 100 Jthe magnitude of work done by the applied force on the crate is 100 JLearn more about work: https://brainly.com/question/18094932?
Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the specific heat capacity of water is 4200 kg −1K −1 and the final temperature of the mixture is 70℃, determine the value of m.
The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
Determine the value of mApplying the principle of energy conservation
Heat lost by the hot body = heat absorbed by the cold water + calorimeter
= m * 4200 * ( 100 - 70 ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )
= m * 126000 = 110250
therefore ;
m = 110250 / 126000
= 0.875 kg
Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
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If a car takes 3500j of total energy to make 1200j of useful energy, how energy efficient is it
Answer: 34%
Explanation: eff = (Eout/Ein) *100(for % form)
1200/3500 * 100 = 34%
"A ball with a mass of 0.1 kg is rolling at a velocity of 5 m/s. What is its
momentum?" What Given is the 5 in this problem? *
mass
velocity
acceleration
momentum
Answer:
velocity
Explanation:
because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.
What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 kg⋅m3⋅s−2⋅C−2
[tex]\text{Given that,}\\\\\text{Electric field strength,}~ E = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} = \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle is}~2.1609\times 10^{-11} ~C[/tex]
If an object accelerates from rest, with a constant acceleration of
10 m/s2, what will its velocity be after 2 s?
Answer: 20 m/s
Explanation:
Acceleration = change in velocity / time → 10 m/s^2 = final velocity - 0 (original velocity) / 2s → final velocity = 20 m/s
What potential difference is required across an 32 -Ω resistor to cause 33.72 A to flow through it?
[tex]\text{Voltage,}~ V = IR =33.72\times 32 = 1079.04~ \text{volt}[/tex]
Two identical spheres, A and B, carry charges of
+6 microcoulombs and -2 microcoulombs,
respectively. If these spheres touch, what will be
the resulting charge on sphere A?
The resulting charge in sphere A from the two given different charges is determined as +2 μC.
Resulting of the two speheres
The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;
Resulting charge = +6 μC - 2 μC
Resulting charge = +4 μC
Charge in sphere AThe resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.
Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC
Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.
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Explain the differences between horticulture and agriculture.
[tex] \tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}[/tex]
[tex] \text{\underline\red {Horticulture}}[/tex]
The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.
[tex] \text{\underline\green{Agriculture}}[/tex]
It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.
Hope This HelpsThree identical 6.67-kg masses hang at rest from three identical springs, numbered as in the figure. Each spring has an unstretched length of 0.23 m and a spring constant of 8.13 kN/m. How long, L , is spring 2?
[Hint: Draw some FBDs and apply Newton's second law. Remember to account for both the spring's stretch and its unstretched length.]
The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
Extension of the spring 2
The extension of the spring 2 is determined from the net force acting on spring 2.
F(net) = Kx
Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.
Net force on spring 2 = (force on 2 + force on 3) - (force on 1)
F(net) = (m₂ + m₃)g - (m₁)g
F(net) = (6.67 + 6.67)9.8 - (6.67)9.8
F(net) = 130.732 - 65.366
F(net) = 65.366 N
x = F/k
x = (65.366)/(8130)
x = 0.00804 m
The length of spring 2 = x + 0.23 m
= 0.00804 m + 0.23 m = 0.238 m
Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
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In absence of friction, to bring an object to rest
a. a force must act in the same direction of its direction of motion
b. a force may not be necessary
C. the object will come to rest by itself
d. a force must act in the opposite direction of its direction of motion
16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current drawn b) The quantity of electricity in Coulombs taken in 5 minutes c) The energy absorbed in 100 hours.
Answer:
If by 1.5 MJ you mean 1.5E6 Joules then
W = P t = power X time
W / t = P power
P = 1.5E6 J / 600 sec = 2500 J / s
P = I V
a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps
b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs
c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules
Differences between fundamental and derived quantities
Answer:
Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.
Three-Dimensional Thinking
2. Aiden collected canned goods for a neighborhood service project. He
pulled a plastic wagon behind him to put the items in. From the time
Aiden began until he finished collecting, the mass of the wagon tripled.
The walk back to Aiden's house was downhill and the speed of the
wagon tripled. What happened to the kinetic energy when the mass
tripled? What happened to the kinetic energy when the speed tripled?
A
When the speed tripled, the kinetic energy increased by a factor of 3.
B
When the mass tripled, the kinetic energy increased by a factor of 3.
When the mass tripled, the kinetic energy increased by a factor of 3.
When the speed tripled, the kinetic energy increased by a factor of 9.
When the mass tripled, the kinetic energy increased by a factor of 9
When the speed tripled, the kinetic energy increased by a factor of 3.
When the mass tripled, the kinetic energy increased by a factor of 9.
When the speed tripled, the kinetic energy increased by a factor of 9.
с
D
Answer:
A.
Explanation: both triple by 3
Answer: B
Explanation: It is because the formula for this eq is KE=V^2. In the eq, it says that the mass is triple meaning the KE also must have tripled. For the speed, since it has a formula then you just have 3^2 which is 9.
Calculate The pressure produced by a force of 392 N acting on an area of 8.0 m^2
Answer:
Explanation:
500-0.05=499.95
500-100+5=405
100+100=10000
Two bodies of specific heats S1 and S2 having the same heat capacities are combined to form a single composite body. What is the specific heat of the composite body?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Heat capacity of body 1 :
[tex]\qquad \sf \dashrightarrow \:m_1s_1[/tex]
Heat capacity of body 2 :
[tex]\qquad \sf \dashrightarrow \:m_2s_2[/tex]
it's given that, the the head capacities of both the objects are equal. I.e
[tex]\qquad \sf \dashrightarrow \:m_1s_1 = m_2s_2[/tex]
[tex]\qquad \sf \dashrightarrow \:m_1 = \dfrac{m_2s_2}{s_1} [/tex]
Now, consider specific heat of composite body be s'
According to given relation :
[tex]\qquad \sf \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2[/tex]
[tex]\qquad \sf \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}[/tex]
[tex]\qquad \sf \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }[/tex]
[ since, [tex] m_2s_2 = m_1s_1 [/tex] ]
[tex]\qquad \sf \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}[/tex]
[tex]\qquad \sf \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{ \cancel{m_2}(\frac{s_2}{s_1} + 1)}[/tex]
[tex]\qquad \sf \dashrightarrow \:s' = \dfrac{ 2 s_2}{ (\frac{s_2 + s_1}{s_1} )}[/tex]
[tex]\qquad \sf \dashrightarrow \: s' = \dfrac{2s_1s_2}{s_1 + s_2} [/tex]
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Two people work together to move a heavy box. One person pulls the box with a force of 200 Newtons. The other person pushes the box with a force of 150 newtons. The force of friction on the box is 400 newtons. Which of the following BEST describes what will happen to the box and people?
A. The person pushing the box will move the box towards the person pulling it.
B. The box will accelerate in the direction of the frictional force.
C. Both people will accelerate in the direction of friction, but the box will remain stationary.
D. Neither the box nor people will move.
Answer:
D. Neither the box nor people will move.
Explanation:
We are given three forces that are present on the box and friction is the result of someone trying to move the box. The net force of the people pulling/pushing is barely 50 Newtons which doesn't compare with the frictional force of 400 Newtons, you will need to surpass a net force of 400 Newtons in order for the box to START moving.
enumerate two ways that you practice to control manage noise pollution
1.
2.
please answer it correctly i really need it
nonsense-report
what are the three gases our atmosphere is mainly composed of
Answer:
the three gases our atmosphere is mainly composed of are nitrogen oxygen and carbon
Write any two differences between series combination and parallel combination of cells.
Answer:
Your answer is attached above
Hope it helps
TC
have a great time
A tire on a car is rolling smoothly. Its center of mass is moving at 18 m/s. How fast is the top of the tire moving in m/s
For a tire on a car is rolling smoothly and It's center of mass is moving at 18 m/s, the speed of the top of the tire is mathematically given as
Vtop=36m/s
What is the speed of the top of the tire?Generally, the equation for the relationship between the top and the core is mathematically given as
Vtop=2*(vcore)
Threrefore
Vtop=2*18
Vtop=36m/s
In conclusion, the speed of the top
Vtop=36m/s
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Give at least 2 reasons why the descendants of the Gullah Geechee people in Cool Spring, South Carolina, continue to practice horticulture.
The 2 reasons why the descendants of the Gullah Geechee continued to practice horticulture include the following:
To preserve their cultural heritage.To provide sources for their staple food.What is Horticulture?This is the branch of plant agriculture dealing with garden crops, generally fruits, vegetables, and ornamental plants.
The descendants of the Gullah Geechee were made to work on farms which comprised mostly of rice and cotton. They preserve their culture which is why horticulture is practised.
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When people are interested in changing their personalities, they are usually most interested in
a.more turbulent less feeling
b.more judging less extroverted
c.more neurotic less assertive
d. More extroverted less neaurotic
When people are interested in changing their personalities, they are usually most interested in more neurotic less assertive.
What is personality?Personality makes up an individual, they are the features or characteristics that forms an individual.
Each individual is made of distinctive character which makes one of different from other.
Therefore, when people are interested in changing their personalities, they are usually most interested in more neurotic less assertive
Learn more on personality here,
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The hot exhaust from a rocket travels in one direction, and the rocket travels in the opposite direction. This is an example of?
A. Equal and opposite forces.
B. Friction.
C. Balanced forces.
D. Inertia.
Answer:
Explanation:
The hot exhaust from a rocket travels in one direction, and the rocket travels in the opposite direction. This is an example of?
A. Equal and opposite forces.
B. Friction.
C. Balanced forces.
D. Inertia.
How does the gravitational force between two objects change if the distance between the objects doubles?
a)
The force decreases by a factor of 4.
b)
The force decreases by a factor of 2.
c)
The force increases by a factor of 4.
d)
The force increases by a factor of 2.
if the distance between the objects is doubled the force is reduced by a factor of 4
Whats is gravitational force?Gravitational force is the force of attraction between objects in the universe.
f = G * m1 * m2 / r^2
f = gravitational force
G = gravitational constant
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects
From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4
Therefore: The force decreases by a factor of 4.
hope it helps
What is the solution of this?
Answer:
1.2 is the correct answer due to the graph
Explanation:
math teacher