A bug starts at point A, crawls 8.0 cm east, then 5.0 cm south, 3.0 west, and 4.0 cm north to point B.

Question:
How far north and east is B from A?

Find the displacement of the turtle from the origin at the point.​

Answer:

a=0.5g ms^-2

Explanation:

Let tension be T

acceleration be a

g be gravitational acceleration 9.81ms^-2

They share same T and a

by force diagram the net force on m:

T-2.1g=2.1a

net force on M:

6.3g-T=6.3a

solve:

(T-2.1g)/(6.3g-T)=2.1a/6.3a

3T+T=12.6g

T=3.15g newton

3.15g-2.1g=2.1a

a=0.5g ms^-2

Answer:

Please see below as the answer is self-explanatory.

Explanation:

       [tex]v_{avgx} = v_{o}*cos 50 = 67 m/s * cos 50 = 43.1 m/s (1)[/tex]

       [tex]t = \frac{\Delta x}{v_{avgx} } = \frac{400m}{43.1m/s} = 9.3 s (2)[/tex]

       [tex]\Delta y = v_{oy} * t - \frac{1}{2} *g*t^{2} (3)[/tex]

       [tex]v_{oy} = v_{o}*sin 50 = 67 m/s * sin 50 = 51.3 m/s (4)[/tex]

       [tex]\Delta y = (53.1m/s * 9.3s) - \frac{1}{2} *9.8m/s2*(9.3s)^{2} = 53.5 m (5)[/tex]

Answer:

An object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Forces are "pushes" or "pulls" on the object, and forces, like velocity and acceleration are vector quantities.

Answer:

Wavelength

Explanation:

Answer:

Wavelength if it's the horizontal distance. Wave Height if it's vertical distance.

Explanation:

Answer:

B

Explanation:

the reason the small turtle has more momentum is because it was less an example is I have two rocks a rock that weighs 1 oz and another rock that weighs half a pound the one that is half a pound Falls faster in the one that weighs an ounce Falls last hopefully that makes sense

Answer:

that should be the right answer

Answer:

That energy is the elastic potential energy of the rubber band. At the bottom position, all the energy is being stored in the stretched rubber band, in the form of elastic potential energy.

Explanation:

When the glider reaches the bottom, its kinetic energy and potential energy become zero due to zero velocity and zero height, respectively. So, the sum of these energies will become zero. This will violate the law of conservation f energy. Hence, there must be a third type of energy that accounts for the conservation of the energy of the system at other configurations.

That energy is the elastic potential energy of the rubber band. At the bottom position, all the energy is being stored in the stretched rubber band, in the form of elastic potential energy.

Answer:

56.55 m/s

Explanation:

Frequency=1/T

1/6 = 0.1666666

V=(2*pi*1.5)/0.166666

Answer:

AC)=(AB)2+(BC)2−−−−−−−−−−−−√=42+32−−−−−−√

⇒displacement=16+9−−−−−√=25−−√=5m

Answer:

i THINK it’s false. You don’t have to give me points ;-;

Explanation:

Answer:

i think false and true is spelt wrong lol

Explanation:

Answer:

The surface of Mercury has landforms that indicate its crust may have contracted. They are long, sinuous cliffs called lobate scarps. These scarps appear to be the surface expression of thrust faults, where the crust is broken along an inclined plane and pushed upward.

Explanation:

I hope this helps a little bit.

Answer:

Fb = 490.4 N

Explanation:

       [tex]F_{b} = \rho * V * g (1)[/tex]

       [tex]V = \frac{4}{3}*\pi * R^{3} = \frac{4}{3} *\pi *(2.1m)^{3} = 38.8 m3 (2)[/tex]

       [tex]F_{b} = \rho * V * g = 1.29 kg/m3* 38.8m3*9.8m/s2 = 490.4 N (3)[/tex]

Answer: C. Charge and distance

Answer:

The period is more, but not doubled.

Explanation:

Recall that the period of a mass on a spring is T=2πmk.

Answer:

20mm per second

Explanation:

lol

Answer:

Weight

Explanation:

We call it "Ralph" or "the object's weight".

Answer:   Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form. An internal combustion engine provides a good example of the ease with which gases can be compressed.

Explanation:

Answer:Mass of the body = 20 kg.

Final Velocity = 5.8 m/s.

Initial velocity = 0

Time = 3 seconds.  

Using the Formula,  

Acceleration = (v - u)/ t

= (5.8 - 0)/ 3

= 1.6 m /s².

Now, Using the Formula,  

Force = mass × acceleration

= 20 × 1.6

=

Explanation: I REALLY  HOPE THIS HELPS I'M KINDA NEW AT THIS :] :]

The magnitude of requires force, that is exerted on a 20 kg mass to give it an acceleration of 10.0 m/s^2 is 200 Newton.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given parameters:

Mass of the object: m = 20 kg.

Acceleration of the object: a = 10.0 m/s^2.

Hence, according to Newton's 2nd law of motion:

the magnitude of requires force = mass ×acceleration

= 20 × 10 Newton

= 200 Newton.

Hence, the magnitude of requires force is 200 Newton.

Learn more about force here:

https://brainly.com/question/13191643

#SPJ5

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

Answer:

v = 3.74 m/s

Explanation:

Given that,

The acceleration of the object in circular path, a = 0.4 m/s²

The radius of the circle, r = 35 m

We need to find the velocity of the object. The acceleration of an object on the circular path is given by :

[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{0.4\times35}\\\\v=3.74\ m/s[/tex]

So, the velocity of the object is equal to 3.74 m/s.

Answer:

gravitational potential energy

Explanation:

Projectile motion, Bernoulli's principle, and Magnus Effect.

Sure I would be happy to discuss projectile motion!

I'll do it if you mark brainliest :) I need the points thanks

Answer:

Explanation:

He first thought of his system of gravitation which he hit upon by observing an apple fall from a tree,

The incident occurring in the late summer of 1666.

Hi there!

[tex]\large\boxed{\text{C. 17.7m/s}}[/tex]

Use the following kinematic equation to solve:

vf² = vi² + 2(ad)

Since the initial velocity is 0 m/s because it started at rest, we can eliminate this part of the equation:

vf² = 2ad

Plug in the given acceleration and distance:

vf² = 2(9.8)(16)

vf ≈ 17.7. The correct answer is C.

Answer:

2

Explanation:

Because 2 waves 4 secs means 1 in 2s

The period of these waves is 2s. and The right option is A)2s.

The period of a wave is the time taken by a wave to complete one cycle.

The formula of period from the question is given below.

⇒ Formula:

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these value above into equation 1

Hence, The period of these waves is 2s.

The right option is A)2s

Learn more about period here: https://brainly.com/question/22059232

Answer:

The magnitude of the induced current is 4.73 x 10⁻³ A.

Explanation:

Given;

number of turns, N = 1

cross sectional area of the loop, A = 8.8  cm² = 8.8 x 10⁻⁴ m²

change in magnetic field strength, ΔB = 1.8 T -  0.5 T = 1.3 T

change in time, Δt = 1.10 s

resistance of the loop, R = 2.2 ohm

The magnitude of the induced emf is calculated as;

[tex]emf = \frac{NA \Delta B}{\Delta t} \\\\emf = \frac{1 \times 8.8\times 10^{-4} \times 1.3}{1.10} \\\\emf = 1.04 \times 10^{-3} \ V[/tex]

The induced current in the loop is calculated as;

[tex]I = \frac{emf}{R} \\\\I = \frac{1.04 \times 10^{-3}}{2.2} \\\\I= 4.73 \times 10^{-4} \ A[/tex]

Therefore, the magnitude of the induced current is 4.73 x 10⁻³ A

Answer:

C. amplitude = 0.10 m, wavelength = 0.60 m

Explanation:

The diagram shows an oscillating progressive wave, with its amplitude and wavelength.

Amplitude of a wave is the maximum distance covered either upward or downward.

So that,

amplitude of the wave, A = [tex]\frac{0.2}{2}[/tex]

                                          = 0.1

Amplitude of the wave = 0.1 m

Wavelength in this case is the distance from crest to crest, or trough to trough of the wave.

So that,

wavelength = [tex]\frac{1.5}{2.5}[/tex]

                   = 0.6

wavelength of the wave = 0.6 m

Therefore, the amplitude of the wave is 0.10 m, while the wavelength is 0.60 m.