A 2km long stretch of road needs to be resurfaced. The width of the road is 8.3m. Model this stretch of road as a rectangle.Work out the area of road that needs to be resurfaced in metre squared. Resurfacing this road costs £30 per square metre What is the total cost to resurface this road?

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

Answer:

The given relation is presented as follows;

[tex]\dfrac{1}{a} + \dfrac{1}{b} +\dfrac{1}{c} = \dfrac{1}{a + b + c}[/tex]

Where 'a', 'b', and 'c' are member of real numbers, we have;

a⁹, b⁹, and c⁹ are also member of real numbers

When a⁹ = x, b⁹ = y, and c⁹ = z

By the above relationship, we have;

[tex]\dfrac{1}{x} + \dfrac{1}{y} +\dfrac{1}{z} = \dfrac{1}{x + y + z}[/tex]

Substituting x = a⁹, y = b⁹, and z = c⁹, we get;

[tex]\dfrac{1}{a^9} + \dfrac{1}{b^9} +\dfrac{1}{c^9} = \dfrac{1}{a^9 + b^9 + c^9}[/tex]

Step-by-step explanation:

Answer:

y = 2*(x - 3)^2 - 2

Step-by-step explanation:

Remember that a quadratic equation of vertex (h, k) is written as:

y = a*(x - h)^2 + k

Where a is the leading coefficient.

So, if we know that the vertex is at (3, - 2)

we have:

y = a*(x - 3)^2 + (-2)

And we want the y-intercept to be (0, 16)

This means that, when we take x = 0, we must have y = 16

if we replace these in the above equation we get:

16 = a*(0 - 3)^2 - 2

now we can solve this for a

16 = a*(-3)^2 - 2

16 = a*9 - 2

16 + 2 = a*9

18 = a*9

18/9 = a

2 = a

Then the quadratic equation is:

y = 2*(x - 3)^2 - 2

Answer:

5 shirts

Step-by-step explanation:

Y=12x+3 equation 1

y=8x+23 equation 2

12x+3=8x+23 substituting y value will cause equations to equal

4x=20

x=5 shirts

check answer

y=12x+3

y=12(5)+3

y=60+3

y=63

y=8x+23

y=8(5)+23

y=40+23

y=63

Answer:

correct bayan HAHAHAHAHAHA

Step-by-step explanation:

answers I the above photo

some of the questions are not clear

Answer:

1. C(13inches)

2. A(40°)

3. B(126°)

4. C(50°)

5. 7cm

Step-by-step explanation:

According To the Question,

1. Given, The sum of all the sides of a STOP sign is 104 inches. A STOP sign is Octagon  with all sides equal.

Thus, Octagon has 8 equal side

So, Each Side Measure = 104/8 ⇔ 13inches

2. Given, In Triangle ABC, ∠A & ∠B each measure 70°

And, We Know Sum of all angles of a triangle is 180°.

Thus, ∠C = 180° - (∠A + ∠B)  ⇔  180°-140° ⇒ 40°

3. Given, The measures of the three angles of a quadrilateral are ∠A=49° ,∠B=58° & ∠C=127° .

And, We know sum of all angles of quadrilateral is 360°.

Thus, ∠D=360° - (∠A+∠B+∠C)  ⇔ 360°-234° ⇒ 126°

4. Given, The measure of all the Four angles of a quadrilateral are ∠A=(x+40)°, ∠B=130°, ∠C=x° & ∠D=(2x-10)° .

And, We know sum of all the angles of quadrilateral is 360°.

Thus, ∠A+∠B+∠C+∠D = 360°

Put all the Values, we get

x+40+130+x+2x-10 = 360

4x+160 = 360

4x = 200 ⇔ 200/4 ⇒ 50°

5. Given, the length of the two sides of an isosceles triangle are 3cm and 7cm .

Now, in order to form a triangle the sum of any two side of a triangle is always greater than the third side of a triangle.

So, We have an isosceles triangle in which two sides is always equal & we have given two sides of 3cm & 7cm .

Assume, if third side be 3cm (First Side+Third side > Second side)

3+3 ⇒6cm which is not greater than 7cm(thus, the Triangle not possible if we assume 3cm as triangle's third side)

Hence, The other Side of Triangle Surely be 7 cm.  

Answer:

[tex]18 + 18 + 18 = 18 \times 3 = 54[/tex]

Step-by-step explanation:

I ain't sure but it might help you out:D

Answer:

140.3 cm²

Step-by-step explanation:

area of an equilateral triangle

[tex] = \frac{\sqrt{3} }{4} {a}^{2} [/tex]

where a is the side of the triangle

[tex] = \frac{ \sqrt{3} }{4} \times {18}^{2} \\ = 140.3 \: cm {}^{2} [/tex]

Answer:

1. x = -6, -8, -90

2. solutions for [tex]-2x\geq 10[/tex] include -5, while -5 is not a solution for [tex]-2x>10[/tex]

Step-by-step explanation:

Answer:

I think it's D

Answer:

its D

Step-by-step explanation:

Answer:

1/11

Step-by-step explanation

There are 12 marbles in the bag. When we first pick we have 4 blue marbles. So 4 blue marbles/12 random marbles. When we pick blue and noted, there are 3 marbles in the bag because of we didn't put it back. So when we choose again there are 11 marbles and 3 blue marbles in the bag. Choosing a blue one case is 3/11.

The last part of this case is happening as a chain. So we need to multiply our two answers.

=4/12*3/11

=1/3*3/11

=1/11

Answer:

x = + 5/4 or x = - 5/4

Step-by-step explanation:

[tex]4 x^2 = 6\frac{1}{4}\\\\4 x^2 = \frac{25}{4}\\\\x^2 =\frac{25}{16}\\\\x = \pm \frac{5}{4}[/tex]

Answer:

it's B

Step-by-step explanation:

I'm quite sure it is. Hope it helps u

Answer:

7√10 / 10.

Step-by-step explanation:

7/√10

Multiply top and bottom by √10:

= 7√10 / 10

Answer:

[tex]Area = 52\sqrt3 \ ft^2[/tex]

Step-by-step explanation:

Area of trapezoid

                         [tex](\frac{a+ b}{2}) \times h[/tex]      -----------( 1 )

We will split the trapezoid into Triangle and rectangle. To find the height and full length of base.

[tex]sin 60 = \frac{opposite}{hypotenuse}[/tex]   [tex][ opposite \ in \ the \ equation \ \ is \ the \ height \ of \ the \ trapezoid ][/tex]

[tex]\frac{\sqrt3}{2} = \frac{opposite }{ 8}\\\\\frac{\sqrt3}{2} \times 8 = opposite\\\\4\sqrt3 = opposite[/tex]

Therefore, h = 4√3 ft

[tex]cos 60 = \frac{adjacent}{hypotenuse}[/tex]    [tex]adjacent \ in \ the\ equation \ is \ the\ base \ of \ the \ triangle ][/tex]

[tex]\frac{1}{2} = \frac{adjacent}{hypotenuse}\\\\\frac{1}{2} \times 8 = adjacent\\\\4 = adjacent[/tex]

Therefore, a = 11 feet, b = 11 + 4 = 15 feet

Substitute the values in the Area equation :

                                                [tex]Area = \frac{11 + 15}{2} \times 4 \sqrt3 = \frac{26}{2} \times 4\sqrt3 = 13 \times 4\sqrt3=52\sqrt3 \ ft^2[/tex]

Answer:

Step-by-step explanation:

cos(c)= x/ac

ac = cos32/9.4

ac =11.08

Answer:

Step-by-step explanation:

sin(58/9.4 = sin(90)/AC

AC= 11.08

Answer:

(a - b)^2 = 49 - 4b^2 +2ab

Step-by-step explanation:

Given: a^2 + b^2 = 7b (assuming A is really “a”)

b^2 + (2b - a)^2 = 7^2

Find; (a - b)^2

Plan: Use Algebraic Manipulation

Start with b^2 + (2b - a)^2 = 7^2 =>

b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.

a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms

a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>

a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2

(a - b)^2 = 49 - 4b^2 +2ab

Double Check: recalculated ✅ ✅

(a - b)^2 = 49 - 4b^2 +2ab

Answer:

[tex]\frac{7}{4.1}[/tex]

Step-by-step explanation:

the word ''to'' means over

do you have a clearer picture please? I can help :))

Answer:

40

Step-by-step explanation:

A +  B=75

A + C = 61

B = 5/3 *C

A+C * 5/3 = 75 then we got the answer

Answer:

A = 40

Step-by-step explanation:

A+B = 75

A+C = 61

Subtract

A+B = 75

-A-C = -61

----------------------

B-C = 14

B:C

5:3

for every 5B there are 3C

Replace B with 5/3 C

5/3C-C = 14

2/3C = 14

C = 21

A+C = 61

A +21 = 61

A = 40

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

Answer:

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

3 T + 4 B =425

T + B = 125

Where T is the number of tacos sold, and B is the number of burritos sold.

Multiplying the second equation by 3, and subtracting it to the first equation:

3 T + 4 B =425

3T + 3B = 375

___________

B =50

Replacing B in any equation:

T + B = 125

T +50 =125

T =125-50

T = 75

Feel free to ask for more if needed or if you did not understand something.

Answer:

c)  y = 8[tex]\sqrt{3}[/tex]

Step-by-step explanation:

in a 30-60-90° Δ the ratio of the sides, respectively, is 1: [tex]\sqrt{3}[/tex] : 2

if the side opposite the 30°∡ is 8 then 'y' is 8[tex]\sqrt{3}[/tex] and 'x' is 16

Consider that we need to find [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Given:

The functions are:

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

To find:

The function operations [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Solution:

We have,

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

Now,

[tex](a+b)(x)=a(x)+b(x)[/tex]

[tex](a+b)(x)=4x+9+3x-5[/tex]

[tex](a+b)(x)=7x+4[/tex]

Similarly,

[tex](a-b)(x)=a(x)-b(x)[/tex]

[tex](a-b)(x)=4x+9-(3x-5)[/tex]

[tex](a-b)(x)=4x+9-3x+5[/tex]

[tex](a-b)(x)=x+14[/tex]

And,

[tex](ab)(x)=a(x)b(x)[/tex]

[tex](ab)(x)=(4x+9)(3x-5)[/tex]

[tex](ab)(x)=12x^2-20x+27x-45[/tex]

[tex](ab)(x)=12x^2+7x-45[/tex]

And,

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{a(x)}{b(x)}[/tex]

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex]

Therefore, the required functions are [tex](a+b)(x)=7x+4[/tex], [tex](a-b)(x)=x+14[/tex], [tex](ab)(x)=12x^2+7x-45[/tex] and [tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex].

Answer:

bjkfkvdvdejij

Step-by-step explanation:

22333444 ijdcijsivjdivdvndk snciscicicnlvjavjadvj

Answer:

[tex] \sqrt[5]{96x {}^{7} y {}^{11} } = 2xy {}^{2} \sqrt[5]{3x {}^{2}y } [/tex]

Answer:

Here,

CD + DE = CD

x+10 + x+4 = 8

2x + 14 = 8

2x= -6

x= -3