2.75g NaCL is present
in 650g of Water. Is the solution saturated or unsaturated?
(Solubility of wäter is 0.33%6)

In the stepwise formation of [Cu(NH3)4]2 from [Cu(H2O)4]2, [Cu(NH3)4]2+ is formed in the second step.

A coordination compound is formed by the combination of a central metal ion or atom and one or more ligands. The central metal ion or atom is typically positively charged, and the ligands are generally negatively charged or uncharged molecules or ions that have at least one electron pair accessible for coordination.

The coordination complex is represented by a square bracket around the central metal ion, and the ligands are connected to it with a comma.Copper(II) sulfate (CuSO4) is a well-known example of a coordination compound. The Cu2+ ion is the central metal ion, and the four H2O molecules are the ligands in this case. It is represented as [Cu(H2O)4]2+.

In the stepwise formation of [Cu(NH3)4]2 from [Cu(H2O)4]2, the following steps are involved:In the first step, four H2O molecules are replaced by four NH3 molecules. The product of this step is [Cu(NH3)4(H2O)2]2+.The second step is the replacement of the remaining two H2O molecules by NH3.

This step produces the desired [Cu(NH3)4]2+ coordination compound.In short, the copper ion in [Cu(H2O)4]2+ loses two H2O molecules and gains four NH3 molecules, forming [Cu(NH3)4(H2O)2]2+. Then, two more H2O molecules are replaced by NH3, resulting in the formation of [Cu(NH3)4]2+. Therefore, [Cu(NH3)4]2+ is formed in the second step.

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The heat transferred to the surroundings is 644 J.

First, we need to calculate the heat absorbed by the solution, qrxn.

The reaction that takes place is:

AgNO₃(aq) + NaOH(aq) → AgOH(s) + NaNO₃(aq)

The balanced equation tells us that 1 mole of AgNO₃ reacts with 1 mole of NaOH to produce 1 mole of AgOH. The heat absorbed by the solution is given by:

qrxn = -mCΔT

where;

Since the volume of the solution is given in mL, we can convert it to g using its density:

m = Vρ = (59 mL + 65 mL) x 1.00 g/mL = 124 g

ΔT = 24.91 oC - 23.68 oC = 1.23 oC

qrxn = -124 g x 4.184 J/goC x 1.23 oC = -644 J

Note that the negative sign indicates that the reaction is exothermic and releases heat.

Next, we need to calculate the heat transferred to the surroundings, qsurr. Since the calorimeter is an isolated system, we know that:

qrxn = -qsurr

Therefore:

qsurr = 644 J

Note that the positive sign indicates that the heat is transferred to the surroundings, as expected for an exothermic reaction.

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Typically, you must identify the x- and y-axes, which represent the two variables being measured or compared, in order to label a graph.

The graph's shape must be examined in order to determine the type of relationship between the variables. The relationship is considered to be linear if the graph depicts a straight line. The relationship is non-linear if the graph shows a curve. To determine whether the relationship is positive or negative, you would also need to look at the line's slope and direction. The relationship is positive if the line slopes upwards from left to right; this indicates that as one variable rises, so does the other. The relationship is negative if the line slopes downward from left to right, indicating that one variable increases while the other decreases.

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The characteristics of combination and decomposition reactions are as follows:

Combination reactions are chemical reaction where two or more elements or compounds combine to form a single compound.

Decomposition reaction is a reaction in which chemical species such as chemical compounds break up into simpler parts or elements. Usually, decomposition reactions require energy input i.e. endothermic.

Combination reactions give off energy as heat when compounds are formed by joining bonds i.e. they are exothermic.

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Answer:

Neptunium with atomic mass 235 and atomic number 93

Explanation:

elimination of electron increases positive charge on an atom

The notation provided appears to represent a nuclear reaction. Specifically, it represents the formation of radioactive carbon-14 in the upper atmosphere through the reaction of nitrogen-14 and a cosmic ray particle. The notation can be interpreted as follows:

- The symbol on the left side of the equation (Box+ eta mathcal PI ^ 9) represents a nitrogen-14 atom with a mass number of 14 and atomic number of 7 (since nitrogen has 7 protons). The superscript η indicates that the nitrogen atom is bombarded with a cosmic ray particle (represented by the box symbol) and undergoes a nuclear reaction. The subscript 9 indicates the total number of nucleons (protons and neutrons) in the nitrogen atom.

- The arrow in the middle of the equation (←) indicates that a nuclear reaction is taking place.

- The symbol on the right side of the equation (u I ^ 0 +N mathcal P I ^ L) represents a carbon-14 atom with a mass number of 14 and atomic number of 6 (since carbon has 6 protons) and a hydrogen atom. The superscript 0 indicates that the carbon atom is neutral (has no charge). The superscript L indicates that the carbon atom is radioactive and will decay over time.

Overall, the notation represents the nuclear reaction that occurs when a cosmic ray particle collides with a nitrogen-14 atom in the upper atmosphere, resulting in the formation of a carbon-14 atom and a hydrogen atom.

Answer:

The amount of water that can be heated by 1,000.0 J of heat energy depends on the mass of water and the specific heat capacity of water.

Assuming the water is at an initial temperature of 20.0°C, we can use the formula:

Q = mcΔT

Where:

Q = heat energy (Joules)

m = mass of water (in grams)

c = specific heat capacity of water (4.184 J/g°C)

ΔT = change in temperature (final temperature - initial temperature)

Rearranging the formula to solve for the mass of water:

m = Q / (c*ΔT)

Plugging in the given values:

m = 1000 J / (4.184 J/g°C * (final temperature - 20.0°C))

Assuming the final temperature is 100.0°C (the boiling point of water at standard pressure), the calculation becomes:

m = 1000 J / (4.184 J/g°C * (100.0°C - 20.0°C))

m = 1000 J / (4.184 J/g°C * 80.0°C)

m = 2.39 grams

Therefore, 1,000.0 J of heat energy can heat 2.39 grams of water from 20.0°C to 100.0°C.

The hydroxide ion concentration, [OH-], for a solution with a pH of 4.65 is approximately 3.55 x [tex]10^{-10}[/tex]M.

What is concentration?

To calculate the hydroxide ion concentration, [OH-], from the given pH, we can use the following relationship:

pH + pOH = 14

where pOH is the negative logarithm of the hydroxide ion concentration:

pOH = -log[OH-]

Rearranging the first equation, we get:

pOH = 14 - pH

Substituting the given pH value of 4.65, we get:

pOH = 14 - 4.65 = 9.35

Finally, we can calculate the hydroxide ion concentration, [OH-], by taking the antilogarithm (inverse log) of the pOH value:

[OH-] = [tex]10^{(-pOH)}[/tex] = [tex]10^{-9.35}[/tex] = 3.55 x [tex]10^{-10}[/tex] M

Therefore, the hydroxide ion concentration, [OH-], for a solution with a pH of 4.65 is approximately 3.55 x [tex]10^{-10}[/tex] M.

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There are approximately 0.005302 moles of NOs in 3.19 × 10^16 molecules.

Mole is an SI unit used to measure the amount of any substance.

To calculate the number of moles of NOs in 3.19 × 10^16 molecules, we need to use Avogadro's number, which is 6.022 × 10^23 molecules per mole.

First, we need to convert the number of molecules to moles using the formula:

moles = molecules / Avogadro's number

moles of NOs = 3.19 × 10^16 molecules / 6.022 × 10^23 molecules per mole

moles of NOs = 0.005302 moles (rounded to 4 significant figures)

Therefore, there are approximately 0.005302 moles of NOs in 3.19 × 10^16 molecules.

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The number of moles present in 3.19×10¹⁶ molecules of nitrogen dioxide, NO₂ is 5.30×10⁻⁸ mole

The number of moles present in 3.19×10¹⁶ molecules of NO₂ can be obtained by using the Avogadro's hypothesis as illustrated below:

From Avogadro's hypothesis,

6.022×10²³ molecules = 1 mole of NO₂

Therefore,

3.19×10¹⁶ molecules = 3.19×10¹⁶  / 6.022×10²³

3.19×10¹⁶ molecules = 5.30×10⁻⁸ mole of NO₂

Thus, we can conclude that the number of mole is 5.30×10⁻⁸ mole

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Answer:

The solution in the test tube would turn pink earlier with the more concentrated NaOH solution.

This is because the concentration of the NaOH solution is directly proportional to the number of moles of NaOH per unit volume of the solution.

So, with a more concentrated NaOH solution (1.0 M compared to 0.5 M), each mL of NaOH solution contains twice as many moles of NaOH.

Therefore, it would take half as much volume (i.e., 12.4 mL instead of 24.8 mL) of the 1.0 M NaOH solution to react with the same number of moles of the unknown acid as the 0.5 M NaOH solution.

Answer:

See Below.

Explanation:

Problem 1

Let x be the mass of 15% solution needed and y be the mass of 20% solution needed. Then, we have the following system of equations:

x + y = 200 (total mass of solution)

0.15x + 0.20y = 0.17(200) (total amount of solute)

Solving this system of equations gives:

x = 60 g (mass of 15% solution)

y = 140 g (mass of 20% solution)

Therefore, 60 g of 15% solution and 140 g of 20% solution are needed to prepare 200 g of 17% solution.

Problem 2

Let x be the mass of 18% solution needed and y be the mass of 5% solution needed. Then, we have the following system of equations:

x + y = 300 (total mass of solution)

0.18x + 0.05y = 0.07(300) (total amount of solute)

Solving this system of equations gives:

x = 120 g (mass of 18% solution)

y = 180 g (mass of 5% solution)

Therefore, 120 g of 18% solution and 180 g of 5% solution are needed to prepare 300 g of 7% solution.

Problem 3

The total mass of the final solution is

200 g + 350 g = 550 g

The total amount of solute in the final solution is:

0.15(200 g) + 0.20(350 g) = 95 g + 70 g = 165 g

Therefore, the mass percentage of the final solution is:

(mass of solute / total mass of solution) x 100% = (165 g / 550 g) x 100% = 30%

Therefore, the mass percentage of the final solution is 30%.

Problem 4

The total mass of the final solution is

300 g + 35 g = 335 g

The total amount of solute in the final solution is:

0.15(300 g) + 35 g = 75 g + 35 g = 110 g

Therefore, the mass percentage of the final solution is:

(mass of solute / total mass of solution) x 100% = (110 g / 335 g) x 100% = 32.8%

Therefore, the mass percentage of the final solution is 32.8%.

Problem 5

The total mass of the final solution is

400 g + 150 g = 550 g

The total amount of solute in the final solution is

0.25(400 g) = 100 g

Therefore, the mass percentage of the final solution is

(mass of solute / total mass of solution) x 100% = (100 g / 550 g) x 100% = 18.2%

Therefore, the mass percentage of the final solution is 18.2%.

D. Directly scaling to the top of the mountain. The person would end up with the same potential energy or height regardless of the method they use to reach the top of the mountain because the end result is the same: they are at the top.

Potential energy is energy that is stored in an object due to its position relative to other objects, stresses within itself, electric charge, or other factors. When the object is moved or the stresses are released, energy is converted to kinetic energy, which is the energy of a moving object.

Therefore, if they take the switchback trail, parachute out of a plane, teleport using Star Trek technology, or directly scale to the top, they will have the same potential energy or height by the time they reach the top.

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The completed table of maximum moles of water, limiting reactant and excess reactant is as follows:

Q: 6 moles, O₂, 1 mole H₂

R: 6 moles, O₂, 2 moles H₂

S: 5 moles, none, none

T: 5 moles, H₂, 2.5 moles O₂

U: 8 moles, H₂, 2 moles O₂

The mole ratio of the reaction of hydrogen and oxygen to form water is obtained from the equation of the reaction.

The equation of the reaction is given below:

2 H₂ + O₂ --> 2 H₂O

The mole ratio of hydrogen to oxygen is 2:1 in both the water molecule and the reactants, hydrogen gas (H2) and oxygen gas, as can be seen from the balanced equation (O2). 

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Answer:

First, we need to convert the volume of the solution from milliliters (mL) to liters (L) since molarity is expressed in moles of solute per liter of solution.

30 mL = 0.03 L

Next, we can use the formula for molarity:

Molarity = moles of solute / liters of solution

Plugging in the given values:

Molarity = 0.26 moles / 0.03 L = 8.67 M

Therefore, the concentration of the vinegar solution is 8.67 M.

The alkene that is most stabilized through hyperconjugation is 2-methylpropene. The correct option is (C).

Hyperconjugation is a type of resonance that involves the overlapping of an unshared electron pair on an atom, like carbon, with an adjacent sigma bond. In this case, the unshared electron pair on the methyl group of 2-methylpropene provides stabilization to the adjacent sigma bond, making it the most stabilized alkene through hyperconjugation.

The most stabilized alkene through hyperconjugation can be determined by analyzing the degree of substitution. The greater the number of alkyl groups attached to the carbon atoms of the double bond, the greater the degree of substitution and the greater the stability due to hyperconjugation. Hence, the answer to this question would be option C (2-methylpropene.), as it has the greatest degree of substitution and is thus the most stable through hyperconjugation.

Option A (1-butene) has only one methyl group attached to one carbon of the double bond, making it less stable than option C. Option B (2-butene) has two methyl groups attached to the same carbon atom of the double bond, resulting in a similar degree of substitution to option A. Option D (2-methyl-1-pentene) has a lesser degree of substitution than option C because the methyl group is attached to only one carbon atom of the double bond, while in option C, the methyl group is attached to a tertiary carbon atom.

Hence, option C , 2-methylpropene. is the most stabilized alkene through hyperconjugation because of its greater degree of substitution.

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The complete question is:

which of the following alkenes is most stabilized through hyperconjugation? select answer from the options below

A 1-butene

B 2-butene

C 2-methylpropene

D 2-methyl-1-pentene

The reaction between 1 mL of 0.1 M Pb(NO3)2 and 1 mL of 0.1 M NaS would form a black precipitate. The chemical formula of the solid formed is PbS, and the spectator ions are Pb2+ and S2-.

Pb(NO3)2 + NaS → PbS + NaNO3
Pb2+(aq) + 2NO3-(aq) + Na+(aq) + S2-(aq) → PbS(s) + Na+(aq) + 2NO3-(aq)
In the above equation, Pb2+ and S2- are the spectator ions because they remain unchanged throughout the reaction and exist in the same form on both sides of the equation.
The black precipitate that forms is PbS, which is an insoluble compound. The reaction is driven to completion because the ions on the left side of the equation are completely used up in the reaction and are not present in the solution after the reaction is complete.
In conclusion, when 1 mL of 0.1 M Pb(NO3)2 and 1 mL of 0.1 M NaS are mixed, a black precipitate is formed. The chemical formula of the solid formed is PbS, and the spectator ions are Pb2+ and S2-.

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The activation energy of the reverse reaction is also 63 kJ/mol, as it is equal to the activation energy of the forward reaction.

The activation energy of the reverse reaction can be determined using the relationship between the activation energy and the enthalpy of reaction for the forward and reverse reactions:

ΔH_reverse = -ΔH_forward

Ea_reverse = Ea_forward

Since the enthalpy of reaction for the forward reaction is -388 kJ/mol, the enthalpy of reaction for the reverse reaction is:

ΔH_reverse = -ΔH_forward = -(-388 kJ/mol) = 388 kJ/mol

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Answer: This reaction is the combustion, in which a hydrocarbon reacts with oxygen gas to form carbon dioxide and water.

Explanation: balanced combustion reaction for C6H6 Equation: 2C6H6(l)+15O2(g)--> 12CO2+6H2O(l)_6542 KJ.

122.5 grams of oxalic add dihydrate (MW = 126.07 g/mole) and disodium oxalate (MW = 133.99 g/mole) were required to prepare this buffer if the total oxalate concentration is 0.115 M.

Weak acids are defined as acids that don't completely dissociate in solution. It can be explained as any acid that is not a strong acid. The strength of a weak acid depends on how much it gets dissociates and the more it dissociates, the stronger the acid. The mass of the weak acid in a solution of a certain pH can be determined by calculating the original concentration of the acid after calculating the concentration of the hydrogen ions with the help of the pH value of the solution.

The Concentration of oxalate ion is  0.115 M.

pKa1 is 1.250.

pKa2 is 4.266.

pH is 5.193.

Molarity = (mass / molar mass) / 1 / volume in liter

The molar mass is 126.07g/mole.

Mass = Molarity × molar mass × Volume in liter

Mass=0.972 M × 126.07 g/mole × 1.00 L

        = 122.5 gram

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The complete question is,

A buffer prepared by dissolving oxalic add dihydrate (H2C2O4⋅2H2O) and disodium oxalate (Na2C2O4) in 1.00 L of water has a pH of 5.193. How many grams of oxalic add dihydrate (MW = 126.07 g/mole) and disodium oxalate (MW = 133.99 g/mole) were required to prepare this buffer if the total oxalate concentration is 0.115 M? Oxalic acid has pKa values of 1.250 (pKa1) and 4.266 (pKa2).

CCl4 is the only answer choice that would likely dissolve in pentane. So the correct option is A.

The question asks which of the following would likely dissolve in pentane (C5H12). The answer choices are CCl4, MNO, HF, CH3OH, and NH3.
Pentane is a hydrocarbon with a boiling point of 36.1 °C and is insoluble in water. It has a low polarity and does not form strong hydrogen bonds, so molecules that are nonpolar will dissolve in it.
CCl4 is a nonpolar molecule and would therefore be soluble in pentane. MNO is an ionic compound, so it would not be soluble in pentane. HF is a polar molecule and is also insoluble in pentane. CH3OH is also a polar molecule and is insoluble in pentane. NH3 is a polar molecule, and is slightly soluble in pentane, but not as much as CCl4.
So the correct option is A.

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Using CH3NH2 and CH3NH3Cl, one may simulate the blood's buffering properties. A weak acid and its conjugate base, or a weak base and its conjugate acid, make up a buffer system.

Carbonic acid and sodium bicarbonate. Hint: Human blood has a buffer of bicarbonate anion (HCO3) and carbonic acid (H2CO3) to keep the blood's pH between 7.35 and 7.45. Blood pH values higher or lower than 7.8 or 6.8 can be fatal.

Bicarbonate anion and hydronium are in equilibrium with carbonic acid in this buffer. A weak acid and its conjugate base, or a weak base and its conjugate acid, make up a buffer.

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Answer:

CH3NH2 and CH3NH3Cl

Explanation:

Methylamine (CH3NH2) is an organic base. In order to produce a basic buffer solution similar to blood, we can combine this base with a soluble salt of its conjugate acid, such as CH3NH3Cl. The solution of KOH and H2O would not be a good buffer because KOH is a strong base. The solution of HF and NaF is a buffer, but the pKa of HF is about 3.2, which is far from the pH of blood, 7.4.

The charge on the surface of the coagulated colloidal particles is negative.

The source of the charge is likely due to the dissociation of the sodium and potassium salts in water, which results in the formation of ions.

The counter-ion layer is composed of the cations that balance the charge on the negatively charged colloidal particles.

Charge is a fundamental property of matter that describes the amount of electrical energy present in a particle, atom, or molecule. It is a property that can be either positive or negative and is measured in units of coulombs (C).

The charge of a particle can affect how it interacts with other charged particles. For example, particles with opposite charges are attracted to each other, while particles with the same charge repel each other. The interaction between charged particles is fundamental to many chemical and physical phenomena, such as electrostatic interactions, chemical bonding, and the behavior of electrical currents.

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Na, or sodium, is the right response. Among the listed elements, sodium has the lowest IE1 value. The energy needed to remove one electron from a neutral atom when it is in the gaseous form is known as the first ionisation energy (IE1).

A soft, silvery-white, highly reactive metal that is a member of the periodic table's alkali metal family is sodium (Na). Its atomic mass is 22.99 and it has an atomic number of 11. Sodium is a crucial element used in many processes, such as making alloys, chemicals, and electrical parts. It is a frequent component of table salt (NaCl) and other nutritional sources and is also a necessary element for living things. In the human body, sodium regulates fluid balance, nerve transmission, and muscle contraction. However, consuming too much salt has been related to a number of illnesses, such as high blood pressure and cardiovascular disease.

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The correct answer is "two molecules of ATP are needed to 'activate' glucose".

In the first step of glycolysis, glucose is converted into glucose-6-phosphate, which requires the input of ATP. This reaction is catalyzed by the enzyme hexokinase. Therefore, two molecules of ATP are used in the early steps of glycolysis to activate glucose and convert it into glucose-6-phosphate. In the later steps of glycolysis, four molecules of ATP are produced by substrate-level phosphorylation, but since two molecules of ATP were used in the beginning, the net production of ATP is only two molecules per glucose molecule.

It is also important to note that glycolysis is the first step of both aerobic and anaerobic respiration and can occur without oxygen being present. However, the subsequent steps of cellular respiration, such as the Krebs cycle and electron transport chain, require oxygen in aerobic respiration to produce more ATP.

What is an ATP?

ATP stands for Adenosine Triphosphate, which is a molecule that carries energy within cells. It is often referred to as the "energy currency" of the cell because it powers many cellular processes by releasing its stored energy when it is hydrolyzed to ADP (Adenosine Diphosphate) and inorganic phosphate.

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Answer:

4897 J

Explanation:

The heat transferred to the surroundings, q_surr, can be calculated using the equation:

q_surr = -q_rxn = -CmΔT

where C is the specific heat capacity of the mixture (assumed to be the same as water, 4.184 J/g°C), m is the mass of the mixture (which we can calculate using the density, assuming that the volumes are additive), and ΔT is the change in temperature (in Celsius).

First, let's calculate the mass of the mixture:

density of water = 1.00 g/cm^3

volume of mixture = volume of acid + volume of base = 106 mL + 157 mL = 263 mL = 0.263 L

mass of mixture = density of water x volume of mixture = 1.00 g/cm^3 x 0.263 L = 263 g

Next, let's calculate the change in temperature:

ΔT = final temperature - initial temperature = 27.29°C - 22.94°C = 4.35°C

Now we can calculate the heat transferred to the surroundings:

q_surr = -CmΔT

q_surr = -(4.184 J/g°C) x (263 g) x (4.35°C)

q_surr = -4897 J

Note that the negative sign indicates that heat is lost by the system to the surroundings. Therefore, the heat transferred to the surroundings, q_surr, is 4897 J.

The first two statements are false, whereas the last statement, which says that pressure and volume of a gas are inversely related, is true.

Statement 1: This claim was incorrect because, according to the ideal gas law, PV=nRT, pressure (P) and volume (V) are inversely proportional to each other at a constant temperature (T) and amount of gas (n). This means that as pressure increases, volume decreases. This relationship is known as Boyle's law. Therefore, the statement that pressure has no effect on volume of a gas is false.

Statement 2: This claim was incorrect because, pressure and volume of a gas are inversely related according to Boyle's law, which states that at a constant temperature, the pressure of a gas is inversely proportional to its volume. This means that if the pressure of a gas increases, its volume will decrease, and if the pressure decreases, the volume will increase, as long as the temperature remains constant.

Statement 3: This claim was correct because, According to Boyle's law, the pressure and volume of a gas are inversely proportional to each other, which means that when the pressure of a gas increases, its volume will decrease and vice versa, as long as the temperature and the number of particles in the gas are kept constant. This relationship is expressed mathematically as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

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The vapor pressure for methanol at 44.6°C is 36.2 kPa.

The Clausius-Clapeyron equation has a relation to the vapor pressure of a substance to its enthalpy of vaporization and temperature and is expressed :

ln(P2/P1) = -(ΔHvap/R) x (1/T2 - 1/T1)

given values are:

P1 = 101.3 kPa

T1 = 100.0°C = 373.2 K

ΔHvap = 40.7 kJ/mol

R = 8.314 J/(mol K)

r P2 at T2 = 44.6°C = 317.8 K:

ln(P2/101.3) = -(40.7 x 10^3 J/mol / (8.314 J/(mol K) x 317.8 K)) x (1/317.8 K - 1/373.2 K)

ln(P2/101.3) = -3.04

P2/101.3 = e^(-3.04)

P2 = 36.2 kPa

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Answer:

Explanation:

2-bromopropane is the major product because the reaction mechanism involves the formation of the most stable carbocation intermediate. When hydrogen bromide reacts with propene, the hydrogen atom from HBr adds to the carbon atom of the double bond that has fewer hydrogen atoms attached, resulting in the formation of a carbocation intermediate. The intermediate can either form 1-bromopropane or 2-bromopropane depending on the position of the carbocation. The 2-bromopropane is the major product because the secondary carbocation formed in this case is more stable than the primary carbocation formed in the case of 1-bromopropane.

To test for an alkene, bromine water can be used. When an alkene reacts with bromine water, the bromine molecule adds across the double bond, forming a colorless dibromoalkane product. The mechanism for the reaction between hex-1-ene and bromine involves the formation of a cyclic bromonium ion intermediate, followed by the attack of water on the intermediate, resulting in the formation of the dibromoalkane product.

a) Addition polymerization is a process in which unsaturated monomers are joined together to form a polymer. The process involves breaking the double bond of the monomer and joining the monomers together to form a long-chain polymer. The process requires a catalyst to initiate the reaction.

b) The repeating unit of the polymer formed from the addition polymerization of chloroethene monomers is -CH2-CHCl-. This polymer is called polyvinyl chloride (PVC), and it has a wide range of uses, including pipes, electrical cables, and vinyl flooring.