2 numbers add together to make -4 but subtract to make 8 what are the 2 numbers

For equation a, x = 3

For equation b, x = -11/4.

For equation c, x = 1.

For equation d, x = -7/3.

For equation e, x = 9.

For equation f, x = 1/2.

To solve this equation, we need to isolate the variable x on one side of the equation.

7x - 6 = 6x + 3

Subtracting 6x from both sides:

x - 6 = 3

Adding 6 to both sides:

x = 9

Therefore, the solution to the equation is x = 9.

In the other equations:

a) 4x + 7 = 2x + 13

Subtracting 2x from both sides:

2x + 7 = 13

Subtracting 7 from both sides:

2x = 6

Dividing by 2:

x = 3

Therefore, the solution to the equation is x = 3.

b) x - 2 = 10 + 5x

Subtracting x from both sides:

-2 = 9 + 4x

Subtracting 9 from both sides:

-11 = 4x

Dividing by 4:

x = -11/4

Therefore, the solution to the equation is x = -11/4.

c) -3x - 8 = -7x - 4

Adding 7x to both sides:

4x - 8 = -4

Adding 8 to both sides:

4x = 4

Dividing by 4:

x = 1

Therefore, the solution to the equation is x = 1.

d) 2t + 5 = 5t + 12

Subtracting 2t from both sides:

5 = 3t + 12

Subtracting 12 from both sides:

-7 = 3t

Dividing by 3:

t = -7/3

Therefore, the solution to the equation is t = -7/3.

f) 15x = 7x + 4

Subtracting 7x from both sides:

8x = 4

Dividing by 8:

x = 1/2

Therefore, the solution to the equation is x = 1/2.

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Complete Question:

Find X for each equation.

A) 4 x + 7 = 2 x + 13 ;

b) x – 2 = 10 + 5 x ;

c) – 3 x – 8 = – 7 x – 4 ;

d) 2 t + 5 = 5 t + 12 ;

e) 7 x – 6 = 6 x + 3

f) 15 x = 7 x + 4

To perform matrix multiplication in MIPS, we can use nested loops to iterate over the rows and columns of the matrices.

The outer loop iterates over the rows of the first matrix, while the inner loop iterates over the columns of the second matrix. We then perform the dot product of the corresponding row and column, which involves multiplying the elements and summing the products.

To perform multiplication efficiently, we can use MIPS registers to store intermediate values and avoid accessing memory unnecessarily. We can also use assembly instructions like "lw" and "sw" to load and store values from memory, and "add" and "mul" to perform arithmetic operations.

In summary, matrix multiplication in MIPS involves nested loops, efficient use of registers and assembly instructions, and arithmetic operations.

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a. Finding the transition matrix from B1 to B2 using the standard basis for the vector space of lower triangular matrices with zero trace.The standard basis of the vector space of lower triangular matrices with zero trace is given by{(1,0,0),(0,1,0),(0,0,0)}.We are to find the transition matrix from B1 to B2. We start with the definition of the transition matrix. This definition states that if A = [a1,a2,a3] is a matrix whose columns are the vectors of B2, then the transition matrix from B1 to B2 is the matrix S such that S = [b1,b2,b3] where bi is the column vector obtained by expressing the ith vector of B1 as a linear combination of the vectors of B2. Using the standard basis, we have that (1,0,0) = a1, (0,1,0) = a2 and (0,0,0) = a3. Therefore, we need to express each of these standard basis vectors as a linear combination of the vectors of B1.For (1,0,0), we have(1,0,0) = 2e1 - e2For (0,1,0), we have(0,1,0) = -3e1 + e3For (0,0,0), we have(0,0,0) = e2 + e3Therefore, the transition matrix S is given by S = [b1,b2,b3] where bi is obtained by expressing the ith vector of the standard basis as a linear combination of the vectors of B1. Thus,S = [(2,-3,0),(-1,1,0),(0,0,1)]b. Finding the coordinates of v in B if the coordinate vector of v in B1 is c. Let c be the coordinate vector of v with respect to B1. Then we know that v = c1e1 + c2e2 + c3e3. We are to find the coordinate vector of v with respect to B.We know that B is a basis for the vector space of lower triangular matrices with zero trace, so any vector in this space can be expressed uniquely as a linear combination of the vectors in B. Thus, we can write v as a linear combination of the vectors of B.v = a1x1 + a2x2 + a3x3We are to find the coefficients x1, x2 and x3. We do this by using the fact that the transition matrix S from B1 to B is such that v = Sc where c is the coordinate vector of v with respect to B1. Hence, v = Sc = [b1,b2,b3][c1,c2,c3] = (2c1 - c2) b1 - (c1 - c2) b2 + c3 b3Using the expressions for b1, b2 and b3 in terms of the standard basis vectors, we obtainv = (2c1 - c2)(2e1 - e2) - (c1 - c2)(-e1 + e3) + c3e3

Expanding this expression and comparing coefficients with the equation for v above yields(2c1 - c2)(2e1 - e2) - (c1 - c2)(-e1 + e3) + c3e3 = c1e1 + c2e2 + c3e3Therefore, we have the system of equations2(2c1 - c2) - (c1 - c2) = c11(2c1 - c2) + (c1 - c2) = c20 = c3Solving for x1, x2 and x3 yieldsx1 = c2/2, x2 = c1/2, and x3 = 0Therefore, the coordinate vector of v with respect to B is given by the vector( c2/2, c1/2, 0).c. Finding [v]B2 in 200 wordsWe are to find the coordinate vector of v with respect to B2. Since we already have the coordinate vector of v with respect to B1, we can use the transition matrix S from B1 to B2 to obtain this coordinate vector.Let c be the coordinate vector of v with respect to B1. Then, we know that v = c1e1 + c2e2 + c3e3. Since the coordinate vector of v with respect to B1 is c, we have the equationc = [c1,c2,c3]Using the transition matrix S from B1 to B2, we can write the coordinate vector of v with respect to B2 as[x1,x2,x3] = S[c1,c2,c3]Multiplying these matrices together yields the equation[x1,x2,x3] = [(2,-3,0),(-1,1,0),(0,0,1)][c1,c2,c3]

Expanding this equation gives the system of equations2c1 - c2 = x1-3c1 + c2 = x2c3 = x3Solving this system of equations for c1, c2 and c3 yieldsc1 = (x2 - x1)/4, c2 = (3x2 + x1)/4, and c3 = x3Therefore, the coordinate vector of v with respect to B2 is given by the vector((x2 - x1)/4, (3x2 + x1)/4, x3).

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Answer: your answer should be 12.48

have a good day

sorry I didn't read that well

for your calculator you should type in 0.13 divided by 96

The sales of marshmallow is 5 million and the sales of graham cracker is 5 million is 0.5648 and the probability that 3X1-1X2 + 3X3 > 20 is 0.000005.

The multivariate normal distribution is a probability distribution which describes the joint behavior of multiple random variables. In the given case, the profit (in millions) for selling chocolate (Xi), marshmallow (X2) and graham cracker (X3) follows a multivariate normal distribution with parameters 1, 0.3, 0.3 and Σ = 0.31 0 0.3 01.

1. To calculate the probability that the profit for selling chocolate is greater than 6 millions, we need to calculate the probability that X1>6. Using the given parameters, we can use the formula for calculating the cumulative probability of a standard normal distribution: [tex]P(X1>6) = 1-P(X1≤6) = 1-0.9999994 = 0.000006.[/tex]

2. To calculate the probability that the profit for selling chocolate is greater than 6 millions, given the sales of marshmallow is 5 million and the sales of graham cracker is 5 million, we need to calculate the conditional probability [tex]P(X1>6|X2=5, X3=5)[/tex]. Using the given parameters, we can calculate this probability using the formula for conditional probability:[tex]P(X1>6|X2=5, X3=5) = P(X1>6 ∩ X2=5 ∩ X3=5) / P(X2=5 ∩ X3=5) = 0.002207 / 0.003915 = 0.5648.[/tex]

3. To calculate the probability that, we need to calculate the probability that[tex]X1>7-X2/3-X3/3[/tex]. Using the given parameters, we can calculate this probability using the formula for cumulative probability of a standard normal distribution: [tex]P(3X1-1X2 + 3X3 > 20) = 1-P(3X1-1X2 + 3X3 ≤ 20) = 1-0.9999995 = 0.000005.[/tex]

In conclusion, the probability that the profit for selling chocolate is greater than 6 millions is 0.000006, the probability that the profit for selling chocolate is greater than 6 millions

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Meredith will take 8 hours 45 minutes to file 70% of the 10 reports given.

The time taken by Meredith to file 70% of the 10 reports given, given that each report takes an average of 75 minutes is 6 hours, 30 minutes. Therefore, the correct option is B. 6 hours, 30 minutes. How long will it take Meredith to file 70% of 10 reports, given that each report takes an average of 75 minutes to file?

Here, the total number of reports = 10

Average time to file one report = 75 minutes

To find out the time taken to file 70% of 10 reports, we will need to multiply the average time taken to file one report by the number of reports to be filed, which is 7 in this case:

75 × 7 = 525 minutes

We have calculated the time it will take Meredith to file 7 reports. Now, to convert this time to hours and minutes, we divide the total minutes by 60 to get the hours and then find out the remainder for the minutes:

525 ÷ 60 = 8 hours 45 minutes

Therefore, Meredith will take 8 hours 45 minutes to file 70% of the 10 reports given.

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The  [tex]$\vec{a}=\langle2,3\rangle$[/tex] and [tex]\vec{b}=\langle-4,\frac{8}{3}\rangle$[/tex]  are orthogonal.So, the value of k is 8/3.

A quantity or phenomenon with separate characteristics for both magnitude and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, energy, electromagnetic fields, and weight are a few examples of vectors in nature.

Two vectors are orthogonal if and only if their dot product is zero. Therefore, we need to find the value of k such that the dot product of [tex]$\vec{a}$[/tex] and[tex]$\vec{b}$[/tex] [tex]$\vec{b}$[/tex][tex]\vec{b}[/tex] is zero.

The dot product of [tex]$\vec{a}$[/tex] and [tex]$\vec{b}$[/tex] is given by:

[tex]$$\vec{a} \cdot \vec{b} = (2)(-4) + (3)(k) = -8 + 3k$$[/tex]

For the vectors to be orthogonal, their dot product must be zero, so we set -8 + 3k = 0 and solve for k:

-8 + 3k = 0

3k = 8

[tex]$k = \frac{8}{3}$$[/tex]

Therefore, [tex]$\vec{a}=\langle2,3\rangle$[/tex] and [tex]\vec{b}=\langle-4,\frac{8}{3}\rangle$[/tex]  are orthogonal.So, the value of k is 8/3.

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Based on the full rank transformation matrix t, it is true that the eigenvalues of ay and a from part (a) are the same.

We have to show that the eigenvalues of ay and a from part (a) are the same.

Let A be a full rank transformation matrix.

A is a full rank matrix.

Therefore, the rank of A is equal to the number of rows and columns of A.

Let λ be an eigenvalue of Ay.

Then, Ay - λy = 0, where y is the eigenvector corresponding to λ.

Now let us take a look at the eigenvalues of A(y).

A(y) is a full rank matrix since A is a full rank matrix.

This means that det(A(y)) ≠ 0.

We know that λ is an eigenvalue of Ay if and only if λ is a root of the characteristic polynomial det(Ay - λy) = 0.

Using the fact that A(y) is full rank, we have that det(Ay - λy) = det(A(y)A⁻¹yAy - λy) = det(A(y)(A⁻¹yAy - λI)y) = det(A(y))det(A⁻¹yAy - λI).

Since det(A(y)) ≠ 0, we have that λ is an eigenvalue of Ay if and only if λ is a root of the characteristic polynomial det(A⁻¹yAy - λI) = 0.

However, det(A⁻¹yAy - λI) is just the characteristic polynomial of A(y) and therefore has the same roots as the characteristic polynomial of A(y).

Thus, the eigenvalues of Ay and A(y) are the same.

Thus, the statement above is true.

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The probability that the response indicated that the dog is small-sized given that they enjoyed the treat is 0.286 (or 2/7) in fraction in the lowest terms.

Bayes' theorem is used to update probabilities of a hypothesis or an event in light of new data or evidence. It is used to calculate the conditional probability of an event based on prior knowledge of the conditions that might be relevant to the event.In the given problem, we have to find the probability that the response indicated that the dog is small-sized given that they enjoyed the treat.

The probability that the dog is small-sized given that they enjoyed the treat is the conditional probability P(S|T), where S is the event that the dog is small-sized and T is the event that they enjoyed the treat. To find the value of P(S|T), we will use Bayes' theorem. Bayes' theorem states that P(S|T) = P(T|S) * P(S) / P(T) where P(T|S) is the probability that they enjoyed the treat given that the dog is small-sized, P(S) is the prior probability that the dog is small-sized, and P(T) is the probability that they enjoyed the treat.

P(S) = 3/7P(T|S) = 2/3P(T) = (2/3 * 3/7) + (1/4 * 4/7) = 18/84 + 4/28 = 1/3

(adding the probabilities of T given S and T given L)Therefore, P(S|T) = (2/3 * 3/7) / (1/3) = 2/7 = 0.285714...Rounding off to the nearest millionth, the probability is 0.286. Therefore, the probability that the response indicated that the dog is small-sized given that they enjoyed the treat is 0.286 (or 2/7) in fraction in the lowest terms.

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Answer:

the ribbon costs $0.80 per meter.

Step-by-step explanation:

To calculate the cost per meter of ribbon, we can divide the total cost of the ribbon by the length of the ribbon:

Cost per meter = Total cost of ribbon / Length of ribbon

In this case, the total cost of the ribbon is $4, and the length of the ribbon is 5 meters:

Cost per meter = $4 / 5 meters = $0.80/meter

To determine the cost of each meter of the ribbon, we divide the cost for 5 meters of ribbon by 5. That is,

                                       [tex]x = \$4 / 5[/tex]

where x is the cost of each meter. Simplifying will give us an answer of $0.8/m. Converting this to per mm.

                                  [tex]($0.8/m) \times (1 m/ 1000 mm)[/tex]

                              [tex]= \$0.0008/mm[/tex]

The complete table for the amount balance, A when P dollars is invested at rate r for t years and compounded n times per year is present in above figure 2.

The compound interest formula is written as A = P( 1 + r/n)ⁿᵗ

where, A--> total Amount of money after t years

P --> Principal

r --> Annual rate of interest (as a decimal)

t --> Number of years:

n--> number of times interest is compounded per year

Here, principle, P = $1300, rate of interest, r = 8.5% = 0.085 , time periods, t = 11 years. We have to complete the above table for compound interest.

Case 1: n = 1

Substitute the known values in above formula, A = 1300( 1 + 0.085/1)¹¹

= 1300( 1.085)¹¹

= 3,189.12

Case 2: n = 2

A = 1300( 1 + 0.085/2)²²

= 1300( 2.085/2)²²

= 1300( 1.0425)²²

= 3,248.01

I'll let you work out the cases where n = 4, 12 and 365 since all you need to do is place those in for n as done in the 1st 2 cases. For the Compounded continuously case, the formula becomes,

[tex] A = Pe^{rt}[/tex]

Where: A-> Total amount of money after t years

P --> Principal Amount

e --> Natural log constant:

r = Annual rate of interest (as a decimal)

Case: Continuous: e = 2.71828 (approx), r = 0.085

A = 1300( 2.71828)⁰·⁰⁸⁵⁽¹¹⁾

= 1300(e)⁰·⁹³⁵ = 3,311.34

Hence, required value is $3,311.3775.

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Complete question :

The above table completes the question.

Complete the table by finding the balance A when P dollars is invested at rate r for t years and compounded n times per year. (Round your answers to the nearest cent. ) P = $1300, r = 8. 5%, t

= 11 years

The area of the composite figure with the given subshapes is 99.13 square feet

Given the following parameters:

The composite figure with the following shapes

Semi-circle with diameter 8 ft

Triangle with base of 8 ft and height of 6 feet

Rectangle of 10 by 5 feet

The area of the composite figure is the sum of the individual areas

So, we have

Area = 1/2 * π(8/2)² + 1/2 * 8 * 6 + 10 * 5

Evaluate

Area = 99.13

Hence, the area is 99.13 square feet

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Hi!
Let's write this out.
Her limit is $900, and she's used $450. So, we subtract 450 from 900.
900-450 = 450.

So, she has $450 available credit left.
Hope this helps!
~~~PicklePoppers~~~

Answer: your credit utilization ratio on that card would be 50% but the answer is 450

Step-by-step explanation:

900-450 = 450

Three numbers have a product of 115 and a sum of 3(√115), which is the smallest possible sum.

In mathematics, a positive number is any number that is greater than zero. This includes all numbers that are written without a minus sign or are explicitly denoted as positive, such as 1, 2, 3, 4, 5, and so on

To find three positive numbers whose product is 115 and whose sum is as small as possible, we can use the AM-GM inequality. In other words, if we have three positive numbers x, y, and z, then:

(x + y + z)/3 ≥ (xyz)^(1/3)

If we rearrange this inequality, we get:

x + y + z ≥ 3(√(xyz))

Now, let's apply this inequality to the given problem. We want to find three positive numbers x, y, and z whose product is 115 and whose sum is as small as possible. Therefore, we want to minimize x + y + z while still satisfying the condition xyz = 115.

Using the AM-GM inequality, we have:

x + y + z ≥ 3(√(xyz)) = 3(√115) ≈ 16.75

Therefore, the sum of the three numbers is at least 16.75. To find three numbers that achieve this minimum sum, we can use trial and error or solve the system of equations:

xyz = 115

x + y + z = 3(√115)

One solution to this system is:

x = √(115/3)

y = √(115/3)

z = 3(√(115/3)) / 5

These three numbers have a product of 115 and a sum of 3(√115), which is the smallest possible sum.

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The complete question is Find three positive numbers whose product is 115.

Answer:

1,000

Step-by-step explanation:20*50

The function is a set of ordered pairs (x, y), where x is an element of the domain and y is the corresponding element of the range. The notation f(x) is commonly used to denote the output value of the function for a given input value x.

At x=3, the derivative is negative, f'(3)=-12, so the function is decreasing at x=3.

The function is always decreasing since its derivative is constant and negative. Therefore, the interval where f(x) is decreasing is the entire real line, or (-∞, ∞).

Since the function is always decreasing, it does not have a relative maximum.

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Flipping a coin 3 times, the probability of getting 3 heads is 0.125.

The probability of getting 3 heads when a coin is flipped 3 times can be calculated using the binomial probability formula. The formula is:

P(X=k) = nCk × p^k × (1-p)^(n-k)

where n is the number of trials, k is the number of successes, p is the probability of success, and (1-p) is the probability of failure.

Here, n=3, k=3 and p=0.5 (since the coin has two sides and the probability of getting heads or tails is 0.5 each). Substituting the values, we get:

P(X=3) = 3C3 × 0.5³ × (1-0.5)⁽³⁻³⁾ = 1 × 0.125 × 1 = 0.125

Therefore, the probability of getting 3 heads as a decimal rounded to 3 decimal places is 0.125.

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The required value of the base of the triangle is   [tex]\frac{7\sqrt{3} }{3}[/tex].

Right-angle triangles are formed when the angle formed by two of their edges is exactly 90 degrees. Obtuse angle triangle: An obtuse angle triangle is one in which the angle formed by two sides is larger than 90 degrees.

In the given triangle, we will use tangent function to find the value of x.

tan(∅) = Perpendicular/ base

tan(60°) = 7/x

x = 7/tan(60°)

x = 7/√3                         ∴ (tan(60°) =√3  )

On rationalizing

x = [tex]\frac{7\sqrt{3} }{3}[/tex]

Thus, required value of x is [tex]\frac{7\sqrt{3} }{3}[/tex].

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According to the question the value of the 5 digit in 4,597 is 9.

Digit is a numerical symbol used to represent numbers in the decimal system. It is a single symbol used to represent a number ranging from 0 to 9. Digits are used to represent numbers in all forms of mathematical calculations and equations. The most common digits used in calculations are 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. Each digit has an associated numerical value, which can be used to create larger numbers or to perform complex mathematical operations.

The answer is D) 9. The value of the 5 digit in 4,597 is 5. To find the 10 times its value, you must multiply 5 by 10, which equals 50. Therefore, the value of the 5 digit in 4,597 is 9.

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There are, 6300 different possibilities for the researcher’s study.

Total number of class I railroads = 10Number of class I railroads selected = 3Total number of class II railroads = 6Number of class II railroads selected = 2Total number of class III railroads = 5Number of class III railroads selected = 1Number of different possibilities for selecting 3 class I railroads from 10 class I railroads = 10C3 = (10 x 9 x 8)/(3 x 2 x 1) = 120

Number of different possibilities for selecting 2 class II railroads from 6 class II railroads = 6C2 = (6 x 5)/(2 x 1) = 15Number of different possibilities for selecting 1 class III railroad from 5 class III railroads = 5C1 = 5Total number of different possibilities for selecting 3 class I railroads from 10 class I railroads, 2 class II railroads from 6 class II railroads, and 1 class III railroad from 5 class III railroads = 10C3 x 6C2 x 5C1= 120 x 15 x 5= 6300Therefore, there are 6300 different possibilities for the researcher’s study.

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For the transformations of translation, the following is correct -

A. by vector (7, 11).

What is translation?

A translation in mathematics does not turn a shape; instead, it moves it left, right, up, or down. They are congruent if the translated shapes (or the image) seem to be the same size as the original shapes. They have only changed their direction or directions.

The single transformation that represents the following sequence of transformations -

i) a translation vector by (2, -3) followed by

ii) a translation vector by (-5, 8)

is a translation by the vector (-3, 5).

To see why, we can combine the two translation vectors by adding them component-wise -

(2, -3) + (-5, 8) = (-3, 5)

This vector represents the total displacement of a point on the plane after both translations are applied.

So, a single translation by the vector (-3, 5) will have the same effect as applying both of the original translations in sequence.

Therefore, the correct statement is, by vector (7, 11).

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The difference between the numbers whose sum is of 96 and have a ratio of 11:1 is of 80.

The difference between the two amounts is obtained applying the proportions in the context of the problem.

The variables that are going to represent the two amounts are given as follows:

x and y.

The sum of two numbers is 96, hence:

x + y = 96.

The ratio between them is 11:1, hence:

x/y = 11.

x = 11y.

Replacing the second equation into the first, the value of y is given as follows:

y + 11y = 96

12y = 96

y = 8.

The value of x is given as follows:

x = 11 x 8 = 88.

The difference is then given as follows:

x - y = 88 - 8 = 80.

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Step-by-step explanation:

You need solve for y:

[tex]y-4=3(x-1)\\y-4=3x-3\\y=3x-3+4\\\therfore \quad y=3x+1[/tex]

now, evaluate in each x's value, for example:

[tex]y=3(-2)+1\\\therefore \quad y=-5[/tex]

This, is the value of [tex]y[/tex], when [tex]x=-2[/tex]

Therefore:

[tex]\begin{tabular}{|c|c|} \cline{0-1}x & y \\ \cline{0-1}-2 & -5 \\ -1 & -2\\ 0& 1 \\ 1& 4\\ 2& 7\\ \cline{0-1}\end{tabular}[/tex]

[tex]\text{-B$\mathfrak{randon}$VN}[/tex]

The information for a 95% confidence interval for the mean cholesterol are:Sample mean = x = 161.5 Standard Deviation = σ = 19.5 Sample size = n = 169 Z or t = Z Standard Error (Rounded to nearest tenth)= 1.5 Margin of Error (Rounded to nearest tenth) = 2.83 Lower limit (Rounded to nearest tenth) = 158.67 Upper limit (Rounded to nearest tenth) = 164.33

Given that the sample size, n = 169, sample mean, x = 161.5, and population standard deviation, σ = 19.5 are to be used to compute the confidence interval for the mean cholesterol. We are to find the following information for a 95% confidence interval for the mean cholesterol.

We know that if the population standard deviation is known and the sample size is greater than 30, then we use the z-value instead of the t-value. Since the sample size is n = 169, we can use the z-value. Z or t = Z For a 95% confidence level, α = 0.05/2 = 0.025 Zα/2 = Z 0.025 (from the standard normal distribution table)Z 0.025 = 1.96 The formula to calculate the standard error of the mean cholesterol is:Standard error = σ/√n=19.5/√169= 1.5

The margin of error is given by Margin of error = Zα/2 × (σ/√n)Margin of error = 1.96 × (19.5/√169)= 2.83 (rounded to the nearest tenth)The lower limit and upper limit of the confidence interval are given by the formulas:Lower limit = x - Margin of error Upper limit = x + Margin of error Lower limit = 161.5 - 2.83 = 158.67 (rounded to the nearest tenth)Upper limit = 161.5 + 2.83 = 164.33 (rounded to the nearest tenth)

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x³ + 343 = (x + 7) (x² - 7x + 49)    is the function.

A relation is any subset of a Cartesian product.

As an illustration, a subset of is referred to as a "binary connection from A to B," and more specifically, a "relation on A."

A binary relation from A to B is made up of these ordered pairs (a,b), where the first component is from A and the second component is from B.

Every item in a set X is connected to one item in a different set Y through a connection known as a function (possibly the same set).

A function is only represented by a graph, which is a collection of all ordered pairs (x, f (x)).

Every function, as you can see from these definitions,

is a relation from X

Hence, x³ + 343 = (x + 7) (x² - 7x + 49)    is the function.

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[tex]x=30^o,270^o \ [0^0\leq x\leq 360^0][/tex]

Explanation:

We know,

[tex]cos2x=cos^2 \ x-sin^2 \ x=1-2sin^2 \ x[/tex]

So, let's solve the equation now,

[tex]sin \ x=cos2x=1-2 \ sin^2 \ x[/tex]

[tex]\longrightarrow \ 2 \sin^2 \ x+sin \ x-1=0[/tex]

[tex]\longrightarrow \ 2 \sin^2 \ x+2\sin x-sin \ x-1=0[/tex]

[tex]\longrightarrow \ 2\sin \ x(sin\ x+1)-1(sin \ x+1)=0[/tex]

[tex]\longrightarrow \ (2\sin \ x-1)(sin \ x+1)=0[/tex]

Now,

[tex]2\sin \ x-1=0[/tex]

[tex]\longrightarrow \ sin \ x=\dfrac{1}{2}[/tex]

[tex]\longrightarrow x=sin^{-1}(\dfrac{1}{2})[/tex]

[tex]\longrightarrow x=30^o[/tex]

And, [tex]sin \ x+1=0[/tex]

[tex]\longrightarrow x=sin^{-1}(-1)=270^o[/tex]

As we just need the general solutions, we should take only this two values as the general solutions.

Answer:

[tex]30^0,270^0[/tex]

That's it!

The sum of the real and imaginary parts of $c$ is$$\operatorname{Re}(c) + \operatorname{Im}(c) = \frac{\operatorname{Re}(2c)}{2} + \frac{\operatorname{Im}(2c)}{2}$$$$= \frac{\operatorname{Re}(z_0+z_2)}{2} - \frac{\operatorname{Im}(z_0)}{2}(1-\cos(\theta/2)) - \frac{\operatorname{Re}(z_0)}{2}\sin(\theta/2)$$$$+ \frac{\operatorname{Im}(z_0+z_2)}{2} - \frac{\operatorname{Re}(z_0)}{2}(1-\cos(\theta/2)) + \frac{\operatorname{Im}(z_0)}{2}\sin(\theta/2).$$

The given problem can be solved using algebraic and geometric methods. We can use algebraic methods, such as the equations given in the problem, and we can use geometric methods by visualizing what the problem is asking. To start, let's translate the given problem into mathematical equations. Let $z_0$ be the original complex number. We want to rotate this point by 90 degrees counter-clockwise about some complex number $c$ to get $z_2$. Thus,$$z_2 = c + i(z_0 - c)$$$$=c + iz_0 - ic$$$$= (1-i)c + iz_0.$$We also know that this transformation will rotate the point $z_1 = (z_0 + z_2)/2$ by 45 degrees. Thus, using similar logic,$$z_1 = (1-i/2)c + iz_0/2.$$Now let's use the formula for rotating a point about the origin by $\theta$ degrees (where $\theta$ is measured in radians) to find a relationship between $z_1$ and $z_0$.$$z_1 = z_0 e^{i\theta/2}$$$$\implies (1-i/2)c + iz_0/2 = z_0 e^{i\theta/2}$$$$\implies (1-i/2)c = (e^{i\theta/2} - 1)z_0/2.$$We can solve for $c$ by dividing both sides by $1-i/2$.$$c = \frac{e^{i\theta/2} - 1}{1-i/2}\cdot\frac{z_0}{2}.$$We can now use the information given in the problem to solve for the sum of the real and imaginary parts of $c$. We know that rotating $z_0$ by 90 degrees counter-clockwise will result in the complex number $z_2$. Visually, this means that $c$ is located at the midpoint between $z_0$ and $z_2$ on the line that is perpendicular to the line segment connecting $z_0$ and $z_2$. We can use this geometric interpretation to solve for $c$. The midpoint of the line segment connecting $z_0$ and $z_2$ is$$\frac{z_0+z_2}{2} = c + i\frac{z_0-c}{2}.$$Solving for $c$, we get$$c = \frac{z_0+z_2}{2} - \frac{i}{2}(z_0-c)$$$$\implies 2c = z_0+z_2 - i(z_0-c)$$$$\implies 2c = z_0+z_2 - i(z_0- (e^{i\theta/2} - 1)(z_0/2)/(1-i/2)).$$We can now find the real and imaginary parts of $c$ and add them together to get the desired answer. Let's first simplify the expression for $c$.$$2c = z_0+z_2 - i(z_0 - (e^{i\theta/2} - 1)\cdot(z_0/2)\cdot(1+i)/2)$$$$= z_0 + z_2 - i(z_0 - z_0(e^{i\theta/2} - 1)(1+i)/4)$$$$= z_0 + z_2 - i(z_0 - z_0e^{i\theta/2}(1+i)/4 + z_0(1-i)/4)$$$$= z_0 + z_2 - i(z_0(1-e^{i\theta/2})/4 + z_0(1-i)/4)$$$$= z_0 + z_2 - i(z_0/4(1-e^{i\theta/2} + 1 - i))$$$$= z_0 + z_2 - i(z_0/2(1-\cos(\theta/2) - i\sin(\theta/2)))$$$$= z_0 + z_2 - i(z_0(1-\cos(\theta/2)) + z_0\sin(\theta/2) - i(z_0\cos(\theta/2))/2.$$Now we can find the real and imaginary parts of $2c$ and divide by 2 to get the real and imaginary parts of $c$. We have$$\operatorname{Re}(2c) = \operatorname{Re}(z_0+z_2) - \operatorname{Im}(z_0)(1-\cos(\theta/2)) - \operatorname{Re}(z_0)\sin(\theta/2)$$$$\operatorname{Im}(2c) = \operatorname{Im}(z_0+z_2) - \operatorname{Re}(z_0)(1-\cos(\theta/2)) + \operatorname{Im}(z_0)\sin(\theta/2).$$Thus, the sum of the real and imaginary parts of $c$ is$$\operatorname{Re}(c) + \operatorname{Im}(c) = \frac{\operatorname{Re}(2c)}{2} + \frac{\operatorname{Im}(2c)}{2}$$$$= \frac{\operatorname{Re}(z_0+z_2)}{2} - \frac{\operatorname{Im}(z_0)}{2}(1-\cos(\theta/2)) - \frac{\operatorname{Re}(z_0)}{2}\sin(\theta/2)$$$$+ \frac{\operatorname{Im}(z_0+z_2)}{2} - \frac{\operatorname{Re}(z_0)}{2}(1-\cos(\theta/2)) + \frac{\operatorname{Im}(z_0)}{2}\sin(\theta/2).$$

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The Statement 1: She is 95% confident that the mean systolic blood pressure for students in the sample is between 108.6 and 120.3 mm Hg. This statement is accurate and conveys the meaning of a 95% confidence interval.

The confidence interval is the range of values within which a statistical parameter is estimated to be accurate with a certain level of confidence.

A confidence interval gives an estimated range of values which is likely to include an unknown population parameter. Suppose that a student is working on a statistics project using data on systolic blood pressure collected from a random sample of 100 students from her college.

Statement 2: She is 95% confident that mean systolic blood pressure for students is between 108.6 and 120.3 mm Hg. This statement is inaccurate because the confidence interval obtained from the sample cannot be generalized to the entire population of students.

The correct statement should mention that the confidence interval is only for the random sample.Statement 2 is the incorrect statement.

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Step-by-step explanation:

it would mean that she made 53 batches of soap and 4 batches of lotion.

now, is it a solution ?

then both inequalities must be true with these values.

5×53 + 15×4 <= 325

265 + 60 <= 325

325 <= 325 correct

20×53 + 35×4 <= 1200

remember, 1 hour = 60 minutes.

1060 + 140 <= 1200

1200 <= 1200 correct

so, (53, 4) is the intersection point of both limit lines. and it is as such an extreme point and optimum.